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Pembahasan Soal Ujian Nasional Mata pelajaran Matematika SMP Tahun Pelajaran 2013/2014

Transcript of Pembahasan Soal Mtk UN 2013 Paket 02

• SMP NEGERI 3 KALIBAGOR

Alfa Kristanti

1

PAKET 2

• SMP NEGERI 3 KALIBAGOR

Alfa Kristanti

2

• SMP NEGERI 3 KALIBAGOR

Alfa Kristanti

3

Pelangi Matematika Viandre Al4-kristanty.blogspot.com

23 + 32 = 1

23+

1

32=

1

8+

1

9=

9

72+

8

72=

17

72

7 7 14 = 7 7 14 = 7 7 7 2 = 7 49 2

= 7 7 2 = 49 2

22

3 1

2

3 4

1

5=

8

3

5

3

21

5=

8

3

3

5

21

5

= 8

5

21

5=

13

5= 2

3

5

Selisih = 4 3

4 + 3 560.000 =

1

7 560.000

= 80.000

Bunga 9 bln = 9

12 12% = 9%

Tabungan setelah 9 bln = 100% T + 9% T = 109% T

109% T = 3.815.000 T = 3.815.000

109% =

3.815.000109

100

= 3.815.000 100

109

= 3.500.000

• SMP NEGERI 3 KALIBAGOR

Alfa Kristanti

4

b = 18

3= 6

b = 7 4

74=

3719

3

U4 = a + 3b

19 = a + 3(6)

19 = a + 18 a = 19 18 a = 1

Sn =

2 ( 2a + (n 1)b )

S24 = 24

2 ( 2(1) + (24 1) 6) = 12 (2 + (23) 6) = 12 (2 + 138)

= 12 (140) = 1.680

a = U1 = 7

b = U2 U1 = 12 7 = 5

Un = a + (n 1)b

U52 = 7 + (52 1) 5 = 7 + (51) 5

= 7 + 255 = 262

r = 21

= 9

27=

1

3

a = U1 = 27

Un = a r n 1

= 27 1

3 1

= 33 31 1

Un = 33 3 + 1 = 33 + 1 = 34

3x 2 < 8x + 13 3x 8x < 13 + 2

5x < 15

x > 3

I. 4x2 10x = 2x (2x 5)

II. 7x2 49 = 7(x2 7)

III. x2 3x 18 = (x 6)(x + 3)

IV. x2 + 5x 36 = (x + 9)(x 4)

m = 2 12 1

= 3 (6)

4 1 =

3+6

4+1=

3

3= 1

y y1 = m (x x1)

y (1) = 1 (x (6))

y + 1 = 1 (x + 6)

y + 1 = x 6

y + x = 6 1

x + y = 7

• SMP NEGERI 3 KALIBAGOR

Alfa Kristanti

5

ax + by + c = 0

a = 8 ; b = 4

m =

=

8

4= 2

M = { 1, 3, 5, 7 }

N = { 5, 7, 11 }

M N = { 1, 3, 5, 7, 11 }

f(3) = 15

3a + b = 15

f(2) = 0

2a + b = 0

3a + b = 15

2a + b = 0

5a = 15 a = 3

2a + b = 0

2(3) + b = 0

6 + b = 0

b = 0 6

b = 6

f(5) = 3(5) + ( 6)

= 15 6

= 21

Misal :

Parkir mobil = p

Parkir motor = q

12 12 K

L

M

N

O

Lbelahketupat ABCD = 384

1

2 KM LN = 384

1

2 24 LN = 384

12 LN = 384

4p + 2q = 18.000

4p + 2(1.000) = 18.000

4p + 2.000 = 18.000

4p = 16.000

p = 4.000

20p + 30q = 20(4000)+30(1000)

= 80.000 + 30.000

= 110.000

3p + 5q = 17.000 4 12p + 20q = 68.000

4p + 2q = 18.000 3 12p + 6q = 54.000 14q = 14.000

q = 1.000

LN = 384

12 = 32 OL =

2=

32

2 = 16

KL = 2 + 2 = 122 + 162

KL = 144 + 256 = 400 = 20 Keliling = 4 KL = 4 20 = 80

ABC KLM maka AB = LM, BC = KL,

AC = KM L

M

K 62

o

80o

B

A

C 62

o

80o

38o

38o

Jumlah bilangan terbesar dan terkecil

= 2

3 jml ketiga bilangan

= 2

3 162 = 108

• SMP NEGERI 3 KALIBAGOR

Alfa Kristanti

6

Q

30

24

18

P R B

C

A

12 9

15

=

12

24=

1

2 ,

=

15

30=

1

2 ,

=

9

18=

1

2

FC = 4 20 + 6 5

4 + 6

= 80 + 30

10=

110

10 = 11

L daerah tdk diarsir = LKLMN + LPQRS 2 L daerah diarsir = 20

2 + 10 15 2 67

= 400 + 150 134 = 416

Banyak pohon =

=

2(24+ 18)

3

= 2(42)

3=

84

3 = 28

B

A

C D

(3x 5) + (2x + 5) = 90 5x + 0 = 90

5x = 90

x = 18

Penyiku POR = ROQ = 2x + 5 = 2(18) + 5 = 36 + 5 = 41

• SMP NEGERI 3 KALIBAGOR

Alfa Kristanti

7

Sudut keliling menghdp

busur yg sama maka

ABE = 96

3 = 32

AOE = 2 ABE = 2 32

= 64

= 676 100 = 576 = 24

luar = 262 12 2 2 = 676 102

LOBC =

= 120

50 30

= 72

Panjang rusuk 1 balok = 4 (p + l + t) = 4 (40 + 24 + 36)

= 4 (100) = 400 cm = 4 m

Kawat tersedia = 10 m

Banyak kerangka balok yg dibuat = 10

4 = 2,5 2

Garis pelukis

BC =

4=

72

4 = 18

t

9

15 t = 152 92 = 225 81

t = 144 = 12

Vlimas = 1

3 La t =

1

3 18

2 12 = 324 4 = 1.296

• SMP NEGERI 3 KALIBAGOR

Alfa Kristanti

8

dbola = rusuk kubus

dbola = 30, maka :

r = 30

2 = 15

Vbola = 4

3 r3 =

4

3 153 =

4

3 3.375

= 4 1.125 = 4.500

Ldinding = 2 (pt + lt) = 2(8 5 + 6 5)

= 2(40 + 30) = 2(70) = 140

Biaya = 140 Rp 50.000,- = Rp 7.000.000,-

s2 + s

2 = 8 2

2

2 s2 = 64 2

2 s2 = 128

s2 = 64 s = 64 = 8

8 2 s

s

Lkubus = 6 s2

= 6 8 2 = 6 64

= 384

d = 28 r = 14

Ltabung = 2r (r + t) = 2 22

7 14 (14 + 26)

= 88 (40) = 3.520

Jumlah siswa = 18 + 22 = 40 anak

Jml tinggi = 18 156 + 22 152 = 2.808 + 3.344 = 6.152

Rata-rata tinggi =

=

6.152

40 = 153,8

Data 5 6 7 8 9

frekuensi 2 3 4 3 2

Modus

• SMP NEGERI 3 KALIBAGOR

Alfa Kristanti

9

32 30

Selisih produksi pupuk Maret dan Mei = 10 6 = 4

• SMP NEGERI 3 KALIBAGOR

Alfa Kristanti

10

n(S) = 2 2 2 = 8

3 gambar = GGG

P (3 gambar) = 1

8

6

5 5

2 2

4

3 3

Banyak kelereng = 6 + 5 + 3 + 3 + 2 + 4 + 2 + 5 = 30

Kelereng merah = 6

P ( 1 merah) = 6

30 100 % = 20 %