LAPORAN TUGASBESAR

MEKANIKA REKAYASA III

DISUSUN QLSH;

NAMA

NIM

: ASRY MEFPITASARI

z \OT22OlOl24

PROGRAM STUDI TEKNIK SIPIL

FAKULTAS TEKNIK

T]NTVERSITAS AI\ITAKUST'MA ( I]NTAMA )

PANGKALAN BT'N

JAI\IUARI 2OI2

7

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U N IVERSITAS ANTAKUSUMA PANGKALAN BUNFAKULTAS TEKNIK

JURUSAN TEKNIK SIfSIPIL

Tugas Besar Mekanika Rekayasa lll

Konstruksi beton (gedung bertingkat) seperti diatas dengan d{ta teknis sebagai berikut:

1. Ht=..l,f, H2=.3 n2. L L=...&-.m, tZ =4^,13=-.9.m3. Ukuran batang sebaqai berikut dipilih oleh asisten;

AF = """" @,oo/*,40160lFG=........ @/:g+o4o,4o / 60lFH=........ { 3al N @lg),4a1 6alGl=........ (

911=........ ( 301

Ht=........ { 3O/4o,4O/40

tJ=........ (3O14A,4

HC=........ { 3Ol 4o,4A/

tD=........ { 30l40,4Ol

JE=.....:.. (3ol40@d /6014- Bebanmerata, qt=.{tlm; qZ=.ht/m; qZ=*.tlm; qa=.Q-:tlm; pr=.\-t p2=9rp3=1..t

P4=...t { Ditentukan oleh asisten}

5. Hitung dan garnbarkan bidang Mornen, Lintang dan Normal6. Pergunakan metoda Cross

7. Asistensi dengan Asisten Tugas minimal 5 kali pertemuan.

:Fr

PROGRAM STUDI TEKNIK SIPIL

FAKULTAS TEKNIKUNIVERSITAS ANTAKUSUMA PANGKALAN BUN

NAMANIM

TUGAS EESAR / PRAKTTKUM :

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NAMAASISTEN

NAMADOSEN}IARUS SETESAI TANGGAT

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MEKAN//KA REKAY,SA /l/,I

TU6AS BESAR

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lt.,?_<, t{tobtt -= QLa z a.l* : 216A tnr. Ct'l;ct4n ; " "'6'

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TU6N BESAR

Bocq..g (lcrrsqrr (ew.) Mow\cr\ tnCrsicr Cctl 4) AneCo. teleo.Fr^orrlrt30 IAF: ,A.bu'" tASr3. I

AY h '4o : /r2.3o.4o3 qLL .2oo : t6o.ooo :3 " 16o.oorr

z 20()

= 6oolasA =g,,qp = 6oo

lt:3o tsF6=l el6O.aOQ =4o0F6 h.4o 'Az.s.hs L loo

Le4so : i6S.OS tF6:ltGF = 4OO

hr:30 IF\t = '/,..1'"ht !<FU=t z 2t3.383r33fu h:4s = t/tz.Ao.Asg L 3oa

L:3s a 2\3333133 : ?tt,\rttTIr = blts: Trr, trl

b= As 16r:942.bh3 FEF: I : 2\3.3331336r h. 4o : 7tz-4o-Ao3 L 3@

t- = 3oo :213-333,33 = Tllr lltst -_Ft6: ?ilrttr

b= As tg$ = Xz.t t"g lgt\: 1 - 213.33.3B\r [:4s z V\L. Ao.4o3 L bo

L:2'oo :1r'B-333r3=l = 1(r€6166kEt{=EttB:1066,G

L-'lG lHt = t/rz.bxs F$t=l =?20.S0

HI h= 60 ? Vrz. Ao,6os L htpL.4oo :4bS : t.€S

tstlt: Ftt{= t.8oOllX =

t/tz.uur !+a= I :4ZO.oOtrt1 b=4o : VrZ.I{9.603 L 3oo

ho 6D zTro.@ : 2..looL:b kDSe\ag = Z.I<@b=lao ltlc:. Vrz.tot s kblc =l . ?zo.O0tt

llc h:6 7 vZ.Ao.603 L hmL : l,roo -- ?o.sct : t,&O

tsFtc: t=Ctr: t.Sob! r$ tE$B = Vt.bug tslD. 1 :72o.o8

}D lnz 6o . Ytz.Ao.6os L mL: 4oo =42o.OOo = l-&o

KID: t<Df = t-Orrrrt>'Ao I3E " tz1r. Ul-F t-3€g1 : 213.333,33

f,E 1.. . lO z 'lrz-ho,d& L IML =&oo :2\3.333 r33 . 533'33

FIE:t=€3-- E33'33

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ruGN BESAR

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r?lLIFFt\: :Ht,il ch^3 DFree AGCI : Or23

?--E--:..11!trti <,F.n3 FllruDFtt{gTll,tt: o{,$

t+lt;lt..............8*.

EoF: r 'k€F = hg Cr',r DG6F=4oo : 0136

.e* FGC = {ivil-.a;t lllt, ll?-_F.:.!!.!!r!t cn^3 IrFGI : ?ll, \l = OtQ

I lll, ll;^;"-T-kh5 . Tl\rtt <',S Dptrs:?ll,$ : drt?

br ts\tB: r0661G1 q*3 #[r?nr*r i i'iii["'-" di;:' D-FBp= toG6rgT z c,tr9kttc ' t'Oq) cFJ 9EEAO

?-ts.i fi?O er.3 DFHI: l-Oe .ot%53F+Fn

53r+flo9oeal

ktlr = t0cnr <r-3 Deru : l,ocr ,6t,flI F!6 : atlr I\ Cvn3 d+\t,tr

b-c-c-c-c-c-c-c-c-c-c-c-c-c-ci-l--:_,i,r;g6""'e;i' EF tG : TtV tr : drtf.!.9.= t.6oo o;g-- e+{tr\t

ZE:Clltrtt qw.3 Dgia = 2..Lr:t: elt'?e6+ttrll

itcitt';l:di6':;;t{'6?tt,tr;#':'-:1-'

l<3t : 2.ltob aw.3 DFJI :- eAM) :6103 ..F]..Q.3. 9 33133 cr"e

-...,2k : ?;9i3?133 eE^?'u,73t

DFStr s93!n3=or229EB,339-$tr : I

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MEKANIKA REKAYASA IU

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-.Y1\{. 4 + Q. 2 -M}rt + \^1\\ -_ O-vtH.A t ts.2-Oft6+665=0

Vr\\ = Sr4S St Crt)

2rSS*5rAS-O =O

MEKAN'IKA REKAYASA 'II

ru6,AS EESAR

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I *3t:r.-s.*....19.:.....8.-u..)..

Vt{T -VFH =n

Ew\f = C)

-tH3 -t^FH -\.rHp=O-F\{3 -Ofl4-0136'=.0

MEKAN/IKA REKAYN,A "I

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H.u...;..$.g.=.9

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