Theoretical Investigation of Stresses and Displacement in RC ...

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62 American Scientific Research Journal for Engineering, Technology, and Sciences (ASRJETS) ISSN (Print) 2313-4410, ISSN (Online) 2313-4402 Β© Global Society of Scientific Research and Researchers http://asrjetsjournal.org/ Theoretical Investigation of Stresses and Displacement in RC Rectangular Slab Shvan Mohamad Sharif a *, Salahuddin Ahmed b a,b Department of Civil Engineering, Salahaddin University-Erbil, Erbil, Iraq a Email: [email protected] b Email: [email protected] Abstract The aim of this paper is the static bending analysis of reinforced concrete (RC) rectangular slab using analytical methods, i.e. classical plate theories and finite element method (FEM). Three cases of rectangular slabs, in which the thickness of the plate varies, and they are simply supported. The bending stresses and deflection were determined by using different approaches of the classical theory of plates based on Love-Kirchhoff’s (L-K) hypothesis, then compared the achieved results to the numerical analysis-FEM results. For this purpose, the 3D- modelling and simulation, with the subsequent analysis of rectangular slab were done in ABAQUS computer program. Three-dimensional 8-node first order fully integration continuum elements (C3D8 - Bricks) are used to model the rectangular concrete slab. Also, three-dimensional 2-node first order truss elements (T3D2 - Truss) are used to model the steel reinforcing bars. Once deflection, bending moments and bending stresses are obtained by both methods, some approaches show close results with a significant difference. This difference in results can be explained by the fact, that FE analysis represents the exact model of rectangular plate (i.e. 3D model representation) which is consist of concrete and reinforcements 3D modeled slab with all properties for each material. All of these properties and the combination of materials cannot be done throw the classical plate theories equations. Also, classical plate theories depend on several assumptions, which has a significant effect on the results. Keywords: Stress; Bending moment; Displacement; FEM. ------------------------------------------------------------------------ * Corresponding author. CORE Metadata, citation and similar papers at core.ac.uk Provided by American Scientific Research Journal for Engineering, Technology, and Sciences (ASRJETS)

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American Scientific Research Journal for Engineering, Technology, and Sciences (ASRJETS) ISSN (Print) 2313-4410, ISSN (Online) 2313-4402

Β© Global Society of Scientific Research and Researchers http://asrjetsjournal.org/

Theoretical Investigation of Stresses and Displacement in

RC Rectangular Slab

Shvan Mohamad Sharifa*, Salahuddin Ahmedb

a,bDepartment of Civil Engineering, Salahaddin University-Erbil, Erbil, Iraq aEmail: [email protected]

bEmail: [email protected]

Abstract

The aim of this paper is the static bending analysis of reinforced concrete (RC) rectangular slab using analytical

methods, i.e. classical plate theories and finite element method (FEM). Three cases of rectangular slabs, in

which the thickness of the plate varies, and they are simply supported. The bending stresses and deflection were

determined by using different approaches of the classical theory of plates based on Love-Kirchhoff’s (L-K)

hypothesis, then compared the achieved results to the numerical analysis-FEM results. For this purpose, the 3D-

modelling and simulation, with the subsequent analysis of rectangular slab were done in ABAQUS computer

program. Three-dimensional 8-node first order fully integration continuum elements (C3D8 - Bricks) are used to

model the rectangular concrete slab. Also, three-dimensional 2-node first order truss elements (T3D2 - Truss)

are used to model the steel reinforcing bars. Once deflection, bending moments and bending stresses are

obtained by both methods, some approaches show close results with a significant difference. This difference in

results can be explained by the fact, that FE analysis represents the exact model of rectangular plate (i.e. 3D

model representation) which is consist of concrete and reinforcements 3D modeled slab with all properties for

each material. All of these properties and the combination of materials cannot be done throw the classical plate

theories equations. Also, classical plate theories depend on several assumptions, which has a significant effect

on the results.

Keywords: Stress; Bending moment; Displacement; FEM.

------------------------------------------------------------------------

* Corresponding author.

CORE Metadata, citation and similar papers at core.ac.uk

Provided by American Scientific Research Journal for Engineering, Technology, and Sciences (ASRJETS)

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1. Introduction

Nowadays, rectangular slabs are an integral part of residential and administrative buildings in modern cities. If

from a practical point of view, the application of a rectangular plate is more important than circular and annular

plates; however, the theoretical aspects are quite interesting. When using classical methods of analysis and by

making use of axial symmetry, the exact solution for a large number of problems comes within reach. This even

holds for incremental elastic-plastic calculations and anisotropic material behavior [1]. A long time ago, the

effectiveness of classical methods in the analysis of rectangular homogeneous plates (steel plates) was proven.

Another thing, when these methods are faced with such plates as reinforce concrete slabs. However, the

appearance of the computer made a turn towards numerical methods, especially the development of the

computer programs based on the FEM, for example, ABAQUS, which can solve all the nuances of the adequate

modelling during simulation ([2, 3, 4, 1, 5]) Known, that in classical plate theory, because of the smallness of

thickness dimension, it is often not necessary to model them using 3D elasticity equations. Simple 2D plate

theories can be developed to study the strains and stresses in plate structures. However, in the presence of

powerful computing tools, it is worthwhile to take a look at the stress state of plates modeled in 3D form ([6]).

When structural engineers carry out finite element analysis (FEA) of plates, in most cases, they are primarily

interested in determining the maximum value of the stresses and displacement, an indication of their location,

that is absolutely correct in terms of subsequent design ([7, 8, 9]). In modern literature, the issues of analysis of

rectangular reinforced concrete plates are covered. It complicates the use of results which were obtained in

theory and often leads to approximate methods application, due to the difficulty of applying exact methods ([6],

[10]). The flexural properties of rectangular plates largely depend on its thickness rather than its two dimensions

(length and width). The value of deflection and stresses can be determined by solving the differential equations

of an appropriate plate theory using different analytical approaches([11, 12, 13]). Fwa and his colleagues

derived Westergaard solutions for maximum bending stress and deflection, by assuming infinite slab width and

length, and ignoring possible thick plate behavior of slab under loading [14]. This paper examines the effects of

these two factors on Westergaard solutions by comparing with thick plate solutions for rectangular slabs. The

infinite slab assumption is found valid if the slab length is more than four times the radius of relative stiffness.

However, because of thick plate action, not all solutions for slab responses converge to Westergaard values

when slab sizes are large. For large slabs where the effect of slab dimensions is negligible, the difference of

thick plate solutions and Westergaard solutions for maximum bending stress are less than 15% for square slabs,

and less than 20% for 3.66 m wide rectangular slabs. For large slabs, the values of maximum deflection obtained

from the two solutions show good agreement in the case of square slabs. However, for 3.66m wide rectangular

slabs, Westergaard solutions underestimate maximum deflection by 10-70%, depending on the value of radius

of relative stiffness of the slab-on-grade system. The main aim of this research is a comparative evaluation of

the value of the maximum deflection, bending stresses in the rectangular reinforced concrete slab and the most

vulnerable locations in terms of these functions applying classical and numerical methods.

2. Structure analysis

Classical plate theory will be used for calculating flexural parameters, i.e., investigating the deflection and

stresses of the rectangular slab. The analytical results obtained from the classical plate theory will be studied

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and compared with the numerical results. Known, that creating an adequate computational model is the first

important step in a finite element analysis of plates. Before embarking on modeling, however, the geometry and

boundary conditions of the structure along with the applied loads must be clearly defined. Proper modeling

starts with a good conceptual understanding of the physical behavior of the plate, which includes the anticipated

stress and deflection patterns [15]. For more realistic approach of the FE modeling, it was decided to create a

three-dimensional model of the rectangular slab. 3D modeling helps to comprehensively investigate the value

and position of the maximum stresses and deflection under uniformly distributed load (UDL) [16].

2.1. Classical Theory

Classical plate theory is the thin plate theory based on L-K hypothesis, which makes assumptions similar to

those done by the Bernoulli-Navier hypothesis used in the theory of thin or shallow beams. It is also called a

small deflection theory. Passing through the literature of the last two centuries, it is easy to notice various

approaches to the analysis of plates in general, and rectangular plate in particular, although the source of all is

the classical theory L-K [7]. In this work, the X-Y coordinates were used, and the following fundamental

assumptions are considered in the classical small deflection theory of thin homogenous elastic plates [12, 15,

17]. The straight line initially normal to the middle surface to the plate remains straight and normal to the

deformed middle surface of the plate and unchanged in length. Displacement w is assumed to be very small.

This means the slope of the deflected surface is small and hence square of the slope would be negligible in

comparison with unity. The normal stresses Οƒx and Οƒy in-plane shear stress Ο„xy are assumed to be zero at the

middle surface of the plate. i.e. (w<<h).

Stress Οƒ z, i.e., normal transverse stress is small as compared to other stress components and may be neglected in

stress-strain relationship Οƒz<<(Οƒx, Οƒy, Ο„xy)

The midplane remains unstrained after bending.

Governing Differential equation for rectangular plate:

οΏ½πœ•πœ•4π‘€π‘€πœ•πœ•π‘₯π‘₯4

+ 2πœ•πœ•4𝑀𝑀

πœ•πœ•π‘₯π‘₯2πœ•πœ•π‘¦π‘¦2+πœ•πœ•4π‘€π‘€πœ•πœ•π‘¦π‘¦4

οΏ½ =π‘žπ‘žπ·π·

. . . . . . . (1)

Or

𝛻𝛻4𝑀𝑀 =π‘žπ‘žπ·π·

. . . . . . . (2)

Where the operator is defined as

𝛻𝛻4 = 𝛻𝛻2𝛻𝛻2. . . . . . . (3)

𝛻𝛻2 =πœ•πœ•2

πœ•πœ•π‘₯π‘₯2+

πœ•πœ•2

πœ•πœ•π‘¦π‘¦2. . . . . . . (4)

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In this research, it is customary to use the following approaches for analysis of the simply supported rectangular

RC slabs, with a plate thickness of 90,75mm and 60mm and subjected to the UDL.

Navier Solution for Simply Supported Plate[12, 13, 15]

The solution of the fourth order partial differential plate theory equation,

οΏ½πœ•πœ•4π‘€π‘€πœ•πœ•π‘₯π‘₯4

+ 2πœ•πœ•4𝑀𝑀

πœ•πœ•π‘₯π‘₯2πœ•πœ•π‘¦π‘¦2+πœ•πœ•4π‘€π‘€πœ•πœ•π‘¦π‘¦4

οΏ½ =π‘žπ‘žπ·π·

. . . . . . . (5)

π‘€π‘€β„Žπ‘’π‘’π‘’π‘’π‘’π‘’ 𝐷𝐷 =πΈπΈβ„Ž3

12(1 βˆ’ 𝑣𝑣2)

For a plate of dimensions ax, ay as shown in Fig 1 and the solution must satisfy the different boundary

conditions.

The procedural development of the Navier method using simply supported slab panel subjected to the

distributed load over the surface of the panel given by the expression

π‘žπ‘ž = οΏ½οΏ½ π‘žπ‘žπ‘šπ‘šπ‘šπ‘š π‘ π‘ π‘ π‘ π‘ π‘ π‘šπ‘šπ‘šπ‘šπ‘₯π‘₯π‘Žπ‘Žπ‘₯π‘₯

π‘ π‘ π‘ π‘ π‘ π‘ π‘ π‘ π‘šπ‘šπ‘¦π‘¦π‘Žπ‘Žπ‘¦π‘¦

. . . . . . . (6)

Figure 1: Plate with dimension ax and ay

The differential equation Eq. (5) for the deflection surface in this case becomes

οΏ½πœ•πœ•4π‘€π‘€πœ•πœ•π‘₯π‘₯4

+ 2πœ•πœ•4𝑀𝑀

πœ•πœ•π‘₯π‘₯2πœ•πœ•π‘¦π‘¦2+πœ•πœ•4π‘€π‘€πœ•πœ•π‘¦π‘¦4

οΏ½ =π‘žπ‘žπ‘šπ‘šπ‘šπ‘šπ·π·

π‘ π‘ π‘ π‘ π‘ π‘ π‘šπ‘šπ‘₯π‘₯π‘Žπ‘Žπ‘₯π‘₯

π‘ π‘ π‘ π‘ π‘ π‘ π‘šπ‘šπ‘¦π‘¦π‘Žπ‘Žπ‘¦π‘¦

. . . . . . . (7)

And the solution has to satisfy the boundary conditions:

𝑀𝑀 = 0,πœ•πœ•2π‘€π‘€πœ•πœ•π‘₯π‘₯2

= 0𝑓𝑓𝑓𝑓𝑒𝑒 β†’ π‘₯π‘₯ = 0, π‘Žπ‘Žπ‘ π‘ π‘Žπ‘Ž, π‘₯π‘₯ = π‘Žπ‘Žπ‘₯π‘₯ . . . . . . (8)

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𝑀𝑀 = 0,πœ•πœ•2π‘€π‘€πœ•πœ•π‘¦π‘¦2

= 0𝑓𝑓𝑓𝑓𝑒𝑒 β†’ 𝑦𝑦 = 0, π‘Žπ‘Žπ‘ π‘ π‘Žπ‘Ž,𝑦𝑦 = π‘Žπ‘Žπ‘¦π‘¦ . . . . . . . (9)

Consider a solution of deflection surface given by the equation,

𝑀𝑀 = οΏ½οΏ½ πΆπΆπ‘šπ‘šπ‘šπ‘š π‘ π‘ π‘ π‘ π‘ π‘ π‘šπ‘šπ‘šπ‘šπ‘₯π‘₯π‘Žπ‘Žπ‘₯π‘₯

π‘ π‘ π‘ π‘ π‘ π‘ π‘ π‘ π‘šπ‘šπ‘¦π‘¦π‘Žπ‘Žπ‘¦π‘¦

. . . . . . . (10)

In which Cmn must be chosen so as to satisfy Eq.(7). Substituting expression of Eq.(10) into Eq.(7), we find

πΆπΆπ‘šπ‘šπ‘šπ‘š =π‘žπ‘žπ‘šπ‘šπ‘šπ‘š

𝐷𝐷 οΏ½( π‘šπ‘šπ‘šπ‘šπ‘Žπ‘Žπ‘₯π‘₯ )2 + ( π‘ π‘ π‘šπ‘šπ‘Žπ‘Žπ‘¦π‘¦ )2οΏ½

2 . . . . . . . (11)

Hence, the deflection surface satisfying Eq.(7) and boundary conditions Eq.(8,9) is

𝑀𝑀 = οΏ½οΏ½ π‘žπ‘žπ‘šπ‘šπ‘šπ‘š

π‘šπ‘š4𝐷𝐷 οΏ½( π‘šπ‘šπ‘Žπ‘Žπ‘₯π‘₯ )2 + ( π‘ π‘ π‘Žπ‘Žπ‘¦π‘¦ )2οΏ½2 𝑠𝑠𝑠𝑠𝑠𝑠

π‘šπ‘šπ‘šπ‘šπ‘₯π‘₯π‘Žπ‘Žπ‘₯π‘₯

π‘ π‘ π‘ π‘ π‘ π‘ π‘ π‘ π‘šπ‘šπ‘¦π‘¦π‘Žπ‘Žπ‘¦π‘¦

. . . . . . . . (12)

If the sinusoidal load distribution is given by the equation

π‘žπ‘žπ‘šπ‘šπ‘šπ‘š =4

π‘Žπ‘Žπ‘₯π‘₯π‘Žπ‘Žπ‘¦π‘¦οΏ½οΏ½ π‘žπ‘žπ‘œπ‘œ 𝑠𝑠𝑠𝑠𝑠𝑠

π‘šπ‘šπ‘šπ‘šπ‘₯π‘₯π‘Žπ‘Žπ‘₯π‘₯

π‘ π‘ π‘ π‘ π‘ π‘ π‘ π‘ π‘šπ‘šπ‘¦π‘¦π‘Žπ‘Žπ‘¦π‘¦

π‘Žπ‘Žπ‘₯π‘₯π‘Žπ‘Žπ‘¦π‘¦. . . . . . . (13)

Where m and n are integer numbers, we can proceed as before, and we shall obtain for the deflection surface the

following expression

𝑀𝑀 = οΏ½οΏ½ π‘žπ‘žπ‘šπ‘šπ‘šπ‘š

π‘šπ‘š4𝐷𝐷 οΏ½( π‘šπ‘šπ‘Žπ‘Žπ‘₯π‘₯ )2 + ( π‘ π‘ π‘Žπ‘Žπ‘¦π‘¦

)2οΏ½2 𝑠𝑠𝑠𝑠𝑠𝑠

π‘šπ‘šπ‘šπ‘šπ‘₯π‘₯π‘Žπ‘Žπ‘₯π‘₯

π‘ π‘ π‘ π‘ π‘ π‘ π‘ π‘ π‘šπ‘šπ‘¦π‘¦π‘Žπ‘Žπ‘¦π‘¦

π‘Žπ‘Žπ‘₯π‘₯π‘Žπ‘Žπ‘¦π‘¦. . . . . . . (14)

From which the expressions for bending and twisting moments can be readily obtained by differentiation.

Levy solution [12, 13, 15]

The solution of the fourth order partial differential plate theory equation 5.

Let us consider a symmetrical case of bending in which a uniform load q is distributed over the shaded rectangle

with the sides u and v. We begin by developing the load in the series

The governing equation is,

οΏ½πœ•πœ•4π‘€π‘€πœ•πœ•π‘₯π‘₯4

+ 2πœ•πœ•4𝑀𝑀

πœ•πœ•π‘₯π‘₯2πœ•πœ•π‘¦π‘¦2+πœ•πœ•4π‘€π‘€πœ•πœ•π‘¦π‘¦4

οΏ½ =4π‘žπ‘žπ‘šπ‘šπ·π·

οΏ½(βˆ’1)(π‘šπ‘šβˆ’1)/2

π‘šπ‘šπ‘ π‘ π‘ π‘ π‘ π‘  οΏ½

π‘šπ‘šπ‘šπ‘šπ‘šπ‘š2π‘Žπ‘Ž

οΏ½ 𝑠𝑠𝑠𝑠𝑠𝑠 οΏ½π‘šπ‘šπ‘šπ‘šπ‘₯π‘₯π‘Žπ‘Ž

�∞

π‘šπ‘š=1,3,5...

… … (15)

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According to Levy approaches, the solution of governing equation (15) can be taken in series form as following,

𝑀𝑀 = 𝑀𝑀1 + 𝑀𝑀2 … … (16)

1w is a particular solution and independent of y. Substitute 1w in differential equation (15) to get,

πœ•πœ•4π‘€π‘€πœ•πœ•π‘₯π‘₯4

=4π‘žπ‘žπ‘šπ‘šπ·π·

οΏ½(βˆ’1)(π‘šπ‘šβˆ’1)/2

π‘šπ‘šπ‘ π‘ π‘ π‘ π‘ π‘  οΏ½

π‘šπ‘šπ‘šπ‘šπ‘šπ‘š2π‘Žπ‘Ž

οΏ½ 𝑠𝑠𝑠𝑠𝑠𝑠 οΏ½π‘šπ‘šπ‘šπ‘šπ‘₯π‘₯π‘Žπ‘Ž

�∞

π‘šπ‘š=1,3,5...

… … (17)

Integrate above with respect to x, to obtain,

𝑀𝑀1 =4π‘žπ‘žπ‘Žπ‘Ž4

π‘šπ‘š5𝐷𝐷�

(βˆ’1)(π‘šπ‘šβˆ’1)/2

π‘šπ‘š5 𝑠𝑠𝑠𝑠𝑠𝑠 οΏ½π‘šπ‘šπ‘šπ‘šπ‘šπ‘š

2π‘Žπ‘ŽοΏ½ 𝑠𝑠𝑠𝑠𝑠𝑠 οΏ½

π‘šπ‘šπ‘šπ‘šπ‘₯π‘₯π‘Žπ‘Ž

�∞

π‘šπ‘š=1,3,5...

… … (18)

2w is homogeneous solution of equation (15) and must satisfy the equation,

οΏ½πœ•πœ•4𝑀𝑀2πœ•πœ•π‘₯π‘₯4

+ 2πœ•πœ•4𝑀𝑀2πœ•πœ•π‘₯π‘₯2πœ•πœ•π‘¦π‘¦2

+πœ•πœ•4𝑀𝑀2πœ•πœ•π‘¦π‘¦4

οΏ½ = 0 … . . (19)

Choose the solution of equation (19) in the form,

𝑀𝑀2 = οΏ½ π‘Œπ‘Œπ‘šπ‘š 𝑠𝑠𝑠𝑠𝑠𝑠 οΏ½π‘šπ‘šπ‘šπ‘šπ‘₯π‘₯π‘Žπ‘Ž

�… … (20)∞

π‘šπ‘š=1

Substitute 2w in equation (19) to obtain,

οΏ½ οΏ½π‘Œπ‘Œπ‘šπ‘šπΌπΌπΌπΌ βˆ’ 2π‘šπ‘š2π‘šπ‘š2

π‘Žπ‘Ž2π‘Œπ‘Œπ‘šπ‘šβ€²β€² +

π‘šπ‘š4π‘šπ‘š4

π‘Žπ‘Ž4π‘Œπ‘Œπ‘šπ‘šοΏ½ 𝑠𝑠𝑠𝑠𝑠𝑠 οΏ½

π‘šπ‘šπ‘šπ‘šπ‘₯π‘₯π‘Žπ‘Ž

�∞

π‘šπ‘š=1

= 0 … … (21)

The above equation can be satisfied for all value of x only when,

π‘Œπ‘Œπ‘šπ‘šπΌπΌπΌπΌ βˆ’ 2π‘šπ‘š2π‘šπ‘š2

π‘Žπ‘Ž2π‘Œπ‘Œπ‘šπ‘šβ€²β€² +

π‘šπ‘š4π‘šπ‘š4

π‘Žπ‘Ž4π‘Œπ‘Œπ‘šπ‘š = 0 … … (22)

The general solution of the above equation is,

π‘Œπ‘Œπ‘šπ‘š =π‘žπ‘žπ‘Žπ‘Ž4

π·π·οΏ½π΄π΄π‘šπ‘š π‘π‘π‘“π‘“π‘ π‘ β„Ž οΏ½

π‘šπ‘šπ‘šπ‘šπ‘¦π‘¦π‘Žπ‘Ž

οΏ½ + π΅π΅π‘šπ‘š οΏ½π‘šπ‘šπ‘šπ‘šπ‘¦π‘¦π‘Žπ‘Ž

οΏ½ π‘ π‘ π‘ π‘ π‘ π‘ β„Ž οΏ½π‘šπ‘šπ‘šπ‘šπ‘¦π‘¦π‘Žπ‘Ž

οΏ½

+πΆπΆπ‘šπ‘š π‘ π‘ π‘ π‘ π‘ π‘ β„Ž οΏ½π‘šπ‘šπ‘šπ‘šπ‘¦π‘¦π‘Žπ‘Ž

οΏ½ + π·π·π‘šπ‘š οΏ½π‘šπ‘šπ‘šπ‘šπ‘¦π‘¦π‘Žπ‘Ž

οΏ½ π‘π‘π‘“π‘“π‘ π‘ β„Ž οΏ½π‘šπ‘šπ‘šπ‘šπ‘¦π‘¦π‘Žπ‘Ž

��… … (23)

Since the deflection of plate is symmetrical about x-axis, we keep only even function of y. So, put

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0m mC D= = to get,

π‘Œπ‘Œπ‘šπ‘š =π‘žπ‘žπ‘Žπ‘Ž4

π·π·οΏ½π΄π΄π‘šπ‘š π‘π‘π‘“π‘“π‘ π‘ β„Ž οΏ½

π‘šπ‘šπ‘šπ‘šπ‘¦π‘¦π‘Žπ‘Ž

οΏ½ + π΅π΅π‘šπ‘š οΏ½π‘šπ‘šπ‘šπ‘šπ‘¦π‘¦π‘Žπ‘Ž

οΏ½ π‘ π‘ π‘ π‘ π‘ π‘ β„Ž οΏ½π‘šπ‘šπ‘šπ‘šπ‘¦π‘¦π‘Žπ‘Ž

��… … (24)

Substitute above in expression of 2w to get,

𝑀𝑀2 = οΏ½ οΏ½π‘žπ‘žπ‘Žπ‘Ž4

π·π·οΏ½π΄π΄π‘šπ‘š π‘π‘π‘“π‘“π‘ π‘ β„Ž οΏ½

π‘šπ‘šπ‘šπ‘šπ‘¦π‘¦π‘Žπ‘Ž

οΏ½ + π΅π΅π‘šπ‘š οΏ½π‘šπ‘šπ‘šπ‘šπ‘¦π‘¦π‘Žπ‘Ž

οΏ½ π‘ π‘ π‘ π‘ π‘ π‘ β„Ž οΏ½π‘šπ‘šπ‘šπ‘šπ‘¦π‘¦π‘Žπ‘Ž

οΏ½οΏ½οΏ½ 𝑠𝑠𝑠𝑠𝑠𝑠 οΏ½π‘šπ‘šπ‘šπ‘šπ‘₯π‘₯π‘Žπ‘Ž

�∞

π‘šπ‘š=1

… … (25)

Thus, we obtain deflection in series form as,

𝑀𝑀 = 𝑀𝑀1 + 𝑀𝑀2

𝑀𝑀 = οΏ½ 𝑠𝑠𝑠𝑠𝑠𝑠 οΏ½π‘šπ‘šπ‘šπ‘šπ‘₯π‘₯π‘Žπ‘Ž

οΏ½ οΏ½π‘Žπ‘Žπ‘šπ‘š + π΄π΄π‘šπ‘š π‘π‘π‘“π‘“π‘ π‘ β„Ž οΏ½π‘šπ‘šπ‘šπ‘šπ‘¦π‘¦π‘Žπ‘Ž

οΏ½ + π΅π΅π‘šπ‘š οΏ½π‘šπ‘šπ‘šπ‘šπ‘¦π‘¦π‘Žπ‘Ž

οΏ½ π‘ π‘ π‘ π‘ π‘ π‘ β„Ž οΏ½π‘šπ‘šπ‘šπ‘šπ‘¦π‘¦π‘Žπ‘Ž

��∞

π‘šπ‘š=1,3,5...

… … (26)

where π‘Žπ‘Žπ‘šπ‘š =4π‘žπ‘žπ‘Žπ‘Ž4

π‘šπ‘š5π·π·π‘šπ‘š5(βˆ’1)(π‘šπ‘šβˆ’1)/2

π‘šπ‘šπ‘ π‘ π‘ π‘ π‘ π‘  οΏ½

π‘šπ‘šπ‘šπ‘šπ‘šπ‘š2π‘Žπ‘Ž

οΏ½

The above equation represents the deflection of the loaded portion. The deflection of the unloaded portion is,

𝑀𝑀′ = οΏ½ οΏ½π΄π΄β€²π‘šπ‘š π‘π‘π‘“π‘“π‘ π‘ β„Ž οΏ½

π‘šπ‘šπ‘šπ‘šπ‘¦π‘¦π‘Žπ‘Ž

οΏ½ + π΅π΅β€²π‘šπ‘š οΏ½π‘šπ‘šπ‘šπ‘šπ‘¦π‘¦π‘Žπ‘Ž

οΏ½ π‘ π‘ π‘ π‘ π‘ π‘ β„Ž οΏ½π‘šπ‘šπ‘šπ‘šπ‘¦π‘¦π‘Žπ‘Ž

οΏ½

+πΆπΆβ€²π‘šπ‘š π‘ π‘ π‘ π‘ π‘ π‘ β„Ž οΏ½π‘šπ‘šπ‘šπ‘šπ‘¦π‘¦π‘Žπ‘Ž

οΏ½ + π·π·β€²π‘šπ‘š οΏ½π‘šπ‘šπ‘šπ‘šπ‘¦π‘¦π‘Žπ‘Ž

οΏ½ π‘π‘π‘“π‘“π‘ π‘ β„Ž οΏ½π‘šπ‘šπ‘šπ‘šπ‘¦π‘¦π‘Žπ‘Ž

οΏ½οΏ½

∞

π‘šπ‘š=1,3,5..

𝑠𝑠𝑠𝑠𝑠𝑠 οΏ½π‘šπ‘šπ‘šπ‘šπ‘₯π‘₯π‘Žπ‘Ž

�… … (27)

There are six constants. To evaluate these, we have following boundary conditions and continuity conditions,

𝑀𝑀′ = 0,πœ•πœ•2𝑀𝑀′

πœ•πœ•π‘¦π‘¦2= 0; for 𝑦𝑦 = 𝑏𝑏/2

𝑀𝑀 = 𝑀𝑀′;β€ƒπœ•πœ•π‘€π‘€πœ•πœ•π‘¦π‘¦

=πœ•πœ•π‘€π‘€β€²

πœ•πœ•π‘¦π‘¦β€ƒ at 𝑦𝑦 = 𝑣𝑣/2

βˆ‚2π‘€π‘€βˆ‚π‘¦π‘¦2

=βˆ‚2𝑀𝑀′

βˆ‚π‘¦π‘¦2; 

βˆ‚3π‘€π‘€βˆ‚π‘¦π‘¦3

=βˆ‚3𝑀𝑀′

βˆ‚π‘¦π‘¦3;  at 𝑦𝑦 = 𝑣𝑣/2

Using the above boundary conditions, we get six equations. Solve those six equations to get,

π΄π΄π‘šπ‘š = βˆ’π‘Žπ‘Žπ‘šπ‘š

π‘π‘π‘“π‘“π‘ π‘ β„Ž π›Όπ›Όπ‘šπ‘šοΏ½π‘π‘π‘“π‘“π‘ π‘ β„Ž(π›Όπ›Όπ‘šπ‘š βˆ’ 2π›Ύπ›Ύπ‘šπ‘š) + π›Ύπ›Ύπ‘šπ‘š π‘ π‘ π‘ π‘ π‘ π‘ β„Ž(π›Όπ›Όπ‘šπ‘š βˆ’ 2π›Ύπ›Ύπ‘šπ‘š) + π›Όπ›Όπ‘šπ‘š

π‘ π‘ π‘ π‘ π‘ π‘ β„Ž 2 π›Ύπ›Ύπ‘šπ‘š2 π‘π‘π‘“π‘“π‘ π‘ β„Ž π›Όπ›Όπ‘šπ‘š

οΏ½

π΅π΅π‘šπ‘š =π‘Žπ‘Žπ‘šπ‘š

2 π‘π‘π‘“π‘“π‘ π‘ β„Ž π›Όπ›Όπ‘šπ‘šπ‘π‘π‘“π‘“π‘ π‘ β„Ž(π›Όπ›Όπ‘šπ‘š βˆ’ 2π›Ύπ›Ύπ‘šπ‘š)

where π›Όπ›Όπ‘šπ‘š =π‘šπ‘šπ‘šπ‘šπ‘π‘2π‘Žπ‘Ž

, π›Ύπ›Ύπ‘šπ‘š =π‘šπ‘šπ‘šπ‘šπ‘£π‘£4π‘Žπ‘Ž

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69

Substitute these constant to get final deflection as

𝑀𝑀 = οΏ½ 𝑠𝑠𝑠𝑠𝑠𝑠 οΏ½π‘šπ‘šπ‘šπ‘šπ‘₯π‘₯π‘Žπ‘Ž

οΏ½

βŽ£βŽ’βŽ’βŽ’βŽ’βŽ’βŽ‘π‘Žπ‘Žπ‘šπ‘š βˆ’

π‘Žπ‘Žπ‘šπ‘š π‘π‘π‘“π‘“π‘ π‘ β„Ž οΏ½π‘šπ‘šπ‘šπ‘šπ‘¦π‘¦π‘Žπ‘Ž οΏ½

π‘π‘π‘“π‘“π‘ π‘ β„Ž π›Όπ›Όπ‘šπ‘šβŽ£βŽ’βŽ’βŽ‘π‘π‘π‘“π‘“π‘ π‘ β„Ž(π›Όπ›Όπ‘šπ‘š βˆ’ 2π›Ύπ›Ύπ‘šπ‘š)+π›Ύπ›Ύπ‘šπ‘š π‘ π‘ π‘ π‘ π‘ π‘ β„Ž(π›Όπ›Όπ‘šπ‘š βˆ’ 2π›Ύπ›Ύπ‘šπ‘š)

+π›Όπ›Όπ‘šπ‘šπ‘ π‘ π‘ π‘ π‘ π‘ β„Ž 2 π›Ύπ›Ύπ‘šπ‘š2 π‘π‘π‘“π‘“π‘ π‘ β„Ž π›Όπ›Όπ‘šπ‘š ⎦

βŽ₯βŽ₯⎀

+ οΏ½π‘Žπ‘Žπ‘šπ‘š

2 π‘π‘π‘“π‘“π‘ π‘ β„Ž π›Όπ›Όπ‘šπ‘šπ‘π‘π‘“π‘“π‘ π‘ β„Ž(π›Όπ›Όπ‘šπ‘š βˆ’ 2π›Ύπ›Ύπ‘šπ‘š)οΏ½ οΏ½

π‘šπ‘šπ‘šπ‘šπ‘¦π‘¦π‘Žπ‘Ž

οΏ½ π‘ π‘ π‘ π‘ π‘ π‘ β„Ž οΏ½π‘šπ‘šπ‘šπ‘šπ‘¦π‘¦π‘Žπ‘Ž

�⎦βŽ₯βŽ₯βŽ₯βŽ₯βŽ₯⎀

∞

π‘šπ‘š=1,3,5...

… … (28)

where π‘Žπ‘Žπ‘šπ‘š =4π‘žπ‘žπ‘Žπ‘Ž4

π‘šπ‘š5π·π·π‘šπ‘š5(βˆ’1)(π‘šπ‘šβˆ’1)/2

π‘šπ‘šπ‘ π‘ π‘ π‘ π‘ π‘  οΏ½

π‘šπ‘šπ‘šπ‘šπ‘šπ‘š2π‘Žπ‘Ž

οΏ½ ; π›Όπ›Όπ‘šπ‘š =π‘šπ‘šπ‘šπ‘šπ‘π‘2π‘Žπ‘Ž

; π›Ύπ›Ύπ‘šπ‘š =π‘šπ‘šπ‘šπ‘šπ‘£π‘£4π‘Žπ‘Ž

Use , 1.a b u v m= = = = to get deflection as

𝑀𝑀

=2 sin οΏ½Ο€π‘₯π‘₯π‘Žπ‘Ž οΏ½ π‘žπ‘žπ‘Žπ‘Ž

3 οΏ½sinh οΏ½Ο€π‘¦π‘¦π‘Žπ‘Ž οΏ½ cosh οΏ½Ο€π‘¦π‘¦π‘Žπ‘Ž οΏ½ Ο€π‘Žπ‘Ž βˆ’ 2𝑦𝑦 sinh οΏ½Ο€π‘¦π‘¦π‘Žπ‘Ž οΏ½Ο€ cosh οΏ½12Ο€οΏ½ βˆ’ 4π‘Žπ‘Ž cosh οΏ½1

2Ο€οΏ½2

+ 4 cosh οΏ½12Ο€οΏ½ cosh οΏ½Ο€π‘¦π‘¦π‘Žπ‘Ž οΏ½ π‘Žπ‘ŽοΏ½

Ο€5π‘Žπ‘Ž(cosh(Ο€) + 1) . . (29)

And the Corresponding Bending stresses can be found from the moments Mx and My by the expression

Οƒ=6M/h2.

In the current study, the bending stresses and deflection according to the equations mentioned above are

determined, then compared the achieved results to the FEA results. Fig.2 presented the schematic illustration of

rectangular RC slabs under UDL and investigated in this research bending stresses, as well as the vertical

deflection in z-direction.

a) b)

Figure 2: Schematic illustration of the simply supported rectangular RC slab under UDL, a- Uniform

distributed load, b- Free body diagram of plate element.

American Scientific Research Journal for Engineering, Technology, and Sciences (ASRJETS) (2019) Volume 57, No 1, pp 62-76

70

2.2. Numerical Analysis

It is of fundamental importance in the numerical analysis of the structures to know how the applied load is

transferred to the stress and what is the stress and displacement distribution pattern within the investigated

models.

FEM is one of the most powerful and effective approaches for analyzing and investigating the stress state of the

materials under different types of loading. FEM is an analytical technique which in its turn is the basis for

computational analysis using software programs ([18, 19, 20, 21]).

This goal could not be achieved without the help of a powerful computer program like ABAQUS. For this

purpose, studied rectangular plates were modeled and simulated under UDL applied to the top face of the slabs.

The solid (or continuum) elements in ABAQUS can be used for linear analysis and complex nonlinear analyses

involving contact, plasticity, and large deformations. Regarding the finite element models introduced in this

work, three-dimensional 8-node first order fully integration continuum elements (C3D8 - Bricks) are used to

model the concrete rectangular slab and loading. Also, reinforcing bars are modeled as three -dimensional truss

elements. Three-dimensional 2-node first order truss elements (T3D2 - Truss) are used to model the steel

reinforcing bars in the FE model of the rectangular concrete slab [22].

2.3. Illustrative examples

Three cases of the simply supported Rectangular slabs are considered for the present study:

1. Simply supported rectangular plate with a 90 mm thickness.

2. Simply supported rectangular plate with a 75 mm thickness.

3. Simply supported rectangular plate with a 60 mm thickness.

The geometrical and physical properties of all investigated rectangular plates are presented below:

Plate dimension =950 mm length & 950 mm width. Poisson’s ratio of Reinforcement (Ξ½s) =0.3. Young’s

modulus of Reinforcement (Es)=200 GPa. Steel Reinforcement Ø10@100mm both directions. Poisson’s ratio of

Concrete (Ξ½c) = 0.2. Modulus Young’s of Concrete (Ec)=23.5 GPa. Applied uniformly distributed Load=20 kPa.

To achieve the more accurate results, after meshing the specimens are subdivided into 6500-10000 3D small

elements (according to the thickness of the slab) of simple cube shapes connected at nods. Thus, the stress of all

small elements was calculated, and there was a complete oblique of the stress-strain state of the entire specimen.

Fig. 3 presents the meshing of the specimen, and it is loading, supporting, and reinforcement.

American Scientific Research Journal for Engineering, Technology, and Sciences (ASRJETS) (2019) Volume 57, No 1, pp 62-76

71

Figure 3: Reinforced concrete slab, a-slab meshing, b- Loading & Supporting of the slab c-Reinforcement

3. Result

This paper proposed to create a three-dimensional model of the rectangular slabs under lateral load, then find all

post analysis parameters, including the bending stress and deflection for investigated in this study three cases,

then compared the achieved results by FEM with the analytical results by above-mentioned approaches based on

classical plate theory. The final results of stress and deflection obtained by analytical approaches and finite

element using ABAQUS software are shown in tables 1 & 2.

Table 1: Deflection of rectangular concrete slab under UDL.

Thickness (mm) Navier Solution(mm) Levy's Solution(mm) FEM(mm)

90 0.044 0.045 0.0539

75 0.076 0.077 0.0899

60 0.150 0.152 0.176

Table 2: Stress of rectangular concrete slab under UDL

Thickness (mm) Navier Solution(MPa) Levy's Solution(MPa) FEM(MPa)

90 0.658 0.640 0.532

75 0.947 0.922 0.721

60 1.480 1.440 1.040

Final equation of bending moment and deflection of Navier Solution for Simply Supported Plate.

a)

b)

c)

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72

wπ‘šπ‘šπ‘šπ‘šπ‘₯π‘₯ = 0.00406 π‘žπ‘ž π‘Žπ‘Ž4

𝐷𝐷

𝑀𝑀π‘₯π‘₯ = 𝑀𝑀𝑦𝑦 = 0.0492 π‘žπ‘žπ‘Žπ‘Ž2

Final equation of bending moment and deflection of Levy Solution for Simply Supported Plate

wπ‘šπ‘šπ‘šπ‘šπ‘₯π‘₯ = 0.004109 π‘žπ‘ž π‘Žπ‘Ž4

𝐷𝐷

𝑀𝑀π‘₯π‘₯ = 𝑀𝑀𝑦𝑦 = 0.0479 π‘žπ‘žπ‘Žπ‘Ž2

And the Corresponding Bending stresses can be found from the moments 𝑀𝑀π‘₯π‘₯ π‘Žπ‘Žπ‘ π‘ π‘Žπ‘Ž 𝑀𝑀𝑦𝑦 by the expression

𝜎𝜎 =6π‘€π‘€β„Ž2

4. Discussion

Figure 4: Location of maximum bending stresses and deflection in rectangular concrete slab

The locations of occurrence of the maximum Ο¬x, Ο¬y, and wz (z-directed deflection) were reliably determined

which are in the center of the rectangular concrete slab, which coincides, with great accuracy, with the results of

some approaches used in this work (Fig.4). The stress fields, as well as the distribution of the stresses, are

presented in Fig. 4 which shows that by the transition from green to red or blue color of the stress fields the

value of the stresses was increased, and stress reached its maximum at the center of the slab.

It is easy to observe that the results obtained for maximum bending stress from analytical equations give a

variety of results; both of them is more than that obtained by FEM.

Sectioning of the slab in the computer model demonstrates the pattern of the distribution of stress in x-y

direction in both field and vector forms (Fig.5 a, b). Fig.5c presents good agreement between the results

obtained according to Navier , levy approaches , and FEA results.

American Scientific Research Journal for Engineering, Technology, and Sciences (ASRJETS) (2019) Volume 57, No 1, pp 62-76

73

Figure 5: Bending Stress illustration, a- Ο¬ field within the slab, b- vector presentation of Ο¬ across the slab, c-

graphically comparative evaluation of the maximum Ο¬ by different methods

There is equality between the result of bending stress obtained from levy and Navior approaches. The result of

bending stress obtained theoretically is differed only about 19% compared with FEM for 90 mm thickness of

rectangular concrete slab, while it is about 23% and 29% for 75 and 60mm thickness subsequently. There is a

difference which can be explained by considering the following assumptions in these equations (levy and

Navier):

a) The plate is flat, of uniform thickness, and of homogeneous isotropic material; b) the thickness is not more

than about one-quarter of the least transverse dimension, and the maximum deflection is not more than about

one-half the thickness; c) all forces loads and reactions are normal to the plane of the plate; d) the plate is

nowhere stressed beyond the elastic limit.

As well as the difference in results can be explained by the fact that FE analysis represents the exact model of

rectangular slab, which is consist of concrete and reinforcements, 3D modeled slab with all properties for each

material. All of these properties and the combination of materials cannot be done throw the classical plate

a)

b)

c)

00.20.40.60.8

11.21.41.6

90 75 60

0.658

0.947

1.480

0.640

0.922

1.440

0.532 0.721

1.040

Οƒx =

Οƒy ,

MPa

Rectangular RC Slabs with different thicknesses, mm

Navier Solution Levy's Solution FEM

American Scientific Research Journal for Engineering, Technology, and Sciences (ASRJETS) (2019) Volume 57, No 1, pp 62-76

74

theories equations. On the other hand, in this work, it was carried out the comparative evaluation of the

maximum stresses as a function of the thickness in the rectangular RC slab. The results presented in the diagram

of the Fig.5c show that in all cases (thickness of plate 60mm,75mm and 90mm), and with the use of various

methods of analysis (classical and numerical) with increasing thickness of the plate, the maximum bending

stress not significantly, but still decreases and will be closer to the result obtained from FEM. In addition to

stress investigation, in this research work, it was carried out the comparative assessment of the maximum

deflection of the slab in z-direction, the analysis performed by FEM and Eq.(14,29) [12, 13]. The vertical

deflection-wz presented in Fig.6a. And the absolute value of the maximum deflection (wz) obtained by analytical

approaches and FEM illustrated in Fig.6b. Obviously that the location of maximum deflection of the

rectangular slab is at the center of the plate, this value decreases gradually and become zero at support. And

according to Fig. 6b results obtained from the analytical methods by Navior and levy approaches for

90mm,75mm and 60mm thickness and ABAQUS nearly match about 78-80 %, 81-83% and 82-84%

subsequently which with good confidence confirms the adequacy of the proposed 3D model and the accuracy of

the analysis using the finite element method.

a)

b)

Figure 6: a- vertical deflection b- The absolute value of the maximum z-directed deflection (wz) obtained by

analytical approaches and FEM

00.020.040.060.080.1

0.120.140.160.18

90 75 60

0.044

0.076

0.150

0.045

0.077

0.152

0.0539

0.0899

0.176

Wz,

mm

Rectangular RC Slabs with different thicknesses, mm

Navier Solution Levy's Solution FEM

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75

5. Conclusion

The comparison of the FEA results with the different plate theory approaches demonstrates the correctness of

the FE modeling of rectangular RC slab, as well as the purity of the 3D simulation in ABAQUS software

environment. This research showed that rectangular slab FEM created according to the developed technology

possesses all necessary strength and rigidity attributes for laterally loading. Suggested modeling and simulation

with high accuracy represent the real rectangular slab, and the selected type of the finite elements is adequate to

the investigation of the stress-strain state of the structure. As well as this research showed sufficient accuracy of

some approaches to the classical theory in the search for bending stresses. The use of these approaches in

determining vertical displacement seems more acceptable, and the results are very close to the output of the

FEA. The investigation of behavior RC rectangular slabs with different thickness showed that the thickness of

the plate significantly affected on the displacement and bending stress. In general, worth noting that the

performed investigations confirm representativeness of 3D finite element modeling of the rectangular RC slabs,

which opens fundamentally new horizons in the analysis of the plates by using numerical methods.

Acknowledgments

The researchers acknowledge the enormous support of the University of Salahaddin- Erbil.

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