FMP 10 LG 18 FINAL EXAM REVIEW Date ______ Name

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FMP 10 LG 18 FINAL EXAM REVIEW Date ____________ Name _____________

Transcript of FMP 10 LG 18 FINAL EXAM REVIEW Date ______ Name

FMP10LG18FINALEXAMREVIEWDate____________Name_____________

FMP10LG18FINALEXAMREVIEWDate____________Name_____________LG51.FindtheGeneralTermgiven:5,9,13,… 2.Givent1 = 17 and d = -9, find 𝑑"# 3.Find the 5 arithmetic means: 3, _____, ______, ______, ______, ______, 27 4.Findthesumofeacharithmeticseries.a)2+4+6+……30b)5+1–3–7……..–27

FMP10LG18FINALEXAMREVIEWDate____________Name_____________

FMP10LG18FINALEXAMREVIEWDate____________Name_____________

FMP10LG18FINALEXAMREVIEWDate____________Name_____________

FMP10LG18FINALEXAMREVIEWDate____________Name_____________

FMP10LG18FINALEXAMREVIEWDate____________Name_____________

FMP10LG18FINALEXAMREVIEWDate____________Name_____________

FMP10LG18FINALEXAMREVIEWDate____________Name_____________

FMP10LG18FINALEXAMREVIEWDate____________Name_____________

FMP10LG18FINALEXAMREVIEWDate____________Name_____________ANSWERS:Chapt.21π‘Ž) 244 ≃ 15.62𝑏) 96 ≃ 9.82π‘Ž)π‘₯ = 11.47𝑏)π‘₯ = 5.74𝑐)π‘₯ = 14.3𝑑)∠𝐴 ≃ 37Β°, ∠𝐡 ≃ 53Β°LG51.𝑑< = 4𝑛 + 12.-1543.7,11,15,19,234a)n=154b)n=9Chapt.31π‘Ž)π‘₯" + 10π‘₯ + 24𝑏)2π‘₯" + 7π‘₯ βˆ’ 15𝑐)π‘₯A+6π‘₯" + 5π‘₯ βˆ’ 122π‘Ž)3 π‘₯ βˆ’ 2 𝑏) βˆ’ 5 π‘₯ βˆ’ 2 π‘œπ‘Ÿ5 βˆ’π‘₯ + 2 𝑐) π‘₯ + 10 π‘₯ βˆ’ 10 𝑑) 2π‘₯ + 7 2π‘₯ βˆ’ 7 𝑒) π‘₯ + 6 π‘₯ + 2 𝑓) π‘₯ βˆ’ 6 π‘₯ + 3 𝑔) 2π‘₯ + 5 3π‘₯ βˆ’ 1 β„Ž)3 π‘₯ + 3 π‘₯ βˆ’ 3 Chapt.41π‘Ž)5 2𝑏)10 2𝑐)8𝑑)2 10H 𝑒)4 2H 𝑓)2 5I 2π‘Ž) 20𝑏) 192H 3π‘Ž)8𝑏)16𝑐)π‘π‘Žπ‘›π‘›π‘œπ‘‘π‘ π‘žπ‘’π‘Žπ‘Ÿπ‘’π‘›π‘’π‘”π‘Žπ‘‘π‘–π‘£π‘’π‘Ÿπ‘Žπ‘‘π‘–π‘π‘Žπ‘›π‘‘π‘‘)2𝑒)O

P𝑓)8

4π‘Ž)4QA𝑏)5.5

O"

5π‘Ž)π‘₯𝑦" 𝑏)π‘₯

"𝑦"𝑐)π‘₯S

Chapt.51π‘Ž)π·π‘œπ‘šπ‘Žπ‘–π‘›: 0, 1, 2 ; π‘…π‘Žπ‘›π‘”π‘’: 3, 4, 5 𝑏)𝐷:βˆ’3 ≀ π‘₯ ≀ 4; 𝑅: 0 ≀ 𝑦 ≀ 22)π‘π‘œ, π‘‘π‘œπ‘’π‘ π‘›[π‘‘π‘π‘Žπ‘ π‘ π‘£π‘’π‘Ÿπ‘‘π‘–π‘π‘Žπ‘™π‘™π‘–π‘›π‘’π‘‘π‘’π‘ π‘‘3π‘Ž)𝑦𝑒𝑠𝑏)π‘›π‘œ4π‘Ž)^_`a

^b<= "#cO#

dc"= 5𝑏) βˆ’ 3

5)10

FMP10LG18FINALEXAMREVIEWDate____________Name_____________Chapt.6

1)22) βˆ’55 3)

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4)

5)π‘š = βˆ’2; 4, βˆ’5 6)𝑦 βˆ’ 4 =

32 π‘₯ βˆ’ 1 π‘œπ‘Ÿπ‘¦ βˆ’ 7 =

32 π‘₯ βˆ’ 3

7)𝑦 = βˆ’12π‘₯ + 58)𝑦 = βˆ’

32π‘₯ + 3

Chapt.71)π‘Œπ‘’π‘ , 2, 3 π‘–π‘ π‘ π‘Žπ‘‘π‘–π‘ π‘“π‘–π‘’π‘‘π‘–π‘›π‘π‘œπ‘‘β„Žπ‘’π‘žπ‘’π‘Žπ‘‘π‘–π‘œπ‘›π‘ 2) 1, 4

3) 1, 3 4) βˆ’1, 2 5π‘Ž)π‘›π‘œπ‘›π‘’π‘)𝑖𝑛𝑓𝑖𝑛𝑖𝑑𝑒6π‘Ž)𝐿𝑒𝑑𝑀 = π‘€π‘–π‘‘π‘‘β„Žπ‘)𝐿𝑒𝑑π‘₯ = π‘π‘Ÿπ‘–π‘π‘’π‘œπ‘“1π‘Žπ‘‘π‘’π‘™π‘‘π‘‘π‘–π‘π‘˜π‘’π‘‘π‘™ = π‘™π‘’π‘›π‘”π‘‘β„Žπ‘¦ = π‘π‘Ÿπ‘–π‘π‘’π‘œπ‘“1π‘β„Žπ‘–π‘™π‘‘π‘‘π‘–π‘π‘˜π‘’π‘‘π‘™ = 2𝑀2π‘₯ + 3𝑦 = 352𝑙 = 2𝑀 = 1504π‘₯ + 𝑦 = 45