7/25/2019 tugas Termodinamika II teknik kimia

http://slidepdf.com/reader/full/tugas-termodinamika-ii-teknik-kimia 1/2

1. Diketahui:

R=82,06 cm3atm/mol K 

T=573,15 K 

P=78,9538 atm

Da!i "team ta#el $ = 2,26 cm3/%

= 36,752 cm3/mol

Dita&'a:

..(ϕ

)a*a#:

+& =ϕ   (   1 RT  )  

v− RT 

 P

(¿)dp

∫ p=0

 p= p

¿

= (   1 RT  ) P$-RTl&P

= (   1 RT  )  $P -P0RTl& P0

 P p

= (   1

82,06∗573,15 )   36,75278,9538RTl&0

78,95384¿

=

(  1

82,06∗573,15 ) 383,25

7/25/2019 tugas Termodinamika II teknik kimia

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= 0,7331

=2,08ϕ

= .Pϕ

=2,08478,9538

=16,356

2. Diketahui:

R=82,06 cm3atm/mol K 

T=573,15 K 

P=8,8 atm

Da!i "team ta#le i aatka& &ilai $=21,65 cm3/%

 =389,7 cm3/mol

Dita&'a:

..(ϕ

)a*a#:

= (   1 RT  )  $P -P0RTl& P0

 Pp

= (   1

82,06∗573,15 ) 389,78,8RTl&0

84,8

= (   1

82,06∗573,15 ) 3306,56

=0,702

=2,02ϕ

= .Pϕ

=2,0248,8

=171,3