Kunci Unas Mat Smk 2012 Tipe c
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Transcript of Kunci Unas Mat Smk 2012 Tipe c
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SMK MUH I KLATEN UTARA 2012
KUNCI JAWABAN UNAS MATEMATIKA TIPE C
TAHUN AJARAN 2011/2012
1. m=3log4
1464 3log31log
3 −=
= 3log31 4⋅−
= - m⋅31
= -3m
(a)
2.2525
2556
2556
++⋅
−=
−
=( )
( ) 2225
2556
−
+
= ( )1
2556 +
=6.5+6.2 5
=30+12 5 (a)
3. 3
31
32
223
21
342
342
−
−
⋅⋅
⋅⋅
=( ) ( ) ( ) ( )3
31
3332
22)23()
21(
342
34222
−⋅−⋅−−⋅
⋅
⋅⋅
⋅⋅
= 196
431
342342
−− ⋅⋅⋅⋅
= 149361 334422 ⋅⋅⋅⋅⋅ −
= 567 342 ⋅⋅ − (a)
4. Perbandingan berbalik nilai
26080 x=
x=⋅ 26080
X=6
16
X=232
jam
5. Tabel
jenis luas jumlahTipe mawar 120 (m2) xTipe melati 160 (m2) yModel matematika:
a) 120x+160y<18000 atau
3x+4y<450
b) x+y<125
c) x>0, dan y>0 (b)
6. x+3y<9,2x+y>8,x>0,y>0
x 0 9
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SMK MUH I KLATEN UTARA 2012
y 3 0
Daerah V
.....(e)
7. puncak (-2,a), melalui (0,0)
y=a(x-p)2+q
0=a(0-(-2))2+4
0=a(0+2)+4
0=4a+4
a=-1
y=a(x-p)2+q
y=(-1)(x-(-2))2+4
y=(-1)(x+2)2+4
y=(-1)(x2+4x+4)+4
y=-x2-4x-4+4
y=-x2-4x ......(d)
8. dengan eliminasi
+−=−−=+
××
−=−−=+
3233224
12
323162
yxyx
yxyx
7x=
-35
x = -5
3x-2y=-3
3(-5)-2y=-3
-15-2y=-3
-2y=-3
=15
-2y=12
y=-6
nilai x+y=-5+(-6)
= -11 ........(a)
9. m=23− melalui titik (2,1)
y-y1=m(x-x1)
y-1=
−
23 ( )2−x
2(y-1)=(-3)(x-2)
2y-2=-3x+6
3x+2y-2-6=0
x 0 4y 8 0
94
y
x
3
8
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SMK MUH I KLATEN UTARA 2012
3x+2y-8=0 ..... (d)
10. Garis 1: 10x+5y=50
===dibagi5
2x+y=10
Garis 2:5x+15y=75
===dibagi5
x+3y=15
Titik potong kedua garis
1533036
13
153102
=+=+
××
=+=+
yxyx
yxyx
5x =15
x=3
2x+y=10
2(3)+y=10
y= 10-6
y=4
Titik
optimal
Z=2x+5y
(0,0)
(5,0)
(3,4)
(0,5)
2(0)+5(0)=0
2(5)+5(0)=10
2(3)+5(4)=26 nilai mak
2(0)+5(5)=2511. a = u-2v+3w
a =
−−+
−−
−
11
3
321
211
2
a =
−−+
−−
−
33
9
642
11
2
a =
−+−−−
+−
361341
922
a =
−48
9
a = 9i-8j+4k .......(d)
12.
−
−= 2345N
−−−⋅
=−
5342
)3)(4(2511N
=
− 53
421210
1
=
− 53
422
1
=
−−−−
25
23
21 ...... (b)
13. AXB= ( )312
04
−×
−
=
−
−
6200124
...... (e)
14. Kesimpulan
qp →
p
q∴
Ada siswa yang tidak masuk
sekolah.....(d)
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SMK MUH I KLATEN UTARA 2012
15.
Semua sudut pada segitiga sama
besar dan segitiga itu bukan
segitiga sama sisi
...... (a)
16. Invers=
Jika siswa SMK tidak kreatif
maka jenis produk yang
dihasilkan tidak banyak .....(c)
17. Kerucut: r=6 cm, t= 9 cm
Vol kerucut= 31
La . t
=31
r2.t
=31
.(3,14).(36).(9)
=339,12 ....(b)
18. Balok : p=10 cm, l=8 cm
Luas permukaan =2x(pl+pt +lt)
376 =
2x(10.8+10.t+8.t)
t18802
376 +=
188 = 80 +18t
188-80 = 18t
T=18
108=6 cm... (d)
19. Trapesium sama kaki
Luas = tba ⋅
+
2
= 72
1711 ⋅+
= 8420. P= kell lingk
132=2 r
132=2( )r
r=
r= 21 .... (c)
21.
PP
sinsin=
00 30sin45sin8 Q=
212
21
8 Q=
Q= 242
8 = ....... (d)
22. Menit ke-1= 100 putaran
Menit ke-2=110 putaran
11
17
7
300
450
Q
R
P
8
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SMK MUH I KLATEN UTARA 2012
Menit ke-3=120 putaran
Menit ke-4=130 putaran dst
U1=100=a
b=110-100=10
41
jam=15 menit=U15=....?
Un=a+(n-1)b
U15=100+(15-1)10
U15=100+140
U15=240
S15= 2n
( U1+ U15)
S15= 215
(100+240)
S15=15.(170)
S15=2550
23. Q(-5 3 ,5)
r= 22 yx +
r= ( ) ( ) 22535 +−
r= 25325 +⋅
r= 2575 +
r=100
tg
tg =
tg =
tg =
tg =1500
jadi koordinat kutub(10,1500) ...
(b)
24. Barisan aritmatika:
1,5,9,13,......,93
( )bnaUnbU 14
11 −+=
==
93=1+(n-1)4
93=1+4n-4
96=4n
n=24 ......(e)
25. 5,6,7,8,9
Bilangan ratusan genap berbeda
4 3 2Angka belakang 6 atau 8=24
bilangan
26. Barisan geometri 81,27,9,3,....
1
31
8127
81−⋅=
===
nn raUr
a
1
3181
−
⋅=
n
nU
( ) 114 33 −−⋅= nnU
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SMK MUH I KLATEN UTARA 2012
14 33 +−⋅= nnU
nnU
−= 53 ....... (b)
27. Jumlah panen seluruhnya =9600
Kacang tanah
Kg2880960010030
000
0=×
.... (c)
28. 1 dadu dan 1 uang logam
n(s)=6x2=12
P(A,genap)=41
123 = .......(c)
29. Jumlah 10= ( ) ( ) ( ){ }5,5,6,4,4,6
Fh=P(A)xbanyaknya percobaan
Fh= 300363 ×
Fh= 300121 × =25 ......(b)
30. Modus
Kelas modus 161-165
Tb=160,5
D1=42-20=22
D2=42-24=18
Mo=Tb+p
+ 21
1
ddd
Mo=160,5+5
+ 182222
Mo=160,5+5
4022
Mo=160,5+2,75
Mo=163,25
31. M
Jmlh
siswa
Rata-
rata
Jmlh nilai
11 72 11x72=79211+4=15 70 15x70=1050
Jmlh nilai 4 siswa=1050-792=258
Nilai rata-rata 4
siswa=258:4=64,5 ...(c)
32. 4,6,8,2,5n=5
5525
552864 ==+++++=x
ix xxi − ( )2xxi −
4
6
8
2
5
4-5=-1
6-5=1
8-5=3
2-5=-3
5-5=0
1
1
9
9
0jumlah 20
( )24
520
2
=== ∑nxx
SD i
....(e)
33. F(x)=x3+6x2-7
Titik stasioner y1=0
3x2+12x=0
3x(x2+4x)=0
x1=0 dan x2=-4
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SMK MUH I KLATEN UTARA 2012
untuk x=0
y=03+6.0-7
y=-7 .... (0,-7)
untuk x=-4
y=(-4)3+6.(-4)-7
y=-64+96-7
y=25 ..... (-4,25) ..... (c)
34.56
532
5sin32
0lim =⋅=→ x
xtgx ....(c)
35. F(x)=(4x2+8).(2x+5)
U=4x2+8U1=8x
V=2x+5V1=2
f1(x)=U1.V+U.V1
f1(x)=8x(2x+3)+ (4x2+8).2
f1(x)=16x2+40x+8x2+16
f1(x)=24x2+40x+16 ....(a)
36. y=x2-4 dan y=4x+1
batas daerah
x2-4 =4x+1
x2-4x-4-1=0
x2-4x-5=0
(x-5)(x+1)=0
X1=5 dan x2=-1
Luas= ∫b
a
ydx
Luas= ∫−
−−5
1
2 54 dxxx
=5
1
23 524
31
−
−− xxx
=
( ) ( ) ( )
−−−⋅−−⋅−
⋅−⋅−⋅ 151
241
31555
245
31 2323
=
( ) ( ) ( )
−⋅−−⋅−−−
−⋅−⋅ 15121
3125252125
31
52312550
3125 −++−−
= 7842 − =36 satuan luas ...(c)
37. ∫ ++ dxxx )1)(5(
= ∫ ++ dxxx 562
= Cxxx ++ 526
31 23
=2 ....(a)
38. V= dxyb
a∫ 2π
V= ( ) dxx∫ +3
1
21π
V= dxxx∫ ++3
1
2 12π
V=3
1
23
31
++ xxxπ
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SMK MUH I KLATEN UTARA 2012
V=
++⋅−
++⋅ 111
31333
31 2323π
V= ( )
++−++ 11
31399π
V=π
−
31221
V=π 1832
V=3
56 π satuan volume
39. Garis dan parabola berpotongan
y1=y2
3x-3=-2x2+7x-5
2x2+3x-7x-3+5=0
2x2-4x+2=0
2(x2-2x+1)=0
2(x-1)(x-1)=0
2(x-1)=0 dan
2x-2=0
x=1
x-1=0
x=1
Y=3x-3
Y=3.1-3
Y=3-3
Y=0
Jadi koordinatnya (1,0) ... (a)
40. ( )dxxx∫ +−2
0
2 733
=2
0
23 723
33
+− xxx
=2
0
23 723
+− xxx
=
⋅+⋅−−
⋅+− 070
230272
232 2323
=8-6+14-0
=16 ....(d)