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Boundedness and compactness of positive integral operators on cones of homogeneous groups
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Transcript of Boundedness and compactness of positive integral operators on cones of homogeneous groups
Positivity 13 (2009), 497–518c© 2008 Birkhauser Verlag Basel/Switzerland1385-1292/030497-22, published online October 28, 2008DOI 10.1007/s11117-008-2217-8 Positivity
Boundedness and compactnessof positive integral operators on conesof homogeneous groups
Usman Ashraf, Muhammad Asif and Alexander Meskhi
Abstract. Necessary and sufficient conditions on a weight function v guaran-teeing the boundedness/compactness of integral operators with positive ker-nels defined on cones of homogeneous groups from Lp to Lq
v are established,where 1 < p, q < ∞ or 0 < q ≤ 1 < p < ∞. Behavior of singular numbers forthese operators is also studied.
Mathematics Subject Classification (2000). Primary 26A33, 42B25; Secondary43A15, 46B50, 47B10, 47B34.
Keywords. Operators with positive kernels, potentials, homogeneous groups,trace inequality, weights, singular numbers of kernel operators.
1. Introduction
In this paper boundedness/compactness criteria from Lp(E) to Lqv(E) are estab-
lished for the operator
Kf(x) =∫
Er(x)
k(x, y)f(y)dy, x ∈ E, (1)
with positive kernel k, where 1 < p, q < ∞ or 0 < q ≤ 1 < p < ∞, Er(x) and Eare certain cones in homogeneous groups and k satisfies the conditions which inone-dimensional case are similar to those of [20].
A full characterization of pair of weights (v, w) governing the boundednessof integral operators with positive kernels from Lp
w to Lqv, 1 < p < q < ∞, have
been established in [9] (see also [10], Ch.3). Criteria guaranteeing the bounded-ness/compactness of the operator
Rαf(x) =
x∫
0
(x − t)α−1f(t)dt, x > 0,
The work was partially supported by the INTAS grant No. 05-1000008-8157 and the GeorgianNational Foundation Grant No. GNSF/ST06/3-010.
498 U. Ashraf et al. Positivity
from Lp(R+) to Lqv(R+), 1 < p, q < ∞, 1/p < α < 1 have been obtained in
[19] and [28]. This result was generalized in [20] (see also [6], Ch. 2) for integraloperators with positive kernels involving fractional integrals.
Two-weight Lpw − Lq
v criteria for the Hardy operators have been derived byB. Muckenhaupt [22] for p = q, J. Bradley [3], V. Kokilashvili [14] and V. Maz’ya[18] for p ≤ q. Necessary and sufficient conditions guaranteeing the boundednessof Rα from Lp
w(R+) to Lqv(R+), where 1 < p ≤ q < ∞ and α > 1 were derived in
[17], [31] (see also [16,26,32]).The two-weight problem for higher-dimensional Hardy-type operators defined
on cones in Rn involving Oinarov [25] kernels was studied in [11,34] (see also [29],
for Hardy-type transforms on star-shaped regions).In the present paper we present also two-sided estimates of Schatten-von
Neumann norms for the operator with positive kernel
Kuf(x) = u(x)∫
Er(x)
k(x, y)f(y)dy, x ∈ E, (2)
where u is a measurable function on E.Constants (often different constants in the same series of inequalities) will
generally be denoted by c.
2. Preliminaries
A homogeneous group G is a simply connected nilpotent Lie group G on whichLie algebra g is given one-parameter group of transformations δt = exp(A log t),t > 0, where A is a diagonalized linear operator on G with positive eigenvalues.For G the mappings exp o δt o exp−1, t > 0, are automorphisms on G, which willbe denoted by δt. The number Q = trA is called homogeneous dimension of G.The symbol e will stand for the neutral element in G.
It is possible to equip G with a homogeneous norm r : G → [0,∞) which iscontinuous function on G and smooth on G\e satisfying the following conditions:(i) r(x) = r(x−1) for every x ∈ G;
(ii) r(δtx) = t · r(x) for every x ∈ G and t > 0;
(iii) r(x) = 0 if and only if x = e;
(iv) there exists co ≥ 1 such that
r(xy) ≤ co(r(x) + r(y)), x, y ∈ G.
A ball in G, centered at x and with radius ρ , is defined as
B(x, ρ) = y ∈ G; r(xy−1) < ρ.
It can be observed that δρB(e, 1) = B(e, ρ).
Vol. 13 (2009) Boundedness and compactness 499
Let us fix a Haar measure | · | in G so that |B(e, 1)| = 1. Then |δtE| = tQ|E|,in particular, |B(x, s)| = sQ for x ∈ G, s > 0.
Examples of homogeneous groups are: Euclidean n-dimensional spaces, Heisen-berg group, upper triangular groups etc (see [8] for the definition and basic prop-erties of homogeneous groups).
Let S be the unit sphere in G i.e. S = x ∈ G : r(x) = 1, and let A be ameasurable subset of S with positive measure. We denote by E a measurable conein G defined by
E := x ∈ G : x = δsx, 0 < s < ∞, x ∈ A.
We denote
Et := y ∈ E : r(y) < t.
Now we define the kernel operator by (1), where k(x, y) is non-negative functionon (x, y) ∈ E × E : r(y) < r(x).
In the sequel we shall also use the notation:
Sx := Er(x)/2c0 , Fx := Er(x)\Sx,
where the constant c0 is from the triangle inequality for r.
Let Ω be a measurable subset of G. A locally integrable almost everywherepositive function w on Ω is called a weight. Denote by Lp
w(Ω) (0 < p < ∞) theweighted Lebesgue space, which is the space of all measurable functions f : Ω → C
with finite norm (quasi-norm if 0 < p < 1)
‖f‖Lpw(Ω) =
⎛⎝∫
Ω
|f(x)|pw(x)dx
⎞⎠
1/p
.
Proposition A. Let G be a homogeneous group. There is a (unique) Radon measureσ on S such that for all u ∈ L1(G),
∫
G
u(x)dx =
∞∫
0
∫
S
u(δsy)sQ−1dσ(y)ds.
For the details see e.g. [8], p. 14.
Theorem A. ([6] (Ch. 1)). Let (X,µ) be a measure space and let φ : X → R be aµ-measureable non-negative function. Suppose that 1 < p ≤ q < ∞ and v and ware weight functions on X. Then the operator
(Hφf) (x) =∫
y∈X: φ(y)<φ(x)
f(y)dµ
500 U. Ashraf et al. Positivity
is bounded from Lpw(X) to Lq
v(X) if and only if
supt>0
⎛⎜⎝
∫
x:φ(x)>t
v(x)dµ
⎞⎟⎠
1/q⎛⎜⎝
∫
x:φ(x)<t
w1−p′(x)dµ
⎞⎟⎠
1/p′
< ∞, p′ = p/(p − 1).
Taking X = E, dµ = dx, v = u, w = 1, φ(x) = r(x) in the previous statementand observing that
supt>0
⎛⎜⎝∫
E\Et
u(x)dx
⎞⎟⎠
1/q
tQ/p′ ≈ supj∈Z
⎛⎜⎝
∫
E2j+1\E2j
u(x)dx
⎞⎟⎠
1/q
2jQ/p′,
we have the next statement.
Lemma 2.1. Let 1 < p ≤ q < ∞. Then the operator
(Hf) (x) =∫
Er(x)
f(y)dy
is bounded from Lp(E) to Lqu(E) if and only if
A := supj∈Z
Aj := supj∈Z
⎛⎜⎝
∫
E2j+1\E2j
u(x)dx
⎞⎟⎠
1/q
2jQ/p′< ∞.
Lemma 2.2 ([12] (Ch. XI)). Let (X,µ) and (Y, ν) be σ-finite measure spaces andlet 1 < p, q < ∞. Suppose that for positive function a : X × Y → R, we have∥∥∥‖a(x, y)‖
Lp′ν (Y )
∥∥∥Lq
µ(X)< ∞.
Then the operator
Af(x) =∫
Y
a(x, y)f(y)dν(y)
is compact from Lpν(Y ) to Lq
µ(X).
We shall need also the following statement (see [18] for 1 ≤ q < p < ∞ and[30] for 0 < q < 1 < p < ∞).
Lemma 2.3. Let 0 < q < p < ∞ and p > 1. Then the inequality⎛⎝
∞∫
0
v(x)
⎛⎝
x∫
0
f(t)dt
⎞⎠
q
dx
⎞⎠
1/q
≤ c
⎛⎝
∞∫
0
(f(x))pw(x)dx
⎞⎠
1/p
, f ≥ 0,
Vol. 13 (2009) Boundedness and compactness 501
holds if and only if⎛⎜⎜⎝
∞∫
0
⎡⎢⎣⎛⎝
∞∫
t
v(x)dx
⎞⎠⎛⎝
t∫
0
w1−p′(x)dx
⎞⎠
q−1⎤⎥⎦
p/(p−q)
w1−p′(t)dt
⎞⎟⎟⎠
(p−q)/(pq)
< ∞.
The next lemma is known as the Ando’s theorem (see [1] and [15], Sections5.3 and 5.4) which in our case is formulated for the set E.
Lemma 2.4. Let 0 < q < ∞, 1 < p < ∞ and q < p. Suppose that v and w areHaar-measurable almost everywhere positive functions on E. If the operator
AEf(x) =∫
E
a(x, y)f(y)dy, x ∈ E,
is bounded from Lpw(E) to Lq
v(E), then AE is also compact.
Let H be a separable Hilbert space and let σ∞(H) be the class of all compactoperators T : H → H, which form an ideal in the normed algebra B of all boundedlinear operators on H. To construct a Schatten-von Neumann ideal σp(H) (0 <p ≤ ∞) in σ∞(H), the sequence of singular numbers sj(T ) ≡ λj(|T |) is used,where the eigenvalues λj(|T |) (|T | ≡ (T ∗T )1/2) are non-negative and are repeatedaccording to their multiplicities and arranged in decreasing order. A Schatten-vonNeumann quasinorm (norm if 1 ≤ p ≤ ∞) is defined as follows:
‖T‖σp(H) ≡⎛⎝∑
j
spj (T )
⎞⎠
1/p
, 0 < p < ∞,
with the usual modification if p = ∞. Thus we have ‖T‖σ∞(H) = ‖T‖ and ‖T‖σ2(H)
is the Hilbert-Schmidt norm given by the formula
‖T‖σ2(H) =(∫ ∫
|a(x, y)|2dxdy
)1/2
for the integral operator
Af(x) =∫
a(x, y)f(y)dy.
We refer, for example, to [4,13] for more information concerningSchatten-von Neumann ideals.
Estimates of Schatten-von Neumann ideal norms for the Hardy-type trans-forms and the Riemann-Liouville operators were established in [5,7,23,24]. Thesame problem for operators with positive kernels involving one-sided potentialswas studied in [21].
502 U. Ashraf et al. Positivity
Let ρ be a weight function on E. We denote by lp(L2
ρ(E))
the set of allmeasurable functions g : E → R for which
‖g‖lp(L2ρ(E)) =
⎛⎜⎜⎝∑n∈Z
⎛⎜⎝
∫
E2n+1\E2n
|g(x)|2ρ(x)dx
⎞⎟⎠
p/2⎞⎟⎟⎠
1/p
< ∞.
The next statement deals with interpolation result which is a consequence ofmore general statements from [33] (see also [2]).
Proposition B. Let 1 ≤ p0, p1 ≤ ∞, 0 ≤ θ ≤ 1, 1p = 1−θ
p0+ θ
p1. Suppose that
ρ is a weight function on E. If A is a bounded operator from lpi(L2
ρ(E))
intoσpi
(L2
ρ(E)), where i = 0, 1, then it is also bounded from lp
(L2
ρ(E))
to σp
(L2
ρ(E)).
Moreover,
‖A‖lp(L2ρ(E))→σp(L2(E)) ≤ ‖T‖1−θ
lp0 (L2ρ(E))→σp0 (L2(E))‖T‖θ
lp1 (L2ρ(E))→σp1 (L2(E)).
The following statement is obvious for p = ∞; when 1 ≤ p < ∞ it followsfrom Lemma 2.11.12 of [27].
Proposition C. Let 1 ≤ p ≤ ∞ and let fk, gk be orthonormal systems in aHilbert space H. If T ∈ σp(H), then
‖T‖σp(H) ≥(∑
n
|〈Tfn, gn〉|p)1/p
.
3. Boundedness and compactness criteria
In this section we establish boundedness/compactness criteria for K acting fromLp(E) to Lq
v(E), 1 < p ≤ q < ∞. First we need some definitions regarding thekernel k.
Definition 3.1. Let k be a positive function on (x, y) ∈ E × E : r(y) < r(x) andlet 1 < λ < ∞. We say that k ∈ Vλ, if there exist positive constants c1, c2 and c3
such that
(i) k(x, y) ≤ c1k(x, δ1/(2co)x) (3)
for all x, y ∈ E with r(y) < r(x)/(2co);
k(x, y) ≥ c2k(x, δ1/(2co)x) (3′)
for all x, y ∈ E with r(x)/(2co) < r(y) < r(x);
(ii)∫
Fx
kλ′(x, y)dy ≤ c3r
Q(x)kλ′(x, δ1/(2co)x), λ′ = λ/(λ − 1), (4)
for all x ∈ E.
Vol. 13 (2009) Boundedness and compactness 503
Example. Let G = Rn, r(xy−1) = |x − y|, δtx = tx, x, y ∈ R
n. If k(x, y) = |x −y|λ−n, then k ∈ Vλ, where n/λ < α ≤ n. Indeed, it is easy to see that if y ∈ Sx, then|x| ≤ |x−y|+|y| ≤ |x−y|+|x|/2. Hence |x|/2 = k(x, x/2) ≤ k(x, y). Consequently,(3) holds. Further, it is easy to see that (3′) is also satisfied. Moreover, we have
∫
Fx
|x − y|(α−n)λ′dy =
∞∫
0
∣∣∣y ∈ Fx : |x − y|(α−n)λ′> ε
∣∣∣ dε
≤|x|(α−n)λ′∫
0
(· · · ) +
∞∫
|x|(α−n)λ′
(· · · ) := I1 + I2.
For I1 we have
I1 =
|x|(α−n)λ′∫
0
|B(0, |x|)| dα = c|x|(α−n)λ′+n,
while for I2 we observe that
I2 ≤∞∫
|x|(α−n)λ′
∣∣∣y : |y| < |x|, |x − y| ≤ ε1/(α−n)λ′∣∣∣ dε
≤ c
∞∫
|x|(α−n)λ′
εn/(α−n)λ′dε = cα,n
(|x|(α−n)λ′)1+n/(α−n)λ′
= cα,n|x|n+(α−n)λ′.
Example. It is easy to see that if the following two conditions are satisfied for k:
(i) k(δtx, δτ y) ≤ c1k(δtx, δsz)
for all t, τ, s, x, y, z with 0 < τ < s < t; x, y, z ∈ A;
(ii)t∫
t/(2co)
kλ′(δtx, δτ y)τQ−1dτ ≤ c2t
Q · kλ′((δtx, δt/(2co)x), t > 0, x ∈ A,
then k ∈ Vλ.
Example. Let k(x, y) = k(r(x), r(y)) be a radial kernel. It is easy to check that ifthere exist positive constants c1 and c2 such that(i) k(s, l) ≤ c1k(s, t), 0 < l < t < s,
(ii)t∫
t/(2c0)
kλ′(t, s)sQ−1ds ≤ c2t
Qkλ′(t, t/(2c0)), 1 < λ < ∞, then k ∈ Vλ.
504 U. Ashraf et al. Positivity
Theorem 3.2. Let 1 < p ≤ q < ∞ and let v be a weight on E. Suppose that k ∈ Vp.Then K is bounded from Lp(E) to Lq
v(E) if and only if
B ≡ supj∈Z
B(j) ≡ supj∈Z
⎛⎜⎝
∫
E2j+1\E2j
v(x)kq(x, δ1/(2co)x)dx
⎞⎟⎠
1/q
(2j)Q/p′
< ∞.
Proof. Sufficiency. Let f ≥ 0 on E. We have
‖Kf‖qLq
v(E)≤c
⎡⎣∫
E
v(x)
⎛⎝∫
Sx
k(x, y)f(y)dy
⎞⎠
q
dx +∫
E
v(x)
⎛⎝∫
Fx
k(x, y)f(y)dy
⎞⎠
q
dx
⎤⎦
= c(I1 + I2).
By condition (3) and Lemma 2.1 we find that
I1 ≤ c
∫
E
v(x)kq(x, δ1/(2co)x)
⎛⎜⎝∫
Er(x)
f(y)dy
⎞⎟⎠
q
dx ≤ c
⎛⎝∫
E
fp(x)dx
⎞⎠
q/p
,
while Holder’s inequality and condition (4) yield
I2 ≤∫
E
v(x)
⎛⎝∫
Fx
kp′(x, y)dy
⎞⎠
q/p′ ⎛⎝∫
Fx
fp(y)dy
⎞⎠
q/p
dx
≤ c
∫
E
v(x)kq(x, δ1/(2co))rQq/p′(x)
⎛⎝∫
Fx
fp(y)dy
⎞⎠
q/p
dx
≤ c∑j∈Z
∫
E2j+1\E2j
v(x)kq(x, δ1/(2co))rQq/p′(x)
⎛⎝∫
Fx
fp(y)dy
⎞⎠
q/p
dx
≤ c∑j∈Z
⎛⎜⎝
∫
E2j+1\E2j
v(x)kq(x, δ1/(2co)x)rQq/p′(x)dx
⎞⎟⎠
×
⎛⎜⎝
∫
E2j+1\E2j−1/co
fp(y)dy
⎞⎟⎠
q/p
≤ cBq‖f‖qLp(E).
Sufficiency has been proved.
Vol. 13 (2009) Boundedness and compactness 505
Necessity. To prove necessity we take the functions fj(x) = χE2j+1 (x). Thensimple calculations show that ‖fj‖Lp(E) = c2jQ/p and
‖Kfj(x)‖qLq
v(E)≥
∫
E2j+1\E2j
v(x)
⎛⎝∫
Fx
fj(y)k(x, y)dy
⎞⎠
q
dx
≥ c
⎛⎜⎝
∫
E2j+1\E2j
v(x)kq(x, δ1/(2co)x)dx
⎞⎟⎠ 2jQq.
Finally, due to the boundedness of K we have the desired result. Theorem 3.3. Let 1 < p ≤ q < ∞. Suppose that k ∈ Vp. Then K is compact fromLp(E) to Lq
v(E) if and only if(i) B < ∞; (5)
(ii) limj→−∞
B(j) = limj→+∞
B(j) = 0. (6)
Proof. Sufficiency. Let 0 < a < b < ∞ and represent Kf as follows:
Kf = χEaK(fχEa
) + χEb\EaK(fχEb
)+ χE\Eb
K(fχEb/2c0) + χE\Eb
K(fχE\Eb/2co)
≡ P1f + P2f + P3f + P4f.
For P2 we have
P2f(x) =∫
E
k∗(x, y)f(y)dy,
where k∗(x, y) = χEb\Ea(x)χEr(x)(y)k(x, y). Further, observe that
S :=∫
E
⎛⎝∫
E
(k∗(x, y))p′dy
⎞⎠
q/p′
v(x)dx =∫
Eb\Ea
⎛⎜⎝∫
Er(x)
kp′(x, y)dy
⎞⎟⎠
q/p′
v(x)dx
≤ c
∫
Eb\Ea
⎛⎝∫
Sx
kp′(x, y)dy
⎞⎠
q/p′
v(x)dx + c
∫
Eb\Ea
⎛⎝∫
Fx
kp′(x, y)dy
⎞⎠
q/p′
v(x)dx
:= S1 + S2.
Taking into account the condition k ∈ Vp we have
Si ≤ c
∫
Eb\Ea
kq(x, δ1/(2co)x)rqQ/p′(x)v(x)dx
≤ cbq/p′∫
Eb\Ea
kq(x, δ1/(2co)x)v(x)dx < ∞, i = 1, 2.
506 U. Ashraf et al. Positivity
Finally we have S < ∞ and consequently, by Lemma 2.2 we conclude that P2 iscompact for every a and b. Analogously we can obtain that P3 is compact.
Further, by the arguments used in the proof of Theorem 3.2 we have
‖P1‖ ≤ cB(a) ≡ c supt≤a
⎛⎜⎝∫
Ea\Et
v(x)kq(x, δ1/(2co)x)dx
⎞⎟⎠
1/q
tQ/p′;
‖P4‖ ≤ cB(b) ≡ c supt≥b
⎛⎜⎝∫
E\Et
v(x)kq(x, δ1/(2cox)dx
⎞⎟⎠
1/q
(tQ − bQ
)1/p′.
Therefore
‖K − P2 − P3‖ ≤ ‖P1‖ + ‖P4‖ ≤ c(B(a) + B(b)
).
It remains to show that condition (6) implies
lima→0
B(a) = limb→∞
B(b) = 0.
Let a > 0. Then a ∈ [2m, 2m+1) for some integer m. Consequently B(a) ≤ B(2m+1).Further, for 0 < t < 2m+1, there exists j ∈ Z, j ≤ m, such that t ∈ [2j , 2j+1).Hence
tqQ/p′∫
E2m+1\Et
v(x)kq(x, δ1/(2co)x))dx ≤
≤ 2(j+1)qQ/p′m∑
k=j
∫
E2k+1\E2k
v(x)kq(x, δ1/(2co)x)dx
≤ cBq(k)2jqQ/p′∞∑
k=j
2−kqQ/p′= cBq(k).
Taking into account this estimate we shall find that
B(2m) ≤ supk≤m
Bq(k) ≡ S(m).
If a → 0, then m → −∞. Consequently S(m) → 0, which implies that B(2m) → 0as a → 0. Finally we have that B(a) → 0 as a → 0.
Vol. 13 (2009) Boundedness and compactness 507
Now we take arbitrary b > 0. Then b ∈ [2m, 2m+1) for some m ∈ Z. HenceB(b) ≤ B(2m). Further, for t > 2m, there exists k ≥ m, k ∈ Z such that t ∈[2k, 2k+1). For such a t we have
⎛⎜⎝∫
E\Et
v(x)kq(x, δ1/(2co)x)dx
⎞⎟⎠(tQ − 2mQ
)q/p′≤
≤
⎛⎜⎝
∫
E\E2k
v(x)kq(x, δ1/(2co)x)dx
⎞⎟⎠(2(k+1)Q − 2mQ
)q/p′
≤ c2kqQ/p′∞∑
j=k
⎛⎜⎝
∫
E2j+1\E2j
v(x)k(x, δ1/(2co)x)q(x)dx
⎞⎟⎠
≤ cBq(k)2kqQ/p′∞∑
j=k
2−jqQ/p′ ≤ cBq(k).
Consequently, B(2m) ≤ supk≥m
B(k). From the last inequality we conclude that the
condition limk→+∞
B(k) = 0 implies limb→∞
B(b) = 0.
Necessity. Let K be compact. Since (5) is obvious we have to prove (6). Letj ∈ Z and put fj(y) = χE2j+1\E2j−1/c0
(y)2−jQ/p. Then for φ ∈ Lp′(E), we have
∣∣∣∣∣∣∫
E
fj(y)φ(y)dy
∣∣∣∣∣∣ ≤
⎛⎜⎝
∫
E2j+1\E2j−1/c0
|fj(y)|pdy
⎞⎟⎠
1/p⎛⎜⎝
∫
E2j+1\E2j−1/c0
|φ(y)|p′dy
⎞⎟⎠
1/p′
=
⎛⎜⎝
∫
E2j+1\E2j−1/c0
|φ(y)|p′dy
⎞⎟⎠
1p′
→ 0
as j → −∞ or j → +∞. On the other hand,
‖Kfj‖Lqv(E) ≥
⎛⎜⎝
∫
E2j+1\E2j
(Kfj(x))qv(x)dx
⎞⎟⎠
1/q
≥ c
⎡⎢⎣
∫
E2j+1\E2j
⎛⎝∫
Fx
k(x, y)fj(y)dy
⎞⎠
q
v(x)dx
⎤⎥⎦
1/q
508 U. Ashraf et al. Positivity
≥ c
⎡⎢⎣
∫
E2j+1\E2j
kq(x, δ1/(2co)x)
⎛⎝∫
Fx
fj(y)dy
⎞⎠
q
v(x)dx
⎤⎥⎦
1/q
≥ c
⎛⎜⎝
∫
E2j+1\E2j
kq(x, δ1/(2co)x)v(x)dx
⎞⎟⎠
1/q
2jQ/p′= cB(j).
As a compact operator maps a weakly convergent sequence into a strongly con-vergent one, we conclude that (6) holds.
Now we consider the case when q < p.
Theorem 3.4. Let 0 < q < p < ∞ and let p > 1. Suppose that k ∈ Vp. Then thefollowing conditions are equivalent:
(i) K is bounded from Lp(E) to Lqv(E);
(ii) K is compact from Lp(E) to Lqv(E);
(iii)
D ≡
⎛⎜⎜⎝∫
E
⎛⎜⎝
∫
E\Er(x)
kq(y, δ1/(2co)y)v(y)dy
⎞⎟⎠
p/(p−q)
r(x)Qp(q−1)/(p−q)dx
⎞⎟⎟⎠
(p−q)/pq
< ∞.
Proof. First we show that (iii) ⇒ (i). Suppose that f ≥ 0. Keeping the notationof sufficiency of the proof of Theorem 3.2, using Proposition A and condition (3)we have
I1 ≤ c
∫
E
v(x)kq(x, δ1/(2c0)x)
⎛⎝∫
Sx
f(y)dy
⎞⎠
q
dx
= c
∞∫
0
V (t)
⎛⎜⎝
t/(2c0)∫
0
F (τ)dτ
⎞⎟⎠
q
dt,
where
V (t) := tQ−1
∫
A
v(δtx)kq(δtx, δt/(2c0)x)dσ(x),
F (t) := tQ−1
∫
A
F (δtx)dσ(x).
Vol. 13 (2009) Boundedness and compactness 509
Notice that
D =
⎛⎜⎝
∞∫
0
⎛⎝
∞∫
t
V (τ)dτ
⎞⎠
p/(p−q)
tQp(q−1)/(p−q)+Q−1dt
⎞⎟⎠
(p−q)/(pq)
= c
⎛⎜⎝
∞∫
0
⎛⎝
∞∫
t
V (τ)dτ
⎞⎠
p/(p−q)
×⎛⎝
t∫
0
τ (Q−1)(1−p)(1−p′)dτ
⎞⎠
p(q−1)/(p−q)
t(Q−1)(1−p)(1−p′)dt
⎞⎟⎠
(p−q)/(pq)
.
Consequently, due to Lemma 2.3, Holder’s inequality and Proposition A we findthat
I1 ≤ c
⎛⎝
∞∫
0
t(Q−1)(1−p)F p(t)dt
⎞⎠
q/p
= c
⎛⎝
∞∫
0
t(Q−1)(1−p)
⎛⎝∫
A
f(δtx)dσ(x)
⎞⎠
p
t(Q−1)pdt
⎞⎠
q/p
≤ c
⎛⎝
∞∫
0
tQ−1
⎛⎝∫
A
fp(δtx)dσ(x)
⎞⎠ dt
⎞⎠
q/p
= c
⎛⎝∫
E
fp(x)dx
⎞⎠
q/p
.
Further, applying Holder’s inequality twice and condition (4) we find that
I2 ≤∫
E
v(x)
⎛⎝∫
Fx
fp(y)dy
⎞⎠
q/p⎛⎝∫
Fx
kp′(x, y)dy
⎞⎠
q/p′
dx
≤ c
∫
E
v(x)
⎛⎝∫
Fx
fp(y)dy
⎞⎠
q/p
rQq/p′(x)kq(x, δ1/(2c0)x)dx
= c∑j∈Z
∫
E2j+1\E2j
v(x)
⎛⎝∫
Fx
fp(y)dy
⎞⎠
q/p
r(x)Qq/p′kq(x, δ1/(2c0)x)dx
510 U. Ashraf et al. Positivity
≤ c∑j∈Z
⎛⎜⎝
∫
E2j+1\E2j−1/co
fp(y)dy
⎞⎟⎠
q/p ∫
E2j+1\E2j
v(x)rQq/p′(x)kq(x, δ1/(2co)x)dx
≤ c
⎛⎜⎝∑
j∈Z
∫
E2j+1\E2j−1/co
fp(y)dy
⎞⎟⎠
q/p
×
⎛⎜⎜⎝∑j∈Z
⎛⎜⎝
∫
E2j+1\E2j
v(x)rQq/p′(x)kq(x, δ1/(2co)x)dx
⎞⎟⎠
p/(p−q)⎞⎟⎟⎠
(p−q)/p
≤ c‖f‖qLp(E)
⎛⎜⎜⎝∑j∈Z
⎛⎜⎝
∫
E2j+1\E2j
v(x)rQq/p′(x)kq(x, δ1/(2co)x)dx
⎞⎟⎠
p/(p−q)⎞⎟⎟⎠
(p−q)/p
≡ c‖f‖qLp(E)(D)q.
Further,
(D)pq/(p−q) ≤ c∑j∈Z
2Qq(p−1)j/(p−q)
⎛⎜⎝
∫
E2j+1\E2j
v(x)kq(x, δ1/(2co)x)dx
⎞⎟⎠
p/(p−q)
≤ c∑j∈Z
∫
E2j \E2j−1
r(y)Qp(q−1)/(p−q)
×
⎛⎜⎝
∫
E\Er(y)
v(x)kq(x, δ1/(2c0)x)dx
⎞⎟⎠
p/(p−q)
dy
≤ cDpq/(p−q).
Now we show that (i)⇒(iii). Let vn(x) = v(x)χEn\E1/n(x), where n is an integer
with n ≥ 2. Let
fn(x) =
⎛⎜⎝
∫
E\Er(x)
vn(z)kq(z, δ1/(2c0)z)dz
⎞⎟⎠
1/(p−q)
r(x)Q(q−1)/(p−q).
Vol. 13 (2009) Boundedness and compactness 511
It is easy to see that
‖f‖Lp(E) =
⎛⎜⎜⎝∫
E
⎛⎜⎝
∫
E\Er(x)
kq(y, δ1/(2co)y)vn(y)dy
⎞⎟⎠
p/(p−q)
×r(x)Qp(q−1)/(p−q)dx)1/p
< ∞.
On the other hand, by condition (3′) and integration by parts we find that
‖Kf‖Lqv(E) ≥
⎛⎝∫
E
vn(x)
⎛⎝∫
Fx
fn(y)k(x, y)dy
⎞⎠
q
dx
⎞⎠
1/q
≥ c
⎛⎝∫
E
vn(x)kq(x, δ1/(2c0)x)
⎛⎝∫
Fx
fn(y)dy
⎞⎠
q
dx
⎞⎠
1/q
= c
⎛⎜⎜⎝∫
E
vn(x)kq(x, δ1/(2co)x)
⎛⎜⎜⎝∫
Fx
⎛⎜⎝
∫
E\Er(y)
vn(z)kq(z, δ1/(2co)z)dz
⎞⎟⎠1/(p−q)
×r(y)Q(q−1)/(p−q)dy)q
dx)1/q
≥ c
⎛⎜⎜⎝∫
E
vn(x)kq(x, δ1/(2co)x)
⎛⎜⎝
∫
E\Er(x)
vn(z)kq(z, δ1/(2co)z)dz
⎞⎟⎠
q/(p−q)
×⎛⎝∫
Fx
r(y)Q(q−1)/(p−q)dy
⎞⎠
q
dx
⎞⎠
1/q
≥ c
⎛⎜⎜⎝∫
E
vn(x)kq(x, δ1/(2co)x)
⎛⎜⎝
∫
E\Er(x)
vn(z)kq(z, δ1/(2co)z)dz
⎞⎟⎠
q/(p−q)
×r(x)Qq(p−1)/(p−q)dx)1/q
512 U. Ashraf et al. Positivity
= c
⎛⎝
∞∫
0
tQ−1
⎛⎝∫
A
vn(δtx)kq(δtx, δt/(2co)x)dσ(x)
⎞⎠⎛⎝
∞∫
t
τQ−1
×⎛⎝∫
A
vn(δτ z)kq(δτ z, δτ/(2co)z)dσ(z)
⎞⎠dτ
⎞⎠
q/(p−q)
tQq(p−1)/(p−q)dt
⎞⎟⎠
1/q
= c
⎛⎜⎝
∞∫
0
d
⎛⎝
∞∫
t
τQ−1
⎛⎝∫
A
vn(δτ x)kq(δτ x, δτ/(2co)x)dσ(x)
⎞⎠ dτ
⎞⎠
p/(p−q)
×tQq(p−1)/(p−q)dt)1/q
= c
⎛⎜⎝
∞∫
0
⎛⎝
∞∫
t
τQ−1
⎛⎝∫
A
vn(δτ x)kq(δτ x, δτ/(2co))dσ(x)
⎞⎠ dτ
⎞⎠
p/(p−q)
×tQq(p−1)/(p−q)dt)1/q
= c
⎛⎜⎝
∞∫
0
tQ−1
⎛⎝
∞∫
t
τQ−1
⎛⎝∫
A
vn(δτ x)kq(δτ x, δτ/(2co)x)dσ(x)
⎞⎠dτ
⎞⎠
p/(p−q)
×tQq(p−1)/(p−q)−Qdt)1/q
= c
⎛⎜⎜⎝∫
E
⎛⎜⎝
∫
E\Er(x)
vn(x)kq(x, δ1/(2co)x)dx
⎞⎟⎠
p/(p−q)
r(x)Qp(q−1)/(p−q)dx
⎞⎟⎟⎠
1/q
.
Now the boundedness of K and Fatou’s lemma completes the proof of the impli-cation (i)⇒ (iii).
Lemma 2.4 implies that (i)⇔(ii). The theorem has been proved.
4. Schatten-von Neumann norm estimates
In this section we give necessary and sufficient conditions guaranteeing two-sidedestimates of the Schatten-von Neumann norms for the operator (2).
We denote by k0 the function r(x)Qk2(x, δ1/(2co)x).
Theorem 4.1. Let 2 ≤ p < ∞ and let k ∈ V2. Then Ku ∈ σp(L2(E)) if and only ifu ∈ lp(L2
k0(E)). Moreover, there exist positive constants b1 and b2 such that
b1‖u‖lp(L2k0
(E)) ≤ ‖Ku‖σp(L2(E)) ≤ b2‖u‖lp(L2k0
(E)).
Vol. 13 (2009) Boundedness and compactness 513
Proof. Sufficiency. First observe that
J(x) :=∫
Er(x)
k2(x, y)dy ≤ ck0(x),
where c is a positive constant. Indeed, splitting the integral over Er(x) into twoparts and taking into account the condition k ∈ V2 we have
J(x) =∫
Sx
k2(x, y)dy +∫
Fx
k2(x, y)dy ≤ c1k0(x) + c2k0(x) ≤ c3k0(x).
Hence, the Hilbert-Schmidt formula yields
‖Ku‖σ2(L2(E))=
⎛⎜⎝
∫
E×Er(x)
(k(x, y)u(x))2 dxdy
⎞⎟⎠
1/2
=
⎛⎜⎝∫
E
u2(x)
⎛⎜⎝∫
Er(x)
k2(x, y)dy
⎞⎟⎠ dx
⎞⎟⎠
1/2
≤ c
⎛⎝∫
E
u2(x)k0(x)dx
⎞⎠
1/2
= c
⎛⎜⎝∑
n∈Z
∫
E2n+1\E2n
u2(x)k0(x)dx
⎞⎟⎠
1/2
= c‖u‖l2(L2k0
(E)).
On the other hand, by Theorem 3.2 and Proposition B we have that there is apositive constants c such that
‖Ku‖σp(L2(E)) ≤ c‖u‖lp(L2k0
(E)),
where 2 ≤ p < ∞.Necessity. Let Ku ∈ σp
(L2(E)
). We set
fn(x) = χE2n+1\E2n (x)|E2n+1 \ E2n |− 12 ;
gn(x) = u(x)χE2n+1\E3·2n−1 (x)k1/20 (x)α−1/2
n ,
where
αn =∫
E2n+1\E3·2n−1
u2(x)k0(x)dx.
514 U. Ashraf et al. Positivity
Then it is easy to verify that fn and gn are orthonormal systems in L2(E).By proposition C we find that
∞ > ‖Ku‖σp(L2(E)) ≥(∑
k∈Z
|< Kufn, gn >|p)1/p
=
⎡⎢⎣∑
n∈Z
⎛⎜⎝
∫
E2n+1\E3·2n−1
k1/20 (x)(Kfn)(x)u2(x)α−1/2
n dx
⎞⎟⎠
p⎤⎥⎦
1/p
≥ c
⎡⎢⎣∑
n∈Z
⎛⎜⎝
∫
E2n+1\E3·2n−1
k1/20 (x)u2(x)α−1/2
n
⎛⎜⎝
∫
Er(x)\E2n
k(x, y)fn(y)dy
⎞⎟⎠ dx
⎞⎟⎠
p⎤⎥⎦
1/p
≥ c
⎡⎢⎣∑
n∈Z
⎛⎜⎝
∫
E2n+1\E3·2n−1
k(x, δ1/(2c0)x)u2(x)α−1/2n 2−nQ/2(r(x)Q− 2nQ)dx
⎞⎟⎠p
⎤⎥⎦
1/p
≥ c
⎡⎢⎣∑
n∈Z
⎛⎜⎝
∫
E2n+1\E3·2n−1
u2(x)k0(x)α−1/2n dx
⎞⎟⎠
p⎤⎥⎦
1/p
= c
[ ∞∑n=0
αp/2n
]1/p
.
Let us now take
f ′n(x) = χE3·2n−1\E3·2n−2 (x)|E3·2n−1\E3·2n−2 |− 1
2 ;
g′n(x) = u(x)χE3·2n−1\E2n (x)k1/2
0 (x)β−1/2n ,
where
βn =∫
E3·2n−1\E2n
u2(x)k0(x)dx
and argue as above. Then we will find that
∞ > ‖Ku‖σp(L2(E)) ≥ c
[ ∞∑n=0
βp/2n
]1/p
.
Summarizing the estimates obtained above we have⎛⎜⎜⎝∑n∈Z
⎛⎜⎝
∫
E2n+1\E2n
u2(x)k0(x)dx
⎞⎟⎠
p/2⎞⎟⎟⎠
1/p
≤(∑
n∈Z
(αn + βn)p/2
)1/p
≤ c(‖Ku‖σp(L2(0,∞)) + ‖Ku‖σp(L2(0,∞)))
≤2c‖Ku‖σp(L2(0,∞)).
Vol. 13 (2009) Boundedness and compactness 515
5. Convolution-type operators with radial kernels
Let ϕ be a positive function on [0,∞) and let
Kf(x) =∫
Er(x)
ϕ(r(xy−1))f(y)dy, x ∈ E.
We say that ϕ belongs to Uλ, 1 < λ < ∞, if
(a) there exists a positive constants c1 and c2 such that
ϕ(r(xy−1)) ≤ c1ϕ(r(x)), y ∈ Sx,
ϕ(r(xy−1)) ≥ c2ϕ(r(x)), y ∈ Er(x);
(b) there is a positive constant c3 for which the inequality
∫
Fx
ϕλ′(r(xy−1))dy ≤ c3(r(x))Qϕλ′
(r(x)).
Example. Let ϕ(t) = tα−Q, where Q/λ < α < Q. Then it is easy to see thatϕ ∈ Uλ. Indeed, (a) is obvious due to the properties of the quasi-norm r. Let usshow (b). We have
I : =∫
Fx
ϕλ′(r(xy−1)dy =
∫
Fx
(r(xy−1)(α−Q)λ′dy
=
∞∫
0
|B(0, r(x))| ∩ y ∈ E : (r(xy−1))(α−Q)λ′> s|ds
=
(r(x)(α−Q)λ′∫
0
(· · · ) +
∞∫
(r(x)(α−Q)λ′
(· · · ) := I1 + I2.
It is clear that I1 ≤ (r(x))Qϕλ′(r(x)), while for I2 we find that
I2 ≤∞∫
(r(x)(α−Q)λ′
sQ
(α−Q)λ′ ds = c(r(x))(α−Q)λ′+Q = c(r(x))Qϕλ′(r(x)).
The statements of this section are proved just in the same way as for theoperator K( see the previous sections); therefore the proofs are omitted.
516 U. Ashraf et al. Positivity
Theorem 5.1. Let 1 < p ≤ q < ∞ and let k ∈ Up. Then(i) K is bounded from Lp(E) to Lq
v(E) if and only if
B ≡ supj∈Z
B(j) ≡ supj∈Z
⎛⎜⎝
∫
E2j+1\E2j
v(x)ϕq(r(x))dx
⎞⎟⎠
1/q
(2j)Q/p′
< ∞;
(ii) K is compact from Lp(E) to Lqv(E) if and only if B < ∞ and limj→−∞ Bj =
limj→+∞ Bj = 0.
Theorem 5.2. Let 0 < q < p < ∞ and let p > 1. Suppose that ϕ ∈ Up. Then thefollowing conditions are equivalent:(i) K is bounded from Lp(E) to Lq
v(E);(ii) K is compact from Lp(E) to Lq
v(E);(iii)
⎛⎜⎜⎝∫
E
⎛⎜⎝
∫
E\Er(x)
ϕq(r(y))v(y)dy
⎞⎟⎠
p/(p−q)
r(x)Qp(q−1)/(p−q)dx
⎞⎟⎟⎠
(p−q)/(pq)
< ∞.
Let now ϕ(t) = tQϕ2(t) and let k(x) = ϕ(r(x)). Suppose that
Kuf(x) = u(x)∫
Er(x)
ϕ(r(xy−1))f(y)dy, x ∈ E,
where u is a measurable function on E. Then we have
Theorem 5.3. Then Ku ∈ σp(L2(E)) if and only if u ∈ lp(L2k(E)). Moreover, there
exist positive constants b1 and b2 such that
b1‖u‖lp(L2k(E)) ≤ ‖Ku‖σp(L2(E)) ≤ b2‖u‖lp(L2
k(E)).
Acknowledgement
The authors would like to express their gratitude to the referee for valuable remarksand suggestions.
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Usman Ashraf and Muhammad AsifAbdus Salam School of Mathematical SciencesGC UniversityLahore, Pakistane-mail: [email protected]
Alexander MeskhiA. Razmadze Mathematical InstituteGeorgian Academy of Sciences1, M. Aleksidze St.0193 Tbilisi, Georgiae-mail: [email protected]
Received 26 December 2007; accepted 7 July 2008
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