Pembahasan mtk un 2013 paket 04

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  • SMP NEGERI 3 KALIBAGOR

    Alfa Kristanti

    1

    PAKET 4

  • SMP NEGERI 3 KALIBAGOR

    Alfa Kristanti

    2

  • SMP NEGERI 3 KALIBAGOR

    Alfa Kristanti

    3

    Pelangi Matematika Viandre Al4-kristanty.blogspot.com

    21 + 31 = 1

    21+

    1

    31=

    1

    2+

    1

    3=

    3

    6+

    2

    6=

    5

    6

    7 7 14 = 7 7 14 = 7 7 7 2 = 7 49 2

    = 7 7 2 = 49 2

    31

    2+ 2

    2

    5 1

    1

    5= 3

    1

    2+

    12

    5

    6

    5= 3

    1

    2+

    12

    5

    5

    6

    = 31

    2+

    2

    1=

    7

    2+

    4

    2=

    11

    2

    Selisih = 5 3

    5 + 3 24 =

    2

    8 24 = 6

    Bunga 9 bln = 9

    12 12% = 9%

    Tabungan setelah 9 bln = 100% T + 9% T = 109% T

    109% T = 3.815.000 T = 3.815.000

    109% =

    3.815.000109

    100

    = 3.815.000 100

    109

    = 3.500.000

  • SMP NEGERI 3 KALIBAGOR

    Alfa Kristanti

    4

    b = 7 3

    7 3=

    22 10

    4

    b = 12

    4= 3

    U3 = a + 2b

    10 = a + 2(3)

    10 = a + 6 a = 10 6

    a = 4

    Sn =

    2 ( 2a + (n 1)b )

    S30 = 30

    2 ( 2(4) + (30 1) 3) = 15 (8 + (29) 3) = 15 (8 + 87)

    = 15 (95) = 1.425

    a = U1 = 3

    b = U2 U1 = 7 3 = 4

    Un = a + (n 1)b

    U45 = 3 + (45 1) 4 = 3 + (44) 4

    = 3 + 176 = 179

    r = 2

    1=

    32

    64=

    1

    2

    a = U1 = 64

    Un = a r n 1

    = 64 1

    2 1

    = 26 2 1

    Un = 26 2 + 1 = 26 + 1 = 27

    x 3 5 3x

    x + 3x 5 + 3

    4x 8

    x 2

    I. 2x2 + x 3 = (2x + 3)(x 1)

    II. x2 + x 6 = (x + 3)(x 2)

    III. 4x2 9 = (2x)

    2 3

    2 = (2x + 3)(2x 3)

    IV. 6x2 15x = 3x(2x 5)

    m = 2 1

    2 1=

    2 5

    3 1=

    2 + 5

    2=

    7

    2

    y y1 = m (x x1)

    y (5) = 7

    2 (x 1)

    y + 5 = 7

    2 (x 1)

    2(y + 5) = 7(x 1)

    2y + 10 = 7x 7

    2y 7x = 7 10

    7x + 2y = 17

    7x 2y = 17

  • SMP NEGERI 3 KALIBAGOR

    Alfa Kristanti

    5

    ax + by + c = 0

    a = 6 ; b = 3

    m =

    =

    6

    3=

    6

    3= 2

    Jumlah bilangan terbesar dan terkecil

    = 2

    3 jml ketiga bilangan

    = 2

    3 84 = 56

    M = { 1, 3, 5, 7 }

    N = { 5, 7, 11 }

    M N = { 1, 3, 5, 7, 11 }

    f(5) = 15

    5a + b = 15

    f(5) = 5

    5a + b = 5

    5a + b = 15

    5a + b = 5

    10a = 20

    a = 2

    5a + b = 5

    5( 2) + b = 5

    10 + b = 5

    b = 5 + 10

    b = 5

    F(1) = 2 (1) + 5

    = 2 + 5

    = 3

    Misal :

    Harga pulpen = p

    Harga pensil = q

    5p + 4q = 30.000 3 15p + 12q = 90.000

    2p + 6q = 23.000 2 4p + 12q = 46.000

    11p = 44.000

    p = 4.000

    2p + 6q = 23.000

    2(4000) + 6q = 23.000

    8.000 + 6q = 23.000

    6q = 15.000

    q = 2.500

    3p + 2q = 3(4000)+2(2500)

    = 12.000 + 5.000

    = 17.000

    26 26

    26 26

    10 10 A

    B

    C

    D

    E

    S =

    4=

    104

    4= 26

    DE = 2 2 = 262 102 = 676 100 = 576 = 24 BD = 2 DE = 2 24 = 48

    Lbelahketupat ABCD = 1

    2 d1 d2 =

    1

    2 AC BD = =

    1

    2 20 48 = 480

    Pada gambar di samping:

    ABC KLM maka

    AB = LM, BC = KL,

    AC = KM L

    M

    K 62

    o

    80o

    B

    A

    C 62

    o

    80o

    38o

    38o

  • SMP NEGERI 3 KALIBAGOR

    Alfa Kristanti

    6

    P

    16

    12 10

    Q R A

    B

    C

    6 5

    8

    =

    8

    16=

    1

    2 ,

    =

    5

    10=

    1

    2 ,

    =

    6

    12=

    1

    2

    KL = 3 12 + 2 27

    3 + 2

    = 36 + 54

    5=

    90

    5 = 18

    L daerah tdk diarsir = LEFGH + LABCD 2 L daerah diarsir

    = 42 + 12 8 2 8

    = 16 + 96 16

    = 96

    Banyak pohon cemara =

    =

    2(48+ 32)

    4

    = 2(80)

    4 = 40

    Q

    P

    R

    (3x 6) + (4x + 25) = 180

    7x + 19 = 180

    7x = 180 19

    7x = 161

    x = 23

    Pelurus AOC = COB = 4x + 25

    = 4(23) + 25 = 92 + 25 = 117

  • SMP NEGERI 3 KALIBAGOR

    Alfa Kristanti

    7

    Sudut keliling menghdp

    busur yg sama maka

    ABE = ACE =ADE

    ABE = 96

    3 = 32

    AOE = 2 ABE

    = 2 32

    = 64

    = 289 64 = 225 = 15

    dalam = 172 5 + 3 2 = 289 82

    LAOD =

    = 40

    100 50

    = 20

    Panjang kawat minimal = Panjang rusuk balok

    = 4 (p + l + t) = 4 (40 + 40 + 35)

    = 4 (115)

    = 460

    Garis pelukis

    BC =

    4=

    72

    4 = 18

    t

    9

    15 t = 152 92 = 225 81

    t = 144 = 12

    Vlimas = 1

    3 La t =

    1

    3 18

    2 12 = 324 4 = 1.296

  • SMP NEGERI 3 KALIBAGOR

    Alfa Kristanti

    8

    dbola = rusuk kubus

    dbola = 24, maka :

    r = 24

    2 = 12

    Vbola = 4

    3 r

    3 =

    4

    3 12

    3 =

    4

    3 1.728

    = 4 576 = 2.304

    Ldinding = 2 (pt + lt) = 2(6 4 + 8 4)

    = 2(24 + 32) = 2(56) = 112

    Biaya = 112 Rp 50.000,- = Rp 5.600.000,-

    s2 + s

    2 = 10

    2

    2 s2 = 100

    s2 = 50

    s = 50 = 25 2 = 5 2

    10 s

    s

    Lkubus = 6 s2

    = 6 5 2 2

    = 6 50

    = 300

    Ltabung = 2r (r + t) = 2 22

    7 35 (35 + 10)

    = 220 (45) = 9.900

    Jumlah siswa = 18 + 22 = 40 anak

    Jml tinggi = 18 156 + 22 152 = 2.808 + 3.344 = 6.152

    Rata-rata tinggi =

    =

    6.152

    40 = 153,8

    Data 5 6 7 8 9

    frekuensi 3 2 3 4 2

    Modus

  • SMP NEGERI 3 KALIBAGOR

    Alfa Kristanti

    9

    32 30

    Banyak siswa dapat nilai kurang dari 8 = 1 + 4 + 5 = 10

  • SMP NEGERI 3 KALIBAGOR

    Alfa Kristanti

    10

    n(S) = 2 2 2 = 8

    3 gambar = GGG

    P (3 gambar) = 1

    8

    6

    5 5

    2 2

    4

    3 3

    Banyak kelereng = 6 + 5 + 3 + 3 + 2 + 4 + 2 + 5 = 30

    Kelereng merah = 6

    P ( 1 merah) = 6

    30 100 % = 20 %