Lampiran AB Didim

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LAMPIRAN A DATA PERCOBAAN A.1 Analisa Kadar Air Kayu Pohon Cemara dan Pulp Tabel A.1 Analisa Kadar Air Kayu Pohon Cemara dan Pulp Waktu (menit) Massa (gram) Kadar Air (%) Kayu Pohon Cemara Pulp Kayu Pohon Cemara Pulp 0 2,25 5 42,6 % 72,6 % 5 1,45 4,43 10 1,31 3,87 15 1,29 3,34 20 1,29 2,82 25 1,29 2,28 30 1,9 35 1,64 40 1,37 45 1,37 50 1,37 A.2 Analisa Kadar Abu Pulp Tabel 4.2 Analisa Kadar Abu Pulp Massa Cawan (gram) Massa Cawan + Abu (gram) Massa Abu (gram) Kadar Abu (%) 45,84 46,13 0,29 14,5

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Transcript of Lampiran AB Didim

Page 1: Lampiran AB Didim

LAMPIRAN A

DATA PERCOBAAN

A.1 Analisa Kadar Air Kayu Pohon Cemara dan Pulp

Tabel A.1 Analisa Kadar Air Kayu Pohon Cemara dan Pulp

Waktu

(menit)

Massa (gram) Kadar Air (%)

Kayu Pohon

CemaraPulp

Kayu Pohon

CemaraPulp

0 2,25 5

42,6 % 72,6 %

5 1,45 4,43

10 1,31 3,87

15 1,29 3,34

20 1,29 2,82

25 1,29 2,28

30 1,9

35 1,64

40 1,37

45 1,37

50 1,37

A.2 Analisa Kadar Abu Pulp

Tabel 4.2 Analisa Kadar Abu Pulp

Massa Cawan

(gram)

Massa Cawan + Abu

(gram)Massa Abu (gram) Kadar Abu (%)

45,84 46,13 0,29 14,5

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A.3 Analisa Kadar α-β-γ Selulosa Pulp

Tabel A.3 Analisa Kadar α-β-γ Selulosa Pulp

AnalisaVolume Titrasi

Pulp (mL)

Volume Titrasi

Blanko (mL)Kadar (%)

α selulosa

β selulosa

γ selulosa

3,2

-

5

10

-

2

81,368

10,412

8,220

A.4 Analisa Bilangan Kappa

Tabel A.4 Analisa Bilangan Kappa

Volume Titrasi Pulp (mL) Volume Titrasi Blanko (mL) Bilangan Kappa

16 40 15,936

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LAMPIRAN B

CONTOH PERHITUNGAN

B.1 Persiapan Kayu Pohon Cemara

Kayu pohon cemara : larutan pemasak = 1 : 4

Kayu pohon cemara (basis basah) = 200,000 gram

Kayu pohon cemara (basis kering) = 114,667 gram

Kadar air =

massa bahan baku basah - massa bahan baku keringmassa bahan baku basah

×100%

=

(2,250 - 1,290 )2,250

×100 %

= 42,667 %

Keadaan kering = (100 – 42,667) % = 57,333 %

Berat kayu pohon cemara kering =

57,333100

×200

= 114,667 gram

Larutan pemasak = 4 114,667 gram = 458,667 gram

Komponen larutan pemasak 12,5 :

NaOH (80 ) = 0,125 0,8 458,667 = 45,867 gram

Na2CO3 (20 ) = 0,125 0,2 458,667 = 11,467 gram

Aquadest = 458,667 – (45,867 + 11,467) = 401,333 gram

Densitas air pada suhu 30 oC = 0,99568 gr/ml (Geankoplis, 2003)

Volume aquadest =

401,333 gr0,99568 gr/ml

= 403,075 ml

B.2 Perhitungan Kadar Air

B.2.1 Kayu Pohon Cemara

Massa Kayu Pohon Cemara basah = 2,25 gram

Massa Kayu Pohon Cemara kering = 1,29 gram

Kadar air =

massa bahan baku basah - massa bahan baku keringmassa bahan baku basah

×100%

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=

(2,250 - 1,290 )2,250

×100 %

= 42,6 %

B.2.2 Pulp

Massa pulp basah = 5 gram

Massa pulp kering = 1,37 gram

Kadar air =

massa pulp basah - massa pulp keringmassa bahan baku basah

×100 %

=

(5,000 - 1,370 )5,000

×100 %

= 72,6 %

B.3 Perhitungan Kadar Abu

Massa pulp kering = 2 gram

Massa abu = 0,29 gr

Kadar air =

massa abumassa pulp kering

×100 % (TAPPIc, 2002)

=0,29

2×100 %

= 14,5 %

B.4 Perhitungan Kadar Alfa Selulosa

Titrasi Blanko (V2) = 10 ml

Titrasi Sampel (V1) = 3,2 ml

Normalitas Amonium Sulfat = 0,1 N

Volume filtrate digunakan (A) = 25 ml

Pulp dikeringkan pada oven (W) = 5 gram

% α−selulosa=100−[6,85 (v2−v1 )×N×20/A×W ] (TAPPIa, 1999)

= 100−[6 ,85 (10 ,000−3 ,200 )×0 ,100×20/25 ,000×5 ,000 ] = 81,368 %

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B.5 Perhitungan Kadar Gamma Selulosa

Volume setelah pengendapan = 5 ml

Volume titrasi blanko = 2 ml

%γ−selulosa=[ 6,85 (v4−v3 )×N×20/A×W ] (TAPPIa, 1999)

= [6 ,85 (5 ,000−2 ,000 )×0 ,100×20/25 ,000×5 ,000 ] = 8,220 %

B.6 Perhitungan Kadar Beta Selulosa

% β−selulosa = [100− (%α selulosa+% γ selulosa ) ](TAPPIa, 1999)

= [100−(81,368+8,22)]= 10,412 %

B.7 Perhitungan Bilangan Kappa

Larutan Thiosulfat yang terpakai titrasi blanko (b) = 40 ml

Larutan Thiosulfat yang terpakai titrasi sampel (a) = 16 ml

Normalitas Thiosulfat (N) = 0,2 N

Berat sampel kering oven (W) = 3 gr

p = (b−a ) N

0,1(TAPPIb, 2006)

= (40−16 ) 0,2

0,1

= 48 ml

Tabel B.1 Faktor “f” koreksi perbedaan pemakaian persentase permanganat

p + 0 1 2 3 4 5 6 7 8 93040506070

0,9580,9791,0001,0221,044

0,9600,9811,0021,024

0,9620,9831,0041,026

0,9640,9851,0061,028

0,9660,9871,0091,030

0,9680,9891,0111,033

0,9700,9911,0131,035

0,9730,9941,0151,037

0,9750,9961,0171,039

0,9770,9981,0191,042

(TAPPIb, 2006)

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Dari tabel B.1, pada p = 48, didapat f = 0,996

K = (p× f )W

(TAPPIb, 2006)

= (48×0,996 )

3

= 15,936

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LAMPIRAN E

FOTO PERCOBAAN

E.1 Foto Analisa Kadar Air

Gambar E.1 Foto Analisa Kadar Air

E.2 Foto Analisa Kadar Abu

Gambar E.2 Foto Analisa Kadar Abu

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E.3 Foto Analisa Kadar Alfa Selulosa

Gambar E.3 Foto Analisa Kadar Alfa Selulosa

E.4 Foto Analisa Kadar Beta dan Gamma Selulosa

Gambar E.4 Foto Analisa Kadar Beta dan Gamma Selulosa

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LAMPIRAN F

FOTO PENGAMBILAN SAMPEL

F.1 Foto Pengambilan Sampel

Gambar F.1 Foto Pengambilan Sampel