Indikator Pencapaian Kompetensi
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Transcript of Indikator Pencapaian Kompetensi
Indikator Pencapaian Kompetensi
Penilaian skorTeknik Penilaian Instrumen Soal Kunci Jawaban
Menentukan penjumlahan dan pengurangan matriks
Intrumen tertulis individu dan kelompok
1. A= [5 46 97 0 ],
B= [3 65 41 2]
C= [3 75 81 2 ]
Tentukan:a. A+Bb. A−Bc. A+(B+C)
2. C= [ 3 −8 04 7 2
−1 8 4 ],
D= [ 3 7 25 2 6
−1 8 4 ],A= [0 0 0
0 0 0 ],B= [0 0 0
0 0 0 ],E= [2 7 2
5 2 6]a. C+D=.. ..b. C+E=... .c. A+B= ....
1. A). A= [5 46 97 0 ],
B= [3 65 41 2],
untuk A+B maka
[5+3 4+66+5 9+47+1 0+2] =
[ 8 1011 138 2 ]
b). A= [5 46 97 0 ],
B= [3 65 41 2],
untuk A−B maka
[5−3 4−66−5 9−47−1 0−2 ] =
[ 2 −2−1 56 −2]
. c). A= [5 46 97 0 ],
B= [3 65 41 2], C= [3 7
5 81 2 ],
untuk A+(B+C)maka
[5 46 97 0 ]+
15
15
20
Kunci Jawaban dan Pedoman Pensekoran
([3 65 41 2]+[3 7
5 81 2 ])
=
[5 46 97 0 ]+[ 6 13
10 122 4 ]
= [11 1716 219 4 ]
2. a). C+D=¿
[ 3 −8 04 7 2
−1 8 4 ]+[ 3 7 2
5 2 6−1 8 4 ]=[ 3+3 −8+7 0+2
4+5 7+2 2+6−1±1 8+8 4+4 ]
= [ 6 −1 29 9 8
−2 16 8]b.) A+E=¿ [0 0 0
0 0 0 ]+
[2 7 25 2 6]=[2 7 2
5 2 6]c). A+B=¿ [0 0 0
0 0 0 ]+[0 0 00 0 0 ]=[0 0 0
0 0 0]
20
15
15
Menentukan perkalian matriks
Intrumen tertulis individu dan kelompok
1. P = [3 85 1 ], maka 4 P=
…
2. A = [1 23 4], B =
[1 0 10 2 0 ]. Tentukan
A×B = …
1. P = [3 85 1 ], maka
4 P = 4[3 85 1 ] =
[12 3220 4 ]
2. A = [1 23 4], B =
15
35
3. K= [1 4 −93 7 05 9 −13]. Maka
4 K=¿....
4. A= [2 38 −71 −5
4 59 −47 −8 ],
B= [ 1 27 −64 −911 3
]A B=... .
[1 0 10 2 0 ].
Tentukan A×B=¿
[1 23 4] x
[1 0 10 2 0 ] =
[ (1×1 )+(2×0 ) (1×0 )+ (2×2 ) (1×1 )+(2×0 )(3×1 )+(4×0 ) (3×0 )+( 4×2 ) (3×1 )+(4×0 )]
= [1 4 13 2 3]
3. K= [1 4 −93 7 05 9 −13].
Maka 4 K=... .Jawaban:
4 K= 4 [1 4 −93 7 05 9 −13]=
[4×1 4×4 4×−94×3 4×7 4×04×5 4×9 4×−13 ]
=
[ 4 16 −3612 28 020 36 −52 ]
4. A= [2 38 −71 −5
4 59 −47 −8 ]
, B= [ 1 27 −64 −911 3
]A×B=... .
Jawaban:A×B=
20
30
[2 38 −71 −5
4 59 −47 −8 ]×[ 1 2
7 −64 −911 3
]=
[ (2×1 )+(3×7 )+(4×4 )+(5×11) (2×2 )+(3×−6 )+( 4×−9 )+(5×3)(8×1 )+(−7×7 )+(9×4 )+(−4×11) (8×2 )+ (−7×−6 )+(9×−9 )+(−4×3)(1×1 )+(−5×7 )+(7×4 )+(−8×11) (1×2 )+(−5×−6 )+(7×−9 )+(−8×3)]
=
[ 2+21+16+55 4±18±36+158±49+36±44 16+42±49±121±35+28±88 2+30±63±24 ]
=[ 94 −35−49 −3−97 −64 ]