VR
3
Soal nomor 1.a V R + V L =Ri +L di dt di dt + R L i=0 di i = −R L dt ∫ I0 i (t ) di i = ∫ 0 t −R L dt ln i |¿ − ¿ i0 i R L t ¿ 0 t ¿ ln i−ln I 0 = −R L ( t−0 ) i ( t ) =I 0 e −Rt L ( arus asimetri) I natural = V R ( arus simetri)
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VR
Transcript of VR
Soal nomor 1.a
V R+V L=Ri+ Ldidt
didt
+ RLi=0
dii=−RLdt
∫I 0
i (t )dii=∫
0
t−RLdt
ln i|¿− ¿i0i RLt ¿0
t ¿
ln i− ln I 0=−RL
(t−0)
i (t )=I 0 e−RtL (arus asimetri )
I natural=VR
(arus simetri)
Soal nomor 1.b
Soal nomor 2
f 50
VLL 11000
P 10000
R 0.01
L 0.005
pf 0.8
Vm VLL 2
Vm 1.556 104
Z P R i 2 f L( )[ ]
Z 100 1.571i 104
acos pf( )
0.644
n 1 100
tn
n
1000
I1n
Vm
Z
cos 2 f tn
I2n
Vm
Z
e
R
L
tn
In
I1n
I2n
In
-0.051-33.839·10
-0.038
-0.172
-0.386
-0.658
-0.962
-1.266
-1.543
-1.763
-1.906
-1.957
-1.911
...
I1n
0.937
0.99
0.946
0.81
0.594
0.32
0.015
-0.292
-0.57
-0.792
-0.937
-0.99
-0.946
...
n
1
2
3
4
5
6
7
8
9
10
11
12
13
...
I2n
0.988
0.986
0.984
0.982
0.98
0.979
0.977
0.975
0.973
0.971
0.969
0.967
0.965
...
S 1000000000
VLL 66000
VLNVLL
3 VLN 3.811 10
4
ZpuVLL
2
S Zpu 4.356
Z Zpu 3 Z 13.068
Vm VLL 2 Vm 9.334 104
pf 1 acos pf( )
0
f 50
m 1 10
tm
m
1000
IacVm
Z 2 f
tan 2 f t0
Idc 2 IacIb 3 Iac
Soal nomor 3
t1
Iac 7.387Idc 10.447Ib 12.795
t2Iac 16.518Idc 23.36Ib 28.61
t3Iac 31.292Idc 44.254Ib 54.2
t4Iac 69.972Idc 98.955Ib 121.195
t5
Iac 3.713 1017
Idc 5.251 1017
Ib 6.431 1017
t6
Iac 69.972Idc 98.955Ib 121.195
t7
Iac 31.292Idc 44.254Ib 54.2
t8
Iac 16.518Idc 23.36Ib 28.61
t9
Iac 7.387Idc 10.447Ib 12.795
t10
Iac 2.784 1015
Idc 3.937 1015
Ib 4.822 1015
