SP
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. PERHITUNGAN UKURAN DIAMETER PIPA PLAMBING DENGAN METODE PANJAANG EKIVALEN-1 (SOLUSI UTS) 1. Pengelompokan alat-alat saniter Debit air yang disyaratkan pada alat saniter menurut Tabel 4.1, adalah : - Water closet (WC) = 0.11 Liter/detik. - Bath tub (bak mandi) = 0.30 Liter/detik. - Lavatory (washtafel) = 0.15 Liter/detik. - Kichen sink (bak cuci dapu = 0.19 Liter/detik. 2. Tinggi tekan air yang tersedia terhadap lantai = 8.50 m. 3. Perhitungan diameter setiap ruas pipa. Diameter Panjang Panjang ekivalen (m) Panjang Tinggi tekan Panjang Kehilangan Tekanan Debit yang Ruas pipa, mm sebenarnya ekivalen yg. tersedia ekiv. total tekanan kritis diperlukan pipa (asumsi) (L) 25% x (L) Tabel 4.2 (m) (m) Liter/detik (1) (2) (3) (4) (5) (6) (2) (3) (4) (6) (7) f - j ¾ 4.50 1.13 6.00 11.63 7.30 112.38 0.90 0.90 0.19 f - i ¾ 2.50 0.63 6.00 9.13 7.30 100.75 0.90 0.15 e - h 1 2.50 0.63 9.00 12.13 7.30 91.63 0.90 0.30 d - g ¾ 1.50 0.38 6.00 7.88 8.30 79.50 1.50 0.90 0.11 e - f 1 2.50 0.63 9.00 12.13 8.80 71.63 1.20 0.90 0.34 d - e 1 2.00 0.50 9.00 11.50 8.80 59.50 0.90 0.64 c - d 2.50 0.63 11.00 14.13 8.80 48.00 0.90 0.75 b - c 1.00 0.25 11.00 12.25 8.80 33.88 0.90 0.75 a - b 8.50 2.13 11.00 21.63 8.80 21.63 0.90 0.75 hL major hL minor (m) (kN/m 2 ) (kN/m 2 ) 1¼ 1¼ 1¼ R eservoir atas LV 8 , 0 0 WC KM KS 1 , 5 0 a f g h i j 1 , 2 0 Ø ¾” Ø ¾” Ø 1” ” Ø 1¼ ”
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tugasPERHITUNGAN UKURAN DIAMETER PIPA PLAMBING DENGAN METODE PANJAANG EKIVALEN-1 (SOLUSI UTS)PERHITUNGAN UKURAN DIAMETER PIPA PLAMBING DENGAN METODE PANJANG EKIVALEN-2 1. Pengelompokan alat-alat saniter1. Pengelompokan alat-alat saniterDebit air yang disyaratkan pada alat saniter menurut Tabel 4.1, adalah :Debit air yang disyaratkan pada alat saniter menurut Tabel 4.1, adalah :- Water closet (WC) =0.11Liter/detik.- Water closet (WC) =0.11Liter/detik =1.744gpm.- Bath tub (bak mandi) =0.30Liter/detik.- Bath tub (bak mandi) =0.30Liter/detik =4.756gpm.- Lavatory (washtafel) =0.15Liter/detik.- Lavatory (washtafel) =0.15Liter/detik =2.378gpm.- Kichen sink (bak cuci dapur)=0.19Liter/detik.- Kichen sink (bak cuci dapur)=0.19Liter/detik =3.012gpm.
2. Tinggi tekan air yang tersedia terhadap lantai = 8.50m.2. Head yang tersedia terhadap lantai =+ 8,5m = +ERROR:#VALUE!feet.9m =29.529feet
3. Perhitungan diameter setiap ruas pipa.DiameterPanjangPanjang ekivalen (m)PanjangTinggi tekanPanjangKehilanganTekananDebit yangDiameter pipaRuaspipa, mmsebenarnyahL majorhL minorekivalenyg. tersediaekiv. totaltekanankritisdiperlukanyg. diperlukanpipa(asumsi)(L)25% x (L)(Tabel 4.2)(m)(m)(m)(kN/m2)(kN/m2)(Liter/detik)(mm)(inch)(1)(2)(3)(4)(5)(6)(2)(3)(4)(6)(7)(8)(9)f - j4.501.136.0011.637.30112.380.900.900.1916 (18)f - i2.500.636.009.137.30100.750.900.1515 (18)e - h12.500.639.0012.137.3091.630.900.3019 (25)1d - g1.500.386.007.888.3079.501.500.900.1113 (18)e - f12.500.639.0012.138.8071.631.200.900.3420 (25)1d - e12.000.509.0011.508.8059.500.900.6424 (25)1.c - d12.500.6311.0014.138.8048.000.900.7526 (32)1b - c11.000.2511.0012.258.8033.880.900.7526 (32)1a - b18.502.1311.0021.638.8021.630.900.7526 (32)1
DiameterPanjangPerlengkapan pipa yg terpasang : fitting, valve, faucet, dll. (Tabel 4.3)PanjangTotalhLmajor Total head HeadDiameterRuaspipapipa90oStd.GateGlobeCheckFaucetFootStrainerekivalenDebit yangpanjangyang terjadiyg dibutuhkanyang tersediapipapipa"asumsi"terukurElbowTeevalvevalvevalvevalve"minor"diperlukanekivalenfeet /100 feet= (15)/100*(16)terpakai(inch)(m)(feet)(feet)(feet)(feet)(feet)(feet)(feet)(feet)(feet)(feet)(gpm)(feet)(Tabel 4.4)(feet)(m)(feet)(inch)(1)(2)(3)(4)(5)(6)(7)(8)(9)(10)(11)(12)(13)(14)(15)(16)(17)(18)(19)(20)1q-u4.5014.765.40---16.00--36.163.012467.7427.00126.2917.8029.5232q-t2.508.203.60---16.00-27.802.38431.5815.80068.1907.8029.5233p-s2.508.203.60---16.00-27.804.76403.7854.860221.5127.8029.5234o-r1.203.943.60---21.00-28.541.74375.977.40027.8229.3035.2015p-q2.508.20-4.50----12.7035.39347.4418.19063.1999.3035.2016o-p2.006.56-4.50----11.06210.15334.7453.000177.4109.3035.2017n-o12.508.202.254.50----14.95311.89323.6724.05077.8439.3035.2018m-n11.003.282.25-----5.53111.89308.7224.05074.2479.3035.2019b-m15.2017.06------17.06111.89303.1924.05072.9179.0034.06510h-l4.5014.766.75---21.00-42.5153.012286.137.00020.0293.8014.38311h-k2.508.204.50----21.0033.7032.38243.614.1009.9883.8014.38312g-j2.508.204.50---21.00--33.7034.756209.9114.1529.7023.8014.38313f-i1.203.943.60---21.00-28.5371.74176.217.40013.0394.8018.16814g-h12.508.20-5.80---14.0035.39147.675.6308.3145.3020.06115f-g12.006.56-5.80---12.36210.15133.6715.76021.0665.3020.06116e-f12.508.202.757.50----18.45311.89121.3124.05029.1745.3020.06117d-e11.003.282.75-----7.03111.89102.8524.05024.7375.3020.06118c-d11.203.942.75-----7.88711.8995.8224.05023.0465.3020.06119b'-c10.100.33---27.00--27.32811.8987.9424.05021.1494.1015.51920b-b'10.100.332.75----3.07811.8960.6124.05014.5764.1015.51921a-b13.8012.472.75-----15.21823.7857.5389.00051.2024.1015.51922a'-a10.200.66--27.00--27.6560.0042.31--0.000.00023a''-a'10.200.66-------14.0014.6560.0014.66--0.000.000
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Sheet1
Debit sumurSOLUSI UTS KELAS : 2D4-TPPG_2014Soal-1.a : SUMUR DANGKAL TANPA SPSoal 1.b : SUMUR DALAM TANPA SPData : k =1*10-4 m/s =0.0001m/detikData : k =2,5*10-4 m/s =0.00025m/detikH =16,00 - 5,00 =11.00m.H =50,00 - 5 =45.00m.b = 20 m.hw =16,00 - 6,50 =9.50m.hw =50,00 - 6,5 =43.50m.m/hari =0.9rw =0,075/2 =0.0375m.rw =0,15/2 =0.075m.Jawab :Jawab :R = 300*s*(k0,5) s =H - hw = 1.50m.R = 300*s*(k0,5) s = H - hw =1.50m.=4.500m.=7.115m.Q =p k (H2 - hw2) / (ln (R/rw))Q =2 p k b (H - hw) / (ln (R/rw))=0.002m3/detik =2.017liter/detk=0.010m3/detik=10.346liter/detk
Soal Latihan 1.2 : SUMUR DANGKAL DENGAN SPSoal Latihan 2.2 : SUMUR DALAM DENGAN SPData : k =1*10-4 =0.0001m/detikData : k =3*10-4 m/s =0.0003m/detikh1 =34.6m.hw =32.5m.b = 30 m.h2 =35m.h =34.9m.m/hari =1.08r1 =3m.r1 =12m.r2 =7.5m.rw =0.075m.Jawab :Jawab :Q =p k (h22 - h12) / (ln (r2/r1))Q =2 p k b (h - hw) / (ln (r1/rw))=0.010m3/detik =9.540liter/detk=0.027m3/detik =26.728liter/detk
