Perhitungan Perc Enzimatis
9
LAMPIRAN Grafik METODE INTEGRAL DATA I Awal reaksi Orde 0 0 10 20 30 40 50 60 70 -0.14 -0.12 -0.1 -0.08 -0.06 -0.04 -0.02 0 f(x) = − 0.000895714285714286 x − 0.0795 R² = 0.721142575384199 Grafik (A-Ao) vs t t (sekon) (A-Ao) Orde 1 0 10 20 30 40 50 60 70 -0.25 -0.2 -0.15 -0.1 -0.05 0 f(x) = − 0.00180057142857143 x − 0.14198 R² = 0.731848967345496 Grafik ln (A-Ao) vs t t (sekon) ln (A-Ao) t (sekon) A-Ao 10 -0.0727 20 -0.1071 30 -0.1174 40 -0.1197 50 -0.1225 60 -0.1257 70 -0.1302 Diperoleh : a = - 0.0795 b = - 0.0009 r = 0.8491 t (sekon) ln (A- Ao) 10 -0.1292 20 -0.1967 30 -0.2178 40 -0.2226 50 -0.2285 60 -0.2352 70 -0.2448 Diperoleh : a = - 0.142 b = - 0.0018 r = 0.8554
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Transcript of Perhitungan Perc Enzimatis
LAMPIRAN Grafik
METODE INTEGRALDATA I
Awal reaksiOrde 0
0 10 20 30 40 50 60 70
-0.14
-0.12
-0.1
-0.08
-0.06
-0.04
-0.02
0
f(x) = − 0.000895714285714286 x − 0.0795R² = 0.721142575384199
Grafik (A-Ao) vs t
t (sekon)
(A-A
o)
Orde 1
0 10 20 30 40 50 60 70
-0.25
-0.2
-0.15
-0.1
-0.05
0
f(x) = − 0.00180057142857143 x − 0.14198R² = 0.731848967345496
Grafik ln (A-Ao) vs t
t (sekon)
ln (A
-Ao)
t (sekon) A-Ao10 -0.072720 -0.107130 -0.117440 -0.119750 -0.122560 -0.125770 -0.1302
Diperoleh :a = -0.0795b = -0.0009r = 0.8491
t (sekon) ln (A-Ao)10 -0.129220 -0.196730 -0.217840 -0.222650 -0.228560 -0.235270 -0.2448
Diperoleh :a = -0.142b = -0.0018r = 0.8554
Orde 2
0 10 20 30 40 50 60 700
0.050.1
0.150.2
0.250.3
0.350.4
0.450.5
f(x) = 0.00362114285714286 x + 0.253993333333333R² = 0.741947420100103
Grafik (1/A-1/Ao) vs t
t (sekon)
(1/A
- 1/
Ao)
Orde reaksi yang diperoleh terhadap Br2 pada awal reaksi adalah orde 2
Akhir reaksiOrde 0
925 930 935 940 945 950 955 960 965 970 975
-0.485
-0.48
-0.475
-0.47
-0.465
-0.46
-0.455
f(x) = − 0.000433 x − 0.0611500000000004R² = 0.996327983845255
Grafik (A-Ao) vs t
t (sekon)
(A-A
o)
Orde 1
925 930 935 940 945 950 955 960 965 970 975
-1.65
-1.6
-1.55
-1.5
-1.45
-1.4
f(x) = − 0.003412 x + 1.68958R² = 0.994449004025719
Grafik ln (A-Ao) vs t
t (sekon)
ln (A
-Ao)
t (sekon) (1/A-1/Ao)10 0.2320 0.362530 0.405940 0.415850 0.42860 0.442270 0.4624
Diperoleh :a = 0.254b = 0.0036r = 0.8613
t (sekon) A-Ao910 -0.4642920 -0.4677930 -0.4727940 -0.4764950 -0.4815960 -0.4865970 -0.4904
Diperoleh :a = -0.0612b = -0.0004r = 0.99814
t (sekon) ln (A-Ao)910 -1.4875920 -1.5136930 -1.5522940 -1.5818950 -1.624960 -1.6673970 -1.7023
Diperoleh :a = 1.6896b = -0.0034r = 0.9972
Orde 2
925 930 935 940 945 950 955 960 965 970 9755
5.5
6
6.5
7
f(x) = 0.026947 x − 19.38707R² = 0.991800873781415
Grafik (1/A-1/Ao) vs t
t (sekon)
(1/A
- 1
/Ao)
orde reaksi yang diperoleh terhadap Br2 pada akhir reaksi adalah orde 0
DATA II
Awal reaksiOrde 0
0 10 20 30 40 50 60 70
-0.06
-0.05
-0.04
-0.03
-0.02
-0.01
0
f(x) = − 0.000220857142857143 x − 0.03752R² = 0.84721637352276
Grafik (A-Ao) vs t
t (sekon)
A-Ao
Orde 1
0 10 20 30 40 50 60 70
-0.16
-0.14
-0.12
-0.1
-0.08
-0.06
-0.04
-0.02
0
f(x) = − 0.000628 x − 0.09892R² = 0.846732916206601
Grafik ln (A-Ao) vs t
t (sekon)
ln(A
-Ao)
t (sekon) (1/A-1/Ao)910 5.7126920 5.9083930 6.2065940 6.4428950 6.7927960 7.1664970 7.4816
Diperoleh :a = -19.387b = 0.0269r = 0.9959
t (sekon) A-Ao10 -0.042420 -0.040230 -0.042440 -0.045650 -0.048960 -0.05270 -0.0555
Diperoleh :a = -0.0375b = -0.0002r = 0.9204
t (sekon) ln (A-Ao)10 -0.112820 -0.106630 -0.112840 -0.121850 -0.131260 -0.140270 -0.1503
Diperoleh :a = -0.0989b = -0.0006r = 0.9201
Orde 2
0 10 20 30 40 50 60 700
0.050.1
0.150.2
0.250.3
0.350.4
f(x) = 0.00178914285714286 x + 0.260913333333333R² = 0.847014021482162
Grafik (1/A-1/Ao) vs t
t (sekon)
(1/A
o - 1
/Ao)
Akhir reaksi
Orde 0
650 660 670 680 690 700 710 720
-0.365-0.36
-0.355-0.35
-0.345-0.34
-0.335-0.33
-0.325-0.32
f(x) = − 0.000465428571428571 x − 0.0276647619047619R² = 0.997587521576908
Grafik (A-Ao) vs t
t (sekon)
(A-A
o)
Orde 1
640 650 660 670 680 690 700 710 720
-3
-2.5
-2
-1.5
-1
-0.5
0
f(x) = − 0.00986107142857143 x + 4.58561428571428R² = 0.990461036918508
Grafik ln (A-Ao) vs t
t (sekon)
ln (A
-Ao)
t (sekon) (1/A-1/Ao)10 0.300420 0.28330 0.300440 0.325950 0.352960 0.378670 0.4082
Diperoleh :a = 0.2609b = 0.0018r = 0.9203
t (sekon) A-Ao650 -0.3346660 -0.3395670 -0.3444680 -0.3494690 -0.3528700 -0.3582710 -0.3631
Diperoleh :a = -0.0277b = -0.0005r = 0.99879
t (sekon) ln (A-Ao)650 -1.8436660 -1.9247670 -2.013680 -2.1119690 -2.1852700 -2.3139710 -2.4471
Diperoleh :a = 4.5856b = -0.0099r = 0.99523
Orde 2
640 650 660 670 680 690 700 710 7200
5
10
15
20
25
30
f(x) = 0.213432142857143 x − 126.285857142857R² = 0.968021296186445
Grafik (1/A-1/Ao) vs t
t (sekon)
(1/A
- 1/
Ao)
DATA IIIAwal reaksiOrde 0
0 10 20 30 40 50 60 70
-0.06
-0.05
-0.04
-0.03
-0.02
-0.01
0
f(x) = − 0.000319142857142857 x − 0.0356466666666667R² = 0.999848275806803
Grafik (A-Ao) vs t
t (sekon)
(A-A
o)
Orde 1
0 10 20 30 40 50 60 70 80
-0.2-0.18-0.16-0.14-0.12
-0.1-0.08-0.06-0.04-0.02
0
f(x) = − 0.00101285714285714 x − 0.102628571428571R² = 0.999883637549864
Grafik ln (A-Ao) vs t
t (sekon)
ln (A
-Ao)
t (sekon) (1/A-1/Ao)650 13.282660 14.726670 16.316680 18.274690 19.855700 22.929710 26.554
Diperoleh :a = -126.29b = 0.2134r = 0.9838
t (sekon) A-Ao10 -0.038820 -0.04230 -0.045340 -0.048550 -0.051560 -0.054870 -0.058
Diperoleh :a = -0.0356b = -0.0003r = 0.99989
t (sekon) ln (A-Ao)10 -0.112920 -0.122830 -0.133140 -0.143250 -0.152860 -0.163470 -0.1738
Diperoleh :a = -0.1026b = -0.001r = 0.99995
Orde 2
0 10 20 30 40 50 60 70 800
0.1
0.2
0.3
0.4
0.5
0.6
f(x) = 0.00322071428571428 x + 0.295385714285714R² = 0.999668646885458
Grafik (1/A-1/Ao) vs t
t (sekon)
(1/A
- 1/
Ao)
Akhir reaksiOrde 0
620 630 640 650 660 670 680 690
-0.316-0.314-0.312
-0.31-0.308-0.306-0.304-0.302
-0.3-0.298
f(x) = − 0.000217142857142857 x − 0.168804761904762R² = 0.908814366483798
Grafik (A-Ao) vs t
t (sekon)
(A-A
o)
Orde 1
610 620 630 640 650 660 670 680 690
-2.05
-2
-1.95
-1.9
-1.85
-1.8
-1.75
-1.7
f(x) = − 0.003455 x + 0.293807142857145R² = 0.886592609917227
Grafik ln (A-Ao) vs t
t (sekon)
ln (A
-Ao)
t (sekon) (1/A-1/Ao)10 0.328920 0.359530 0.391840 0.423850 0.454360 0.488670 0.5226
Diperoleh :a = 0.2954b = 0.0032r = 0.99985
t (sekon) A-Ao620 -0.304630 -0.3081640 -0.3113650 -0.3135660 -0.3142670 -0.3151680 -0.3154
Diperoleh :a = -0.1688b = -0.0002r = 0.9533
t (sekon) ln (A-Ao)620 -1.8112630 -1.8827640 -1.9423650 -1.9854660 -1.9996670 -2.0181680 -2.0243
Diperoleh :a = 0.2938b = -0.0035r = 0.9416
Orde 2
METODE DIFFERENSIAL
Data 3
Log V = log k +αlog A
Awal reaksi
-2.53 -2.525 -2.52 -2.515 -2.51 -2.505 -2.5 -2.495 -2.49 -2.485 -2.48 -2.475
-3.53
-3.52
-3.51
-3.5
-3.49
-3.48
-3.47
-3.46
f(x) = − 0.16924370223503 x − 3.91511384107306R² = 0.0252290279452675
Grafik log V vs log A
log A
log
V
Diperoleh :a = -3.9151b = -0.1692r = 0.1587slope = orde = -0.1692 (orde 0)
t (sekon) (1/A-1/Ao)620 14.0832630 15.3314640 16.4421650 17.2883660 17.5734670 17.9521680 18.0815
Diperoleh :a = -25.96b = 0.0656r = 0.9493
A V log A log V0.0032 0.00032 -2.49485002 -3.49490.0033 0.00033 -2.48148606 -3.48150.0032 0.00033 -2.49485002 -3.48150.003 0.00032 -2.52287875 -3.4949
0.0033 0.0003 -2.48148606 -3.52290.0032 0.00033 -2.49485002 -3.4815
MENENTUKAN HARGA Vmax DAN Km DENGAN METODE DIFFERENSIAL
1V
= 1Vmax
+ KmVmax
.1s
Slope KmVmax
intersept1
Vmax
1. Percobaan 1Awal reaksi
S V 1/S 1/V
0.03440.0034
429.069
8290.69
8
0.01030.0010
397.087
4970.87
4
0.00230.0002
3434.78
34347.8
3
0.00280.0002
8357.14
33571.4
3
0.00320.0003
2 312.5 3125
0.00450.0004
5222.22
22222.2
2a = 0b = 10r = 1
intersept =1
Vmax
0=1
VmaxVmax =
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