Lampiran AB Didim
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LAMPIRAN A
DATA PERCOBAAN
A.1 Analisa Kadar Air Kayu Pohon Cemara dan Pulp
Tabel A.1 Analisa Kadar Air Kayu Pohon Cemara dan Pulp
Waktu
(menit)
Massa (gram) Kadar Air (%)
Kayu Pohon
CemaraPulp
Kayu Pohon
CemaraPulp
0 2,25 5
42,6 % 72,6 %
5 1,45 4,43
10 1,31 3,87
15 1,29 3,34
20 1,29 2,82
25 1,29 2,28
30 1,9
35 1,64
40 1,37
45 1,37
50 1,37
A.2 Analisa Kadar Abu Pulp
Tabel 4.2 Analisa Kadar Abu Pulp
Massa Cawan
(gram)
Massa Cawan + Abu
(gram)Massa Abu (gram) Kadar Abu (%)
45,84 46,13 0,29 14,5
A.3 Analisa Kadar α-β-γ Selulosa Pulp
Tabel A.3 Analisa Kadar α-β-γ Selulosa Pulp
AnalisaVolume Titrasi
Pulp (mL)
Volume Titrasi
Blanko (mL)Kadar (%)
α selulosa
β selulosa
γ selulosa
3,2
-
5
10
-
2
81,368
10,412
8,220
A.4 Analisa Bilangan Kappa
Tabel A.4 Analisa Bilangan Kappa
Volume Titrasi Pulp (mL) Volume Titrasi Blanko (mL) Bilangan Kappa
16 40 15,936
LAMPIRAN B
CONTOH PERHITUNGAN
B.1 Persiapan Kayu Pohon Cemara
Kayu pohon cemara : larutan pemasak = 1 : 4
Kayu pohon cemara (basis basah) = 200,000 gram
Kayu pohon cemara (basis kering) = 114,667 gram
Kadar air =
massa bahan baku basah - massa bahan baku keringmassa bahan baku basah
×100%
=
(2,250 - 1,290 )2,250
×100 %
= 42,667 %
Keadaan kering = (100 – 42,667) % = 57,333 %
Berat kayu pohon cemara kering =
57,333100
×200
= 114,667 gram
Larutan pemasak = 4 114,667 gram = 458,667 gram
Komponen larutan pemasak 12,5 :
NaOH (80 ) = 0,125 0,8 458,667 = 45,867 gram
Na2CO3 (20 ) = 0,125 0,2 458,667 = 11,467 gram
Aquadest = 458,667 – (45,867 + 11,467) = 401,333 gram
Densitas air pada suhu 30 oC = 0,99568 gr/ml (Geankoplis, 2003)
Volume aquadest =
401,333 gr0,99568 gr/ml
= 403,075 ml
B.2 Perhitungan Kadar Air
B.2.1 Kayu Pohon Cemara
Massa Kayu Pohon Cemara basah = 2,25 gram
Massa Kayu Pohon Cemara kering = 1,29 gram
Kadar air =
massa bahan baku basah - massa bahan baku keringmassa bahan baku basah
×100%
=
(2,250 - 1,290 )2,250
×100 %
= 42,6 %
B.2.2 Pulp
Massa pulp basah = 5 gram
Massa pulp kering = 1,37 gram
Kadar air =
massa pulp basah - massa pulp keringmassa bahan baku basah
×100 %
=
(5,000 - 1,370 )5,000
×100 %
= 72,6 %
B.3 Perhitungan Kadar Abu
Massa pulp kering = 2 gram
Massa abu = 0,29 gr
Kadar air =
massa abumassa pulp kering
×100 % (TAPPIc, 2002)
=0,29
2×100 %
= 14,5 %
B.4 Perhitungan Kadar Alfa Selulosa
Titrasi Blanko (V2) = 10 ml
Titrasi Sampel (V1) = 3,2 ml
Normalitas Amonium Sulfat = 0,1 N
Volume filtrate digunakan (A) = 25 ml
Pulp dikeringkan pada oven (W) = 5 gram
% α−selulosa=100−[6,85 (v2−v1 )×N×20/A×W ] (TAPPIa, 1999)
= 100−[6 ,85 (10 ,000−3 ,200 )×0 ,100×20/25 ,000×5 ,000 ] = 81,368 %
B.5 Perhitungan Kadar Gamma Selulosa
Volume setelah pengendapan = 5 ml
Volume titrasi blanko = 2 ml
%γ−selulosa=[ 6,85 (v4−v3 )×N×20/A×W ] (TAPPIa, 1999)
= [6 ,85 (5 ,000−2 ,000 )×0 ,100×20/25 ,000×5 ,000 ] = 8,220 %
B.6 Perhitungan Kadar Beta Selulosa
% β−selulosa = [100− (%α selulosa+% γ selulosa ) ](TAPPIa, 1999)
= [100−(81,368+8,22)]= 10,412 %
B.7 Perhitungan Bilangan Kappa
Larutan Thiosulfat yang terpakai titrasi blanko (b) = 40 ml
Larutan Thiosulfat yang terpakai titrasi sampel (a) = 16 ml
Normalitas Thiosulfat (N) = 0,2 N
Berat sampel kering oven (W) = 3 gr
p = (b−a ) N
0,1(TAPPIb, 2006)
= (40−16 ) 0,2
0,1
= 48 ml
Tabel B.1 Faktor “f” koreksi perbedaan pemakaian persentase permanganat
p + 0 1 2 3 4 5 6 7 8 93040506070
0,9580,9791,0001,0221,044
0,9600,9811,0021,024
0,9620,9831,0041,026
0,9640,9851,0061,028
0,9660,9871,0091,030
0,9680,9891,0111,033
0,9700,9911,0131,035
0,9730,9941,0151,037
0,9750,9961,0171,039
0,9770,9981,0191,042
(TAPPIb, 2006)
Dari tabel B.1, pada p = 48, didapat f = 0,996
K = (p× f )W
(TAPPIb, 2006)
= (48×0,996 )
3
= 15,936
LAMPIRAN E
FOTO PERCOBAAN
E.1 Foto Analisa Kadar Air
Gambar E.1 Foto Analisa Kadar Air
E.2 Foto Analisa Kadar Abu
Gambar E.2 Foto Analisa Kadar Abu
E.3 Foto Analisa Kadar Alfa Selulosa
Gambar E.3 Foto Analisa Kadar Alfa Selulosa
E.4 Foto Analisa Kadar Beta dan Gamma Selulosa
Gambar E.4 Foto Analisa Kadar Beta dan Gamma Selulosa
LAMPIRAN F
FOTO PENGAMBILAN SAMPEL
F.1 Foto Pengambilan Sampel
Gambar F.1 Foto Pengambilan Sampel