Tugas 5 Matlab Fajariswan

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    2 .bahlah *ersamaan "i++erensial beri$ut $e "alam bentu$ $an%ni$al2

    2 3 10 0

    d x dxx

    dt dt =

    a.

    3 2

    3 2

    3 2 10 0

    d T d T dT t t T

    dt dt dt + =

    b

    23 2

    3

    3 2 / 0

    d y d y dyy y

    dx dx dx

    + =

    awab :

    2b

    d2x

    dt23

    dx

    dt10x=0

    x=y1

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    dx

    dt=

    dy1

    dt=y

    2

    d2x

    d t2=

    dy2

    dt=y

    3

    dy1

    dt=y

    2

    dy2

    dt=y

    3=10y

    1+3y

    2

    M&T,K :

    [dy

    1

    dt

    dy2

    dt]=[ 0 110 3] [y1y2]

    [ 0 1

    10 3

    ]=0

    (AkI)wk=0

    det(AkI)=0

    det|(0) 110 (3)|=( (0) (3))(101 )=23 10

    1 Buat *ersamaan "alam m-+ile ber"asar$an "ata "iatas

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    2 im*an *ersamaan

    "alam m-+ile

    3 ,un *ersamaaan 'ang a"a "alam m-+ile $e "alam %mman" win"%w

    Ma$a nilai

    1=5 dan

    2=2

    |(0) 110 (3)||y 1y 2|=0

    Karena #et%r eigen w ti"a$ bernilai n%l ma$a $ita misal$an hargay

    2 sebagai basis

    bernilai 1

    ()y1+y

    2=0

    1+ ( 3)y2=0

    10y

    Ma$a

    y1=

    1

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    y2=1

    Memasu$$an harga nilai eigen untu$

    1=5 dan

    2=2

    y[1]=|0,21|

    y[2]=[0,51 ]

    N%rmalisasi #et%r-#e$t%r eigen tersebut "engan mengguna$an n%rma $e-2

    y[1]

    '=0,22+12=1,02

    y[1]=[0,2/1,021 /1,02]=[0,1960,980 ]

    y [2 ]'=(0,52 )+(12 )=1,12

    y[2]=[0,5 /1,121 /1,12 ]=[0,4460,893]

    a"i nilai "an #et%r eigen matri$s [ 0 110 3]adalah :

    =[ 0,20,5]dan y=[

    0,196 0,4460,980 0,893]

    1 Masu$$an *ersamaan $e "alam m-+ile ber"asar$an "ata "iatas

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    2 im*an *ersamaan "ari m-+ile

    3 ,un *r%gram $e %mman" win"%w

    2 b

    d3

    T

    dt3+t3

    d2

    T

    dt2t2

    dT

    dt10T=0

    T=y1

    dT

    dt=

    dy1

    dt=y

    2

    d2

    T

    d t2=

    dy2

    dt=y

    3

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    d3

    T

    d t3=

    dy3

    dt=y

    4

    dy1

    dt=y

    2

    dy2

    dt=y

    3

    3

    dy3

    dt=y

    4=10y

    1+y

    1

    2y

    2y

    1

    2y

    M&T,K : -

    Karena P6B ta$ linear ma$a ti"a$ "a*at "itulis "alam bentu$ matri$s

    2.c

    y = y

    1

    dy

    dx=y

    2

    d y1

    dt =y

    2

    d2y

    d x2=y

    3

    d y2

    dt =y

    3

    d3y

    d x3=y

    4

    d y3

    dt =9y 1y13 . y3+y22

    Karena *ersamaan "i atas a"alah P6B ta$ linier ma$a ti"a$ "a*at "itulis$an "alam bentu$

    matri$s

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