Stresses in Pavements
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Transcript of Stresses in Pavements
Stresses in Pavements
Introduction to Vehicle Pavement Interaction (VPI)
Vehicle pavement interaction (VPI) is a system in which mutual forces develop between the
vehicle tyre and the pavement surface. The VPI describes all the components related to vehicle
and pavement and their effect on each other including their influence on expected output. The
basic elements involved with their associated characterises as inputs to the VPI may be broadly
classified as three types, which are (a) pavement profile or roughness, (b) vehicle
characteristics including its operating conditions and (c) pavement layered structures with
their stiffness values. Applications of dynamic loads through tyre rolling cause transient
pavement responses that differ from the static type of loading effects. The incorporation of
this transient nature of loading effect into the design of pavements and vehicles is the most
important issue associated with VPI.
2.1 Components of Vehicle Pavement Interaction (VPI)
There are different types of models based on different parametric components and their
defined interface conditions. These models are analysed to determine the resulting pavement
stresses, strains and deflections.
The details of the main components with their representing interface conditions considered
for modelling VPI may be categorised as given below (Collop and Cebon, 1995).
(a) Longitudinal profile of pavement: - The surface profile characteristics in terms of unevenness
(BI), roughness (IRI or PI), texture and surface friction (SN) are considered to be the main causes
for dynamic tyre loads
(b) The vehicle characteristics: - The Vehicle/ tyre loading history (i.e., time versus loading
intensity) under the influence of pavement surface is modelled with vehicular characteristics
such as suspension system, axle loads with configuration, tyre contact area, speed, vehicle
dimension and acceleration/deceleration.
(c) Stiffness or resilience characteristics of pavement layered structure: - The resulting response
(i.e., stress/strain/deflection) due to the above input conditions of loading is analysed with
defined boundary conditions of pavement layered structure. With reference to the calculated
and measured responses in terms of stresses or strains or deflections (or also in combination)
are evaluated to evolve failure criteria of pavement and such analysis results are ultimately
used for design of mixes and thickness.
(d) Criteria considered for evaluation of VPI The type of analysis to be carried out and the
decision criteria depend on the type of analysis method used such as linear, elastic or a
combination of methods such as non-linear elastic or finite element methods. Based on these
results, a suitable type of pavement/structure will be designed with appropriate economic
models (i.e., life cycle cost analysis-LCCA), as final decision for construction.
The nature of VPI largely depends on special relationship between vehicle tyre dynamic loads,
pavement profile characteristics, pavement structural strength variation and the response of
vehicle suspension system (Divine, 1997). The following methods are widely used to consider
the above components (Styen et al., 2012)
Stresses in Flexible Pavements
3.1 Engineering Properties of Bituminous Materials
The behaviour of bitumen is determined with reference to anticipated climatic conditions and
intensity of traffic loads. These input parameters play a vital role during selection of suitable
binders for construction of pavements. Thus, engineering properties of bitumen should be
determined considering the following factors.
β’ Temperature (maximum, minimum and average values)
β’ Loading time
β’ Intensity of load Bitumen behaves differently in different combinations of the above values.
For example, bitumen behaves elastic under short duration of loading at normal temperature.
But, in case of prolonged loading and as the temperature increases, it loses elasticity and flows
like a fluid. This is the reason why bituminous pavements at higher temperature tend to deform
without cracking.
3.1.1 Stiffness Modulus of Bitumen
In 1954, van der Pod developed the concept of a stiffness modulus for thermoplastic polymers
which was useful for determining of the engineering properties of bitumen. The concept NOS
modified by Heukelom and Klomp (1964) and Heukelom (1973). In this method, the bitumen
is characterised by its stiffness modulus, (ail), the ratio between applied stress to the observed
strain at a given time of loading (t in s) and temperature (T in Β°C). The value of the stiffness
modulus of bitumen may be expressed as follows.
Ebit (t,T)= stress/ strain at (t,T)β¦β¦β¦β¦β¦β¦.3.1
The above equation holds good and is suitable for in service pavements if the assumed strain
is not more than 1 per cent. If the loading time changes, preferably under variable
temperatures similar to seasonal variations, the value of stiffness of bitumen also changes. To
account for this variability of the stiffness modulus of bitumen, a stiffness nomograph was
developed by van der Poel and modified by Heukelom based on three parameters, viz. time of
loading (t), temperature difference (T-T800 pen) and penetration index (PI). The equation
developed by Heukelom and Klomp (1964) or a method prescribed by Bonnaure et al. (1977)
may be used to determine the stiffness values of bituminous mixes. Measured stiffness values
greatly agree with the values predicted by Bonnaure's method and it is adopted by the Shell
method (1977) of the asphalt pavement design (Ullidtz and Peattie 1980). To understand the
implication of the true engineering properties of bitumen at different ranges of temperatures
from cold to hot under cyclic loading similar to field conditions, it is necessary to know its visco-
elastic properties.
3.1.2 Visco-elastic Properties of Bituminous Materials
Bitumen becomes hard and soft by cooling and heating respectively. These states of bitumen
may be reversed as and when required. This property of bitumen is known as thermos-
plasticity. Based on temperature and rate of loading, the bitumen may behave like a dual
characteristic material. Elastic material at a given temperature, the material undergoes
immediate deformation or strain under loading and immediately recovers upon unloading. In
other words, if the material is linear elastic, the stress is proportional to the strain according to
Hooke's law, i.e., stress = Young's modulus value x strain (Wilhelm Flugge 1975). Viscous
material At a given temperature, the material undergoes delayed deformation or strain under
loading but it may or may not recover its initial conditions. A Newtonian material will recover
completely. But in Bingham materials, power law fluids and pseudo-plastic materials, complete
recovery of strain will not take place due to plastic straining during loading. In other words, if
the material is viscous, the stress is proportional to the strain rate (Wilhelm Flugge 1975).
Bitumen exhibits intermediate characteristics ranging from elastic to viscous and vice versa
due to change in temperature and rate of application of load. Because of this, bituminous mixes
are known as visco-elastic materials. The behaviour of visco-elastic material depends on
temperature, time and frequency of loading.
Figure 3.1 Phase difference between stress and strain (Yang 2004; Relent 2001)
When a visco-elastic material is subjected to sinusoidal loading (Figure 3.1), the occurrence of
strain (Co) is delayed due to the phase difference of the applied stress (0-0) at a given time (t).
This difference of response is known as phase angle (y). As the material transforms from being
elastic to visco-elastic during change of temperature, the value of the phase angle (9) changes
from 0 Β°C to 90 Β°C. The energy dissipated by the material is determined by using the phase
angle value. The values of complex modulus and dynamic complex modulus of bitumen are
determined from the following popularly known relationships (Huang 2004; Di Benedetto et
al. 2001 and Kailas 1970). Complex modulus (E*) = Real part of modulus value + Imaginary part
of modulus value
β¦β¦β¦β¦β¦β¦.3.2 πΈβ(π, π‘) = (ππ/ππ) sin (ππ‘) +i. (ππ/ππ) sin(ππ‘ β β )
Dynamic modulus = Absolute value of complex modulus = [E]*. β¦β¦β¦β¦β¦β¦ (3.3)
If the viscous effect is ignored, the ratio between the maximum values of stress to strain is
termed as the elastic modulus. The values of complex bulk modulus (K*) and shear modulus
(G*) may be determined from the following popularly known relationships.
K* = E*/ (3 β 6Β΅) β¦β¦β¦.. (3.4) G* = E/ [2(1+ Β΅)] β¦β¦β¦β¦β¦ (3.5)
Where, Β΅ = Poisson's ratio
To characterise visco-elastic properties of binders at lower temperatures, another parameter
called the creep compliance is used. The creep compliance may be calculated using the
following relationship.
D (t, T) = 1 / E bit (t, T)β¦β¦β¦β¦. (3.6)
Shear compliance is also used to characterise the visco-elasticity of bituminous materials. The
following relationship is used to calculate shear compliance (J (t, T)).
J (t, T) = 3/ E bit (t, T) (3.7) β¦β¦β¦β¦β¦.3.7
The above equations holds good if the material is assumed to be linear visco-elastic and
isotropic. The values of dynamic modulus, bulk modulus, shear modulus, creep compliance and
shear compliance provide important information to explain the visco-elastic behaviour of the
bituminous mix over a range of temperature and frequency of loading.
STRESS ANALYSIS OF FLEXIBLE PAVEMENTS
3.2.1 BOUSSINESQ'S THEORY (SINGLE LAYER THEORY)
In 1885, Boussinesq presented a theory for calculating the stresses in soil mass based on the
following assumptions.
1. The soil is homogenous (without any stratification) and isotropically linear elastic which
means that it abides by Hook's law.
2. The soil mass boundary is a semi-infinite elastic half-space.
3. The load is applied on to a level surface.
4. The soil mass is weightless.
The following equations are based on Boussinesq's theory and are widely used to calculate
stresses in soil mass.
CASE 1: Point load
Figure 3.2 Stress due to point load
Consider a point load on the soil mass as depicted in Figure 3.2.
Vertical stress due to point load ππ§ =3π
2ππ§2
1
[+(ππ§β )2]5/2β¦β¦β¦β¦.3.8
CASE 2:
Uniformly distributed load over a circular area generally, for pavement analysis, the equivalent
circular contact area of a tyre on pavement surface is taken.
For this purpose, a uniformly loaded circular area is considered for calculating the stresses in
the soil mass. To calculate stresses under a uniformly loaded area using flexible plates (similar
to a rubber tyre), equation (3.8) may be integrated over the circular area (Figure 3.3).
3
Figure 3.3 Stress under a uniformly loaded circular area
β« β« (3π((πππ)ππ)
2ππ§2
π
0[
2π
0
1
1+(π/π§)2]β¦β¦β¦β¦1
The above equation can be simplified as
Vertical stress under the centre of the circular area (ππ§)= π(1 β [1
1+(π/π§)2]3/2β¦. 2
Horizontal or radial stress beneath the centre of circular area,(ππ)
(ππ)= 0.5π[(1 + 2π) β (2π§(1+π)
β(π2+π§2)+ (
π§3
(π2+π§2)32
)]β¦β¦β¦β¦ 3
Elastic vertical displacement at z=0, under a circular flexible plate βπ =2ππ(1βπ2)
πΈβ¦β¦β¦β¦ 3
If π = 0.5 the above equation can be written as βπ =1.5ππ
πΈ β¦β¦.. 4
Where, π= uniformly distributed pressure
π= radius of circularly loaded area
πΈ= Elastic modulus of soil
π= Poissonβs ratio of soil
The stress distribution under the flexible plate is uniform since the flexible plate bends (or
flexes) under loading, similar to a rubber sheet. Therefore; the elastic surface deflection under
the flexible plate is non-uniform. If a circular rigid plate (or steel plate) is used to apply load on
to the soil, the elastic surface displacement is uniform but the stress' distribution is non-
uniform (Ullidtz 1987). Analysis of plate load test data is one of the best examples of an
application of Boussinesq's theory. The following formula may be used to calculate the elastic
surface deflection under a rigid plate.
Vertical displacement at z=0, under a circular rigid plate (βπ ) =πππ(1βπ2)
πΈβ¦.. 5
If π = 0.5 the above equation can be written as βπ =1.18ππ
πΈβ¦β¦ 6
Q. A semi-infinite soil mass is subjected to stress under a circular plate having a 15 cm radius.
The load intensity over the plate is 4000 kg. Calculate the vertical stress in the soil under the
axis of the circular plate at 2 m depth.
Solution: - Intensity of pressure over plate = 4000/ (n x 152) = 5.66 kg/cm2.
Use equation 2
(ππ§)= 5.66(1 β [1
1+(15/2)2]3/2
= 5.64kg/cm2
Q. Calculate the rebound surface deflection on single layer pavement under a wheel load of
40KN with a tyre pressure of 0.8 Mpa. The effective elastic modulus of sub-grade may be taken
as 40MPa and Poissonβs ratio of the soil as 0.5
Solution π‘π¦ππ ππππ π π’ππ = ππ»πΈπΈπΏ πΏππ΄π·
πππ πΈ πΆππππ΄πΆπ π΄π πΈπ΄
πΉπ¨π«π°πΌπΊ πΆπ π»ππΉπ¬ πͺπΆπ΅π»π¨πͺπ» π¨πΉπ¬π¨ = π βπΎπ―π¬π¬π³ π³πΆπ¨π«
π πΏ π»ππΉπ¬ π·πΉπ¬πΊπΊπΌπΉπ¬
π βπππΏπππ
π πΏ π.ππΏπππ= 0.126m = 12.6 cm
Intensity of pressure =π =ππππ
ππππ=
ππππππ
π ππ.ππππ= 80990.14N/m2
If a flexible pavement is considered, rebound surface deflection= βπ =1.5ππ
πΈ
βπ =1.580990.14π₯0.126
40π₯106= 0.00378m= 3.78mm
TWO LAYER THEORY
3.2.2 Burmister's Theory
In 1943, Donald M. Burmister developed a method of analysing a two-layered soil system which
resembled a flexible pavement having its top layer stiffer than its bottom layer. Later, ' in 1945,
he extended the method to include three-layered system. As an important outcome of
Burmister's numerical solutions, the flexible pavement thickness design method was
developed for airfield pavements (ASCE vol.115, 1950).
In 1962, Ahlvin and Ulery of the US Army Corps of Engineers (USACE) reported solutions for
calculating the stresses, strains and deflections on a homogenous half-space withstanding a
uniform circular load (Ahlvin and Ulery) 1962). Since then, the Burmister's theory with required
modifications is being used for various pavement engineering applications.
Many researchers have developed different methods for analysing multi-layered systems
based on elastic, non-linear, visco-elastic and finite element methods. The solution of various
problems related to a multi-layered system is made easy by the use of computers. Burmister's
two-layered system of analysis is briefly explained below.
Assumptions
β’ Every layer material is homogenous, isotropic and ideally elastic. They are characterised by a
unique elastic modulus and Poisson's ratio.
β’ A pavement consists of two layers. The elastic modulus value" of the top layer is more than
the bottom layer (i.e., El > E2).
β’ The layers are weightless and infinite in the horizontal direction.
β’ The top layer has finite thickness (h) but the bottom layer is infinitely thick.
β’ The top layer is in full contact with the bottom layer.
β’ The interface between these layers is rough and there is no loss of transfer of applied stress
from the top layer to the bottom layer.
β’ There will be no shear and normal stresses outside the loaded area.
β’ The applied stress is uniform over a circular area. The displacement. equations given by
Burmister for a two-layered system are as follows (Figure 3.4).
Surface deflection under the centre of the flexible plate= β=1.5ππ
πΈ2xπΉd
Surface deflection under the centre of the flexible plateβ=1.18ππ
πΈ2xπΉd
where, β = Vertical deflection at surface (when z = 0)
β’ P = Uniform pressure on circular plate
a = Radius of the circular plate
E2 = Elastic modulus of sub-grade
Fd = Displacement factor, depends on ratios of E1/E2 and h/a Refer to Figure 3.5
E1 = Elastic modulus of the top layer
h = Thickness of the top layer
Fig- 3.5 Burmisterβs two layered system
By introducing additional pavement layers over the sub-grade; the vertical stress induced on
the sub-grade, exactly under the centre of the loading plate, can be reduced from 68% to 30%.
To make this possible, the radius of the additional layer has to be equal to the radius of the
loading plate, the elastic modulus value of the additional layer has to be approximately equal
to ten times the elastic modulus value of the sub-grade (E1 β 10E2) and Poisson's ratio of both
the layers has to be equal to 0.5. Due to this reason, construction of pavements is carried out
in multiple layers instead of a single thicker layer.
πΈ. π«ππππππππ πππ ππππππππ πππππππππ ππ ππ ππππππππ ππππππππ ππππππππ
πππππ ππ π©ππππππππβ²π ππππππ πππππ πππ πππππππππ πππππ ππππ ππππ (π·. π³π)π πππ
πππ πππππ πππππ ππππππππππ:
π«πππππππ ππ πππππ ππππ β ππππ
β’ π·πππππππ ππππππππ ππ π. ππ ππ π πππππππππ ππππ πππ πππππ ππππ ππππ ππ ππππ πππππ
ππ πππ πππππππ π π. ππππ/πππ. π·πππππππ ππππππππ ππ π. ππ ππ π πππππππππ ππππ
πππ πππππ ππππ ππππ ππ ππππ πππππ ππ π ππππ ππππππ ππ πππ πππππππππ
= π. π ππ/πππ. π«πππππ πππππ ππππ = πππππ ππ; π»πππ ππππππππ
= ππ ππ/πππ; (π) π°π πππππππππ π πππππππππ
= π. πππ ππ πππ (π). π°π πππππππππ π πππππππππ. = π. ππ ππ
Solution:- (π)π«ππππππππππππ ππ πππ πππππππ πππ ππππ ππ πππ πππ
β ππππ π ππππ π πππππ ππππ ππππ ππππ πππππ . ππ πππ πππ β ππππ π
ππππ πππ πππππ πππ ππππππππππππ, π πππππππππ β=1.18ππ
πΈ2
πππππ, π¬π ππ πππ πππππππ πππ ππππ ππ πππ πππ β ππππ π πππ
π =π πππππππ ππ πππππ
π=
ππ
π= ππ. πππ
πΆπ ππππππππππππ ππ ππππππ
π. πππ ππ = π. πππΏ
π. πππππππ πΏππ. πππ)
π¬π
π¬π = πππ. ππππ/πππ
(ii) Determination of elastic modulus of granular layer from the results of a plate load test conducted
on a granular layer
Use this equation for deflection β=
1.18ππ
πΈ2xπΉπ
πΉπ ππ π βπππ ππππ‘ππ πππ ππ ππ π‘βπ πππ‘πππ ππ β
π πππ
πΈ1
πΈ1 πππ πΈ2 ππ ππππ π‘ππ ππππ’ππ’π ππ π‘βπ π π’ππππππ
πΉπ = 0.39 πππ‘ππ ππ β
π=
16ππ
37.5 ππ= 0.426
πππ€ ππππ π‘βπ π£πππ’π ππ πΈ1
πΈ2 πππ‘ππ ππππ π‘βπ ππππ’ππ 3.5 β΄
πΈ1
πΈ1 = 200 β΄ πΈ1 = 200πΈ2; πΈ1 = 200π₯290.28 = 58056ππ/ππ2
(III) DESIGN OF FLEXIBLE PAVEMENT:-
π‘π¦ππ ππππ‘πππ‘ ππππ ππ πππ£πππππ‘ = πππ2 π€βπππ π = πππππ’π ππ π‘π¦ππ ππππ‘πππ‘ ππ πππ£πππππ‘
πππ2 =ππ»πΈπΈπΏ πΏππ΄π·
πππ πΈ ππππ π π’ππ=
23000ππ
15ππ/ππ2 β΄ π = 22.09ππ
π€π ππππ€ π‘βππ‘ π‘βπ πππππππ‘πππ πππ’ππ‘πππ πππ π ππππ₯ππππ πππππ’πππ ππππ‘π ππ βπ= 1.5π. π
πΈ2πΉπ
(a)if allowable deflection = 0.125cm therfore on substituting the values, we get
0.125 = 1.515ππ/ππ2π22.09ππ
290.28ππ/ππ2πΉπ
Therefore πΉπ = 0.073
πππ€ π‘βπ πππ‘ππ ππ β
ππππ ππ ππ
πΈ1
πΈ2= 200
β
π= 2.79, β β = 2.79ππ = 2.79π22.09 = 61.63ππ
Therefore for the base course provide a thickness of 62cm
(b)if allowable deflection = 0.50cm
0.50 = 1.515ππ/ππ2π22.09ππ
290.28ππ/ππ2 πΉπ πΉπ = 0.438
πππ€ π‘βπ πππ‘ππ ππ β
ππππ ππ ππ
πΈ1
πΈ2= 200
β
π= 0.36, β β = 0.36ππ = 0.36π22.09 = 7.95ππ
Therefore for the base course provide a thickness of 8cm
3.2.3 Linear Elastic Multi-Layered Pavement System
πΌπ ππππππ‘π¦, π ππππ₯ππππ πππ£πππππ‘ ππ π ππ’ππ‘ππππ¦ππππ π π‘ππ’ππ‘π’ππ ππ π€βππβ πππβ πππ¦ππ ππ ππππ π‘ππ’ππ‘ππ π€ππ‘β πππππππππ‘ π‘βππππππ π (β), πππβ βππ£πππ π πππ ππππ‘ππ£π πππ‘πππππ πβπππππ‘ππππ π‘πππ π π’πβ ππ π‘βπ ππππ π‘ππ ππππ’ππ’π (πΈ)πππ ππππ π ππβ²π πππ‘ππ (Β΅). π΄ π‘π¦πππππ πππππππ’πππ‘πππ ππ π πππππ’πππ ππππ‘π π π’πππππ‘ππ π‘π π π’ππππππ ππππ π π’ππ (π) ππππππ ππ π ππ’ππ‘πβ πππ¦ππππ πππ£πππππ‘ π π¦π π‘ππ ππ ππππππ‘ππ ππ πΉπππ’ππ 3.9. πβπ ππππππ€πππ ππ π π’πππ‘ππππ πππ πππππππππ¦ ππππ πππ πππππ¦π ππ ππ π π‘πππ π ππ , π π‘πππππ πππ πππππππ‘ππππ ππ π ππ’ππ‘π β πππ¦ππππ ππππ₯ππππ πππ£πππππ‘ π π¦π π‘ππ. β’ πβπ πππ‘π‘ππ (ππ‘β) πππ£ππ ππ π‘βπ π π’π β πππππ πππ βππ ππ πππππππ‘π π‘βππππππ π . β’ π΄πππ£π π‘βπ π π’ππππππ, πππβ πππ£ππ βππ π πππππ‘π π‘βππππππ π πππ πππππππ‘π ππππππ πππ ππ π‘βπ βππππ§πππ‘ππ ππππππ‘πππ.
β’ πβπ π πππ/π€πππβπ‘ ππ π‘βπ π π’π β πππππ πππ ππ‘βππ πππ¦πππ πππ ππππ ππππππ ππ π€πππβπ‘πππ π πβπππ ππ ππ πππ π ππ π π‘πππ π ππ‘ πππβ πππ¦ππ πππ‘ππππππ. πβπ πππ¦πππ πππ πππππππ‘ππ¦ ππ ππππ‘πππ‘ π‘βπ π‘ππ πππ. πππ‘π‘ππ π π’ππππππ . π΅π’π‘ πππ π πππ πππ‘βπππ , π π ππππ‘β πππ¦ππ πππ‘ππππππ πππ¦ ππ ππππ ππππππ. β’ πβπππ ππ ππ π βπππ π π‘πππ π ππ ππππππ πππ πππππππππ‘ ππ π‘βπ π‘ππ πππ¦ππ. β’ πβπ π π’πππππ ππ π‘βπ π‘ππ πππ¦ππ ππ πππππππ‘ππ¦ βππππ§πππ‘ππ πππ βππ ππ π’πππ’πππ‘ππππ . β’ ππππ¦ π π‘ππ‘ππ πππππ πππ ππππ ππππππ. β’ πΈππβ πππ¦ππ ππ π‘βπ πππ£πππππ‘ π π¦π π‘ππ ππ ππππππππ¦ β ππππ π‘ππ βππππππππ’π πππ ππ ππ‘πππππ. β’ πβπππ π€πππ ππ ππ π π‘πππ π ππ , π π‘πππππ πππ πππππππ‘ππππ ππ‘ πππππππ‘π ππππ‘β ππ π‘βπ π π’π β πππππ.
Figure 3.9.- Multi-layered pavement system
Ξ¦(r, z) = [{π΄ + π΅π§}]πβππ§ + (πΆ + π·π§)πππ§}]π½π(ππ) πβπππ, π = ππππππ πππ π‘ππππ π = ππππ‘β π΄, π΅, πΆ, π· = πΈππβ πππ¦ππ ππππ π‘πππ‘π ππ πππ‘πππππ‘πππ π½π = π΅ππ π ππ ππ’πππ‘πππ ππ π‘βπ ππππ π‘ ππππ ππ πππππ π§πππ
πππ‘β π‘βπ ππππ£π π π‘πππ π ππ’πππ‘πππ πππ ππ π π’πππ‘ππππ (πππ’πππππ¦ ππππππ‘ππππ )
π‘βππ‘ π ππ‘ππ ππ¦ π‘βπ πππ£ππππππ πππππππππ‘πππ πππ’ππ‘πππ,
π‘βπ π»πππππ π‘ππππ ππππ ππ πππππππ π‘π πππ‘πππ
π π‘πππ π ππ πππ πππ πππππππππ‘π ππ π‘ππππ ππ ππ’πππππππ πππ‘ππππππ ..
πβπ πππ‘ππππ ππ π‘βπ πππππ¦π ππ πππ¦ ππ πππ‘πππππ
ππππ π½ππ’πππππ¦ πππ π΅ππβππππ§ (1962), ππππ π‘ππππ‘ππ (1967; 1972)πππ
πππ ππ€βπππ (ππβππππππ 1962; π΄π βπ‘ππ πππ ππππ£πππ§πππβ 1967).
πβπ πππππ¦π ππ πππ‘βπππ πππ ππ ππ π‘βπ
ππππ£π ππππ‘πππππ ππ π π’πππ‘ππππ πππ π’πππππππ π‘ππ ππ πππππ‘πππ ππ’π π‘π π‘βπ ππππππ€πππ ππππ πππ . β’ πΈππβ πππ¦ππ ππ π‘βπ πππ£πππππ‘ ππ πππ ππππ π‘ππ, ππβπππππππππ’π πππ ππ ππππ ππ‘πππππ π ππππ.
πβππ¦ πππ£ππ π‘ππ’ππ¦ ππππ¦ π»πππβ²π πππ€.β’ β’ πβπβ²πππ‘ππππππ π’π ππ πππ π‘βπ π π’ππππ π πππ πππ π πππ¦πππ πππ πππππ’πππ πππ‘ππππππ π€βππβ π βππ€
πππππππππ ππβππ£πππ’π ππ πππππππ. β’ πβπ π π’π β πππππ πππ¦ ππππ ππ π‘ ππ πππ β ππππππ π π‘ππππππ π π€ππ‘β ππππ‘β. β’ πβπ πππ‘π’πππππ’π π π’πππππ πππ¦ππ π βππ€π π£ππ ππππππ π‘ππ π΅πβππ£πππ’π
π€βππβ π£πππππ πππ ππ ππ πππππππ π‘πππ πππ π‘πππππππ‘π’ππ. β’ πβπ ππππ π ππβ²π πππ‘ππ ππ β²πππ£πππππ‘ πππ‘ππππππ ππ π£πππππππ πππ πππππππ ππ ππ π ππ‘π’ ππππππ‘ππππ β’ πβπ π€βπππ πππππππ ππ πππππππππ¦ ππ¦πππππ πππ π‘ππππ ππππ‘β² ππ πππ‘π’ππ. β’ πβπ πππ’πππππ¦ ππππππ‘πππ . ππ πππππ πππππππ‘π ππ π‘βπ βππππ§πππ‘ππ ππππππ‘πππ ππ πππ£ππ π π‘ππ’π ππππππ‘πππ β’ πβπππ πππ ππππππ π π‘πππ π ππ π€πππ ππ πππ£ππππππ ππ π‘βπ π π’πππππ πππ¦ππ ππ’ππππ πππππππ π€βπππ πππππ . β’ πΆππππππ πππ’ππ πππ¦πππ πππ’π π πππ ππππ‘πππ’ππ πππ π‘ππππ’π‘πππ ππ ππππ π π’ππ.
ASSIGNMENT-1
Q1. Write a short note on stiffness modulus of bitumen.
Q2. What is the limitation of Boussinesq's theory of stress analysis?
Q3. Derive an expression for determination of vertical stress under a uniformly loaded circular area
with a neat sketch.
Q4. Explain why the pressure distribution is different under flexible and rigid plates.
Q5. What is the significance of multi-layered flexible pavement analysis? Explain the
considerations/ assumptions made for analysis of stresses, strains and deflections in a multi-
layered flexible pavement system.
Q6. Define how the assumptions made in a multi-layered flexible pavement system are unrealistic
in practice or in service conditions of pavement.
Q7. List out a few programs with salient details of the analytical solution/programs of multi-layered
flexible pavements.