SRIGAYATRIEDUCATIONAL INSTITUTIONS

26
SRIGAYATRI EDUCATIONAL INSTITUTIONS INDIA OUTGOING SR Date: 07-06-2020 Time: 3 Hours Max. Marks: 300 M JEE MAIN MODEL PHYSICS Section Question type +Ve Marks - Ve Marks No.of Qs Total marks Sec I(Q.N : 01 20) Questions with Single Answer Type 4 -1 20 80 Sec II(Q.N : 21 25) Questions with Numerical Answer Type (+/ - Decimal Numbers) 4 0 5 20 Total 25 100 CHEMISTRY Section Question type +Ve Marks - Ve Marks No.of Qs Total marks Sec I(Q.N : 26 45) Questions with Single Answer Type 4 -1 20 80 Sec II(Q.N : 46 50) Questions with Numerical Answer Type (+/ - Decimal Numbers) 4 0 5 20 Total 25 100 MATHEMATICS Section Question type +Ve Marks - Ve Marks No.of Qs Total marks Sec I(Q.N : 51 70) Questions with Single Answer Type 4 -1 20 80 Sec II(Q.N : 71 75) Questions with Numerical Answer Type (+/ - Decimal Numbers) 4 0 5 20 Total 25 100 JEE MAINS MODEL UT-III

Transcript of SRIGAYATRIEDUCATIONAL INSTITUTIONS

SRIGAYATRI EDUCATIONAL INSTITUTIONS

INDIA

OUTGOING SR Date: 07-06-2020 Time: 3 Hours Max. Marks: 300 M

JEE MAIN MODEL PHYSICS

Section Question type +Ve Marks

- Ve Marks

No.of Qs

Total marks

Sec – I(Q.N : 01 – 20) Questions with Single Answer Type 4 -1 20 80

Sec – II(Q.N : 21 – 25) Questions with Numerical Answer Type (+/ - Decimal Numbers)

4

0

5

20

Total

25

100

CHEMISTRY

Section Question type +Ve Marks

- Ve Marks

No.of Qs

Total marks

Sec – I(Q.N : 26 – 45) Questions with Single Answer Type 4 -1 20 80

Sec – II(Q.N : 46 – 50) Questions with Numerical Answer Type (+/ - Decimal Numbers)

4

0

5

20

Total

25

100

MATHEMATICS

Section Question type +Ve Marks

- Ve Marks

No.of Qs

Total marks

Sec – I(Q.N : 51 – 70) Questions with Single Answer Type 4 -1 20 80

Sec – II(Q.N : 71 – 75) Questions with Numerical Answer Type (+/ - Decimal Numbers)

4

0

5

20

Total

25

100

JEE MAINS MODEL UT-III

S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A

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SECTION – I

(SINGLE CORRECT ANSWER TYPE) This section contains 20 multiple choice questions. Each question has 4 options (A), (B),

(C) and (D) for its answer, out of which ONLY ONE option can be correct.

Marking scheme: +4 for correct answer, 0 if not attempted and -1 if not correct.

MATHEMATICS

SYLLABUS: Areas and Differential equations, Applications of increasing and decreasing functions,

Maximum and Minimum.

1. The area enclosed between the curves 2 2sin cosy xand y x in the interval 0 x is

A) 2 sq unit B) 1

2squnit C) 1squnit D) 3squnit

2. The area of the region enclosed by the curves 2y x and y x is

A) 1

3squnit B)

2

3squnit C)

1

6squnit D) 1squnit

3. The area of the region bounded by , , 0 1x xy e y e x and x

A) 1

ee

B) 4

loge

C) 4

4 loge

D) 1

2ee

4. The area in the first quadrant between 2 2 2 sinx y and y x is

A) 3 8

4

B)

3

4

C)

3 16

4

D)

3 8

2

5. The area bounded by the x axis and the part of graph of cosy x between 2

x

and 2

x

is separated into two regions by the line x k . If the area of the region for 2

x k is three

times the area of the region for 2

k x k

A) 1 1sin

4

B) 1 1sin

3

C) 6

D)

3

6. The order of the differential equation whose general solution is 2 2

1 2 3 4cos2 cos siny c x c x c x c is

A) 2 B) 4 C) 3 D) 6

7. The general solution of 2 2 21dy

x y xdx

is

A) 1 22sin 1y x y c B) 1 11

sin sin2

y x c

C) 1 1cos cosy x x c D) 31 1

log2 1 3

y xx c

y

8. The family of curves passing through 0,0 and satisfying the differential equation

2

1

1(n

n n

y d ywhere y

y dx

A) y k B) y kx C) 1xy k e D) 1xy k e

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9. The solution of the differential equation 2 2 2 0y dx x xy y dy is

A) 1tan log 0x

y cy

B) 12 tan log 0

xx c

y

C) 2 2log log 0y x y y c D) 2 2log 0x x y c

10. If y t satisfies the differential equation 1 22 2 , 0 2 1ty t y t e y y

A) 3

e B)

2

3

e C)

4

e D)

2

4

e

11. Let 31 .f x x x In which of the following intervals, inequality 31 1 5f x f x f x

is satisfied

A) 2,0 2, B) 3,4 4,5 C) 3, 2 4, 3 D) 6,7

12. If 2 3 , 0, 0ab a b a b then the minimum value of ab is

A) 12 B) 24 C) 1

3 D)

1

4

13. Let a, b, c, d, e, f, g, h be distinct elements in the set 7, 5, 3, 2,2,4,6,13 . The minimum

value of 2 2

a b c d e f g h is

A) 30 B) 32 C) 34 D) 40

14. If 3 29 9 3f x kx x x is monotonically increasing in R, then

A) 3k B) 2k

C) 3k D) 0k

15. The value of ' 'a for which the function 1

sin sin 33

f x a x x has an extremed at 3

x

is

A) 1 B) -1 C) 0 D) 2

16. The number of values of x where the function cos cos 2f x x x attains its maximum is

A) 0 B) 1 C) 2 D) 4

17. Let f x and g x be two continuous functions from ,R R such the

1 2 1 2 1 2f x f x and g x g x x x the solution set of 2 2 3 4f g f g is

A) 1,4 B) ,1 C) 4, D) ,1 4,

18. Area enclosed by the curve y f x defined parametrically as 2

2 2

1 2,

1 1

t tx y

t t

is equal to

A) .sq units B) .2

sq units

C) 3

.4

sq units

D) 2

.2

sq units

19. The area enclosed between the curves 2 2 0 1 .y ax and x ay wherea is sq unit then the value

of a is

A) 1

3 B)

1

2 C) 1 D)

1

3

20. The solution of the differential equation

3 5

2 4

...3! 5!

1 ...2! 4!

x xx

dx dy

x x dx dy

is

A) 2 22 1x xye ce B) 2 22 1x xye ce C) 2 2 2x xye ce D) 2 2 2x xye ce

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SECTION-II

(Numerical Value Answer Type)

This section contains 5 questions. The answer to each question is a Numerical values

comprising of positive or negative decimal numbers. Each question has 4 options (1), (2), (3)

and (4) for its answer, out of which ONLY ONE option can be correct. Marking scheme: +4 for correct answer, 0 in all other cases.

21. If 2 2, 1 1 2dy

x y y ydx

__________

22. The function 25

1k

f x x k

assumes the minimum value of x given by _____________

23. If m is the minimum value of 2 2, 4 6f x y x x y y when x and y are subjected to the

restrictions ___________

24. Let y y x be the solution of differential equation sin cos 4 , 0, .dy

x y x x xdx

If

20,2 6 9

ky then y k

25. If y y x satisfies the differential equation

8 9 4 9 , 0, 0 7 256x x dy x dx x and y then y

SECTION – I

(SINGLE CORRECT ANSWER TYPE) This section contains 20 multiple choice questions. Each question has 4 options (1), (2),

(3) and (4) for its answer, out of which ONLY ONE option can be correct.

Marking scheme: +4 for correct answer, 0 if not attempted and -1 if not correct.

PHYSICS

SYLLABUS: Electro magnetism, EMI and AC

26. The magnetic field intensity at the point ‘0’ of a loop with current i, whose shape is illustrated

below is

A) 0 3 2

4 2

i

a b

B) 0

2

2

4

ib

a

C) 0 1 1

2

i

a b

D) 0 1 1

4

i

a b

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27. A square frame of side l carries a current. The magnetic field at its centre is B. The same

current is passed through a circular coil having the same perimeter as the square. The field at

the centre of the circular coil is 1.B The ratio of

1

B

B is

A) 8 2

B)

3

8 2

C)

8 2

D)

2

4 2

28. The oscillator frequency of a cyclotron is 10 MHZ . What should be the operating magnetic

field for accelerating proton?

A) 0.156T B) 0.256T C) 0.356T D) 0.656T

29. The radius of a circular current carrying coil is R. At what distance from the centre of the coil

on its axis, the in tensing of magnetic field will be 1

2 2times that at the centre?

A) 2 R B) 3

2

R C) R D)

2

R

30. A proton and an alpha particle entre the same magnetic field which is perpendicular to their

velocity. If they have same kinetic energy then ratio of radii of their circular path is

A) 1 : 1 B) 1 : 2 C) 2 : 1 D) 1 : 4

31. A galvanometer having a coil resistance of 60 shows full scale deflection when a current of

1.0 A passes through it. It can be converted into an ammeter to read currents up to 5.0 A by

A) putting in parallel a resistance of 15 B) putting in parallel a resistance of 240

C) putting in series a resistance of 15 D) putting in series a resistance of 240

32. If the planes of two identical concentric coils are perpendicular and magnetic moment of each

coil is then the resultant magnetic moment of the two coils will be

A) M B) 2 M C) 3 M D) 2M

33. Flux (in weber) in a closed circuit of resistance 10 various with time (in second) according to

the equation 26 5 1t t . What is the magnitude of the induced current at 0.25sect

A) 1.2 A B) 0.2 A C) 0.6 A D) 0.8 A

34. An aeroplane is flying horizontally with a velocity of 360km/h. The distance between the tips

of the wings of aeroplane is 25m. The vertical component of earth’s magnetic field is 4 24 10 /wb m . The induced e.m.f. is

A) 1 V B) 100 V C) 100 KV D) Zero

35. A coil of resistance 20 ohm and inductance 5H has been connected to a 100 volt battery. The

energy stored in coil is

A) 31.25 J B) 62.5 J C) 125 J D) 250 J

36. When the number of turns in a solenoid are doubled without any change in the length of the

solenoid, itself inductance becomes

A) Half B) Double C) 4 times D) 8 times

37. A flat coil of 500 turns, each of area 250 ,cm rotates in a uniform magnetic field of 20.14 /wb m

about an axis normal to the field at an angular speed of 150 / .rad s The coil has resistance of

15 . The induced e.m.f. is applied to an external resistance of 10 . The peak current

through the resistance is

A) 1.5 A B) 2.5 A C) 3.5 A D) 4.5 A

38. A conducting rod AB of length l is projected on frictionless frame PSRQ with velocity 0v at

any instant. The velocity of the rod after time t is

S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A

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A) 0v v B)

0v v C) 0v v D) None of these

39. A copper disc of radius 0.1m is rotated about its centre with 10 /rev s . In a uniform magnetic

field of 0.1T with its plane perpendicular to field. The e.m.f. induced across the radius of disc

is

A) 10

valt

B) 100

valt

C) 1000

valt

D) Zero

40. Figure shows an L R circuit. When the switch is s is closed, the current through resistors

A) 1 2 3 0I I I B) 1 2 3

1

, 0E

I I IR

C) 1 2 3

2 3

0, ,E E

I I IR R

D) 1 2 3

1 2 1 3 3

, ,E E E

I I IR R L R L

41. In a series RLC circuit, potential across R, L and C are 30 V, 60 V, 100 V respectively as

shown in figure. The e.m.f. of source (in volts) is

A) 190 B) 70 C) 50 D) 40

42. The reading of ammeter in the circuit

A) 2 A B) 3 A C) Zero D) 1 A

43. The mean value of current for half cycle for a current variation shown & by the graph is

A) 0

2

i B) 0i C) 0

3

i D) 0

3

i

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44. In a series RLC circuit, the r.m.s. voltage across the resistor and the inductor are respectively

400 V and 700 V. If the equation for the applied voltage is 500 2 sin t then the peak

voltage across the capacitor is,

A) 1200V B) 1200 2V C) 400V D) 400 2V

45. A step-up transformer operates on 220V line and supplies 2.2 A. The ratio of primary and

secondary winding is 11 : 50. The output voltage in the secondary is

A) 220V B) 100V C) 1000V D) 0V

SECTION- II

(Numerical Value Answer Type)

This section contains 5 questions. The answer to each question is a Numerical values

comprising of positive or negative decimal numbers. Each question has 4 options (1), (2), (3)

and (4) for its answer, out of which ONLY ONE option can be correct. Marking scheme: +4 for correct answer, 0 in all other cases.

46. A coil has resistance 30 and inductive reactance 20 at 50HZ frequency. If an AC source

of 200 valt, 100 HZ is connected across the coil, the current in the coil (in ampears) will be

________

47. With the decrease of current in the primary coil from 2A to zero in 0.01s, the e.m.f generated

in the secondary coil is 1000 V. The mutual inductance of the two coil is (in H) ________

48. The magnetic field of given length of wire for single turn coil at its center is B then its value

for two turns coil for the same wire interms of B is __________

49. A coil having 500 square loops each of side 10cm is placed with its plane perpendicular to a

magnetic field which increases at a rate of 1.0 tesla/s. The induced e.m.f. (in volts) is _______

50. In a coil of resistance 10 , the induced current developed bt changing magnetic flux through

it, is shown in fig as a function of time. The magnitude of change in flux through the coil in

weber is ____________

SECTION – I

(SINGLE CORRECT ANSWER TYPE) This section contains 20 multiple choice questions. Each question has 4 options (1), (2),

(3) and (4) for its answer, out of which ONLY ONE option can be correct.

Marking scheme: +4 for correct answer, 0 if not attempted and -1 if not correct.

CHEMISTRY

SYLLABUS: Chemical properties of Alcohols and Amines, conversions of Alcohols and Aldehyde

S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A

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51. Arrange the reactivity of given four alcohols in decreasing order for hydration

A) A>B>C>D B) D>C>B>A C) C>B>D>A D) B>C>A>D

52. 0.037 g of an alcohol R OH was added to 3CH MgBr and the gas evolved measured of 11.2 ml

at STP the molecular mass of R OH will be

A) 47 B) 79 C) 74 D) 77

53.

What is B in the above conversion?

54. ________ formed when methyl amine is treated with chloroform and alcoholic solution of

potassium hydroxide.

A) 3 3CH CH B) 3CH CN C) 3CH COOH D) 3CH NC

55. Which one of the following oxidizing agent is suitable to oxidizing 03 alchohol

A) Alkaline 4KMnO B) Neutral

4KMnO C) chromic acid D) Acidified 4KMnO

56. In the reaction 2 2

2 5 2 ;NaNO H O

HClC H NH Y

unstable

Y is

A) 2 5 2C H N Cl B) 2 5C H Cl C) 2 5C H OH D) 2 6C H

57. 3 2 ;PCC OHCH CH OH A B

What is B in the above conversion?

A) 2 2CH CH B) 3CH CHO

C) 3 2CH CH OH D) 3 2CH CH OH CH CHO

58. An organic compound 3 3CH CH OH CH on treatment with acidified 2 2 7K Cr O gives a

compound ‘Y’ which reacts with 2I and sodium carbonate to form tri iodo methane. The

compound ‘Y’ is

A) 3CH OH B) 3 3CH COCH C) 3CH CHO D) 3 3CH CH OH CH

S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A

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59. is

60. For the conversion of Aniline to N-methyl aniline, the reagent used is

A) 3CH I B) 2 5C H Cl C) 4CH D)

6 5C H Cr

61. What is the end product is the following sequence of reactions?

5 32

2 3 2

PCl NHHNOC H NH A B C

A) Ethyl cyanide B) Methyl amine C) Acetamide D) Ethyl amine

62. 3 2 2

3 2

CH CO O Br H

CH COOH H OA B C

What is ‘C’?

A) B)

C) D)

63. The reagent which is easily converts alcohol to carboxylic acid is

A) PCC B) Anhydrous 3CrO C) / 573Cu K D) 4 /KMnO H

64. ?

2 2 2 2 2 2R CH CH OH RCH CH CH NH

Identify the sequence of the reagents in order to carry out the above conversion.

A) 3 4i PBr ii KCN iii LiAlH B) 3 2i PBr ii KCN iii H

C) 3 4i HCN ii PBr iii LiAlH D) 4i HCN ii LiAlH

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65. Which of the following product is formed in the given reaction?

NH2

2 2/

2 ?Br H O

Br

A)

NH2

Br

B)

NH2

Br C)

NH2

Br

BrBr

D) Both A and B

66. Dehydration of alcohols is an example of ____________

A) Bimolecular elimination/E2 reaction B) SN2 reaction

C) SN1 reaction D) Unimolecular elimination/E1 reaction

67. Compound ‘A’ undergoes formation of cyanohydrins which on hydrolysis gives lactic acid

3CH CHOHCOOH therefore compound ‘A’ is

A) Formaldehyde B) Acetaldehyde C) acetone D) benzaldehyde

68. Compounds A and C in the following reaction

3

23

CH MgBr

H OCH CHO A 2 4H SO

Hydroboration

oxidation CB

A) Identical B) position isomers C) functional isomers D) optical isomers

69. In the given reaction:

6 5 6 5 2 2 2C H CH CH CHO C H CH CH CH OH

will be

A) 4NaBH B) Aluminium isopropoxide

C) 4LiAlH D)

4KMnO

70. Which one of the following will not NOT give carbylamine reaction?

A) 2 2 2CH CH CH NH B) 6 5 2C H NH

C)

NH2

D) 6 5C H NH R

SECTION-II

(Numerical Value Answer Type)

This section contains 5 questions. The answer to each question is a Numerical values

comprising of positive or negative decimal numbers. Each question has 4 options (1), (2), (3)

and (4) for its answer, out of which ONLY ONE option can be correct. Marking scheme: +4 for correct answer, 0 in all other cases.

71. Among the following the number of alcohols showing iodoform test is

3 3 2 3 32 3

3 2 2 2 3 2 3 3 2 2

2 5 3 32 2

, , , ,

, ,

,

CH OH CH CH OH CH CHOH CH C OH

CH CH CH CH OH CH CHOHCH CH CH CH CH OH

C H CHOH CH CHOHCH CH

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72. How many of the following amines can give carbylamine reaction?

NH2

,

N

H ,

N

3CH

,

N

H

3CH

,

PH

2NH

H

3H C

,

2NH

73. Of the following amines how many can be separated by Hoffmann’s mustard oil reaction?

2NH,

N

H

3CH

, 2NH,

N

3CH

PH

3CH

2NHPH

,

2NH2CH -

,

NPH

H

74. In the following reaction 6.0g of 3CH COOH reacts with 4.6g of 3 2CH CH OH .

3 3 2 3 2 5 2CH COOH CH CH OH CH COOC H H O the amount (in grams) of water formed is

____

75. Alcoholic group at _______ position reacts fastest with Lucas’ reagent.

OH

5

OH

4

3

OH

2

1

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SRIGAYATRI EDUCATIONAL INSTITUTIONS

INDIA

OUTGOING SR Date: 07-06-2020 Time: 3 Hours Max. Marks: 300 M

KEY SHEET MATHEMATICS

1) 3 2) 2 3) 4 4) 1 5) 3 6) 1 7) 4 8) 4 9) 1 10) 4

11) 1 12) 2 13) 2 14) 3 15) 4 16) 2 17) 1 18) 1 19) 1 20) 2

21) 2 22) 3 23) 3 24) 8 25) 3

PHYSICS

26) 1 27) 1 28) 4 29) 3 30) 1 31) 1 32) 4 33) 2 34) 1 35) 2

36) 3 37) 3 38) 3 39) 2 40) 2 41) 3 42) 1 43) 1 44) 4 45) 3

46) 4 47) 5 48) 4 49) 4 50) 2

CHEMISTRY

51) 3 52) 3 53) 2 54) 4 55) 4 56) 3 57) 4 58) 2 59) 3 60) 1

61) 4 62) 3 63) 4 64) 1 65) 3 66) 4 67) 2 68) 2 69) 3 70) 4

71) 4 72) 3 73) 4 74) 1.8

or

1.80

75) 3

HINTS & SOLUTIONS

MATHEMATICS

1. 2 2sin cosy xand y x solving

2 2 3sin cos , .

4 4x x x

Graph of functions is as shown in the following figure.

JEE MAINS MODEL UT-III

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From the figure, the required are

3 3

4 42 2

4 4

3

4

4

sin cos cos 2

sin 2 11 1 1

2 2

x x dx xdx

x

2. 2y x is upward parabola0

0

x xy x

x x

The graph of the function is as shown in the following figure.

2

0,1, 1

x x

x

11 3 3

2 2

0 0

22 2

3 3

2.

3

xA x x dx x

sq unit

3. The graph of the function is as shown in the following figure.

1

0

1

0

1

2

1 1

12

x x

x x

A e e dx

e e

e e

ee

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4. Graph of the functions is as shown

in the following figure.

A=Area quarter of circle-(Area bounded by

sin 0 )2

y x and x axisbetween x and x

2

3

12

4

8

4

5.

2

2

2

2

cos 3 cos

sin 3 sin

sin 1 3 1 sin

4sin 2

1sin

2 6

k

k

k

k

xdx xdx

x x

k k

k

k k

6.

1 2 3

324 1

324

1 cos 2 1 cos 2cos 2

2 2

cos 22 2

2 2

cos 2

x xy c x c c

ccc y c x

ccc

y A B x

There are two independent parameters.

The order of D.E is 2.

7.

2 2 2

2

2

2

3

1 1 11

11

1

1 1log

2 1 3

dy dyx y x dx

dx y

dy x dxy

y xx c

y

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8.

2 1

1 11 1

log .

It passes through 0,0

1

x c x c

c x x

x x

x x

x

dy dpy y Let p p

dx dx

dp dx dp dxp p

p x c p e p e e

Let e k p e k p ke

dyke dy ke dx

dx

dy k e dx y ke

k

y k e

9.

2

2

2

2

2

-1

1

1 0

1

1 11

1

integrating tan log

tan log 0

dx x xput x vy

dy y y

dx dv dvv y v y v v

dy dy dy

dvy v dv dy

dy v y

v c y

xy c

y

10.

1

2

2dt 2 2t 2 2

2

2

2 1

2

2

2 is linear differential equation

If=e .solution is y e 2 .

2 0 2 0, 2

2 2 2

put 1 1 2 2

41

t

t t t

t

t

y t y t

e

e c e e dt

y e c t y put t y

c y e t

t y e

ye

11.

3 1 2

1 3

3 3

1 1 3

0 is decreasing for all x. Now 1- 1 52

1 5 1 5

1 1 5 4 0

2 2 0

f x x x f x x

f x x R f x f x f x f

f f x f x f x x

x x x x x

x x x

2,0 2,x

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12.

2

22

2 2

22 22

22

2

2

2 3 3 2

23 2

3

22

3 3

23 2 12

3 3

0 0, 6

3 2 6 6 3

3

At 6 , 12 0

4

minimum at / min 6 4

ab a b ab b a

ab a a b

a

a aLet z ab a

a a

a baa a adz

da a a

dza a

da

a a a a ad z

da a

a d zz

b da

has a b a b

24

13.

22

2

2

22

8

, 8

8 1

2 2 8 1

2 16 2 4 16

4 0, 0

4 16 0 4

min 4

min 4 8 4 32

a b c d e f g h

Let a b c d x e f g h x

Let y x x

dyx x

dx

dyx x x

dx

d y dyNow

dx dx

x x

y has at x

y

14.

1 2 23 18 9 3 6 3 0

0, 0 . 36 12 0

3

f x kx x kx x

x R k i e k

k

15.

1 1cos cos3 03

11 0 2

2

f x a x x f

a a

16. The maximum value of cos cos 2f x x x

Occurs when

cos 1 cos 2 1 2 ,

2 2 , . comparing the value of ,

22 0, 0

2

0 .

x and x x x n z and

x m m z x

mm m n

x only

S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A

Page | 17 SR:: JEE MAINS MODEL 07 – 06 – 2020

17.

2

2

2 2

is increasing and g is decreasing in R.

f g 2 3 4

2 3 4

2 3 4 5 4 0

1,4

Given f

f g

g g

18.

2

2

2

2 2 2

2

1 tantan

1 tan

2 tancos 2 , sin 2

1 tan

1 1,

1 .

Let t x

x y

x y r Area r

sq units

19.

2 2

2 2 2

2

2

16Thearea bounded by 4 4

3

1 11

4 4Thearea bounded by 33

1 1 11

3 3 3

10

3

aby ax and x by is

bx y a ay x is aa a

Given a aa

a a

20.

2

2 2

22

2 2

2

2

Applying componendo & dividendo

dy

dx

2

22

2 1

x x

x x

x x

x x

xx

x

x xdx

xx

x x

e edx dy

e e dx dy

e e dx dy

e e dx dy

ee

e

dy e dx dy e

ey k y e c

y e ce

21.

1

log

2 2

1 2

1Now general solution by

2 1

1 12,

1, 1 2

2 2 2 2 2 2 2 2

dxx

x

dyy x If e

dx x x

ex

yc x dx

x x x

y putyx c

x x x y c

y x x y

S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A

Page | 18 SR:: JEE MAINS MODEL 07 – 06 – 2020

22.

2 2 2 2

2 1

1 11

1 2 3 4

5 2 1 2 3 4 5 2 5 15

0 3 10 0

min 3

f x x x a x

x f x x x x x x x

f x x and f x

x f x is for x

23.

2 2

2 2

1

, 4 6

, cos ,sin 0,2

, cos sin

4cos 6sin 1 4cos 6sin

6cos 4sin 0 0,2

is strictly increasing in 0,2

0 1 4

min 3

3 3

f x y x y x y

Let x y then

and f x y f

f

f

f f

f

m m

24.

2

2 2

22

2 2

22

2

sin cos 4

sin 4 Integrating we get

sin 2

,0 0 22 4 2

sin 22

6

12

2 36 2

436

88

6 9

xdy y xdx x

d y x xdx

y x x c passes through

c c

y x x

Put x

y

y

y k

S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A

Page | 19 SR:: JEE MAINS MODEL 07 – 06 – 2020

25.

2

2

12 2

19 2

2

4 9

8 9 4 4 9

12 Integrating

4

2 2 4

4 9 12

0, 7

7 7 02

4 9

256 4 9 256 3

Put x t dx tdtx

dx t t dt

t t dy t t t dt

dy dtt

y t c

cy x

Put x y

cc

y x

y

PHYSICS

26.

00 01

0 02

to square part:-

to side OA and OC

will be zero at point OB due to

side AB and BC will be equal. So,

B 2 sin 45 04 2 2

to circular part

3

32

2 2 8

B due

B due

i i

b b

B due

i iB

a a

1 2 0

0

3 1

8 2 2

3 2

4 2

net

net

B B B ia b

iB

a b

S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A

Page | 20 SR :: JEE MAINS MODEL 07-06-2020

27. 2

lOD

0 00

0

1 0 0

1 0

2

1

4 sin 45 sin 45

42

2 2

For circle 2 r=4

2

222

4

8

iB

l

iB

l

l

i ilr so B

lr

iB

l

Bso

B

28.

196

27

2

2

1.6 1010 10

2 1.6 10

0.656

qB mf T

m qB

B

B T

29.

2

0 0

32 2 2

33 2 2 2

23 2 2 2

2 2 2 2

1

22 22

2 2

2 2

2

iR i

RR x

R R x

R R x

x R R R

x R

30.

2.

1 21:1

4 1

p p

p

mkr here k is same

qB

mso r

q

r m q

r m q

S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A

Page | 21 SR :: JEE MAINS MODEL 07-06-2020

31. 60

155

1 11

g

s

g

RR

i

i

32. 2 2

2

netM M M

M

33.

26 5 1

12 5

112 5

40.2

10

t t

dt

dt

I AR

34. 4 54 10 360 25

18

Blu

IV

35. 22

1005

20

1 15 5

2 2

62.5

I A

Li

J

36.

2

1

1

2

4

L n

soif n n

L L

37.

2 2500, 50 , 0.14 /

150 / , 5 2

3.5

man

manman

N A cm B wb m

w rod s R

NBAW

I AR

38. The rod will experience magnetic for i.e in the direction

Opposite to initial force. So velocity will decrease with time.

39.

2

2

1, 0.1 , 0.1

2

20 /

10.1 0.1 20

2

100

BWR R m B J

w rod s

volt

40. 1 2 3

1

0,inductor offers intinite resistance

so I , 0

At t

EI I

R

S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A

Page | 22 SR :: JEE MAINS MODEL 07-06-2020

41.

22

2 2

2 2

. .

30 100 60

. . 30 40 50

rms R L ce m f v v v v

e m f V

42.

22

255 55

110

55

2

cz R x

z

V IZ

I

I A

43.

/ 2

0

0

0

22 2

00

0 0

2

02

0

2

0 straight line.2

so the function I

2

2

22 2 2

2

4 10

2 4

2

J

mean

T T

mean

Idt

IT

TFrom tp graph is

iwill be t

J

it

T

i tso I t dt i

T T T T

Ti

T

i

S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A

Page | 23 SR :: JEE MAINS MODEL 07-06-2020

44.

2

0 2

22

2 2 2

2

2

500 2 sin

400 , 700

500500

2 2

500 400

250000 16000

90000

300

700 300

400

2 400 2

R

rms

rms R L c

L c

L c

L c

L c

c

c

c rms

wt

V V V V

VV

V V V

V V

V V

V V

V V

V

V V

V V V

45.

50

220 10011

P P

S S

S Ps

P

N V

N V

N VV

N

v

46.

2 22 2

20 100

1

5

12 100 40

5

30

30 40 50

2004

50

L

L

L

L

WL

and R

Z R X

I A

47.

21000

0.01

110 5

2

Mi

d diM

dt dt

M

M

S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A

Page | 24 SR :: JEE MAINS MODEL 07-06-2020

48.

0

1 0

0

1

2

2

22

42

4

4

iB N

R

iB N

R

iN

R

B B

49. 2

500 0.1 1

5

dBNA

dt

V

50.

.

10.1 4 2

2

It R

I t R

or d Idt R

Total flux R Idt

idt represents area under it curve

so R

CHEMISTRY

51. Nearer is the –I group to the alcoholic group, greater is it reactivity for dehydration.

.

52. 3 4R OH CH MgBr CH Mg

Br

OR

4

4

1 1

22400

11.2 is formed by 0.037g ROH

22400 ml is formed by?

22400 0.03774

11.2

mole mole

ml STP

ml CH

CH

53.

54. 3 2 3 3 2CH 3 3 3NH CHCl KOH CH NC KCl H O

55. Only with strong acidic oxidizing agent like acidified

4 3KMnO and conc HNO is used because first it has to

S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A

Page | 25 SR :: JEE MAINS MODEL 07-06-2020

Undergo elimination to alkene and then oxidation.

56. Alcohol is obtained for when an 01 amine is treated with

2 /NaNO HCl .

57.

1

3 2 3 3 2

PCC OHCH CH OH CH CHO CH CH OH CH CHO

Aldol Aldol

condensation

58. Secondary alcohols on oxidation gives ketones.

59.

60. Alkylation with 3CH I , Aniline gives N-methyl aniline.

61.

62. Acetylation protects amino group and bromination

occurs at ortho position to amino group.

63. Strong oxidizing agents such as acidified 4KMnO are used for getting carboxylic acids from alcohols

directly.

64.

2 2 3 2 2

2 2 2 2

2 2 4 2 2 2 2

i RCH CH OH PBr R CH CH Br

ii RCH CH Br KCN RCH CH CN

iii RCH CH CN LiAlH RCH CH CH NH

65. Aniline reacts with bromine water at room temperature to give a white precipitate of 2,4,6-

tribomoaniline.

66. Dehydration of alcohols is an example of unimolecular elimination reaction (E1)

67.

3

3 3 3

H OHCNCH CHO CH CH CN CH CH COOH

lactic acid

OH OH

68.

3 2 4

23 3 3 3 2 3 2 2

Hydroborationi CH MgBr H SO oxidation

ii H OCH CHO CH CH CH CH CH CH CH CH CH CH

OH

I

A B C

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Page | 26 SR :: JEE MAINS MODEL 07-06-2020

69. 4LiAlH is good reducing agent for unsaturated aldehyde to change to an alcohol.

70. 02 amines will not give carbylamines reaction.

71.

4

4 6 64

5

100 5 0.52 0.1

100 0.262 100.262

b b

b

b

T i k m

K fe CN K Fe CN

i

T

T

72.

1

0

0

. .

1 ( 1) 2

1 1 0.3 1.3

.

. 0 .

e

e

Tf i kf m

HX H X

l n n

l

T Tf ikf m

Tf T ikf m i kf m

ikfm

73. 1 , 0.542

xi i

74. Electrodes with low S.R.P is always taken as Anode(L.H.S)

75. 1 2

Paper Setters:

SNO Subject Name of the Paper Setter Phone No Branch

1 PHYSICS SATYARAMULU 9703653307 HYDHB

2 CHEMISTRY S. NAZIMA PARVEEN 7416026160 HYDHB

3 MATHS B P PRATHAP REDDY 9490457263 HYDHB

4 MATHS A N.V RAMANA REDDY 9291606106 HYDHB