Apakah Struktur Gelagar dibawah ini SST tau SSTT?? fileApakah Struktur Gelagar dibawah ini SST tau...
Embed Size (px)
Transcript of Apakah Struktur Gelagar dibawah ini SST tau SSTT?? fileApakah Struktur Gelagar dibawah ini SST tau...
-
Apakah Struktur Gelagar dibawah ini SST tau SSTT??
Apakah Struktur Gelagar dibawah ini SST tau SSTT??
-
Apakah Struktur Gelagar dibawah ini SST tau SSTT??
Struktur Gelagar GERBER
Penemu Struktur Gerber : JGH.Gerber
Merupakan Struktur gelagar yang terdiri dari Gelagar anak dan Gelagar Induk.
Dimana, Salah satu/kedua tumpuan Gelagar anak menumpu pada Gelagar Induk.
Reaksi tumpuan pada salah satu tumpuan Gelagar anak akan diteruskan
Ke Gelagar induk sebagai beban Terpusat luar.
-
* SATU sendi dengan TIGA tumpuan.
-
* DUA sendi dengan EMPAT tumpuan.
-
* DUA sendi dengan EMPAT tumpuan.
-
Contoh Pengujian Gelagar Gerber
-
STRUKTUR BALOK GERBER
** Balok : S - C.
MC = 0 RS. 5 - P2. 2,5 = 0 RS = 0,5 P2
MS = 0 RC. 5 - P2. 2,5 = 0 RC = 0,5 P2
V = 0 RS + RC = P2 0,5 P2 + 0,5 P2 = P2 P2 = P2 ok
ME = 2,5 RS
-
MB = 0
RA. 5 + RS. 1,5 - P1. 2,5 = 0
5 RA + 0,5 P2. 1,5 - 2,5 P1 = 0
5 RA + 0,75 P2 - 2,5 P1 = 0
RA = 0,5 P1 - 0,15 P2
MA = 0
RB. 5 - RS. 6,5 - P1. 2,5 = 0
5 RB - 0,5 P2. 6,5 - 2,5 P1 = 0
5 RB - 3,25 P2 - 2,5 P1 = 0
RB = 0,5 P1 + 0,65 P2
RBA = RB - RS
= 0,5 P1 + 0,65 P2 - 0,5 P2
= 0,5 P1 + 0,15 P2
RBS = RS = 0,5 P2
MD = RA. 2,5 = (0,5 P1 - 0,15 P2) 2,5 = 1,25 P1 - 0,375 P2
MB = RS. 1,5
= 0,5 P2. 1,5
= 0,75 P2
-
46) Gambar bidang momen dan gaya lintang. P1 = 400 kg, P2 = 500 kg
RS = RC = 0,5 P2
= 0,5. 500
= 250 kg
Balok : S – C
ME = RC. 2
= 250. 2
= 500 kgm
-
Balok : A – B – S.
MB = 0
RA. 4 + RS. 2 - P1. 2 = 0
4 RA + 250. 2 - 400. 2 = 0
4 RA + 500 - 800 = 0
4 RA = 300
RA = 75 kg
MA = 0
RB. 4 - RS. 6 - P1. 2 = 0
4 RB - 250. 6 - 400. 2 = 0
4 RB - 1500 - 800 = 0
4 RB - 2300 = 0
RB = 575 kg
RBS = RS
= 250 kg
V = 0
RA + RB = P1 + RS
75 + 575 = 400 + 250
650 = 650 ok
RBA = RB - RBS = 575 - 250 = 325 kg
MB = RS. 2 = 250. 2 = 500 kgm
MD = RA. 2 = 75. 2 = 150 kgm
-
BIDANG GESER
-
BIDANG MOMEN
-
47) Gambar bidang momen dan gaya lintang. P = 500 kg, W = 2000 kg/m
Balok : S – C
RS = RC = 0,5 P
= 0,5. 500
= 250 kg
MD = RC. 2 = 250. 2 = 500 kgm
-
Balok : A – B – S.
MB = 0
RA. 4 + RS. 2 + W. 2. 1 - W. 4. 2 = 0
4 RA + 250. 2 + 2000. 2 - 2000. 8 = 0
4 RA + 500 + 4000 - 16000 = 0
4 RA - 11500 = 0
RA = 2875 kg
MA = 0
RB. 4 - RS. 6 - W. 4. 2 - W. 2. 5 = 0
4 RB - 250. 6 - 2000. 8 - 2000. 10 = 0
4 RB - 1500 - 16000 - 20000 = 0
4 RB - 37500 = 0
RB = 9375 kg
V = 0
RA + RB = Q + RS
2875 + 9375 = 2000. 6 + 250
2250 = 12250 ok
RBS = RS + Q = 250 + 2000. 2 = 4250 kg
RBA = RB - RBS = 9375 - 4250 = 5125 kg
-
MX = RA. X - 0,5 W. X2
= 2875 X - 0,5. 2000 X2
X20002875dX
dMX
0dX
dMX
2000 X = 2875 X = 1,44 m
M maks = 2875. 1,44 - 1000. 1,442
= 4140 - 2074
= 2066 kgm
MB = RS. 2 + W. 2. 1 = 250. 2 + 2000. 2 = 500 + 4000 = 4500 kgm
-
BIDANG GESER
-
BIDANG MOMEN
-
48) Gambar bidang momen dan gaya lintang. P = 2000 kg, W = 2500 kg/m
Balok : S – C.
RS = RC = 0,5 P + 0,5 W. 4
= 0,5. 2000 + 0,5. 2500. 4
= 1000 + 5000
= 6000 kg
ME = RC. 2 - W. 2. 1 = 6000. 2 - 2500. 2 = 12000 - 5000 = 7000 kgm
-
Balok : A – B – S
MB = 0
RA. 6 + RS. 2 + W. 2. 1 - W. 6. 3 - P. 3 = 0
6 RA + 6000. 2 + 2500. 2 - 2500. 18 - 2000. 3 = 0
6 RA + 12000 + 5000 - 45000 - 6000 = 0
6 RA - 34000 = 0
RA = 5667 kg
MA = 0
RB. 6 - RS. 8 - W. 6. 3 - W. 2. 7 - P. 3 = 0
6 RB - 6000. 8 - 2500. 18 - 2500. 14 - 2000. 3 = 0
6 RB - 48000 - 45000 - 35000 - 6000 = 0
6 RB - 134000 = 0
RB = 22333 kg
V = 0
RA + RB = Q + RS + P
5667 + 22333 = 2500. 8 + 6000 + 2000
28000 = 28000 ok
RBS = RS + Q
= 6000 + 2500. 2
= 11000 kg
RBA = RB - RBS
= 22333 - 11000
= 11333 kg
-
MX = RA. X - 0,5 W. X2 = 5667 X - 0,5. 2500 X2
X25005667dX
dMX
0dX
dMX
2500 X = 5667 X = 2,27 m
M maks = 5667. 2,27 - 1250. 2,272 = 12864 - 6441 = 6423 kgm
MB = RS. 2 + W. 2. 1 = 6000. 2 + 2500. 2 = 12000 + 5000 = 17000 kgm
MD = RA. 3 - W. 3. 4,5 = 5667.3 - 2500. 4,5 = 17001 - 11250 = 5751 kgm
-
BIDANG GESER
-
BIDANG MOMEN
-
49) Gambar bidang momen dan gaya lintang. P1 = 600 kg, P2 = 1000 kg, P3 = 800 kg
S1
Balok : A – S1
RA = RS1 = 0,5 P1 = 0,5. 600 = 300 kg
ME = RA. 1,5 = 300. 1,5 = 450 kgm
-
Balok : S2 – D
MD = 0
RS2. 3 - P3. 2 = 0
3 RS2 - 800. 2 = 0
RS2 = 533 kg
MS2 = 0
RD. 3 - P3. 1 = 0
3 RD - 800. 1 = 0
3 RD - 800 = 0
RD = 267 kg
V = 0 RS2 + RD = P3 533 + 267 = 800 800 = 800 ok
MG = RD. 2 = 267. 2 = 534 kgm
-
Balok : S1 – B – C – S2
MC = 0
RB. 5 + RS2. 1 - RS1. 6 - P2. 3 = 0
5 RB + 533. 1 - 300. 6 - 1000. 3 = 0
5 RB + 533 - 1800 - 3000 = 0
5 RB - 4267 = 0
RB = 853 kg
MB = 0
RC. 5 + RS1. 1 - P2. 2 - RS2. 6 = 0
5 RC + 300. 1 - 1000. 2 - 533. 6 = 0
5 RC + 300 - 2000 - 3198 = 0
5 RC - 4898 = 0
RC = 980 kg
V = 0 RB + RC = RS1 + P2 + RS2 853 + 980 = 300 + 1000 + 533 1833 = 1833 ok
-
RBS1 = RS1
= 300 kg
RBC = RB - RBS1
= 853 - 300
= 553 kg
RCS2 = RS2
= 533 kg
RCB = RC - RCS2
= 980 - 533
= 447 kg
MB = RS1. 1
= 300. 1
= 300 kgm
MC = RS2. 1
= 533. 1
= 533 kgm
MF = RB. 2 - RS1. 3 = 853. 2 - 300. 3 = 1706 - 900 = 806 kgm
-
BIDANG GESER
-
BIDANG MOMEN
-
50) Gambar bidang momen dan gaya lintang. W1 = 1500 kg/m, W2 = 1800 kg/m, W3 = 2200 kg/m
-
Balok : A – S1
RA = RS1 = 0,5 W1. 3
= 0,5. 1500. 3
= 2250 kg
M maks = 1/8 W1. 32
= 1/8. 1500. 9 = 1688 kgm
Balok : S2 – D
RS2 = RD = 0,5 W2. 4
= 0,5. 1800. 4
= 3600 kg
M maks = 1/8 W2. 42
= 1/8. 1800. 16
= 3600 kgm
-
Balok : S1 – B – C – S2
MC = 0
RB. 5 + RS2. 1 + W2. 1. 0,5 - RS1. 6 - W1. 1. 5,5 - W3. 5. 2,5 = 0
5 RB + 3600. 1 + 1800. 0,5 - 2250. 6 - 1500. 5,5 - 2200. 12,5 = 0
5 RB + 3600 + 900 - 13500 - 8250 - 27500 = 0
5 RB – 44750 = 0
RB = 8950 kg
MB = 0
RC. 5 + RS1. 1 + W1. 1. 0,5 - RS2. 6 - W2. 1. 5,5 - W3. 5. 2,5 = 0
5 RC + 2250. 1 + 1500. 0,5 - 3600. 6 - 1800. 5,5 - 2200. 12,5 = 0
5 RC + 2250 + 750 - 21600 - 9900 - 27500 = 0
5 RC - 56000 = 0
RC = 11200 kg
-
RBS1 = RS1 + Q = 2250 + 1500. 1 = 3750 kg
RBC = RB - RBS1
= 8950 - 3750
= 5200 kg
RCS2 = RS2 + Q = 3600 + 1800. 1 = 5400 kg
RCB = RC - RCS2
= 11200 - 5400
= 5800 kg
V = 0
RB + RC = RS1 + RS2 + W1. 1 + W2. 1 + W3. 5
8950 + 11200 = 2250 + 3600 + 1500. 1 + 1800. 1 + 2200. 5
20150 = 20150 ok
-
MX = RB. X - RS1 (1 + X) - W1. 1 (0,5 + X) - 0,5 W3. X2
= 8950 X - 2250 (1 + X) - 1500 (0,5 + X) - 0,5. 2200 X2
= 8950 X - 2250 - 2250 X - 750 - 1500 X - 1100 X2
= 5200 X - 3000 - 1100 X2
x20005200dX
dMX
0dX
dMX
2200 X = 5200 X = 2,36 m
M maks = 5200. 2,36 - 3000 - 1100. 2,362 = 12272 - 3000 - 6127 = 3145 kgm
MB = RS1. 1 + W1. 1. 0,5 = 2250. 1 + 1500. 0,5 = 2250 + 750 = 3000 kgm
MC = RS2. 1 + W2. 1. 0,5 = 3600. 1 + 1800. 0,5 = 3600 + 900 = 4500 kgm
-
BIDANG GESER
-
BIDANG MOMEN
-
51) Gambar bidang momen dan gaya lintang. P1 = 500 kg, P2 = 800 kg, W1 = 1500 kg/m, W2 = 1800 kg/m, W3 = 2200 kg/m
-
Balok : A – S1
MS1 = 0 RA 3 - P1. 1 - W2. 3. 1,5 = 0 3 RA - 500. 1 - 2000. 4,5 = 0 3 RA - 1500 - 9000 = 0 3 RA - 10500 = 0 RA = 3167 kg
MA = 0 RS1 - P1. 2 - W2. 3. 1,5 = 0 3 RS1 - 500. 1 - 2000. 4,5 = 0 3 RS1 - 500 - 9000 = 0 3 RS1 - 9400 = 0 RS1 = 3333 kg
V = 0
RA + RS1 = P1 + Q
3167 + 3333 = 500 + 2000. 3
6500 = 6500 ok MX = RA. X - W2. X. 0,5 X
= 3167 X - 0,5. 2000 X2
x20003167dX
dMX
0dX
dMX
2000 X = 3167 X = 1,58 m
M maks = 3167. 1,58 - 1000. 1,582
= 5004 - 2496
= 2508 kgm
ME = RS1. 1 - W2. 1. 0,5
= 3333. 1 - 2000. 0,5
= 3333 - 1000
= 2333 kgm
-
Balok : S2 – D
MD = 0
RS2 3 - P1. 2 - W1. 3. 1,5 = 0
3 RS2 - 500. 2 - 1800. 4,5 = 0
3 RS2 - 1000 - 8100 = 0
3 RS2 - 9100 = 0
RS2 = 3033 kg
MS2 = 0
RD. 3 - P1. 1 - W1. 3. 1,5 = 0
3 RD - 500. 1 - 1800. 4,5 = 0
3 RD - 500 - 8100 = 0
3 RD - 8600 = 0
RD = 2867 kg
V = 0 RS2 + RD = P1 + Q 3033 + 2867 = 500 + 1800. 3 5900 = 5900 ok
MX = RD. X - W1. X. 0,5 X = 2867 X - 0,5. 1800 X2
x18002867dX
dMX
0dX
dMX
1800 X = 2867 X = 1,59 m
M maks = 2867. 1,59 - 900. 1,582
= 5004 - 2496
= 2283 kgm
MG = RS2. 1 - W1. 1. 0,5
= 3033. 1 - 1800. 0,5
= 3033 - 900
= 2133 kgm
-
Balok : S1 – B – C – S2
MC = 0
RB. 4 + RS2. 1 + W3. 1. 0,5 - S1. 5 - W3. 1. 4,5 - W3. 4. 2 - P2. 2 = 0
4 RB + 3033. 1 + 2200. 0,5 - 3333. 5 - 2200. 4,5 - 2200. 8 - 800. 2 = 0
4 RB + 3033 + 1100 - 16665 - 9900 - 17600 - 1600 = 0
4 RB - 41632 = 0
RB = 10408 kg
MB= 0
RC. 4 + RS1. 1 + W3. 1. 0,5 - RS2. 5 - W3. 1. 4,5 - W3. 4. 2 - P2. 2 = 0
4 RC + 3333. 1 + 2200. 0,5 - 3033. 5 - 2200. 4,5 - 2200. 8 - 800. 2 = 0
4 RC + 3333 + 1100 - 15165 - 9900 - 17600 - 1600 = 0
4 RC - 39832 = 0
RC = 9958 kg
-
V = 0
RB + RC = RS1 + RS2 + P2 + Q
10408 + 9958 = 3333 + 3033 + 800 + 2200. 6
20366 = 20366 ok
RBS1 = RS1 + Q = 3333 + 2200 .1 = 5533 kg
RCS2 = RS2 + Q = 3033 + 2200. 1 = 5233 kg
RBC = RB - RBS1 = 10408 - 5533 = 4875 kg
RCB = RC - RCS2 = 9958 - 5233 = 4725 kg
-
MX = RC. X - RS2 (1 + X) - W3. 1 (0,5 + X) - W3. X. 0,5 X
= 9958 X - 3033 (1 + X) - 2200 (0,5 + X) - 0,5. 2200 X2
= 9958 X - 3033 - 3033 X - 1100 - 2200 X - 1100 X2
= 4725 X - 4133 - 1100 X2
x22004725dX
dMX
0dX
dMX
2200 X = 4725 X = 2,15 m > 2 m tidak mungkin
-
MX = RB. X - RS1 (1 + X) - W3. 1 (0,5 + X) - W3. X. 0,5 X
= 10408 X - 3333 (1 + X) - 2200 (0,5 + X) - 0,5. 2200 X2
= 10408 X - 3333 - 3333 X - 1100 - 2200 X - 1100 X2
= 4875 X - 4433 - 1100 X2
x22004875dX
dMX
0dX
dMX
2200 X = 4875
X = 2,22 m > 2 m
M maks = MF = RB. 2 - RS1. 3 - W3. 1. 2,5 - W3. 2. 1
= 10408. 2 - 3333. 3 - 2200. 2,5 - 2200. 2
= 20816 - 9999 - 5500 - 4400
= 917 kgm
MB = RS1. 1 + W3. 1. 0,5 = 3333. 1 + 2200. 0,5 = 3333 + 1100 = 4433 kgm
MC = RS2. 1 + W3. 1. 0,5
= 3033. 1 + 2200. 0,5
= 3033 + 1100
= 4133 kgm
tidak mungkin
-
BIDANG GESER
-
BIDANG MOMEN
-
52) Gambar bidang momen dan gaya lintang. P1 = 1000 kg, P2 = 1250 kg, P3 = 1500 kg
-
RS1 = RS2 = 0,5. P2
= 0,5. 1250
= 625 kg
MF = RS1. 2
= 625. 2
= 1250 kgm
Balok : S1 – S2.
Balok : A – B - S1 MB = 0
RA. 4 + RS1. 1 - P1. 3 = 0
4 RA + 625. 1 - 1000. 3 = 0
4 RA + 625 - 3000 = 0
4 RA - 2375 = 0
RA = 594 kg
MA = 0
RB. 4 - RS1. 5 - P1. 1 = 0
4 RB - 625. 5 - 1000. 1 = 0
4 RB - 3125 - 1000 = 0
4 RB - 4125 = 0
RB = 1031 kg
V = 0
RA + RB = P1 + RS1
594 + 1031 = 1000 + 625
1625 = 1625 ok
RBS1 = RS1
= 625 kg
RBA = RB - RBS1
= 1031 - 625
= 406 kg
MB = RS1. 1
= 625. 1
= 625 kgm
ME = RA. 1
= 594. 1
= 594 kgm
-
Balok : S2 – C - D
MD = 0
RC. 4 - RS2. 5 - P3. 3 = 0
4 RC - 625. 5 - 1500. 3 = 0
4 RC - 3125 - 4500 = 0
4 RC - 7625 = 0
RC = 1906 kg
MC = 0
RD. 4 + RS2. 1 - P3. 1 = 0
4 RD + 625. 1 - 1500. 1 = 0
4 RD + 625 - 1500 = 0
4 RD - 875 = 0
RD = 219 kg
V = 0 RC + RD = RS2 + P3 1906 + 219 = 625 + 1500 2125 = 2125 ok
RCS2 = RS2 = 625 kg
RCD = RC – RCS2 = 1906 – 625 = 1281 kg
MC = RS2. 1
= 625. 1
= 625 kgm
MG = RD. 3
= 219. 3
= 657 kgm
-
BIDANG GESER
-
BIDANG MOMEN
-
53) Gambar bidang momen dan gaya lintang. W1 = 1500 kg/m, W2 = 1800 kg/m, W3 = 2100 kg/m
Balok : S1 – S2
1800
RS1 = RS2 = 0,5. W2. 4
= 0,5. 1800. 4
= 3600 kg
M maks = 1/8. W. 42
= 1/8. 1800. 16
= 3600 kgm
-
Balok : A – B -S1 MB = 0 RA. 4 + RS1. 1 + W1. 1. 0,5 - W1. 4. 2 = 0
4 RA + 3600. 1 + 1500. 0,5 - 1500. 8 = 0
4 RA + 3600 + 750 - 12000 = 0
4 RA - 7650 = 0
RA = 1913 kg
MA = 0
RB. 4 - RS1. 5 - W1. 4. 2 - W1. 1. 4,5 = 0
4 RB - 3600. 5 - 1500. 8 - 1500. 4,5 = 0
4 RB - 18000 - 12000 - 6750 = 0
4 RB - 36750 = 0
RB = 9187 kg
V = 0 RA + RB = RS1 + W1. 5 1913 + 9187 = 3600 + 1500. 5 11100 = 11100 ok
RBS1 = RS1 + Q = 3600 + 1500. 1 = 5100 kg
RBA = RB - RBS1
= 9187 - 5100
= 4087 kg
-
Balok : A – B -S1 V = 0 RA + RB = RS1 + W1. 5 1913 + 9187 = 3600 + 1500. 5 11100 = 11100 ok
RBS1 = RS1 + Q = 3600 + 1500. 1 = 5100 kg
RBA = RB - RBS1
= 9187 - 5100
= 4087 kg
MX = RA. X - 0,5 W1. X2
= 1913 X - 0,5. 1500 X2
X15001913dX
dMX
0dX
dMX
1500 X = 1913
X = 1,28 m
M maks = 1913. 1,28 - 750. 1,282
= 2449 - 1229
= 1220 kgm
MB = RS1. 1
= 3600. 1
= 3600 kgm
-
Balok : S2 – C – D
MD = 0
RC. 4 - RS2. 5 - W3. 1. 4,5 - W3. 4. 2 = 0
4 RC - 3600. 5 - 2100. 4,5 - 2100. 8 = 0
4 RC - 18000 - 9450 - 16800 = 0
4 RC - 44250 = 0
RC = 11063 kg
MC = 0
RD. 4 + RS2. 1 + W3. 1. 0,5 - W3. 4. 2 = 0
4 RD + 3600. 1 + 2100. 0,5 - 2100. 8 = 0
4 RD + 3600 + 1050 - 16800 = 0
4 RD - 12150 = 0
RD = 3037 kg
V = 0
RC + RD = RS2 + W3. 5
11063 + 3037 = 3600 + 2100, 5
14100 = 14100 ok
RCS2 = RS2 + Q = 3600 + 2100. 1 = 5700 kg
RCD = RC - RCS2 = 11063 - 5700 = 5363 kg
-
Balok : S2 – C – D
RCS2 = RS2 + Q = 3600 + 2100. 1 = 5700 kg
RCD = RC - RCS2 = 11063 - 5700 = 5363 kg
X21003037dX
dMX
0dX
dMX
MX = RD. X - 0,5 W3. X2
= 3037 X - 0,5. 2100 X2
2100 X = 3037
X = 1,45 m
M maks = 3037. 1,45 - 1050. 1,452
= 4404 - 2208
= 2196 kgm
MC = RS2. 1 + W3. 1. 0,5
= 3600. 1 + 0,5. 2100
= 3600 + 1050
= 4650 kgm
-
BIDANG MOMEN
-
BIDANG MOMEN
-
54) Gambar bidang momen dan gaya lintang. P = 1500 kg, W = 1800 kg/m
-
Balok : S1 – S2 MS2 = 0 RS1. 4 - W. 1,5. 3,25 - P. 1 = 0
4 RS1 - 1800. 4,875 - 1500. 1 = 0
4 RS1 - 8775 - 1500 = 0
4 RS1 - 10275 = 0
RS1 = 2569 kg
MS1 = 0
RS2. 4 - W. 1,5. 0,75 - P. 3 = 0
4 RS2 - 1800. 1,125 - 1500. 3 = 0
4 RS2 - 2025 - 4500 = 0
4 RS1 - 6525 = 0
RS2 = 1631 kg
V = 0
RS1 + RS2 = Q + P
2569 + 1631 = 1800. 1,5 + 1500
4200 = 4200 ok
MX = RS1. X - 0,5 W. X2
= 2569 X - 0,5. 1800 X2
X18002569dX
dMX
0dX
dMX
1800 X = 2569
X = 1,43 m
M maks = 2569. 1,43 - 900. 1,432
= 3674 - 1840
= 1833 kgm
MF = RS1. 1,5 - 0,5 W. 1,52
= 2569. 1,5 - 0,5. 1800. 2,25
= 3854 - 2025
= 1829 kgm
MG = RS2. 1
= 1631. 1
= 1631 kgm
-
Balok : A – B – S1
MB = 0
RA. 4 + RS1. 1 + W. 1. 0,5 - W. 2. 3 = 0
4 RA + 2569. 1 + 1800. 0,5 - 1800. 6 = 0
4 RA + 2569 + 900 - 10800 = 0
4 RA - 7331 = 0
RA = 1833 kg
MA = 0
RB. 4 - RS1. 5 - W. 1. 4,5 - W. 2. 1 = 0
4 RB - 2569. 5 - 1800. 4,5 - 1800. 2 = 0
4 RB - 12845 - 8100 - 3600 = 0
4 RB - 24545 = 0
RB = 6136 kg
V = 0
RA + RB = RS1 + Q1 + Q2
1833 + 6136 = 2569 + 1800. 1 + 1800. 2
7969 = 7969 ok
RBS1 = RS1 + Q
= 2569 + 1800. 1
= 4369 kg
RBA = RB - RBS1
= 6136 - 4369
= 1767 kg
ME = RA. 2 - Q. 1
= 1833. 2 - 1800. 2
= 3666 - 3600
= 66 kgm
MB = RS1. 1 + Q. 0,5
= 2569. 1 + 1800. 0,5
= 2569 + 900
= 3469 kgm
-
MX = RA. X - 0,5 W. X2
= 1833 X - 0,5. 1800 X2
X18001833dX
dMX
0dX
dMX
1800 X = 1833 X = 1,02 m
Balok : A – B – S1
M maks = 1833. 1,02 - 900. 1,022
= 1870 - 936
= 934 kgm
-
Balok : S2 – C – D MD = 0 RC. 4 - RS2. 5 - W. 3. 3,5 - P. 1 = 0
4 RC - 1631. 5 - 1800. 10,5 - 1500. 1 = 0
4 RC - 8155 - 18900 - 1500 = 0
4 RC - 28555 = 0
RC = 7139 kg
MC = 0
RD. 4 + RS2. 1 + W. 1. 0,5 - W. 2. 1 - P. 3 = 0
4 RD + 1631. 1 + 1800. 0,5 - 1800. 2 - 1500. 3 = 0
4 RD + 1631 + 900 - 3600 - 4500 = 0
4 RD - 5569 = 0
RD = 1392 kg
V = 0
RC + RD = Q + P + RS2
7139 + 1392 = 1800. 3 + 1500 + 1631
8531 = 8531 ok
RCS2 = RS2 + Q = 1631 + 1800. 1 = 3431 kg
RCD = RC - RCS2 = 7139 - 3431 = 3708 kg
-
MX = RC. X - RS2 (1 + X) - W. 1 (0,5 + X) - 0,5 W. X2
= 7139 X - 1631 (1 + X) - 1800 (0,5 + X) - 0,5. 1800 X2
= 7139 X - 1631 - 1631 X - 900 - 1800 X - 900 X2
= 3708 X - 2531 - 900 X2
Balok : S2 – C – D
X18003708dX
dMX
0dX
dMX
1800 X = 3708 X = 2,06 m > 2 m tidak mungkin
MC = RS2. 1 + W. 1. 0,5
= 1631. 1 + 1800. 0,5
= 1631 + 900
= 2531 kgm
MH = RD. 2 - P. 1
= 1392. 2 - 1500. 1
= 2784 - 1500
= 1284 kgm
MI = RD. 1
= 1392. 1
= 1392 kgm
-
BIDANG GESER
-
BIDANG MOMEN
-
55) Gambar bidang momen dan gaya lintang. P = 1200 kg, W1 = 1600 kg/m, W2 = 1200 kg/m, W3 = 2200 kg/m
Balok : S1 – S2
RS1 = RS2 = 0,5. 1200. 3,5 = 2100 kg
M maks = 1200. 3,52
= 1838 kgm
8
1
-
Balok : A – B – S1 MB = 0 RA. 4 + RS1. 1 + W1. 1. 0,5 - W1. 4. 2 - P. 2 = 0
4 RA + 2100. 1 + 1600. 0,5 - 1600. 8 - 1200. 2 = 0
4 RA + 2100 + 800 - 12800 - 2400 = 0
4 RA - 12300 = 0
RA = 3075 kg
MA = 0
RB. 4 - RS1. 5 - W1. 5. 2,5 - P. 2 = 0
4 RB - 2100. 5 - 1600. 12,5 - 1200. 2 = 0
4 RB - 10500 - 20000 - 2400 = 0
4 RB - 32900 = 0
RB = 8225 kg
V = 0 RA + RB = RS1 + Q + P 3075 + 8225 = 2100 + 1600. 5 + 1200 11300 = 11300 ok
RBS1 = RS1 + Q
= 2100 + 1600. 1
= 3700 kg
RBA = RB - RBS1 = 8225 - 3700 = 4525 kg
-
Balok : A – B – S1 MX = RA. X - 0,5 W1. X
2
= 3075 X - 0,5. 1600 X2
X16003075dX
dMX
0dX
dMX
1600 X = 3075
X = 1,92 m
M maks = 3075. 1,92 - 800. 1,922
= 5904 - 2949
= 2955 kgm
ME = RA. 2 - W1. 2. 1
= 3075. 2 - 1600. 2
= 6150 - 3200
= 2950 kgm
MB = RS1. 1 + W1. 1. 0,5
= 2100. 1 + 1600. 0,5
= 2100 + 800
= 2900 kgm
-
Balok : S2 – C – D
MD = 0
RC. 4 - RS2. 5,5 - W3. 5,5. 2,75 - P. 2 = 0
4 RC - 2100. 5,5 - 2200. 15,125 - 1200. 2 = 0
4 RC - 11550 - 33275 - 2400 = 0
4 RC - 47225 = 0
RC = 11806 kg
MC = 0
RD. 4 + RS2. 1,5 + W3. 1,5. 0,75 - W3. 4. 2 - P. 2 = 0
4 RD + 2100. 1,5 + 2200. 1,125 - 2200. 8 - 1200. 2 = 0
4 RD + 3150 + 2475 - 17600 - 2400 = 0
4 RD - 14375 = 0
RD = 3594 kg
V = 0
RC + RD = RS2 + P + W3. 5,5
11806 + 3594 = 2100 + 1200 + 2200. 5,5
15400 = 15400 ok
RCS2 = RS2 + W3. 1,5
= 2100 + 2200. 1,5
= 5400 kg
RCD = RC - RCS2
= 11806 - 5400
= 6406 kg
-
Balok : S2 – C – D
MX = RD. X - 0,5 W3. X2
= 3594 X – 0,5. 2200 X2
X22003594dX
dMX
0dX
dMX
2200 X = 3594
X = 1,63 m
M maks = 3594. 1,63 - 1100. 1,632
= 5858 - 2923
= 2935 kgm
MC = RS2. 1,5 + W3. 1,5. 0,75
= 2100. 1,5 + 2200. 1,125
= 3150 + 2475
= 5625 kgm
MF = RD. 2 - W3. 2. 1
= 3594. 2 - 2200. 2
= 7188 - 4400
= 2788 kgm
-
BIDANG GESER
-
BIDANG MOMEN