tugas Termodinamika II teknik kimia
2
1. Diketa hui: R=82,06 cm 3 atm/mol K T=573,15 K P=78,9538 atm Da!i "team ta#el $ = 2,26 cm 3 /% = 36,752 cm 3 /mol Dita&'a: ..( ϕ )a*a#: +& = ϕ ( 1 RT ) v − RT P ( ¿ ) dp ∫ p=0 p= p ¿ = ( 1 RT ) P$-RTl&P = ( 1 RT ) $P -P 0 RTl& P 0 P p = ( 1 82,06∗573,15 ) 36,75278,9538RTl& 0 78,95384 ¿ = ( 1 82,06∗573,15 ) 383,25
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Transcript of tugas Termodinamika II teknik kimia
7/25/2019 tugas Termodinamika II teknik kimia
http://slidepdf.com/reader/full/tugas-termodinamika-ii-teknik-kimia 1/2
1. Diketahui:
R=82,06 cm3atm/mol K
T=573,15 K
P=78,9538 atm
Da!i "team ta#el $ = 2,26 cm3/%
= 36,752 cm3/mol
Dita&'a:
..(ϕ
)a*a#:
+& =ϕ ( 1 RT )
v− RT
P
(¿)dp
∫ p=0
p= p
¿
= ( 1 RT ) P$-RTl&P
= ( 1 RT ) $P -P0RTl& P0
P p
= ( 1
82,06∗573,15 ) 36,75278,9538RTl&0
78,95384¿
=
( 1
82,06∗573,15 ) 383,25
7/25/2019 tugas Termodinamika II teknik kimia
http://slidepdf.com/reader/full/tugas-termodinamika-ii-teknik-kimia 2/2
= 0,7331
=2,08ϕ
= .Pϕ
=2,08478,9538
=16,356
2. Diketahui:
R=82,06 cm3atm/mol K
T=573,15 K
P=8,8 atm
Da!i "team ta#le i aatka& &ilai $=21,65 cm3/%
=389,7 cm3/mol
Dita&'a:
..(ϕ
)a*a#:
= ( 1 RT ) $P -P0RTl& P0
Pp
= ( 1
82,06∗573,15 ) 389,78,8RTl&0
84,8
= ( 1
82,06∗573,15 ) 3306,56
=0,702
=2,02ϕ
= .Pϕ
=2,0248,8
=171,3
