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NAMA : DONI A.R PURBA

NIM : 122406108

GROUP : KC1 ‘12

1 SOAL PERTAMA

>> a=[1 ! "# 2 $ 8 1# 2 ! " $%

a =

  1 ! "

  2 $ 8 1

  2 ! " $

>> a&2':(=a&2':()2*a&1':(

a =

  1 ! "

  0 1 )2 )!

  2 ! " $

>> a&':(=a&':()2*a&1':(

a =

  1 ! "

  0 1 )2 )!

  0 )1 )1 )11

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>> a&':(=a&':(*)1

a =

  1 ! "

  0 1 )2 )!

  0 1 1 11

>> a&':(=a&':()a&2':(

a =

  1 ! "

  0 1 )2 )!

  0 0 16

>> +=a&'4(,a&'(

+ =

  !.

>> -=&a&2'4()+*a&2'((,a&2'2(

- =

  !.666$

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>> = &a&1'4()+*a&1'()-*a&1'2((,a&1'1(

=

  )4.666$

Buat soal dengan cara penyelesaian metode Gauss

>> a = [1 2 4 5; 2 9 3 7; 2 7 9 11]

a =

  1 2 4 5

  2 9 3 7

  2 7 9 11

>> a(2,:) = a(2,:)-2*a(1,:)

a =

  1 2 4 5

  0 5 -5 -3

  2 7 9 11

>> a(3,:) = a(3,:)-2*a(1,:)

a =

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  1 2 4 5

  0 5 -5 -3

  0 3 1 1

>> a(3,:) = (5*a(3,:))-(3*a(2,:))

a =

  1 2 4 5

  0 5 -5 -3

  0 0 20 14

>> z=a(3,4)/a(3,3)

z =

  0.7000

>> y=(a(2,4)-z*a(2,3))/a(2,2)

y =

  0.1000

>> x= (a(1,4)-z*a(1,3)-y*a(1,2))/a(1,1)

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x =

  2

>> a = [1 3 5 7; 3 8 7 11; 2 5 9 18]

a =

  1 3 5 7

  3 8 7 11

  2 5 9 18

>> a(2,:) = a(2,:)-3*a(1,:)

a =

  1 3 5 7

  0 -1 -8 -10

  2 5 9 18

>> a(3,:) = a(3,:)-2*a(1,:)

a =

  1 3 5 7

  0 -1 -8 -10

  0 -1 -1 4

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z =

  2

>> y=(a(2,4)-z*a(2,3))/a(2,2)

y =

  -6

>> x= (a(1,4)-z*a(1,3)-y*a(1,2))/a(1,1)

x =

  15