Tugas 5 Matlab Fajariswan
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Transcript of Tugas 5 Matlab Fajariswan
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2 .bahlah *ersamaan "i++erensial beri$ut $e "alam bentu$ $an%ni$al2
2 3 10 0
d x dxx
dt dt =
a.
3 2
3 2
3 2 10 0
d T d T dT t t T
dt dt dt + =
b
23 2
3
3 2 / 0
d y d y dyy y
dx dx dx
+ =
awab :
2b
d2x
dt23
dx
dt10x=0
x=y1
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dx
dt=
dy1
dt=y
2
d2x
d t2=
dy2
dt=y
3
dy1
dt=y
2
dy2
dt=y
3=10y
1+3y
2
M&T,K :
[dy
1
dt
dy2
dt]=[ 0 110 3] [y1y2]
[ 0 1
10 3
]=0
(AkI)wk=0
det(AkI)=0
det|(0) 110 (3)|=( (0) (3))(101 )=23 10
1 Buat *ersamaan "alam m-+ile ber"asar$an "ata "iatas
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2 im*an *ersamaan
"alam m-+ile
3 ,un *ersamaaan 'ang a"a "alam m-+ile $e "alam %mman" win"%w
Ma$a nilai
1=5 dan
2=2
|(0) 110 (3)||y 1y 2|=0
Karena #et%r eigen w ti"a$ bernilai n%l ma$a $ita misal$an hargay
2 sebagai basis
bernilai 1
()y1+y
2=0
1+ ( 3)y2=0
10y
Ma$a
y1=
1
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y2=1
Memasu$$an harga nilai eigen untu$
1=5 dan
2=2
y[1]=|0,21|
y[2]=[0,51 ]
N%rmalisasi #et%r-#e$t%r eigen tersebut "engan mengguna$an n%rma $e-2
y[1]
'=0,22+12=1,02
y[1]=[0,2/1,021 /1,02]=[0,1960,980 ]
y [2 ]'=(0,52 )+(12 )=1,12
y[2]=[0,5 /1,121 /1,12 ]=[0,4460,893]
a"i nilai "an #et%r eigen matri$s [ 0 110 3]adalah :
=[ 0,20,5]dan y=[
0,196 0,4460,980 0,893]
1 Masu$$an *ersamaan $e "alam m-+ile ber"asar$an "ata "iatas
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2 im*an *ersamaan "ari m-+ile
3 ,un *r%gram $e %mman" win"%w
2 b
d3
T
dt3+t3
d2
T
dt2t2
dT
dt10T=0
T=y1
dT
dt=
dy1
dt=y
2
d2
T
d t2=
dy2
dt=y
3
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d3
T
d t3=
dy3
dt=y
4
dy1
dt=y
2
dy2
dt=y
3
3
dy3
dt=y
4=10y
1+y
1
2y
2y
1
2y
M&T,K : -
Karena P6B ta$ linear ma$a ti"a$ "a*at "itulis "alam bentu$ matri$s
2.c
y = y
1
dy
dx=y
2
d y1
dt =y
2
d2y
d x2=y
3
d y2
dt =y
3
d3y
d x3=y
4
d y3
dt =9y 1y13 . y3+y22
Karena *ersamaan "i atas a"alah P6B ta$ linier ma$a ti"a$ "a*at "itulis$an "alam bentu$
matri$s
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