Dasar Perancangan Alat Teddy Adythia Bp 3d
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DIAGRAM ALIR PROSES Diketahui Kapasitas Molases/Basis = 74000 kg/jam kapasitas molase Perbandingan tetes: air = 1:5 maka tetes = 74000 air = 370000 Perbandingan tetes: air = Ragi (1% dari tetes) = 740 Konversi tetes yg menjadi etanol= 80% Konsentrasi etanol keluar fermentor = 10% Konsentrasi etanol sebagai destilat = 96% Komponen MO 1 MO 2 MO 3 M1 Etanol 0 0 0 0 Air 0 370000 0 0 Tetes 74000 0 0 74000 Ragi 0 0 740 0 TOTAL 74000 370000 740 74000 M 71 = M 81 + M 82 444000 M6 = M 71 + M 72 444740 600 = M81 +M82 80= M81*0.96+ M82*0.03 1 1 M81 444000 0.96 0.03 M82 59200 -0.032258064516129 1.0752688172 M81= 49333.33 1.03225806451613 -1.075268817 M82= 394666.7 M 1 M 2 M 3 TANGKI TETES TANGKI AIR MIXER HE MO 1 MO 2
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Transcript of Dasar Perancangan Alat Teddy Adythia Bp 3d
DIAGRAM ALIR PROSES
DiketahuiKapasitas Molases/Basis = 74000 kg/jam kapasitas molasePerbandingan tetes: air = 1:5
maka tetes = 74000air = 370000
Perbandingan tetes: air =Ragi (1% dari tetes) = 740Konversi tetes yg menjadi etanol= 80%Konsentrasi etanol keluar fermentor = 10%Konsentrasi etanol sebagai destilat = 96%
Komponen MO 1 MO 2 MO 3 M1 M2Etanol 0 0 0 0 0
Air 0 370000 0 0 370000Tetes 74000 0 0 74000 0Ragi 0 0 740 0 0
TOTAL 74000 370000 740 74000 370000
M 71 = M 81 + M 82444000
M6 = M 71 + M 72444740
600 = M81 +M8280= M81*0.96+ M82*0.03
1 1 M81 4440000.96 0.03 M82 59200
-0.032258064516129 1.0752688172 M81= 49333.331.03225806451613 -1.075268817 M82= 394666.7
M 1
M 2
M 3 M 4 TANGKI TETES
TANGKI AIR
MIXERHE
MO 1
MO 2
M3 M4 M5 M6 M 71 M 72 M 81 M 820 0 0 59200 59200 0 47360 11840
370000 370000 370000 370000 370000 0 1973.333 368026.774000 74000 74000 14800 14800 0 0 14800
0 0 0 740 0 1 0 0444000 444000 444000 444740 444000 1 49333.33 394666.7
M 82
M 4 DESTILASI FILTER PRESS
M 6 M 71
M 72
FERMENTORCOOLER
MO 3
M 5
DESTILASI
M 81
Kapasitas Molases/Basis = 74000 kg/jam kapasitas molasePerbandingan tetes: air = 1 : 5
maka tetes = 74000 444000 kgair = 370000
Ragi (1% dari tetes) = 740Konversi tetes yg menjadi etanol= 80%Konsentrasi etanol keluar fermentor = 10%Konsentrasi etanol sebagai destilat = 96%
TANGKI TETES
Bahan Q masuk Q keluar
kJ kJTetes -630406000 -630406000
Air 0 0TOTAL -630406000 -630406000
Q akumulasi 0
TANGKI AIR
Bahan Q masuk Q keluar
kJ kJTetes 0 0
Air -5849700000 -5849700000TOTAL -5849700000 -5849700000
Q akumulasi 0
COOLER
Bahan Q masuk Q keluar
kJ kJTetes -623672000 -631146000
Air -5764600000 -5842300000
1 atm40 oC
1 atm80 oC
Tangki Tetes CoolerHEMixer
T Air
1 atm25 oC
1 atm25 oC
Q 02
Q 02
Q 01 Q 01
1 atm35 oC
1 atm35 oC
Q 11 Q 21
Q 12 Q 221 atm100-75 oC
TOTAL -6388272000 -6473446000Q 22 -85174000∆T = -15 K
Cp air = 4.181 kJ/kg.Kmaka
massa air di Q22 1358112.094
MIXER
Bahan Q masuk Q keluar
kJ kJTetes -630406000 -629666000
Air -5849700000-5827500000TOTAL -6480106000-6457166000
Q akumulasi 22940000Q masuk seharusnya -6457166000
FILTER PRESSBahan Q masuk Q keluar
kJ kJTetes -630850000 -630850000
Air -5842300000-5842300000Etanol -356857600 -356857600TOTAL -6830007600-6830007600
Q akumulasi 0
FERMENTOR
Bahan Q masuk Q keluar
kJ kJ
1 atm30 oC
1 atm32 oC
Q 31 Q 41 Q 51DistilasiFilter PressFermentorCooler
Q 22 1 atm25-40 oC
Q reaksi (asumsi)200 kj
4 bar, 32 oC
Tetes -631146000 -630850000Air -5842300000-5842300000
Etanol 0 -356857600Q reaksi 2000 0TOTAL -6473444000-6830007600
Q akumulasi -356563600Q seharusnya masuk -6830007600
HE
Bahan Q masuk Q keluar
kJ kJTetes -629666000 -623672000
Air -5827500000 -5764600000TOTAL -6457166000 -6388272000
Q12 68894000 ∆T = 25 KCp air = 4.199 kJ/kg.K
maka massa air di Q12 656289.5928DISTILASI kondensor
Bahan Q masuk Q keluar
kJ kJair -356857600 -5857100000
Etanol -5842300000 -287285760TOTAL -6199157600 -6144385760
Q dingin 54771840∆T = -29 K
Cp air = 4.1835 kJ/kg.Kmaka massa air di Q61 -451460.2935 kg
DISTILASI heater
Bahan Q masuk Q keluar
kJ kJ
Qw511 atm, 21-50 C
Qsm21 atm, 100 - 75 C
Q611 atm, 21 -50 C
Q6250 - 90 C
Etanol -356857600 -68956160Air -5842300000 -5749800000
TOTAL -6199157600 -5818756160Q dingin 380401440
∆T = 40 KCp air = 4.183 kJ/kg.K
maka :Massa air di Q62 = 2273496.534 kg
basis molase = 74000 kg/hρ molases = 1316 kg/m^3air = 5 : 1 * 74000 = 370000 kg/hρ air = 996.6 kg/m^3
GENERAL DESIGN CONSIDERATION
F = 56.23100304 m^3/h
V = 56.23100304 m^3
V design = 1.15 * V = 64.665653495
,dimana
maka,
D = 3.80105586 mL = 5.70158379 m
DESIGN PRESSURE
= 1 atm + 0.075 atm = 1.075 atm= 15.8025 psi
geankoplis app A.1-61 m^3 = 264.17 u.s.gal
V design= 17082.7257 u.s.gal
T operasi= 35 C = 95 FMaterial= Carbon Steel A285max allowable stress (S) 100 F 12900 Psiwelded-joint eficiency (E) single-welded butt joit without backing strip category Acorrosion allowance 4 mm
VESSEL THICKNESS
t total = t + corrosion allowance= 6.9146464429205 mm
= 60.066185181
𝑭=𝒎/𝝆V=𝝉∗𝑭
𝑽= 𝟏/𝟒 𝝅𝑫^𝟐 𝑳 𝑳⁄𝑫=𝟑⁄𝟐𝑽=𝟏/𝟒 𝝅𝑫^𝟐 𝟑/𝟐 𝑫
𝑷_𝒅𝒆𝒔𝒊𝒈𝒏= 𝑷_𝒐𝒑𝒆𝒓𝒂𝒕𝒊𝒐𝒏+𝟕,𝟓 % 𝑷_𝒐𝒑𝒆𝒓𝒂𝒕𝒊𝒐𝒏
𝑡=(𝑃_𝑖 𝐷_𝑖)/(2𝑆𝐸 −1∗2𝑃_𝑖 )
20640 - 31.605= 0.00291465 meter= 2.91464644 mm
HEADS AND CLOSURE
menggunakan flat-end curveshead thickness
tipe flanged plate C = 0.1De = Di
= 0.04703567 meter = 4.703567 cm
𝑡=𝐷_𝑒 √((𝐶𝑃_𝑖)/𝑆𝐸)
spot = 0.8
basis molase = 74000 kg/hρ molases = 1316 kg/m^3air = 5 : 1 * 74000 = 370000 kg/hρ air = 996.6 kg/m^3
GENERAL DESIGN CONSIDERATION
F = 371.2623 m^3/h
V = 371.2623 m^3
V design = 1.15 * V = 426.9516
,dimana
maka,
D = 7.130816 mL = 10.69622 m
DESIGN PRESSURE
= 1 atm + 0.075 atm = 1.075 atm= 15.8025 psi
geankoplis app A.1-61 m^3 = 264.17 u.s.gal
V design= 112787.8 u.s.gal
T operasi= 25 C = 77 FMaterial= Carbon Steel A285max allowable stress (S) 100 F 12900 Psiwelded-joint eficiency (E) single-welded butt joit without backing strip category Acorrosion allowance 2 mm
VESSEL THICKNESS
𝑭=𝒎/𝝆V=𝝉∗𝑭
𝑽= 𝟏/𝟒 𝝅𝑫^𝟐 𝑳 𝑳⁄𝑫=𝟑⁄𝟐𝑽=𝟏/𝟒 𝝅𝑫^𝟐 𝟑/𝟐 𝑫
𝑷_𝒅𝒆𝒔𝒊𝒈𝒏= 𝑷_𝒐𝒑𝒆𝒓𝒂𝒕𝒊𝒐𝒏+𝟕,𝟓 % 𝑷_𝒐𝒑𝒆𝒓𝒂𝒕𝒊𝒐𝒏
𝑭=𝒎/𝝆V=𝝉∗𝑭
𝑽= 𝟏/𝟒 𝝅𝑫^𝟐 𝑳 𝑳⁄𝑫=𝟑⁄𝟐𝑽=𝟏/𝟒 𝝅𝑫^𝟐 𝟑/𝟐 𝑫
𝑷_𝒅𝒆𝒔𝒊𝒈𝒏= 𝑷_𝒐𝒑𝒆𝒓𝒂𝒕𝒊𝒐𝒏+𝟕,𝟓 % 𝑷_𝒐𝒑𝒆𝒓𝒂𝒕𝒊𝒐𝒏
𝑡=(𝑃_𝑖 𝐷_𝑖)/(2𝑆𝐸 −1∗2𝑃_𝑖 )
t total = t + corrosion allowance= 7.467904 mm
= 112.684720640 - 31.605
= 0.005468 meter= 5.467904 mm
HEADS AND CLOSURE
menggunakan flat-end curveshead thickness
tipe flanged plate C = 0.1De = Di
= 0.088239 meter = 8.823935 cm
𝑡=𝐷_𝑒 √((𝐶𝑃_𝑖)/𝑆𝐸)
𝑡=(𝑃_𝑖 𝐷_𝑖)/(2𝑆𝐸 −1∗2𝑃_𝑖 )
𝑡=𝐷_𝑒 √((𝐶𝑃_𝑖)/𝑆𝐸)
spot = 0.8
mass flow : 510000 kg/hρ campuran : 1039 kg/m^3
GENERAL DESIGN CONSIDERATION
F = 490.8566 m^3/h
V = 490.8566 m^3
V design = 1.15 * V = 564.4851
,dimana
maka,
D = 7.826433 mL = 11.73965 m
DESIGN PRESSURE
= 1 atm + 0.075 atm = 1.075 atm= 15.8025 psi
geankoplis app A.1-61 m^3 = 264.17 u.s.gal
V design= 149120 u.s.gal
T operasi= 25 C = 77 FMaterial= Carbon Steel A285max allowable stress (S) 100 F 12900 Psiwelded-joint eficiency (E) single-welded butt joit without backing strip category Acorrosion allowance 2 mm
VESSEL THICKNESS
t total = t + corrosion allowance= 8.001302 mm
= 123.677220640 - 31.605
𝑭=𝒎/𝝆V=𝝉∗𝑭
𝑽= 𝟏/𝟒 𝝅𝑫^𝟐 𝑳 𝑳⁄𝑫=𝟑⁄𝟐𝑽=𝟏/𝟒 𝝅𝑫^𝟐 𝟑/𝟐 𝑫
𝑷_𝒅𝒆𝒔𝒊𝒈𝒏= 𝑷_𝒐𝒑𝒆𝒓𝒂𝒕𝒊𝒐𝒏+𝟕,𝟓 % 𝑷_𝒐𝒑𝒆𝒓𝒂𝒕𝒊𝒐𝒏
𝑡=(𝑃_𝑖 𝐷_𝑖)/(2𝑆𝐸 −1∗2𝑃_𝑖 )
= 0.006001 meter= 6.001302 mm
spot = 0.8
1atm100-75 celcius
1atm
1atm 80 celcius40 celcius
