Lkpd bentuk akar
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Lembar Kerja Peserta Didik
LEMBAR KERJA PESERTA DIDIK (LKPD)
Sifat – Sifat Bilangan Berpangkat
Kelompok :
Kelas :
Angoota : 1.
2.
3.
4.
Waktu : 15 menit
Tujuan : Dengan menggunakan model pembelajaran TS – TS (Two Stay – Two Stray)
dengan berbantuan Lembar Kerja Peserta Didik (LKPD), peserta didik dapat
membuktikan sifat-sifat sederhana tentang bentuk akar.
Prasyarat : 1. Memahami konsep bilangan berpangkat.
2. Mengetahui dan memahami sifat-sifat bilangan berpangkat.
a. Sifat Perkaliana. Dengan menggunakan konsep bilangan berpangkat, hitunglah 45 ×42!
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...............................................................................................................................b. Apakah 45 ×42=45+2? Jelaskan
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Lembar Kerja Peserta Didik
c. Selidikilah sifat tersebut berlaku secara umum. Jika dipunyai a sebarang bilangan
real dan m , n bilangan bulat, apakah am× an=am+n? Jelaskan.
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b. Sifat Pembagian
a. Dengan menggunakan konsep bilangan berpangkat, hitunglah 37
33 !
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b. Apakah 37
33 =37−3? Jelaskan.
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c. Selidikilah sifat tersebut berlaku secara umum. Jika dipunyai a sebarang bilangan
real, a ≠ 0 dan m , n bilangan bulat, m>n, apakah am
an =am−n? Jelaskan.
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Lembar Kerja Peserta Didik
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c. Sifat Perpangkatan
a. Dengan menggunakan konsep bilangan berpangkat, hitunglah(24 )3!
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d. Apakah (24 )3=24 ×3? Jelaskan.
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e. Selidikilah sifat tersebut berlaku secara umum. Jika dipunyai dengan a sebarang
bilangan real, a ≠ 0 dan m , n bilangan bulat, apakah (am )n=am× n? Jelaskan.
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Lembar Kerja Peserta Didik
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d. Sifat Pangkat dari Perkaliana. Dengan menggunakan konsep bilangan berpangkat, hitunglah(5.4 )5 !
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b. Apakah (5.4 )5=55 . 45 ? Jelaskan.
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c. Selidikilah sifat tersebut berlaku secara umum. Jika dipunyai dengan a dan b
sebarang bilangan real, a ,b ≠ 0 dan m bilangan bulat, (a . b )m=am. bm? Jelaskan.
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Lembar Kerja Peserta Didik
e. Sifat Pangkat dari
Pembagian
a. Dengan menggunakan konsep bilangan berpangkat, hitunglah( 23 )
4
!
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b. Apakah ( 23 )
4
=24
34 ? Jelaskan.
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c. Selidikilah sifat tersebut berlaku secara umum. Jika dipunyai dengan a dan b
sebarang bilangan real, a ,b ≠ 0 dan m bilangan bulat, apakah ( ab )
m
=am
bm ? Jelaskan.
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Bentuk Umum Sifat Perkalian : am× an=…
Bentuk Umum Sifat Perkalian : am
an =…, m>n
Bentuk Umum Sifat Perpangkatan : (am )n=…
Bentuk Umum Sifat Pangkat dari Perkalian : (a . b )m=…
Bentuk Umum Sifat Pangkat dari Pembagian : ( ab )
m
=…
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Lembar Kerja Peserta Didik
SIMPULAN
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Lembar Kerja Peserta Didik
LEMBAR KUNJUNGAN
Kelompok :
Kelas :
Angoota : 1.
2.
3.
4.
KUNJUNGAN 1
Kelompok : .....................
Hasil :
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KUNJUNGAN 2
Kelompok : .....................
Hasil :
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