ALIRAN FLUIDA - LAMPIRAN

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LAMPIRAN a. Perhitungan T outlet pada kondisi mula-mula Inlet Large a) Bilangan Reynold Re = Dvρ μ = 0 , 1016 m 0,4 m / s 1000 kgm 3 0 , 0008 kg / ms =50800 b) Bilangan Prandl Pr = Cpμ k ¿ 4216 J/ kgK 0 , 0008 kg / ms 0 , 677 W / mK ¿ 4 , 982 c) Bilangan Nusselt Nu=0 , 023Re d 0,8 Pr n ¿ 0 , 023 ( 50800 ) 0,8 ( 4 , 982 ) 0,4 =254 , 198 d) Menghitung koefisien transfer panas (h) Nu = hd k h = Nu k d h inletl arge = 254 , 198 × 0 , 677 W / m . K 0 , 1016 m h inletl arge = 1693 , 819 W / m 2 . K Inlet Small a) bilangan Reynold

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Laporan praktikum aliran fluida

Transcript of ALIRAN FLUIDA - LAMPIRAN

Page 1: ALIRAN FLUIDA - LAMPIRAN

LAMPIRAN

a. Perhitungan T outlet pada kondisi mula-mula

Inlet Largea) Bilangan Reynold

Re =Dv ρ

μ

=0 ,1016m 0,4 m/ s 1000kgm−3

0 ,0008 kg/ms=50800

b) Bilangan Prandl

Pr=Cpμk

¿4216 J /kgK 0 ,0008kg /ms0 ,677W /mK

¿4 ,982c) Bilangan Nusselt

Nu=0 ,023 Red0,8 Prn

¿0 ,023(50800 )0,8( 4 ,982)0,4

=254 ,198d)

Menghitung koefisien transfer panas (h)

Nu=h dk

h = Nu kd

hinletl arg e =254 ,198 × 0 ,677 W /m .K0 ,1016 m

hinletl arg e = 1693 ,819 W /m2 .K

Inlet Smalla) bilangan Reynold

Re

=Dv ρμ

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=0 ,0254m 1,2m /s 1000kgm−3

0 ,0008kg /ms=38100

b)

Bilangan Prandtl

Pr=Cpμk

¿4216 J /kgK 0 ,0008kg /ms0 ,677W /mK

¿4 ,982c)

bilangan Nusselt

Nu=0 ,023 Red0,8 Prn

¿0 ,023(38100 )0,8( 4 ,982 )0,3

=172 ,064d)

Menghitung koefisien transfer panas (h)

Nu=h dk

h = Nu kd

hinletsmall =172 ,064 × 0 ,677 W /m .K0 ,0254 m

hinletsmall = 4586 ,12 W /m2 .K

Menghitung Toutlet dengan persamaan neraca panas

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Q1 = Q2

h inletlarg e . A dT inletl arg e = hinletsmall A dT inletsmall

h inletlarg e π d inletlarg e . L (T out−T inlelarg e )= hinletsmall π d inletsmall L (T inletsmall−T out )(1693 ,819W /m2 .K × 0 ,1016 m × (T out−293 ,15 )K ) =(4586 ,12W /m2. K × 0 ,0254 m × (313 ,15−T out )K )(172 ,092T out ) −(50448 ,77 ) = (36478 ,044−116 ,487T out )

288 ,579 T out = 86926 ,814T out = 301 ,224 K

b.Perhitungan T outlet saat T hotfluid menjadi 675 K

Inlet Large

Inlet Largee) Bilangan Reynold

Re =Dv ρ

μ

=0 ,1016m 0,4 m/ s 1000kgm−3

0 ,0008 kg/ms=50800

f) Bilangan Prandl

Pr=Cpμk

¿4216 J /kgK 0 ,0008kg /ms0 ,677W /mK

¿4 ,982g) Bilangan Nusselt

Nu=0 ,023 Red0,8 Prn

¿0 ,023(50800 )0,8( 4 ,982)0,4

=254 ,198h)

Menghitung koefisien transfer panas (h)

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Nu=h dk

h = Nu kd

hinletl arg e =254 ,198 × 0 ,677 W /m .K0 ,1016 m

hinletl arg e = 1693 ,819 W /m2 .K

Maka:

Q1

L=hπ d (Tout−Tinlarge)

Q1

L=1693,819 x 3,14 x0,1016 (Tout−293,15 )

Q1=305,949Tout−89689,205

Inlet Smalla) bilangan Reynold

Re

=Dv ρμ

=0 ,0254m 1,2m /s 1000kgm−3

0 ,0008kg /ms=38100

b)

Bilangan Prandtl

Pr=Cpμk

¿4216 J /kgK 0 ,0008kg /ms0 ,677W /mK

¿4 ,982c)

bilangan Nusselt

Nu=0 ,023 Red0,8 Prn

¿0 ,023(38100 )0,8( 4 ,982 )0,3

=172 ,064

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d)

Menghitung koefisien transfer panas (h)

Nu=h dk

h = Nu kd

hinletsmall =172 ,064 × 0 ,677 W /m .K0 ,0254 m

hinletsmall = 4586 ,12 W /m2 .K

Maka:

Q2

L=hπ d (Tinsmall−Tout )

Q2

L=4586,12 x3,14 x 0 ,0254 (675−Tout )

Q2=139788,83−207,0946Tout

Menghitung Toutlet dengan persamaan neraca panas

Q1 = Q2

hinletl arg e . A dT inletlarg e = hinletsmall A dT inletsmall

hinletl arg e π d inletlarg e . L (T out−T inlelarg e )= hinletsmall π d inletsmall L (T inletsmall−T out )305 ,949 T out−89689 ,205=139788 ,83−207 ,0946T out

513 ,0436 T out = 229478 ,035T out = 447 ,2875 K

c. Perhitungan T outlet pada saat turbulent intensity menjadi 27%

Inlet Largea) Bilangan Reynold

Re =Dv ρ

μ

=0 ,1016m 0,4 m/ s 1000kgm−3

0 ,0008 kg/ms=50800

b) Bilangan Prandl

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Pr=Cpμk

¿4216 J /kgK 0 ,0008kg /ms0 ,677W /mK

¿4 ,982c) Bilangan Nusselt

Nu=0 ,023 Red0,8 Prn

¿0 ,023(50800 )0,8( 4 ,982)0,4

=254 ,198d)

Menghitung koefisien transfer panas (h)

Nu=h dk

h = Nu kd

hinletl arg e =254 ,198 × 0 ,677 W /m .K0 ,1016 m

hinletl arg e = 1693 ,819 W /m2 .K

Inlet Smalle) bilangan Reynold

Re

=Dv ρμ

=0 ,0254m 1,2m /s 1000kgm−3

0 ,0008kg /ms=38100

f)

Bilangan Prandtl

Pr=Cpμk

¿4216 J /kgK 0 ,0008kg /ms0 ,677W /mK

¿4 ,982

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g)

bilangan Nusselt

Nu=0 ,023 Red0,8 Prn

¿0 ,023(38100 )0,8( 4 ,982 )0,3

=172 ,064h)

Menghitung koefisien transfer panas (h)

Nu=h dk

h = Nu kd

hinletsmall =172 ,064 × 0 ,677 W /m .K0 ,0254 m

hinletsmall = 4586 ,12 W /m2 .K

Menghitung Toutlet dengan persamaan neraca panas

Q1 = Q2

h inletlarg e . A dT inletl arg e = hinletsmall A dT inletsmall

h inletlarg e π d inletlarg e . L (T out−T inlelarg e )= hinletsmall π d inletsmall L (T inletsmall−T out )(1693 ,819W /m2 .K × 0 ,1016 m × (T out−293 ,15 )K ) =(4586 ,12W /m2. K × 0 ,0254 m × (313 ,15−T out )K )(172 ,092T out ) −(50448 ,77 ) = (36478 ,044−116 ,487T out )

288 ,579 T out = 86926 ,814T out = 301 ,224 K

d. Perhitungan T outlet pada kondisi mula-mula saat densitas dan viskositas menjadi

8000 kg/m3 dan 0,0072 kg/ms

Inlet Largea) bilangan Reynold

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Re =Dv ρ

μ

=0 ,1016m 0,4m /s 8000kgm−3

0 ,0072kg /ms¿45155 ,56

b)

bilangan Prandtl

Pr=Cpμk

¿4216 J /kgK 0 ,0072kg /ms0 ,677W /mK

¿44 ,8378c)

bilangan Nusselt

Nu=0 ,023Red0,8 Prn

¿0 ,023( 45155 ,56 )0,8 (44 ,83781 )0,4

=557 ,3841

d)

Menghitung koefisien transfer panas (h)

Nu =h dk

h = Nu kd

hinletl arg e =557 ,3841 × 0 ,677 W /m . K0 ,1016 m

hinletl arg e = 3714 ,065 W /m2 . K

Maka:

Q1

L=hπ d (Tout−Tinlarge)

Q1

L=3714,065 x 3,14 x0,1016 (Tout−293,15 )

Q1=670,8614 Tout−196663,006

Inlet Small

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a) bilangan Reynold

Re =Dv ρ

μ

=0 ,0254 m 0,4m / s 8000 kgm−3

0 ,0072 kg /ms¿33866 ,67

b)

bilangan Prandtl

Pr=Cpμk

¿4216 J /kgK 0 ,0072kg /ms0 ,677W /mK

¿44 ,8378c)

bilangan Nusselt

Nu=0 ,023 Red0,8 Prn

¿0 ,023(33866 ,67 )0,8( 44 ,83781 )0,4

=302 ,7186d)

Menghitung koefisien transfer panas (h)

Nu =h dk

h = Nu kd

hinletl arg e =302 ,7186 × 0 ,677 W /m . K0 ,0254 m

hinletl arg e = 8068 ,524 W /m2 . K

Maka:

Q2

L=hπ d (Tinsmall−Tout )

Q2

L=8068,524 x3,14 x 0,0254 (313,15−Tout )

Q2=114095,84−364,3488Tout

Menghitung Toutlet dengan persamaan neraca panas

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Q1 = Q2

hinletl arg e . A dT inletlarg e = hinletsmall A dT inletsmall

hinletl arg e π d inletlarg e . L (T out−T inlelarg e )= hinletsmall π d inletsmall L (T inletsmall−T out )670 ,8614 T out−196663 ,006=114095 ,84−364 ,3488Tout

1035 ,2102 T out = 310758 ,8419T out = 300 ,189 K