FMP 10 LG 18 FINAL EXAM REVIEW Date ______ Name
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Transcript of FMP 10 LG 18 FINAL EXAM REVIEW Date ______ Name
FMP10LG18FINALEXAMREVIEWDate____________Name_____________LG51.FindtheGeneralTermgiven:5,9,13,β¦ 2.Givent1 = 17 and d = -9, find π‘"# 3.Find the 5 arithmetic means: 3, _____, ______, ______, ______, ______, 27 4.Findthesumofeacharithmeticseries.a)2+4+6+β¦β¦30b)5+1β3β7β¦β¦..β27
FMP10LG18FINALEXAMREVIEWDate____________Name_____________ANSWERS:Chapt.21π) 244 β 15.62π) 96 β 9.82π)π₯ = 11.47π)π₯ = 5.74π)π₯ = 14.3π)β π΄ β 37Β°, β π΅ β 53Β°LG51.π‘< = 4π + 12.-1543.7,11,15,19,234a)n=154b)n=9Chapt.31π)π₯" + 10π₯ + 24π)2π₯" + 7π₯ β 15π)π₯A+6π₯" + 5π₯ β 122π)3 π₯ β 2 π) β 5 π₯ β 2 ππ5 βπ₯ + 2 π) π₯ + 10 π₯ β 10 π) 2π₯ + 7 2π₯ β 7 π) π₯ + 6 π₯ + 2 π) π₯ β 6 π₯ + 3 π) 2π₯ + 5 3π₯ β 1 β)3 π₯ + 3 π₯ β 3 Chapt.41π)5 2π)10 2π)8π)2 10H π)4 2H π)2 5I 2π) 20π) 192H 3π)8π)16π)ππππππ‘π ππ’ππππππππ‘ππ£ππππππππππ)2π)O
Pπ)8
4π)4QAπ)5.5
O"
5π)π₯π¦" π)π₯
"π¦"π)π₯S
Chapt.51π)π·πππππ: 0, 1, 2 ; π ππππ: 3, 4, 5 π)π·:β3 β€ π₯ β€ 4; π : 0 β€ π¦ β€ 22)ππ, ππππ π[π‘πππ π π£πππ‘πππππππππ‘ππ π‘3π)π¦ππ π)ππ4π)^_`a
^b<= "#cO#
dc"= 5π) β 3
5)10
FMP10LG18FINALEXAMREVIEWDate____________Name_____________Chapt.6
1)22) β55 3)
12
4)
5)π = β2; 4, β5 6)π¦ β 4 =
32 π₯ β 1 πππ¦ β 7 =
32 π₯ β 3
7)π¦ = β12π₯ + 58)π¦ = β
32π₯ + 3
Chapt.71)πππ , 2, 3 ππ π ππ‘ππ πππππππππ‘βπππ’ππ‘ππππ 2) 1, 4
3) 1, 3 4) β1, 2 5π)πππππ)πππππππ‘π6π)πΏππ‘π€ = π€πππ‘βπ)πΏππ‘π₯ = πππππππ1πππ’ππ‘π‘πππππ‘π = πππππ‘βπ¦ = πππππππ1πβππππ‘πππππ‘π = 2π€2π₯ + 3π¦ = 352π = 2π€ = 1504π₯ + π¦ = 45