Tugas 3 Mekanika Kontinum
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Transcript of Tugas 3 Mekanika Kontinum
A. DATA PERENCANAAN
x yTitik A1 1 1Titik A2 6 1Titik A3 6 6Titik A4 1 6Titik B1 8 2.5Titik B2 14 2.5Titik B3 14 4.5Titik B4 8 4.5
B. DITANYA
1 . Pertumbuhan x2. Pertumbuhan y3. Regangan Alami x4. Regangan Alami y5. Regangan Teknis x6. Regangan Teknis y7. Regangan Lagrange x8. Regangan Lagrang y9. Regangan Euler x10. Regangan Euler y
C. JAWAB
1. Pertumbuhan x
La x = 6L x = 5λx = La/L = 1.2 > 1 Memanjang
2 4 6 8 10 12 14 16
2
4
6
8
0
A 5X5 B 6X2
A1 (1,1) A2 (6,1)
A3 (6,6)A4 (1,6)
B1 (8,2.5) B2 (14,2.5)
B3 (14,4.5)B3 (8,4.5)
2. Pertumbuhan y
La y = 2L y = 5λy = La/L = 0.4 < 1 Memendek
3. Regangan Alami x
λx = 1.2ηx = 1 - 1/λx = 0.17
4. Regangan Alami y
λy = 0.4ηy = 1 - 1/λy = -1.5
5. Regangan Teknis x
λx = 1.2= 0.20
6. Regangan Teknis y
λy = 0.4= -0.6
7. Regangan Lagrange x
λx = 1.2= 0.22
8. Regangan Lagrange y
λy = 0.4= -0.42
9. Regangan Euler x
λx = 1.2= 0.17
10. Regangan Euler y
λy = 0.4= -2.63
εx = λx - 1
εy = λy - 1
Ex = (λx2 - 1)/2
Ey = (λy2 - 1)/2
ex = (1 - 1/λx2)/2
ey = (1 - 1/λy2)/2
Memanjang
2 4 6 8 10 12 14 16
2
4
6
8
0
A 5X5 B 6X2
A1 (1,1) A2 (6,1)
A3 (6,6)A4 (1,6)
B1 (8,2.5) B2 (14,2.5)
B3 (14,4.5)B3 (8,4.5)