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  • Apakah Struktur Gelagar dibawah ini SST tau SSTT??

    Apakah Struktur Gelagar dibawah ini SST tau SSTT??

  • Apakah Struktur Gelagar dibawah ini SST tau SSTT??

    Struktur Gelagar GERBER

    Penemu Struktur Gerber : JGH.Gerber

    Merupakan Struktur gelagar yang terdiri dari Gelagar anak dan Gelagar Induk.

    Dimana, Salah satu/kedua tumpuan Gelagar anak menumpu pada Gelagar Induk.

    Reaksi tumpuan pada salah satu tumpuan Gelagar anak akan diteruskan

    Ke Gelagar induk sebagai beban Terpusat luar.

  • * SATU sendi dengan TIGA tumpuan.

  • * DUA sendi dengan EMPAT tumpuan.

  • * DUA sendi dengan EMPAT tumpuan.

  • Contoh Pengujian Gelagar Gerber

  • STRUKTUR BALOK GERBER

    ** Balok : S - C.

    MC = 0 RS. 5 - P2. 2,5 = 0 RS = 0,5 P2

    MS = 0 RC. 5 - P2. 2,5 = 0 RC = 0,5 P2

    V = 0 RS + RC = P2 0,5 P2 + 0,5 P2 = P2 P2 = P2 ok

    ME = 2,5 RS

  • MB = 0

    RA. 5 + RS. 1,5 - P1. 2,5 = 0

    5 RA + 0,5 P2. 1,5 - 2,5 P1 = 0

    5 RA + 0,75 P2 - 2,5 P1 = 0

    RA = 0,5 P1 - 0,15 P2

    MA = 0

    RB. 5 - RS. 6,5 - P1. 2,5 = 0

    5 RB - 0,5 P2. 6,5 - 2,5 P1 = 0

    5 RB - 3,25 P2 - 2,5 P1 = 0

    RB = 0,5 P1 + 0,65 P2

    RBA = RB - RS

    = 0,5 P1 + 0,65 P2 - 0,5 P2

    = 0,5 P1 + 0,15 P2

    RBS = RS = 0,5 P2

    MD = RA. 2,5 = (0,5 P1 - 0,15 P2) 2,5 = 1,25 P1 - 0,375 P2

    MB = RS. 1,5

    = 0,5 P2. 1,5

    = 0,75 P2

  • 46) Gambar bidang momen dan gaya lintang. P1 = 400 kg, P2 = 500 kg

    RS = RC = 0,5 P2

    = 0,5. 500

    = 250 kg

    Balok : S – C

    ME = RC. 2

    = 250. 2

    = 500 kgm

  • Balok : A – B – S.

    MB = 0

    RA. 4 + RS. 2 - P1. 2 = 0

    4 RA + 250. 2 - 400. 2 = 0

    4 RA + 500 - 800 = 0

    4 RA = 300

    RA = 75 kg

    MA = 0

    RB. 4 - RS. 6 - P1. 2 = 0

    4 RB - 250. 6 - 400. 2 = 0

    4 RB - 1500 - 800 = 0

    4 RB - 2300 = 0

    RB = 575 kg

    RBS = RS

    = 250 kg

    V = 0

    RA + RB = P1 + RS

    75 + 575 = 400 + 250

    650 = 650 ok

    RBA = RB - RBS = 575 - 250 = 325 kg

    MB = RS. 2 = 250. 2 = 500 kgm

    MD = RA. 2 = 75. 2 = 150 kgm

  • BIDANG GESER

  • BIDANG MOMEN

  • 47) Gambar bidang momen dan gaya lintang. P = 500 kg, W = 2000 kg/m

    Balok : S – C

    RS = RC = 0,5 P

    = 0,5. 500

    = 250 kg

    MD = RC. 2 = 250. 2 = 500 kgm

  • Balok : A – B – S.

    MB = 0

    RA. 4 + RS. 2 + W. 2. 1 - W. 4. 2 = 0

    4 RA + 250. 2 + 2000. 2 - 2000. 8 = 0

    4 RA + 500 + 4000 - 16000 = 0

    4 RA - 11500 = 0

    RA = 2875 kg

    MA = 0

    RB. 4 - RS. 6 - W. 4. 2 - W. 2. 5 = 0

    4 RB - 250. 6 - 2000. 8 - 2000. 10 = 0

    4 RB - 1500 - 16000 - 20000 = 0

    4 RB - 37500 = 0

    RB = 9375 kg

    V = 0

    RA + RB = Q + RS

    2875 + 9375 = 2000. 6 + 250

    2250 = 12250 ok

    RBS = RS + Q = 250 + 2000. 2 = 4250 kg

    RBA = RB - RBS = 9375 - 4250 = 5125 kg

  • MX = RA. X - 0,5 W. X2

    = 2875 X - 0,5. 2000 X2

    X20002875dX

    dMX

    0dX

    dMX

    2000 X = 2875 X = 1,44 m

    M maks = 2875. 1,44 - 1000. 1,442

    = 4140 - 2074

    = 2066 kgm

    MB = RS. 2 + W. 2. 1 = 250. 2 + 2000. 2 = 500 + 4000 = 4500 kgm

  • BIDANG GESER

  • BIDANG MOMEN

  • 48) Gambar bidang momen dan gaya lintang. P = 2000 kg, W = 2500 kg/m

    Balok : S – C.

    RS = RC = 0,5 P + 0,5 W. 4

    = 0,5. 2000 + 0,5. 2500. 4

    = 1000 + 5000

    = 6000 kg

    ME = RC. 2 - W. 2. 1 = 6000. 2 - 2500. 2 = 12000 - 5000 = 7000 kgm

  • Balok : A – B – S

    MB = 0

    RA. 6 + RS. 2 + W. 2. 1 - W. 6. 3 - P. 3 = 0

    6 RA + 6000. 2 + 2500. 2 - 2500. 18 - 2000. 3 = 0

    6 RA + 12000 + 5000 - 45000 - 6000 = 0

    6 RA - 34000 = 0

    RA = 5667 kg

    MA = 0

    RB. 6 - RS. 8 - W. 6. 3 - W. 2. 7 - P. 3 = 0

    6 RB - 6000. 8 - 2500. 18 - 2500. 14 - 2000. 3 = 0

    6 RB - 48000 - 45000 - 35000 - 6000 = 0

    6 RB - 134000 = 0

    RB = 22333 kg

    V = 0

    RA + RB = Q + RS + P

    5667 + 22333 = 2500. 8 + 6000 + 2000

    28000 = 28000 ok

    RBS = RS + Q

    = 6000 + 2500. 2

    = 11000 kg

    RBA = RB - RBS

    = 22333 - 11000

    = 11333 kg

  • MX = RA. X - 0,5 W. X2 = 5667 X - 0,5. 2500 X2

    X25005667dX

    dMX

    0dX

    dMX

    2500 X = 5667 X = 2,27 m

    M maks = 5667. 2,27 - 1250. 2,272 = 12864 - 6441 = 6423 kgm

    MB = RS. 2 + W. 2. 1 = 6000. 2 + 2500. 2 = 12000 + 5000 = 17000 kgm

    MD = RA. 3 - W. 3. 4,5 = 5667.3 - 2500. 4,5 = 17001 - 11250 = 5751 kgm

  • BIDANG GESER

  • BIDANG MOMEN

  • 49) Gambar bidang momen dan gaya lintang. P1 = 600 kg, P2 = 1000 kg, P3 = 800 kg

    S1

    Balok : A – S1

    RA = RS1 = 0,5 P1 = 0,5. 600 = 300 kg

    ME = RA. 1,5 = 300. 1,5 = 450 kgm

  • Balok : S2 – D

    MD = 0

    RS2. 3 - P3. 2 = 0

    3 RS2 - 800. 2 = 0

    RS2 = 533 kg

    MS2 = 0

    RD. 3 - P3. 1 = 0

    3 RD - 800. 1 = 0

    3 RD - 800 = 0

    RD = 267 kg

    V = 0 RS2 + RD = P3 533 + 267 = 800 800 = 800 ok

    MG = RD. 2 = 267. 2 = 534 kgm

  • Balok : S1 – B – C – S2

    MC = 0

    RB. 5 + RS2. 1 - RS1. 6 - P2. 3 = 0

    5 RB + 533. 1 - 300. 6 - 1000. 3 = 0

    5 RB + 533 - 1800 - 3000 = 0

    5 RB - 4267 = 0

    RB = 853 kg

    MB = 0

    RC. 5 + RS1. 1 - P2. 2 - RS2. 6 = 0

    5 RC + 300. 1 - 1000. 2 - 533. 6 = 0

    5 RC + 300 - 2000 - 3198 = 0

    5 RC - 4898 = 0

    RC = 980 kg

    V = 0 RB + RC = RS1 + P2 + RS2 853 + 980 = 300 + 1000 + 533 1833 = 1833 ok

  • RBS1 = RS1

    = 300 kg

    RBC = RB - RBS1

    = 853 - 300

    = 553 kg

    RCS2 = RS2

    = 533 kg

    RCB = RC - RCS2

    = 980 - 533

    = 447 kg

    MB = RS1. 1

    = 300. 1

    = 300 kgm

    MC = RS2. 1

    = 533. 1

    = 533 kgm

    MF = RB. 2 - RS1. 3 = 853. 2 - 300. 3 = 1706 - 900 = 806 kgm

  • BIDANG GESER

  • BIDANG MOMEN

  • 50) Gambar bidang momen dan gaya lintang. W1 = 1500 kg/m, W2 = 1800 kg/m, W3 = 2200 kg/m

  • Balok : A – S1

    RA = RS1 = 0,5 W1. 3

    = 0,5. 1500. 3

    = 2250 kg

    M maks = 1/8 W1. 32

    = 1/8. 1500. 9 = 1688 kgm

    Balok : S2 – D

    RS2 = RD = 0,5 W2. 4

    = 0,5. 1800. 4

    = 3600 kg

    M maks = 1/8 W2. 42

    = 1/8. 1800. 16

    = 3600 kgm

  • Balok : S1 – B – C – S2

    MC = 0

    RB. 5 + RS2. 1 + W2. 1. 0,5 - RS1. 6 - W1. 1. 5,5 - W3. 5. 2,5 = 0

    5 RB + 3600. 1 + 1800. 0,5 - 2250. 6 - 1500. 5,5 - 2200. 12,5 = 0

    5 RB + 3600 + 900 - 13500 - 8250 - 27500 = 0

    5 RB – 44750 = 0

    RB = 8950 kg

    MB = 0

    RC. 5 + RS1. 1 + W1. 1. 0,5 - RS2. 6 - W2. 1. 5,5 - W3. 5. 2,5 = 0

    5 RC + 2250. 1 + 1500. 0,5 - 3600. 6 - 1800. 5,5 - 2200. 12,5 = 0

    5 RC + 2250 + 750 - 21600 - 9900 - 27500 = 0

    5 RC - 56000 = 0

    RC = 11200 kg

  • RBS1 = RS1 + Q = 2250 + 1500. 1 = 3750 kg

    RBC = RB - RBS1

    = 8950 - 3750

    = 5200 kg

    RCS2 = RS2 + Q = 3600 + 1800. 1 = 5400 kg

    RCB = RC - RCS2

    = 11200 - 5400

    = 5800 kg

    V = 0

    RB + RC = RS1 + RS2 + W1. 1 + W2. 1 + W3. 5

    8950 + 11200 = 2250 + 3600 + 1500. 1 + 1800. 1 + 2200. 5

    20150 = 20150 ok

  • MX = RB. X - RS1 (1 + X) - W1. 1 (0,5 + X) - 0,5 W3. X2

    = 8950 X - 2250 (1 + X) - 1500 (0,5 + X) - 0,5. 2200 X2

    = 8950 X - 2250 - 2250 X - 750 - 1500 X - 1100 X2

    = 5200 X - 3000 - 1100 X2

    x20005200dX

    dMX

    0dX

    dMX

    2200 X = 5200 X = 2,36 m

    M maks = 5200. 2,36 - 3000 - 1100. 2,362 = 12272 - 3000 - 6127 = 3145 kgm

    MB = RS1. 1 + W1. 1. 0,5 = 2250. 1 + 1500. 0,5 = 2250 + 750 = 3000 kgm

    MC = RS2. 1 + W2. 1. 0,5 = 3600. 1 + 1800. 0,5 = 3600 + 900 = 4500 kgm

  • BIDANG GESER

  • BIDANG MOMEN

  • 51) Gambar bidang momen dan gaya lintang. P1 = 500 kg, P2 = 800 kg, W1 = 1500 kg/m, W2 = 1800 kg/m, W3 = 2200 kg/m

  • Balok : A – S1

    MS1 = 0 RA 3 - P1. 1 - W2. 3. 1,5 = 0 3 RA - 500. 1 - 2000. 4,5 = 0 3 RA - 1500 - 9000 = 0 3 RA - 10500 = 0 RA = 3167 kg

    MA = 0 RS1 - P1. 2 - W2. 3. 1,5 = 0 3 RS1 - 500. 1 - 2000. 4,5 = 0 3 RS1 - 500 - 9000 = 0 3 RS1 - 9400 = 0 RS1 = 3333 kg

    V = 0

    RA + RS1 = P1 + Q

    3167 + 3333 = 500 + 2000. 3

    6500 = 6500 ok MX = RA. X - W2. X. 0,5 X

    = 3167 X - 0,5. 2000 X2

    x20003167dX

    dMX

    0dX

    dMX

    2000 X = 3167 X = 1,58 m

    M maks = 3167. 1,58 - 1000. 1,582

    = 5004 - 2496

    = 2508 kgm

    ME = RS1. 1 - W2. 1. 0,5

    = 3333. 1 - 2000. 0,5

    = 3333 - 1000

    = 2333 kgm

  • Balok : S2 – D

    MD = 0

    RS2 3 - P1. 2 - W1. 3. 1,5 = 0

    3 RS2 - 500. 2 - 1800. 4,5 = 0

    3 RS2 - 1000 - 8100 = 0

    3 RS2 - 9100 = 0

    RS2 = 3033 kg

    MS2 = 0

    RD. 3 - P1. 1 - W1. 3. 1,5 = 0

    3 RD - 500. 1 - 1800. 4,5 = 0

    3 RD - 500 - 8100 = 0

    3 RD - 8600 = 0

    RD = 2867 kg

    V = 0 RS2 + RD = P1 + Q 3033 + 2867 = 500 + 1800. 3 5900 = 5900 ok

    MX = RD. X - W1. X. 0,5 X = 2867 X - 0,5. 1800 X2

    x18002867dX

    dMX

    0dX

    dMX

    1800 X = 2867 X = 1,59 m

    M maks = 2867. 1,59 - 900. 1,582

    = 5004 - 2496

    = 2283 kgm

    MG = RS2. 1 - W1. 1. 0,5

    = 3033. 1 - 1800. 0,5

    = 3033 - 900

    = 2133 kgm

  • Balok : S1 – B – C – S2

    MC = 0

    RB. 4 + RS2. 1 + W3. 1. 0,5 - S1. 5 - W3. 1. 4,5 - W3. 4. 2 - P2. 2 = 0

    4 RB + 3033. 1 + 2200. 0,5 - 3333. 5 - 2200. 4,5 - 2200. 8 - 800. 2 = 0

    4 RB + 3033 + 1100 - 16665 - 9900 - 17600 - 1600 = 0

    4 RB - 41632 = 0

    RB = 10408 kg

    MB= 0

    RC. 4 + RS1. 1 + W3. 1. 0,5 - RS2. 5 - W3. 1. 4,5 - W3. 4. 2 - P2. 2 = 0

    4 RC + 3333. 1 + 2200. 0,5 - 3033. 5 - 2200. 4,5 - 2200. 8 - 800. 2 = 0

    4 RC + 3333 + 1100 - 15165 - 9900 - 17600 - 1600 = 0

    4 RC - 39832 = 0

    RC = 9958 kg

  • V = 0

    RB + RC = RS1 + RS2 + P2 + Q

    10408 + 9958 = 3333 + 3033 + 800 + 2200. 6

    20366 = 20366 ok

    RBS1 = RS1 + Q = 3333 + 2200 .1 = 5533 kg

    RCS2 = RS2 + Q = 3033 + 2200. 1 = 5233 kg

    RBC = RB - RBS1 = 10408 - 5533 = 4875 kg

    RCB = RC - RCS2 = 9958 - 5233 = 4725 kg

  • MX = RC. X - RS2 (1 + X) - W3. 1 (0,5 + X) - W3. X. 0,5 X

    = 9958 X - 3033 (1 + X) - 2200 (0,5 + X) - 0,5. 2200 X2

    = 9958 X - 3033 - 3033 X - 1100 - 2200 X - 1100 X2

    = 4725 X - 4133 - 1100 X2

    x22004725dX

    dMX

    0dX

    dMX

    2200 X = 4725 X = 2,15 m > 2 m tidak mungkin

  • MX = RB. X - RS1 (1 + X) - W3. 1 (0,5 + X) - W3. X. 0,5 X

    = 10408 X - 3333 (1 + X) - 2200 (0,5 + X) - 0,5. 2200 X2

    = 10408 X - 3333 - 3333 X - 1100 - 2200 X - 1100 X2

    = 4875 X - 4433 - 1100 X2

    x22004875dX

    dMX

    0dX

    dMX

    2200 X = 4875

    X = 2,22 m > 2 m

    M maks = MF = RB. 2 - RS1. 3 - W3. 1. 2,5 - W3. 2. 1

    = 10408. 2 - 3333. 3 - 2200. 2,5 - 2200. 2

    = 20816 - 9999 - 5500 - 4400

    = 917 kgm

    MB = RS1. 1 + W3. 1. 0,5 = 3333. 1 + 2200. 0,5 = 3333 + 1100 = 4433 kgm

    MC = RS2. 1 + W3. 1. 0,5

    = 3033. 1 + 2200. 0,5

    = 3033 + 1100

    = 4133 kgm

    tidak mungkin

  • BIDANG GESER

  • BIDANG MOMEN

  • 52) Gambar bidang momen dan gaya lintang. P1 = 1000 kg, P2 = 1250 kg, P3 = 1500 kg

  • RS1 = RS2 = 0,5. P2

    = 0,5. 1250

    = 625 kg

    MF = RS1. 2

    = 625. 2

    = 1250 kgm

    Balok : S1 – S2.

    Balok : A – B - S1 MB = 0

    RA. 4 + RS1. 1 - P1. 3 = 0

    4 RA + 625. 1 - 1000. 3 = 0

    4 RA + 625 - 3000 = 0

    4 RA - 2375 = 0

    RA = 594 kg

    MA = 0

    RB. 4 - RS1. 5 - P1. 1 = 0

    4 RB - 625. 5 - 1000. 1 = 0

    4 RB - 3125 - 1000 = 0

    4 RB - 4125 = 0

    RB = 1031 kg

    V = 0

    RA + RB = P1 + RS1

    594 + 1031 = 1000 + 625

    1625 = 1625 ok

    RBS1 = RS1

    = 625 kg

    RBA = RB - RBS1

    = 1031 - 625

    = 406 kg

    MB = RS1. 1

    = 625. 1

    = 625 kgm

    ME = RA. 1

    = 594. 1

    = 594 kgm

  • Balok : S2 – C - D

    MD = 0

    RC. 4 - RS2. 5 - P3. 3 = 0

    4 RC - 625. 5 - 1500. 3 = 0

    4 RC - 3125 - 4500 = 0

    4 RC - 7625 = 0

    RC = 1906 kg

    MC = 0

    RD. 4 + RS2. 1 - P3. 1 = 0

    4 RD + 625. 1 - 1500. 1 = 0

    4 RD + 625 - 1500 = 0

    4 RD - 875 = 0

    RD = 219 kg

    V = 0 RC + RD = RS2 + P3 1906 + 219 = 625 + 1500 2125 = 2125 ok

    RCS2 = RS2 = 625 kg

    RCD = RC – RCS2 = 1906 – 625 = 1281 kg

    MC = RS2. 1

    = 625. 1

    = 625 kgm

    MG = RD. 3

    = 219. 3

    = 657 kgm

  • BIDANG GESER

  • BIDANG MOMEN

  • 53) Gambar bidang momen dan gaya lintang. W1 = 1500 kg/m, W2 = 1800 kg/m, W3 = 2100 kg/m

    Balok : S1 – S2

    1800

    RS1 = RS2 = 0,5. W2. 4

    = 0,5. 1800. 4

    = 3600 kg

    M maks = 1/8. W. 42

    = 1/8. 1800. 16

    = 3600 kgm

  • Balok : A – B -S1 MB = 0 RA. 4 + RS1. 1 + W1. 1. 0,5 - W1. 4. 2 = 0

    4 RA + 3600. 1 + 1500. 0,5 - 1500. 8 = 0

    4 RA + 3600 + 750 - 12000 = 0

    4 RA - 7650 = 0

    RA = 1913 kg

    MA = 0

    RB. 4 - RS1. 5 - W1. 4. 2 - W1. 1. 4,5 = 0

    4 RB - 3600. 5 - 1500. 8 - 1500. 4,5 = 0

    4 RB - 18000 - 12000 - 6750 = 0

    4 RB - 36750 = 0

    RB = 9187 kg

    V = 0 RA + RB = RS1 + W1. 5 1913 + 9187 = 3600 + 1500. 5 11100 = 11100 ok

    RBS1 = RS1 + Q = 3600 + 1500. 1 = 5100 kg

    RBA = RB - RBS1

    = 9187 - 5100

    = 4087 kg

  • Balok : A – B -S1 V = 0 RA + RB = RS1 + W1. 5 1913 + 9187 = 3600 + 1500. 5 11100 = 11100 ok

    RBS1 = RS1 + Q = 3600 + 1500. 1 = 5100 kg

    RBA = RB - RBS1

    = 9187 - 5100

    = 4087 kg

    MX = RA. X - 0,5 W1. X2

    = 1913 X - 0,5. 1500 X2

    X15001913dX

    dMX

    0dX

    dMX

    1500 X = 1913

    X = 1,28 m

    M maks = 1913. 1,28 - 750. 1,282

    = 2449 - 1229

    = 1220 kgm

    MB = RS1. 1

    = 3600. 1

    = 3600 kgm

  • Balok : S2 – C – D

    MD = 0

    RC. 4 - RS2. 5 - W3. 1. 4,5 - W3. 4. 2 = 0

    4 RC - 3600. 5 - 2100. 4,5 - 2100. 8 = 0

    4 RC - 18000 - 9450 - 16800 = 0

    4 RC - 44250 = 0

    RC = 11063 kg

    MC = 0

    RD. 4 + RS2. 1 + W3. 1. 0,5 - W3. 4. 2 = 0

    4 RD + 3600. 1 + 2100. 0,5 - 2100. 8 = 0

    4 RD + 3600 + 1050 - 16800 = 0

    4 RD - 12150 = 0

    RD = 3037 kg

    V = 0

    RC + RD = RS2 + W3. 5

    11063 + 3037 = 3600 + 2100, 5

    14100 = 14100 ok

    RCS2 = RS2 + Q = 3600 + 2100. 1 = 5700 kg

    RCD = RC - RCS2 = 11063 - 5700 = 5363 kg

  • Balok : S2 – C – D

    RCS2 = RS2 + Q = 3600 + 2100. 1 = 5700 kg

    RCD = RC - RCS2 = 11063 - 5700 = 5363 kg

    X21003037dX

    dMX

    0dX

    dMX

    MX = RD. X - 0,5 W3. X2

    = 3037 X - 0,5. 2100 X2

    2100 X = 3037

    X = 1,45 m

    M maks = 3037. 1,45 - 1050. 1,452

    = 4404 - 2208

    = 2196 kgm

    MC = RS2. 1 + W3. 1. 0,5

    = 3600. 1 + 0,5. 2100

    = 3600 + 1050

    = 4650 kgm

  • BIDANG MOMEN

  • BIDANG MOMEN

  • 54) Gambar bidang momen dan gaya lintang. P = 1500 kg, W = 1800 kg/m

  • Balok : S1 – S2 MS2 = 0 RS1. 4 - W. 1,5. 3,25 - P. 1 = 0

    4 RS1 - 1800. 4,875 - 1500. 1 = 0

    4 RS1 - 8775 - 1500 = 0

    4 RS1 - 10275 = 0

    RS1 = 2569 kg

    MS1 = 0

    RS2. 4 - W. 1,5. 0,75 - P. 3 = 0

    4 RS2 - 1800. 1,125 - 1500. 3 = 0

    4 RS2 - 2025 - 4500 = 0

    4 RS1 - 6525 = 0

    RS2 = 1631 kg

    V = 0

    RS1 + RS2 = Q + P

    2569 + 1631 = 1800. 1,5 + 1500

    4200 = 4200 ok

    MX = RS1. X - 0,5 W. X2

    = 2569 X - 0,5. 1800 X2

    X18002569dX

    dMX

    0dX

    dMX

    1800 X = 2569

    X = 1,43 m

    M maks = 2569. 1,43 - 900. 1,432

    = 3674 - 1840

    = 1833 kgm

    MF = RS1. 1,5 - 0,5 W. 1,52

    = 2569. 1,5 - 0,5. 1800. 2,25

    = 3854 - 2025

    = 1829 kgm

    MG = RS2. 1

    = 1631. 1

    = 1631 kgm

  • Balok : A – B – S1

    MB = 0

    RA. 4 + RS1. 1 + W. 1. 0,5 - W. 2. 3 = 0

    4 RA + 2569. 1 + 1800. 0,5 - 1800. 6 = 0

    4 RA + 2569 + 900 - 10800 = 0

    4 RA - 7331 = 0

    RA = 1833 kg

    MA = 0

    RB. 4 - RS1. 5 - W. 1. 4,5 - W. 2. 1 = 0

    4 RB - 2569. 5 - 1800. 4,5 - 1800. 2 = 0

    4 RB - 12845 - 8100 - 3600 = 0

    4 RB - 24545 = 0

    RB = 6136 kg

    V = 0

    RA + RB = RS1 + Q1 + Q2

    1833 + 6136 = 2569 + 1800. 1 + 1800. 2

    7969 = 7969 ok

    RBS1 = RS1 + Q

    = 2569 + 1800. 1

    = 4369 kg

    RBA = RB - RBS1

    = 6136 - 4369

    = 1767 kg

    ME = RA. 2 - Q. 1

    = 1833. 2 - 1800. 2

    = 3666 - 3600

    = 66 kgm

    MB = RS1. 1 + Q. 0,5

    = 2569. 1 + 1800. 0,5

    = 2569 + 900

    = 3469 kgm

  • MX = RA. X - 0,5 W. X2

    = 1833 X - 0,5. 1800 X2

    X18001833dX

    dMX

    0dX

    dMX

    1800 X = 1833 X = 1,02 m

    Balok : A – B – S1

    M maks = 1833. 1,02 - 900. 1,022

    = 1870 - 936

    = 934 kgm

  • Balok : S2 – C – D MD = 0 RC. 4 - RS2. 5 - W. 3. 3,5 - P. 1 = 0

    4 RC - 1631. 5 - 1800. 10,5 - 1500. 1 = 0

    4 RC - 8155 - 18900 - 1500 = 0

    4 RC - 28555 = 0

    RC = 7139 kg

    MC = 0

    RD. 4 + RS2. 1 + W. 1. 0,5 - W. 2. 1 - P. 3 = 0

    4 RD + 1631. 1 + 1800. 0,5 - 1800. 2 - 1500. 3 = 0

    4 RD + 1631 + 900 - 3600 - 4500 = 0

    4 RD - 5569 = 0

    RD = 1392 kg

    V = 0

    RC + RD = Q + P + RS2

    7139 + 1392 = 1800. 3 + 1500 + 1631

    8531 = 8531 ok

    RCS2 = RS2 + Q = 1631 + 1800. 1 = 3431 kg

    RCD = RC - RCS2 = 7139 - 3431 = 3708 kg

  • MX = RC. X - RS2 (1 + X) - W. 1 (0,5 + X) - 0,5 W. X2

    = 7139 X - 1631 (1 + X) - 1800 (0,5 + X) - 0,5. 1800 X2

    = 7139 X - 1631 - 1631 X - 900 - 1800 X - 900 X2

    = 3708 X - 2531 - 900 X2

    Balok : S2 – C – D

    X18003708dX

    dMX

    0dX

    dMX

    1800 X = 3708 X = 2,06 m > 2 m tidak mungkin

    MC = RS2. 1 + W. 1. 0,5

    = 1631. 1 + 1800. 0,5

    = 1631 + 900

    = 2531 kgm

    MH = RD. 2 - P. 1

    = 1392. 2 - 1500. 1

    = 2784 - 1500

    = 1284 kgm

    MI = RD. 1

    = 1392. 1

    = 1392 kgm

  • BIDANG GESER

  • BIDANG MOMEN

  • 55) Gambar bidang momen dan gaya lintang. P = 1200 kg, W1 = 1600 kg/m, W2 = 1200 kg/m, W3 = 2200 kg/m

    Balok : S1 – S2

    RS1 = RS2 = 0,5. 1200. 3,5 = 2100 kg

    M maks = 1200. 3,52

    = 1838 kgm

    8

    1

  • Balok : A – B – S1 MB = 0 RA. 4 + RS1. 1 + W1. 1. 0,5 - W1. 4. 2 - P. 2 = 0

    4 RA + 2100. 1 + 1600. 0,5 - 1600. 8 - 1200. 2 = 0

    4 RA + 2100 + 800 - 12800 - 2400 = 0

    4 RA - 12300 = 0

    RA = 3075 kg

    MA = 0

    RB. 4 - RS1. 5 - W1. 5. 2,5 - P. 2 = 0

    4 RB - 2100. 5 - 1600. 12,5 - 1200. 2 = 0

    4 RB - 10500 - 20000 - 2400 = 0

    4 RB - 32900 = 0

    RB = 8225 kg

    V = 0 RA + RB = RS1 + Q + P 3075 + 8225 = 2100 + 1600. 5 + 1200 11300 = 11300 ok

    RBS1 = RS1 + Q

    = 2100 + 1600. 1

    = 3700 kg

    RBA = RB - RBS1 = 8225 - 3700 = 4525 kg

  • Balok : A – B – S1 MX = RA. X - 0,5 W1. X

    2

    = 3075 X - 0,5. 1600 X2

    X16003075dX

    dMX

    0dX

    dMX

    1600 X = 3075

    X = 1,92 m

    M maks = 3075. 1,92 - 800. 1,922

    = 5904 - 2949

    = 2955 kgm

    ME = RA. 2 - W1. 2. 1

    = 3075. 2 - 1600. 2

    = 6150 - 3200

    = 2950 kgm

    MB = RS1. 1 + W1. 1. 0,5

    = 2100. 1 + 1600. 0,5

    = 2100 + 800

    = 2900 kgm

  • Balok : S2 – C – D

    MD = 0

    RC. 4 - RS2. 5,5 - W3. 5,5. 2,75 - P. 2 = 0

    4 RC - 2100. 5,5 - 2200. 15,125 - 1200. 2 = 0

    4 RC - 11550 - 33275 - 2400 = 0

    4 RC - 47225 = 0

    RC = 11806 kg

    MC = 0

    RD. 4 + RS2. 1,5 + W3. 1,5. 0,75 - W3. 4. 2 - P. 2 = 0

    4 RD + 2100. 1,5 + 2200. 1,125 - 2200. 8 - 1200. 2 = 0

    4 RD + 3150 + 2475 - 17600 - 2400 = 0

    4 RD - 14375 = 0

    RD = 3594 kg

    V = 0

    RC + RD = RS2 + P + W3. 5,5

    11806 + 3594 = 2100 + 1200 + 2200. 5,5

    15400 = 15400 ok

    RCS2 = RS2 + W3. 1,5

    = 2100 + 2200. 1,5

    = 5400 kg

    RCD = RC - RCS2

    = 11806 - 5400

    = 6406 kg

  • Balok : S2 – C – D

    MX = RD. X - 0,5 W3. X2

    = 3594 X – 0,5. 2200 X2

    X22003594dX

    dMX

    0dX

    dMX

    2200 X = 3594

    X = 1,63 m

    M maks = 3594. 1,63 - 1100. 1,632

    = 5858 - 2923

    = 2935 kgm

    MC = RS2. 1,5 + W3. 1,5. 0,75

    = 2100. 1,5 + 2200. 1,125

    = 3150 + 2475

    = 5625 kgm

    MF = RD. 2 - W3. 2. 1

    = 3594. 2 - 2200. 2

    = 7188 - 4400

    = 2788 kgm

  • BIDANG GESER

  • BIDANG MOMEN