Tugas Gorong2 Pak Ismail

7/24/2019 Tugas Gorong2 Pak Ismail

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Soal ILHAM TRI

DIO DIKA A

8m

Diket :

V1 = V2 = 0.7m/det K = 60

a = 1.25 l/det/a V! = 1.5

L"a# a$ea %$%!a#% = 700Ha I = 0.0003

0.002&

Hitung :

1. 'lea#% d*+#t$eam !$+!,!$+!

2. Ke%la+!a+ '+e$!%

3. 'lea#% -#t$eam !$+!,!$+!

&. Re+a+a teal !$+!,!$+! %la ea+ e+da$aa+ 15 T+

Penyelesaian :

1. Elevasi downstream gorong-gorong

De%t = a . L"a# a$ea %$%!a#% = 875 L/det = 0.875

= A . V

0875 m3/det = A . 07 m3/det

A = 0875 m3/det = 1.25

07 m/det

= 0.875 m = 1 V = 0.7

/ = 2 K = 60

A = ( m. ).

= ( 2 ). = 2 282

2.34 = &82 = &.30

R = A/ = 062

,,,,,, I = 0.0003

07 =

= 0.84 ,,, 0.4 m

= 2. = 1.78 ,, 178 m

%la+!a+ $"de = = 0.5 OK

A = .H =

m2

L"a# e+ama+! a#a 9a+! d%daat = 1.25 m2

m3/det ,,,,,

= 2.(m2 1)1/2

= 32 =

32

/&82 =

V = K . R2/3. I1/2

60 . (062)2/3. (00003)1/2

10.1810.

V2V1 V!

1018H = 04 m

= 18 m

10.20

:H=

= 18 m

; = 030 m

=05


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= 2H =

(1 22) . 04 . 1/2

= 2.88

,, e$at Ke+da$aa+ = 15000 !/m

, L"a# e$#e!% a+@a+! = (1 . 18 ) m2

= 1.8

, e$at #e+d%$% et+ = (18 288) m2 . 2&00

= 11232

Va2. L

(K . R1/6)2. R

152. 8

(60 . 0&51/6)2. 0&5

= 1 . (15 , 07)2/ 2.! =

= 18 m

; = 030 m

:H ttal

15 T+75 T+75 T+

1 m'TO K225I II

III

H = 040

T = H ; H et+ =22 m

H = 1 m

H et+ = 1 m

= 18 m


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. (3113030018)

. (3113030123)

m/det

m

B

0.727101 60

0.017321 0.7

(!$+!2)

1.54 m2

m3/det

.18H

H = 04 m

=1


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3.57 m

11.08 m

1.54 m2

3.57 m

0.&5 m

) ? . 2

m2

!/m3

K!/m

H = 04 m


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Tugas Gorong2 Pak Ismail

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