Mata Kuliah Teknik Digital
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Transcript of Mata Kuliah Teknik Digital
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Mata Kuliah Teknik Digital
7. PENCACAH
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Pencacah Reguler Tabel 7.1. Tabel keadaan pencacah biner berurutan.
A B C D A+ B+ C+ D+ A B C D A+ B+ C+ D+0 0 0 0 0 0 0 1 0 0 0 0 1 1 1 1 0 0 0 1 0 0 1 0 0 0 0 1 0 0 0 00 0 1 0 0 0 1 1 0 0 1 0 0 0 0 10 0 1 1 0 1 0 0 0 0 1 1 0 0 1 00 1 0 0 0 1 0 1 0 1 0 0 0 0 1 10 1 0 1 0 1 1 0 0 1 0 1 0 1 0 00 1 1 0 0 1 1 1 0 1 1 0 0 1 0 10 1 1 1 1 0 0 0 0 1 1 1 0 1 1 01 0 0 0 1 0 0 1 1 0 0 0 0 1 1 1 1 0 0 1 1 0 1 0 1 0 0 1 1 0 0 01 0 1 0 1 0 1 1 1 0 1 0 1 0 0 1 1 0 1 1 1 1 0 0 1 0 1 1 1 0 1 01 1 0 0 1 1 0 1 1 1 0 0 1 0 1 11 1 0 1 1 1 1 0 1 1 0 1 1 1 0 0 1 1 1 0 1 1 1 1 1 1 1 0 1 1 0 11 1 1 1 0 0 0 0 1 1 1 1 1 1 1 0
(a) (b ) Pencacah naik Pencacah turun
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Pencacah dengan flip-flop T
A B C A+ B+ C+ TA TB TC
0 0 0 0 0 1 0 0 1
0 0 1 0 1 0 0 1 1
0 1 0 0 1 1 0 0 1
0 1 1 1 0 0 1 1 1
1 0 0 1 0 1 0 0 1
1 0 1 1 1 0 0 1 1
1 1 0 1 1 1 0 0 1
1 1 1 0 0 0 1 1 1
TC= 1
AB
C 00 01 11 10
0
1 1 1
TA= BC
Pencacah Naik.
AB
C 00 01 11 10
0
1 1 1 1 1
TB= C
A
T
A
B
T
B
C
T
C
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Pencacah dengan flip-flop T
A B C A+ B+ C+ TA TB TC
0 0 0 1 1 1 1 1 1
0 0 1 0 0 0 0 0 1
0 1 0 0 0 1 0 1 1
0 1 1 0 1 0 0 0 1
1 0 0 0 1 1 1 1 1
1 0 1 1 0 0 0 0 1
1 1 0 1 0 1 0 1 1
1 1 1 1 1 0 0 0 1
TC= 1
Pencacah Turun. AB
C 00 01 11 10
0 1 1
1
TB= BC
AB
C 00 01 11 10
0 1 1 1 1
1
TB= C
A
T
A
B
T
B
C
T
C
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Pencacah dengan flip-flop T
Up/Dn= M
M= 0 Down
M= 1 Up
Pencacah Naik-Turun
TC= P
A
T
A
B
T
B
C
T
C
TB= MPC + MPC TA= MPBC + MPBC
Up/Dn= M
P
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A B C A+B+C+ BC BC BC 0 0 0 0 1 1 A 0 1 A 0 1 A 0 1 0 0 1 - - - 00 1 00 1 00 1 1 0 1 0 1 0 0 01 x 01 x 01 x 0 1 1 0 1 0 11 x 11 1 x 11 x 1 0 0 1 0 1 10 1 x 10 x 10 x 1 0 1 0 0 0 A+ B+ C+
1 1 0 - - - 1 1 1 - - -
Pencacah tak beraturan
00 01 11 10 00 01 11 10 00 01 11 10
0 1 x 0 1 1 x 0 1 x 1
1 x x 1 1 x x 1 x 1 x 1
TA = BC + BC = B + C
TB= AC TC= B + C
AB C
AB C
AB C
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Pencacah tak beraturan:flip-flop T, Diagram Rangkaian
A
T
A
B
T
B
C
T
C
TB= P(A + C) TA= P(B + C)
P
TC= P(B + C)
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Diagram waktu pencacah irreguler
P
A 0 0 0 1 1 0 B
0 1 1 0 0 0 C
0 1 0 0 1 0 TA
TB
TC
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Pencacah dengan flip-flop RS
A B C A+B+C+ RA SA RB SB RC SC Q Q+ R S 0 0 0 0 1 1 x 0 0 1 0 1 0 0 x 0 0 0 1 - - - x x x x x x 0 1 0 1 0 1 0 1 0 0 0 1 1 0 0 x 1 0 1 0 0 1 1 0 1 0 x 0 0 x 1 0 1 1 0 x 1 0 0 1 0 1 0 x 0 x 0 1 1 0 1 0 0 0 1 0 x 0 1 0 1 1 0 - - - x x x x x x 1 1 1 - - - x x x x x x
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Peta-K Pencacah dengan RS
AB AB AB C 00 01 11 10 C 00 01 11 10 C 00 01 11 10
0 0 1 x 1 0 1 0 x 0 0 1 0 x 1
1 x 0 x 0 1 x 1 x 0 1 x 0 x 0
A+ B+ C+
A A A BC 0 1 0 1 BC 0 1 0 1 BC 0 1 0 1
00 x x 00 1 x 00 1 1
01 x x 1 01 x x x 01 x x 1
11 x x x 11 x x x 11 x 1 x
10 1 x x 10 x 1 x 10
x x x
SA RA SB RB SC RC
SA = BC RA= C SB = AB RB = BC SC = BC RC = C
(c)
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Pencacah dengan flip-flop JK
A B C A+B+C+ JA KA JB KB JC KC Q Q+ J K 0 0 0 0 1 1 0 x 1 x 1 x 0 0 0 x 0 0 1 - - - x x x x x x 0 1 1 x 0 1 0 1 0 0 1 x x 1 0 x 1 0 x 1 0 1 1 0 1 0 0 x x 0 x 1 1 1 x 0 1 0 0 1 0 1 x 0 0 x 1 x 1 0 1 0 0 0 x 1 0 x x 1 1 1 0 - - - x x x x x x 1 1 1 - - - x x x x x x
Peta Keadaan Berikut
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Peta-K Pencacah dengan JK
AB AB AB C 00 01 11 10 C 00 01 11 10 C 00 01 11 10
0 0 1 x 1 0 1 0 x 0 0 1 0 x 1
1 x 0 x 0 1 x 1 x 0 1 x 0 x 0
A+ B+ C+
A A A BC 0 1 0 1 BC 0 1 0 1 BC 0 1 0 1
00 x x 00 1 x x 00 1 1 x x
01 x x x 1 01 x x x 01 x x x 1
11 x x x 11 x x x 11 x x 1 x
10 1 x x x 10 x x 1 x 10
x x x
JA KA JB KB JC KC
JA = BC KA= C JB = A KB = C JC = B KC = 1
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Peta-K Pencacah dengan ff D
AB AB AB C 00 01 11 10 C 00 01 11 10 C 00 01 11 10
0 0 1 x 1 0 1 0 x 0 0 1 0 x 1
1 x 0 x 0 1 x 1 x 0 1 x 0 x 0
A+ B+ C+
DA= AC + BC DB= A B + AC DC= B C
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Pencacah dalam Rangkaian Terpadu
R0(1) R0(2) NC VCC NC NC NC
QA QD QC QB
>AR0(1) B< R0(2)
1 2 3 6 4 5 7
14 13 12 911 10 8
Input A
Input BQA QD GND QC QB
J Q
>C
K
K J Q
>C
K
K J Q
>C
K
K J Q
>C
K
K
R0(1) R0(2)
R0(1) R0(2) QD QC QB QA H H L L L L L x C o u n t x L C o u n t