Perhitungan Kadar Vitamin c
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PERHITUNGAN KADAR VITAMIN C Data Baku KONSENTRASI = C (bpj) ABSORBANSI (A) 2,5 0,127 5 0,245 7,5 0,350 10 0,465 15 0,672 a = 0,02364864865 b = 0,04351891892 r = 0,9997 r 2 = 0,9994 pH 4,0 t = 0 menit y = a + bx 0,4495 = 0,02364864865 + 0,04351891892x 0,4495 - 0,02364864865 = 0,04351891892x x = 9,7854 C = 9,7854 Log C = 0,9906 t = 10 menit y = a + bx 0,3385 = 0,02364864865 + 0,04351891892x 0,3385 - 0,02364864865 = 0,04351891892x x = 7,2348 C = 7,2348 Log C = 0,8594
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Transcript of Perhitungan Kadar Vitamin c
PERHITUNGAN KADAR VITAMIN C
Data Baku
KONSENTRASI = C (bpj) ABSORBANSI (A)2,5 0,1275 0,245
7,5 0,35010 0,46515 0,672
a = 0,02364864865
b = 0,04351891892
r = 0,9997
r2 = 0,9994
pH 4,0
t = 0 menity = a + bx0,4495 = 0,02364864865 + 0,04351891892x0,4495 - 0,02364864865 = 0,04351891892xx = 9,7854C = 9,7854Log C = 0,9906
t = 10 menity = a + bx0,3385 = 0,02364864865 + 0,04351891892x0,3385 - 0,02364864865 = 0,04351891892xx = 7,2348C = 7,2348Log C = 0,8594
t = 20 menity = a + bx0,2610 = 0,02364864865 + 0,04351891892x0,2610 - 0,02364864865 = 0,04351891892xx = 5,4540C = 5,4540
Log C = 0,7367
t = 40 menity = a + bx0,2450 = 0,02364864865 + 0,04351891892x0,2450 - 0,02364864865 = 0,04351891892xx = 5,0863C = 5,0863Log C = 0,7064
pH 4,5 t = 0 menit
y = a + bx0,6400 = 0,02364864865 + 0,04351891892x0,6400 - 0,02364864865 = 0,04351891892xx = 14,1628C = 14,1628Log C = 1,1516
t = 10 menity = a + bx0,5930 = 0,02364864865 + 0,04351891892x0,5930 - 0,02364864865 = 0,04351891892xx = 13,0828C = 13,0828Log C = 1,1167
t = 20 menity = a + bx0,5305 = 0,02364864865 + 0,04351891892x0,5305 - 0,02364864865 = 0,04351891892xx = 11,6467C = 11,6467Log C = 1,0662
t = 40 menity = a + bx0,5145 = 0,02364864865 + 0,04351891892x0,5145 - 0,02364864865 = 0,04351891892xx = 11,2790C = 11,2790Log C = 1,0523
PERHITUNGAN TETAPAN LAJU PERURAIAN BERDASARKAN ORDE 1
pH = 4,0
t (menit) Log C0 0,990610 0,859420 0,736740 0,7064
a = 0,94418
b = -6,908857143.10-3
r = 0,9098015113
r2 = 0,82773879
b = −k
2,303
-6,908857143.10-3 = −k
2,303
K = 0,015911098/menit
pH = 4,5
t (menit) Log C0 1,151210 1,116720 1,066240 1,0523
a = 1,14018
b = -2,490285714.10-3
r = -0,9301573259
r2 = 0,8651926508
b = −k
2,303
-2,490285714.10-3 = −k
2,303
K = 0,05735127999/menit
pH K Log K Log K + 34,0 0,015911098 -1,798299849 1,20174,5 0,05735127999 -2,241456885 0,75855,06,0
PENIMBANGAN DAN HASIL PEMBUATAN LARUTAN DAPAR
150 ml lar. Dapar pH
direncanakan
HASIL PENIMBANGAN (gram) pH SESUNGGUHNYAAs. Sitrat NaOH Terhitung pH meter
4,0 2,46578 0,5387 3,89 4,04,5 3,2535 0,83864 4,14 4,55,06,0
pH ABSORBANSIt = 0 menit t = 10 menit t = 20 menit t = 40 menit
4,0 0,440 0,330 0,265 0,2380,450 0,347 0,257 0,252
x = 0,4495 x = 0,3385 x = 0,2610 x = 0,24504,5 0,640 0,593 0,531 0,515
0,640 0,593 0,530 0,514x = 0,640 x = 0,593 x = 0,5305 x = 0,5145
5,0
6,0
pH KADAR VITAMIN C TERHITUNG PADA PENDIAMAN :t = 0 menit t = 10 menit t = 20 menit t = 40 menit
4,0 C = 9,7854 C = 7,2348 C = 5,4540 C = 5,0863Log C = 0,9906 Log C = 0,8594 Log C = 0,7367 Log C = 0,7064
4,5 C = 14, 1628 C = 13, 0828 C = 11,6467 C = 11,2790Log C = Log C = Log C = 1,0662 Log C =1,0523
5,0 C = C = C = C =Log C = Log C = Log C = Log C =
6,0 C = C = C = C =Log C = Log C = Log C = Log C =
pH TETAPAN LAJU PERURAIAN TERHITUNG (satuan??)
4,0 0,015911098/menit4,5 0,005735127999/menit5,06,0
