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### Transcript of Pembahasan mtk un 2013 paket 04

• SMP NEGERI 3 KALIBAGOR

Alfa Kristanti

1

PAKET 4

• SMP NEGERI 3 KALIBAGOR

Alfa Kristanti

2

• SMP NEGERI 3 KALIBAGOR

Alfa Kristanti

3

Pelangi Matematika Viandre Al4-kristanty.blogspot.com

21 + 31 = 1

21+

1

31=

1

2+

1

3=

3

6+

2

6=

5

6

7 7 14 = 7 7 14 = 7 7 7 2 = 7 49 2

= 7 7 2 = 49 2

31

2+ 2

2

5 1

1

5= 3

1

2+

12

5

6

5= 3

1

2+

12

5

5

6

= 31

2+

2

1=

7

2+

4

2=

11

2

Selisih = 5 3

5 + 3 24 =

2

8 24 = 6

Bunga 9 bln = 9

12 12% = 9%

Tabungan setelah 9 bln = 100% T + 9% T = 109% T

109% T = 3.815.000 T = 3.815.000

109% =

3.815.000109

100

= 3.815.000 100

109

= 3.500.000

• SMP NEGERI 3 KALIBAGOR

Alfa Kristanti

4

b = 7 3

7 3=

22 10

4

b = 12

4= 3

U3 = a + 2b

10 = a + 2(3)

10 = a + 6 a = 10 6

a = 4

Sn =

2 ( 2a + (n 1)b )

S30 = 30

2 ( 2(4) + (30 1) 3) = 15 (8 + (29) 3) = 15 (8 + 87)

= 15 (95) = 1.425

a = U1 = 3

b = U2 U1 = 7 3 = 4

Un = a + (n 1)b

U45 = 3 + (45 1) 4 = 3 + (44) 4

= 3 + 176 = 179

r = 2

1=

32

64=

1

2

a = U1 = 64

Un = a r n 1

= 64 1

2 1

= 26 2 1

Un = 26 2 + 1 = 26 + 1 = 27

x 3 5 3x

x + 3x 5 + 3

4x 8

x 2

I. 2x2 + x 3 = (2x + 3)(x 1)

II. x2 + x 6 = (x + 3)(x 2)

III. 4x2 9 = (2x)

2 3

2 = (2x + 3)(2x 3)

IV. 6x2 15x = 3x(2x 5)

m = 2 1

2 1=

2 5

3 1=

2 + 5

2=

7

2

y y1 = m (x x1)

y (5) = 7

2 (x 1)

y + 5 = 7

2 (x 1)

2(y + 5) = 7(x 1)

2y + 10 = 7x 7

2y 7x = 7 10

7x + 2y = 17

7x 2y = 17

• SMP NEGERI 3 KALIBAGOR

Alfa Kristanti

5

ax + by + c = 0

a = 6 ; b = 3

m =

=

6

3=

6

3= 2

Jumlah bilangan terbesar dan terkecil

= 2

3 jml ketiga bilangan

= 2

3 84 = 56

M = { 1, 3, 5, 7 }

N = { 5, 7, 11 }

M N = { 1, 3, 5, 7, 11 }

f(5) = 15

5a + b = 15

f(5) = 5

5a + b = 5

5a + b = 15

5a + b = 5

10a = 20

a = 2

5a + b = 5

5( 2) + b = 5

10 + b = 5

b = 5 + 10

b = 5

F(1) = 2 (1) + 5

= 2 + 5

= 3

Misal :

Harga pulpen = p

Harga pensil = q

5p + 4q = 30.000 3 15p + 12q = 90.000

2p + 6q = 23.000 2 4p + 12q = 46.000

11p = 44.000

p = 4.000

2p + 6q = 23.000

2(4000) + 6q = 23.000

8.000 + 6q = 23.000

6q = 15.000

q = 2.500

3p + 2q = 3(4000)+2(2500)

= 12.000 + 5.000

= 17.000

26 26

26 26

10 10 A

B

C

D

E

S =

4=

104

4= 26

DE = 2 2 = 262 102 = 676 100 = 576 = 24 BD = 2 DE = 2 24 = 48

Lbelahketupat ABCD = 1

2 d1 d2 =

1

2 AC BD = =

1

2 20 48 = 480

ABC KLM maka

AB = LM, BC = KL,

AC = KM L

M

K 62

o

80o

B

A

C 62

o

80o

38o

38o

• SMP NEGERI 3 KALIBAGOR

Alfa Kristanti

6

P

16

12 10

Q R A

B

C

6 5

8

=

8

16=

1

2 ,

=

5

10=

1

2 ,

=

6

12=

1

2

KL = 3 12 + 2 27

3 + 2

= 36 + 54

5=

90

5 = 18

L daerah tdk diarsir = LEFGH + LABCD 2 L daerah diarsir

= 42 + 12 8 2 8

= 16 + 96 16

= 96

Banyak pohon cemara =

=

2(48+ 32)

4

= 2(80)

4 = 40

Q

P

R

(3x 6) + (4x + 25) = 180

7x + 19 = 180

7x = 180 19

7x = 161

x = 23

Pelurus AOC = COB = 4x + 25

= 4(23) + 25 = 92 + 25 = 117

• SMP NEGERI 3 KALIBAGOR

Alfa Kristanti

7

Sudut keliling menghdp

busur yg sama maka

ABE = 96

3 = 32

AOE = 2 ABE

= 2 32

= 64

= 289 64 = 225 = 15

dalam = 172 5 + 3 2 = 289 82

LAOD =

= 40

100 50

= 20

Panjang kawat minimal = Panjang rusuk balok

= 4 (p + l + t) = 4 (40 + 40 + 35)

= 4 (115)

= 460

Garis pelukis

BC =

4=

72

4 = 18

t

9

15 t = 152 92 = 225 81

t = 144 = 12

Vlimas = 1

3 La t =

1

3 18

2 12 = 324 4 = 1.296

• SMP NEGERI 3 KALIBAGOR

Alfa Kristanti

8

dbola = rusuk kubus

dbola = 24, maka :

r = 24

2 = 12

Vbola = 4

3 r

3 =

4

3 12

3 =

4

3 1.728

= 4 576 = 2.304

Ldinding = 2 (pt + lt) = 2(6 4 + 8 4)

= 2(24 + 32) = 2(56) = 112

Biaya = 112 Rp 50.000,- = Rp 5.600.000,-

s2 + s

2 = 10

2

2 s2 = 100

s2 = 50

s = 50 = 25 2 = 5 2

10 s

s

Lkubus = 6 s2

= 6 5 2 2

= 6 50

= 300

Ltabung = 2r (r + t) = 2 22

7 35 (35 + 10)

= 220 (45) = 9.900

Jumlah siswa = 18 + 22 = 40 anak

Jml tinggi = 18 156 + 22 152 = 2.808 + 3.344 = 6.152

Rata-rata tinggi =

=

6.152

40 = 153,8

Data 5 6 7 8 9

frekuensi 3 2 3 4 2

Modus

• SMP NEGERI 3 KALIBAGOR

Alfa Kristanti

9

32 30

Banyak siswa dapat nilai kurang dari 8 = 1 + 4 + 5 = 10

• SMP NEGERI 3 KALIBAGOR

Alfa Kristanti

10

n(S) = 2 2 2 = 8

3 gambar = GGG

P (3 gambar) = 1

8

6

5 5

2 2

4

3 3

Banyak kelereng = 6 + 5 + 3 + 3 + 2 + 4 + 2 + 5 = 30

Kelereng merah = 6

P ( 1 merah) = 6

30 100 % = 20 %