Revisi Soal & Penyelesaian, Metode Hardy Cross
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SOAL Batang AB a 2m b 2m L ( a+b) 4m Mab = Pab^2/l^2 = 1.05 Mba = Pa^2b/l^2 = -1.05 Titik B nBA : nBC = 4EIBA/LBA : 4EIBC/LBC = EI/4 : 2EI/4 nBA : nBC = 0.25 : 0.5 nBA = 0.333333 nBC = 0.666667 Titik C nBC : nCD = 4EICB/LCB:3EICD/LCD = 4.2EI/4 : 3EI/4 nBC : nCD = 8 : 3 Ncb = 0.727273
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Transcript of Revisi Soal & Penyelesaian, Metode Hardy Cross
SOAL
Momen primer
Batang AB Batang BC
a 2 mb 2 mL ( a+b) 4 m
Mab = Pab^2/l^2 = 1.05 MBCMba = Pa^2b/l^2 = -1.05 MCB
L
Faktor distribusiTitik BnBA : nBC = 4EIBA/LBA : 4EIBC/LBC
= EI/4 : 2EI/4nBA : nBC = 0.25 : 0.5
nBA = 0.333333nBC = 0.666667
Titik CnBC : nCD = 4EICB/LCB:3EICD/LCD
= 4.2EI/4 : 3EI/4nBC : nCD = 8 : 3Ncb = 0.727273
nCD = 0.272727
TABEL CROSSTitik A B C DBatang AB BA BC CB CD DCFak.distribusi 0.333333 0.66666666667 0.72727273 0.27272727 0
1.05 -1.05 1.6 -1.6 2.5375 0Distribusi 0 -0.183333 -0.3666666667 -0.68181818 -0.25568182 0Induksi -0.0916666667 -0.3409090909 -0.18333333Distribusi 0 0.113636 0.22727272727 0.13333333 0.05 0Induksi 0.05681818182 0.06666666667 0.11363636Distribusi 0 -0.022222 -0.0444444444 -0.08264463 -0.03099174 0Induksi -0.0111111111 -0.041322314 -0.02222222Distribusi 0 0.013774 0.02754820937 0.01616162 0.00606061 0Induksi 0.00688705234 0.00808080808 0.0137741Distribusi 0 -0.002694 -0.0053872054 -0.01001753 -0.00375657 0Induksi -0.0013468013 -0.0050087653 -0.0026936Distribusi 0 0.00167 0.00333917689 0.00195898 0.00073462 0Induksi 0.00083479422 0.00097949189 0.00166959Distribusi 0 -0.000326 -0.0006529946 -0.00121425 -0.00045534 0Induksi -0.0001632486 -0.0006071231 -0.0003265Distribusi 0 0.000202 0.00040474871 0.00023745 8.90447E-05 0Induksi 0.00010118718 0.00011872629 0.00020237Distribusi 0 -3.96E-05 -7.915086E-05 -0.00014718 -5.5193E-05 0Induksi -1.978771E-05 -7.3590675E-05 -3.9575E-05Distribusi 0 2.453E-05 4.906045E-05 2.87821E-05 1.07933E-05 0Induksi 1.2265113E-05 1.4391065E-05 2.45302E-05Distribusi 0 -4.8E-06 -9.5940436E-06 -1.784E-05 -6.6901E-06 0Induksi -2.398511E-06 -8.9200819E-06 -4.797E-06jumlah 1.01034346668 -1.129313 1.12930414657 -2.30345251 2.30344771 0
FREE BODYBatang AB Batang BC
2.1 ton
MAB 1.01 Ton.m MBA 1.13 Ton.m MBARA RB RB
RA = p/2+(MAB MBA)/L RBRA = 1.020258 Ton RB
Mo
RB = P-RA RCRB = 1.079742 Ton RC1
Reaksi perletakan
RARBRCRD
PERHITUNGAN MOMEN & GESER
MAE X ≤2
JARAK JARAK YG DI MOMEN GESER0 0 -1.010343 1.0202576
0.25 0.25 -0.755279 1.02025760.5 0.5 -0.500215 1.0202576
0.75 0.75 -0.24515 1.02025761 1 0.009914 1.0202576
1.25 1.25 0.264979 1.02025761.5 1.5 0.520043 1.0202576
1.75 1.75 0.775107 1.02025762 2 1.030172 1.0202576
MEB 0≤ X ≤2
0 2 1.030172 -1.0797420.25 2.25 0.760236 -1.079742
0.5 2.5 0.490301 -1.0797420.75 2.75 0.220365 -1.079742
1 3 -0.049571 -1.0797421.25 3.25 -0.319506 -1.079742
1.5 3.5 -0.589442 -1.0797421.75 3.75 -0.859377 -1.079742
2 4 -1.129313 -1.079742
MBC 0≤ X ≤4
0 4 -1.129313 3.63965780.25 4.25 -0.640197 3.3396578
0.5 4.5 -0.226082 3.03965780.75 4.75 0.113034 2.7396578
1 5 0.37715 2.43965781.25 5.25 0.566266 2.1396578
1.5 5.5 0.680381 1.83965781.75 5.75 0.719497 1.5396578
2 6 0.683613 1.23965782.25 6.25 0.572728 0.9396578
2.5 6.5 0.386844 0.63965782.75 6.75 0.12596 0.3396578
0≤
MBC 0≤ X ≤4
3 7 -0.209924 0.03965783.25 7.25 -0.620809 -0.260342
3.5 7.5 -1.106693 -0.5603423.75 7.75 -1.667577 -0.860342
4 8 -2.303461 -1.160342
MCF 0≤ X ≤2
0 8 -2.303461 6.82586310.25 8.25 -1.796996 6.5258631
0.5 8.5 -1.29053 6.22586310.75 8.75 -0.784064 5.9258631
1 9 -0.277598 5.62586311.25 9.25 0.228867 5.3258631
1.5 9.5 0.735333 5.02586311.75 9.75 1.241799 4.7258631
2 10 1.748265 4.4258631
MFD 0≤ X ≤2
0 10 1.748265 6.82586310.25 10.25 2.164106 5.8008631
0.5 10.5 2.398696 4.77586310.75 10.75 2.452037 3.7508631
1 11 2.324128 2.72586311.25 11.25 2.014969 1.7008631
1.5 11.5 1.52456 0.67586311.75 11.75 0.8529 -0.349137
2 12 -8.92E-06 -1.374137
GAMBAR DIAGRAM MOMEN & GESERSOAL
GAMBAR DIAGRAM MOMEN
0 2 4 6 8 10 12 14
-3
-2
-1
0
1
2
3
MOMEN
MOMEN
GAMBAR DIAGRAM GESER
0 2 4 6 8 10 12 14
-3
-2
-1
0
1
2
3
MOMEN
MOMEN
0 2 4 6 8 10 12 14
-2
-1
0
1
2
3
4
5
6
7
8
GAYA GESER
GAYA GESER
Nama Harry HutagalungNim 3101001129
DATA INPUT
A = 1B = 2C = 9P = 2.1q1 = 1.2q2 = 2.9AB = 4BC = 4CD = 4
Momen primer
S
= ql^2/12 = 1.6= ql^2/12 = -1.6 MCD = 7ql^2/128 =
4 m
Faktor distribusi
TABEL CROSS
FREE BODYBatang CD
q1 1.2 ton/m
MCD 2.303453 Ton.m1.13 Ton.m MCB 2.303 Ton.m RC
RC
= ql/2+(MBC+MCB)/L RC2 = 2.025863= 2.1064629 RD = 2.424137
= Q1-RB= 2.6935371
Reaksi perletakan
= 1.0202576 Ton= 3.1862053 Ton= 4.7194002 Ton= 2.4241369 Ton
PERHITUNGAN MOMEN & GESER
GAMBAR DIAGRAM MOMEN & GESERSOAL
GAMBAR DIAGRAM MOMEN
0 2 4 6 8 10 12 14
-3
-2
-1
0
1
2
3
MOMEN
MOMEN
GAMBAR DIAGRAM GESER
0 2 4 6 8 10 12 14
-3
-2
-1
0
1
2
3
MOMEN
MOMEN
0 2 4 6 8 10 12 14
-2
-1
0
1
2
3
4
5
6
7
8
GAYA GESER
GAYA GESER
Harry Hutagalung
Momen primer
L 4 m
2.5375
Faktor distribusi
TABEL CROSS
FREE BODY
q2 2.9
RDTon/m
Reaksi perletakan
PERHITUNGAN MOMEN & GESER
GAMBAR DIAGRAM MOMEN & GESER
