Getting to Know Fly Lab
Transcript of Getting to Know Fly Lab
Johann Gregor Mendel (1822-1884)
Father of Genetics
“Gregor Mendel, through his work on pea plants, discovered
the fundamental laws of inheritance. He deduced that genes
come in pairs and are inherited as distinct units, one from
each parent. Mendel tracked the segregation of parental
genes and their appearance in the offspring as dominant or
recessive traits. He recognized the mathematical patterns of
inheritance from one generation to the next. Mendel's Laws
of Heredity are usually stated as:
1) The Law of Segregation: Each inherited trait is defined
by a gene pair. Parental genes are randomly separated to the
sex cells so that sex cells contain only one gene of the
pair. Offspring therefore inherit one genetic allele from
each parent when sex cells unite in fertilization.
2) The Law of Independent Assortment: Genes for different
traits are sorted separately from one another so that the
inheritance of one trait is not dependent on the inheritance
of another.
3) The Law of Dominance: An organism with alternate forms of
a gene will express the form that is dominant.
The genetic experiments Mendel did with pea plants took him
eight years (1856-1863) and he published his results in
1865. During this time, Mendel grew over 10,000 pea plants,
keeping track of progeny number and type. Mendel's work and
his Laws of Inheritance were not appreciated in his time. It
wasn't until 1900, after the rediscovery of his Laws, that
his experimental results were understood.” (Center, 2011).
Fly lab Notes for DeVry Biology
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Results of Cross #1
Parents
(Female: +) x (Male: +)
Offspring
Phenotype Number Proportion Ratio
Female: + 5043 0.5031
1.013
Male: + 4980 0.4969
1.000
Total 10023
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Results of Cross #1
Parents
(Female: +) x (Male: +)
Offspring
Phenotype Number Proportion Ratio
Female: + 5043 0.5031
1.013
Male: + 4980 0.4969
1.000
Total 10023
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Results of Cross #1
Parents
(Female: +) x (Male: +)
Offspring
Phenotype Number Proportion Ratio
Female: + 5043 0.5031
1.013
Male: + 4980 0.4969
1.000
Total 10023
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Results of Cross #2
Parents
(Female: +) x (Male: SE)
Offspring
Phenotype Number Proportion Ratio
Female: + 4945 0.4960
1.000
Male: + 5025 0.5040
1.016
Total 9970
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Results of Cross #2
Parents
(Female: +) x (Male: SE)
Offspring
Phenotype Number Proportion Ratio
Female: + 4945 0.4960
1.000
Male: + 5025 0.5040
1.016
Total 9970
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Results of Cross #3
Parents
(Female: VG) x (Male: VG)
Offspring
Phenotype Number Proportion Ratio
Female: VG 5043 0.5022
1.009
Male: VG 4999 0.4978
1.000
Total 10042
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Results of Cross #4
Parents
(Female: E) x (Male: E)
Offspring
Phenotype Number Proportion Ratio
Female: E 5023 0.4954
1.000
Male: E 5117 0.5046
1.019
Total 10140
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Results of Cross #5
Parents
(Female: DP) x (Male: DP)
Offspring
Phenotype Number Proportion Ratio
Female: DP 5050 0.5030
1.012
Male: DP 4990 0.4970
1.000
Total 10040
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Results of Cross #6
Parents
(Female: BW) x (Male: BW)
Offspring
Phenotype Number Proportion Ratio
Female: BW 5015 0.5002
1.001
Male: BW 5011 0.4998
1.000
Fly lab Notes for DeVry Biology
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Results of Cross #1
Parents
(Female: +) x (Male: +)
Offspring
Phenotype Number Proportion Ratio
Female: + 5043 0.5031
1.013
Male: + 4980 0.4969
1.000
Total 10023
There are two types of chromosomes and this type identifies
the sex of the organism. We have the x and the y. in most
plants and animals, we see them are x and y only but in
humans, we call it the male and female and to most mammals
as well. During the combination of chromosomes or what we
call meiosis there is a segregation of the egg and sperm
cells then they will be paired. This normally happens during
mating. The pair that forms determines the gender of the
offspring. For female offspring, the pair is XX while XY
represents a male offspring (Gilbert, 2000; Griffiths, et
al., 2000).
One organism we will look at is the fruit flies or known as
Drosophila melanogaster. The offspring of a fruit fly is also
being determined by and XX and XY combination. Two X
chromosomes means it got a female offspring while a single x
chromosome represents a male one. In the mating process, the
chance of getting an xx or xy pair is 1:1 all the time 1
(Gilbert, 2000; Griffiths, et al., 2000).
The predicted value we have above is supported by the
information we have in Table 1. It shows in table 1 the
ration of xx and xy pairing which is 1:1.
Monohybrid Cross
Using Mendel’s law of segregation, we will see a monohybrid
cross. In this law, we uses alleles that are segregated.
Using one allele at a time, it is randomly transferred to
the gamete (Khanna, 2010).
Khanna posits that an organism’s phenotype appearance will
be lead over by the alleles’ dominant appearance. This is
through heterozygote. Looking at the phenotype of the F1 and
F2 generation, we can determine the dominant and recessive
alleles. The traits would be of the alleles since it is more
dominant. For the inheritance, Punnet square can be used to
predict its ratio. In this sample, we will use D for
dominant and d for recessive ones. If the mating happens
between a DD and dd, the offspring will be Dd on the first
generation. If there will be cross breeding soon, the F1
generation will yield a phenotype ratio of 3:1.
Check the table below for further samples.
Table 2. Punnet square of F1 generation
d d
D Dd Dd
D Dd Dd
Table 3. Punnet square of F2 generation
D d
D DD Dd
d Dd dd
Wild Type (WT) vs Sepia Eyes (SE)
The results for the F1 and F2 generation for WT and SE cross
are shown in Table 4.
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Results of Cross #2
Parents
(Female: +) x (Male: SE)
Offspring
Phenotype Number Proportion Ratio
Female: + 4945 0.4960
1.000
Male: + 5025 0.5040
1.016
Total 9970
Results of Cross #3
Parents
(Female: VG) x (Male: VG)
Offspring
Phenotype Number Proportion Ratio
Female: VG 5043 0.5022
1.009
Male: VG 4999 0.4978
1.000
Total 10042
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In table 4, it shows that the SE or sepia eyes is recessive
and is not observed in F2 at all hence the ration after
mating id 1:3. This concludes the hypothesis we have earlier
about dominant and recessive phenotypes.
Wild Type (WT) vs VG (Vestigial Wing)
The results for the F1 and F2 generation for WT and VG cross
are shown in Table 5.
Table 5. Results for the F1 and F2 generation for WT and VG
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Results of Cross #4
Parents
(Female: E) x (Male: E)
Offspring
Phenotype Number Proportion Ratio
Female: E 5023 0.4954
1.000
Male: E 5117 0.5046
1.019
Total 10140
Results of Cross #5
Parents
(Female: DP) x (Male: DP)
Offspring
Phenotype Number Proportion Ratio
Female: DP 5050 0.5030
1.012
Male: DP 4990 0.4970
1.000
Total 10040
In this table, the VG or vestigial wing is recessive and is
also not seen in F1. This gives as a ratio of 1:3 as well.
It coincides with the fact that recessive type might not
show in the first generation.
Wild Type (WT) vs Ebony Body (E)
The results for the F1 and F2 generation for WT and E cross
are shown in Table 6.
Results of Cross #6
Parents
(Female: BW) x (Male: BW)
Offspring
Phenotype Number Proportion Ratio
Female: BW 5015 0.5002
1.001
Male: BW 5011 0.4998
1.000
Total 10026
Results of Cross #7 (F2, WT vs E)
Ignoring Sex
Parents
(Female: +) x (Male: +)
Offspring
Phenotype Number Proportion Ratio
+ 7601 0.7532 3.051
E 2491 0.2468 1.000
Total 10092
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In this table, table 6, the E or ebony body is recessive and
is also not seen in F1. This gives as a ratio of 1:3 as
well. It coincides with the fact that recessive type might
not show in the first generation.
Wild Type (WT) vs Dumpy Wing (DP)
The results for the F1 and F2 generation for WT and DP cross
are shown in Table 7.
Results of Cross #8 (F1, WT vs DP)
Ignoring Sex
Parents
(Female: +) x (Male: DP)
Offspring
Phenotype Number Proportion Ratio
+ 10010 1.0000 1.000
Total 10010
Results of Cross #9 (F2, WT vs DP)
Ignoring Sex
Parents
(Female: +) x (Male: +)
Offspring
Phenotype Number Proportion Ratio
+ 7454 0.7565 3.107
DP 2399 0.2435 1.000
Total 9853
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In this table, table 7, the E or ebony body is recessive and
is also not seen in F1. This gives as a ratio of 1:3 as
well. It coincides with the fact that recessive type might
not show in the first generation. Earlier predictions are
true on this part.
Wild Type (WT) vs Brown Eye (BW)
The results for the F1 and F2 generation for WT and BW cross
are shown in Table 8.
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Results of Cross #10 (F1, WT vs BW)
Ignoring Sex
Parents
(Female: +) x (Male: BW)
Offspring
Phenotype Number Proportion Ratio
+ 10074 1.0000 1.000
Total 10074
Results of Cross #11 (F2, WT vs BW)
Ignoring Sex
Parents
(Female: +) x (Male: +)
Offspring
Phenotype Number Proportion Ratio
+ 7420 0.7503 3.005
BW 2469 0.2497 1.000
Total 9889
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In this table, table 8, the BW or brown eyes is recessive
and is also not seen in F1. This gives as a ratio of 1:3 as
well. It coincides with the fact that recessive type might
not show in the first generation. Earlier predictions are
true on this part.
Dihybrid Cross
As the word implies, it means there are two traits being
crossed reference here. Using law of independent assortment,
the chance of a trait to emerge depends on the other’s
traits (Khanna, 2010).
In a dihybrid, the heterozygotes ratio is 1 on the F1
generation. If there will be a cross breeding, the ratio
would be 9:3:3:1at F1 (Khanna, 2010). Using Punnet square,
you can determine the expected phenotypes in dihybrid cross.
Say we have two real parents in alleles that are alleles
DDEE and ddee, we will show you the possible F1 and F2
generation in the table below.
Table 9. F1 generation of dihybrid cross DDEE and ddee
de de de de
DE DdE
e
DdE
e
DdE
e
DdE
e
DE DdE
e
DdE
e
DdE
e
DdE
e
DE DdE
e
DdE
e
DdE
e
DdE
e
DE DdE
e
DdE
e
DdE
e
DdE
e
Table 10. F2 generation of dihybrid cross DdEe and DdEe
DE De DE de
DE DDEE DdEe DdEe DdEe
De ddee DDee DdEe Ddee
DE ddee DdEe ddEE ddEe
de DdEe Ddee ddEe ddee
Legend:
Both dominant phenotype (yellow): 9
D dominant and e recessive phenotype (green): 3
D recessive and E dominant phenotype (turquoise): 3
Both recessive phenotype (pink): 1
Wild Type (WT) vs Sepia Eye (SE), Dumpy Wing (DP)
The results for the F1 and F2 generation for WT and SE, DP
cross are shown in Table 11.
Table 11. Results for the F1 and F2 generation for WT and
SE, DP
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Results of Cross #14 (F1, WT vs SE, DP)
Ignoring Sex
Parents
(Female: +) x (Male: SE; DP)
Offspring
Phenotype Number Proportion Ratio
+ 10074 1.0000 1.000
Total 10074
Results of Cross #15 (F1, WT vs SE, DP)
Ignoring Sex
Parents
(Female: +) x (Male: +)
Offspring
Phenotype Number Proportion Ratio
+ 5632 0.5599 9.026
SE 1963 0.1951 3.146
DP 1840 0.1829 2.949
SE; DP 624 0.0620 1.000
Total 10059
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Table 11 shows that in F1 generation, there is a ratio of 1
for the F1 and a ratio of 9:3:3:1 for the F2 generation.
This reflects our prediction above.
REFERENCES
Gilbert, S. F. (2000). Developmental Biology, 6th ed.
Sunderland: Sinauer Associates.
Griffiths, A. J. F., J. H. Miller, D. T. Suzuki, R. C.
Lewontin, and W. M. Gelbart. (2000). an Introduction to
Genetic Analysis, 7th Ed. New York: W. H. Freeman.