Tugas 4 Masalah Nilai Awal
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Transcript of Tugas 4 Masalah Nilai Awal
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7/28/2019 Tugas 4 Masalah Nilai Awal
1/7
Tugas 4 MNA
http://www.usmcr010.blogspot.com Page 1
NAMA : PHELIPUS MERE
NIM : 1001036019
PRODI : P MATEMATIKA
SEMESTER : VI
1. + 2 + 4 = 0
:
=
=
= ( 1)
:
+ 2 + 4 = 0
( 1) + 2 + 4 = 0
( + 2)( + 1) + 2 ( + 1) + 4 = 0
2 + 2 = 0 ,( ( + 2)( + 1) + 2( + 1) + 4 ) = 0
=
:
=( )
( )( ), m= 1,2,3,..
= 1
= =
= 2
= =
= 3
= = . = .
= = + + + +. . +..
= + + + + . +..
= + + + + + +
= 1 + +. . + + + +
= +
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http://www.usmcr010.blogspot.com Page 2
2. (1 2) = 2
:
=
=
:
(1x2)y - 2xy = 0
1 x 2 = 0
2 = 0
( + 1) ( 1) 2 = 0
+ 2 2 + { (( + 1) ( 1) 2 ) = 0
= 0
2 2 = 0 => =
:
=( )
=( )
= , = 2,3,4,
= 2
= =
= 3
= =
= 4
= = 0
= 5
= =
= = + + + +..+..
= + 0. + + 0. + + 0. + . +
= (1 + + + + ) + 0( + + + )
= + 0( + + + )
= +
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3. ( + 1) (2 + 3) = 0
:
=
=
:
(x + 1)y (2x + 3)y = 0
(x + 1) (2x + 3) = 0
+ 2 3 = 0
+ ( + 1) 2 3 = 0
3 + ( + ( + 1) 2 3 ) = 0
3 = 0,=> = 3
:
=( )
, = 1,2,3,.
= 1
= = + = 4
= 2
= = =
= 3
= =.
= 2
= = + + + +..+..
= + 3 + 4 + + 2 +
= 1 + 3 + 4 + + 2 +
= +
4. (1 2) 2 + 2 = 0
:
=
=
= ( 1)
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http://www.usmcr010.blogspot.com Page 4
:
(1x2)y 2xy + 2y = 0
1 x ( 1) 2x + 2 = 0
( 1) ( 1) 2 +
2 = 0
( + 2)( + 1) ( 1) 2 +
2 = 0
2 + 6 2 + 2 + 2 + ( ( ( + 2)( + 1) ( 1)
2 + 2 ) ) = 0
2 + 2 = 0,=> =
6 2 + 2 =0, => 6 = 0,=> = 0
:
=( )
( )( ), = 2,3,4,
= 2
= = =
= 3
= = = 0
= 4
= = = =
= = + + + +..+..
= + + 0. 0. +
= 1 + +
= +
5. : + = 0, = 1
:
= ( 1)
= ( 1)
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Tugas 4 MNA
http://www.usmcr010.blogspot.com Page 5
= ( 1) ( 1)
:
+ = 0
( 1) ( 1) + ( 1) = 0
( + 2)( + 1) ( 1) + ( 1) = 0
(( + 2)( + 1) + )( 1) = 0
:
=( )( )
, = 0,1,2,3,
= 0
=
= 1=
= 2
= =
= 3
= =
= = + + + +..+..
= + +
2+
6
= +
2!+ +
6
= cos + sin
6.
=
= 2 + 3
:
" =
" = 2 + 3
" = 2 + 3( )
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Tugas 4 MNA
http://www.usmcr010.blogspot.com Page 6
" 3 + 2 = 0
:
3 + 2 = 0
( 1)( 2) = 0
= 1, = 2
:
( ) = + , =
( ) = + 2
7.
= 2
= 9 + 2
:
:2 19 2
=>2 1
9 2
: (2 ) 9.(1) => 4 + 13 = 0
:
, =
, = . .
, =
, =
,=>23
= 2 + 3 , = 2 3
= = 2 + 3
2 (2 + 3 ) + (1) = 0
3 A = 0,=> 3 = A
= 1,maka A = 3i
= e( )
3ie( )
= = 2 3
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http://www.usmcr010.blogspot.com Page 7
2 (2 3 ) = 0
3 A = 0,=> 3 = A
= 1,maka A = 3i
=
e( )
3ie( )
:
= e( )
3ie( )+ = e
( )
3ie( )
