Modul semester 2 kelas 10
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Transcript of Modul semester 2 kelas 10
PERCOBAAN 4
PEMBIASAN LENSA CEMBUNG
Tujuan : Menentukan titik focus lensa cembung dan menyelidiki sifat bayangan yang
dibentuk lensa cembung.
Alat dan bahan :
1. Lensa cembung2. Lampu3. Layar4. Preparat5. Power suplly6. Rel
Landasan teori :
Cermin cembung bersifat menyebarkan sinar. Berkas sinar sejajar sumbu utama dipantulkan menyebar seolah-olah berasal dari titik focus. Panjang focus sama dengan setengah jari-jari kelengkungan cermin. Sehingga didapat rumus :
1f= 1S+ 1S '
Cara kerja :
1. Susunlah alat – alat seperti gambar di atas.2. Geser lensa atau layar kekiri atau kekanan sehingga diperoleh bayangan
tjam pada layar.3. Ulangi kembali percobaan sehingga mendapatkan data S dan S’ yang
berbeda, kemudian catat datanya pada tabel.
Data – data percobaan
No S (cm) S’ (cm) 1/S 1/S’Titik focus
(f)1234
Pengolahan data :
1. Hitung titik focus (f)………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………..
2. Hitung titik fokus rata – rata
f= f 1+ f 2+ f 3+f 44
……………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………..
3. Hitung simpangan rata – rata
∆ f=|f 1−f|+|f 2−f|+|f 3−f|+|f 4−f|
4……………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………..
4. Ketelitian∆ ffx100 %
………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………
5. Kesalahan percobaan
(1−∆ ff
) x100 %
………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………….………………………………..………………………………………………………………………………………………………………………………………………………………………………………..
6. Kesimpulan ……………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………..
PERCOBAAN 5
RANGKAIAN HAMBATAN SERI DAN PARALEL
Tujuan : Mengetahui besar hambatan total yang dirangkai seri dan besar hambatan total yang dirangkai paralel.
Alat dan bahan :
1. Hambatan/Resistor2. Kabel3. Multitester
Landasan Teori :
Untuk menghitung hambatan pengganti yang disusun secara seri dapat menggunakan rumus
RS = R1 + R2 + R3 + … + Rn
Untuk menghitung hambatan pengganti yang disusun secara paralel dapat menggunakan rumus
1RP
= 1R1
+ 1R2
+ 1R3
+…+ 1Rn
Cara kerja :
1. Ukur masing – masing hambatan dengan multitester dengan ukuran Ohmmeter.
2. Susunlah tiga hambatan secara seperti gambar di bawah ini secara seri dan ukur besar hambatan tersebut.
Data Percobaan
NoHambatan penyusun Hambatan Ukur
(Rs) Ʃ Hitung RsR1 R2 R3
1 Ω Ω Ω Ω Ω
Hitunglah a. Hambatan total dalam rangkaian seri!
………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………
b. Kesalahan = |Rsukur−R shitungR shitung |x 100%
………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………
c. Ketelitian = 1−|R sukur−RshitungR shitung |x100 %
………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………3. Susunlah tiga hambatan secara seperti gambar di bawah ini secara paralel
dan ukur besar hambatan tersebut.
Data percobaan
NoHambatan penyusun Hambatan Ukur
(Rp) Ʃ Hitung RpR1 R2 R3
1 Ω Ω Ω Ω Ω
Hitunglah a. Hambatan total dalam rangkaian seri!
…………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………
b. Kesalahan = |Rpukur−RphitungRphitung |x100 %
…………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………
c. Ketelitian = 1−|Rpukur−R phitungR phitung |x 100 %
…………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………
Kesimpulan : …………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………
……………………………………………………………………………………………………………………………………………………………………
PERCOBAAN 6HUKUM OHM
Tujuan : 1. Dapat menemukan hubungan antara tegangan kuat arus dan hambatan.2. Dapat menggambarkan grafik antara kuat arus dan tegangan penghantar.
Alat dan bahan :1. Power supply/ catu daya2. Hambatan geser3. Voltmeter4. Ampermeter
Landasan teori :Sebuah hambatan ujung-ujungnya dipasang tegangan V, pada penghantar akan mengalir arus listrik ( i ). Menurut hukum Ohm kuat arus yang mengalir pada suatu penghantar berbanding lurus dengan tegangan dan berbanding terbalik dengan hambatannya.Pernyataan itu di tulis dengan pernyataan :
i=VRatau V=i .Ratau R=V
iKeterangan :i : kuat arusV : teganganR : Hambatan
Langkah kerja :
1. Susun rangkaian seperti gambar di bawah ini
A : AmperemeterV : VoltmeterE : Tegangan sumberR : Hambatan
2. Ukuran hamabatan R dengan ohmmeter.
A
V
E
R
3. Hidupkan sumber tegangan atau catu daya dengan memilih tegangan keluaran 3 Volt.
4. Baca Ampermeter dan voltmeter dalam rangkaian.5. Ulangi percobaan 3 dan 4 dengan mengubah tegangan sumber sesuai data
pada tabel dibawah.
No. E (Volt) V(Volt) I(Amper) Hambatan (Ω)1. 32. 63. 9
Pengolahan data :
1. Hitung Hambatan ……………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………
2. Hitung hambatan rata – rata
R=R1+R2+R33
………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………
………………………………………………………………………………………………………………………………………………………………
3. Hitung simpangan rata – rata
∆ R=|R1−R|+|R2−R|+|R3−R|
3……………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………..
4. Ketelitian ∆ RRx 100 %
………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………
5. Kesalahan percobaan
(1−∆ RR
)x 100 %
………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………….………………………………..
…………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………
6. Kesimpulan ………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………