SRIGAYATRIEDUCATIONAL INSTITUTIONS
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Transcript of SRIGAYATRIEDUCATIONAL INSTITUTIONS
SRIGAYATRI EDUCATIONAL INSTITUTIONS
INDIA
OUTGOING SR Date: 07-06-2020 Time: 3 Hours Max. Marks: 300 M
JEE MAIN MODEL PHYSICS
Section Question type +Ve Marks
- Ve Marks
No.of Qs
Total marks
Sec – I(Q.N : 01 – 20) Questions with Single Answer Type 4 -1 20 80
Sec – II(Q.N : 21 – 25) Questions with Numerical Answer Type (+/ - Decimal Numbers)
4
0
5
20
Total
25
100
CHEMISTRY
Section Question type +Ve Marks
- Ve Marks
No.of Qs
Total marks
Sec – I(Q.N : 26 – 45) Questions with Single Answer Type 4 -1 20 80
Sec – II(Q.N : 46 – 50) Questions with Numerical Answer Type (+/ - Decimal Numbers)
4
0
5
20
Total
25
100
MATHEMATICS
Section Question type +Ve Marks
- Ve Marks
No.of Qs
Total marks
Sec – I(Q.N : 51 – 70) Questions with Single Answer Type 4 -1 20 80
Sec – II(Q.N : 71 – 75) Questions with Numerical Answer Type (+/ - Decimal Numbers)
4
0
5
20
Total
25
100
JEE MAINS MODEL UT-III
S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A
Page | 2 SR:: JEE MAINS MODEL 07 – 06 – 2020
SECTION – I
(SINGLE CORRECT ANSWER TYPE) This section contains 20 multiple choice questions. Each question has 4 options (A), (B),
(C) and (D) for its answer, out of which ONLY ONE option can be correct.
Marking scheme: +4 for correct answer, 0 if not attempted and -1 if not correct.
MATHEMATICS
SYLLABUS: Areas and Differential equations, Applications of increasing and decreasing functions,
Maximum and Minimum.
1. The area enclosed between the curves 2 2sin cosy xand y x in the interval 0 x is
A) 2 sq unit B) 1
2squnit C) 1squnit D) 3squnit
2. The area of the region enclosed by the curves 2y x and y x is
A) 1
3squnit B)
2
3squnit C)
1
6squnit D) 1squnit
3. The area of the region bounded by , , 0 1x xy e y e x and x
A) 1
ee
B) 4
loge
C) 4
4 loge
D) 1
2ee
4. The area in the first quadrant between 2 2 2 sinx y and y x is
A) 3 8
4
B)
3
4
C)
3 16
4
D)
3 8
2
5. The area bounded by the x axis and the part of graph of cosy x between 2
x
and 2
x
is separated into two regions by the line x k . If the area of the region for 2
x k is three
times the area of the region for 2
k x k
A) 1 1sin
4
B) 1 1sin
3
C) 6
D)
3
6. The order of the differential equation whose general solution is 2 2
1 2 3 4cos2 cos siny c x c x c x c is
A) 2 B) 4 C) 3 D) 6
7. The general solution of 2 2 21dy
x y xdx
is
A) 1 22sin 1y x y c B) 1 11
sin sin2
y x c
C) 1 1cos cosy x x c D) 31 1
log2 1 3
y xx c
y
8. The family of curves passing through 0,0 and satisfying the differential equation
2
1
1(n
n n
y d ywhere y
y dx
A) y k B) y kx C) 1xy k e D) 1xy k e
S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A
Page | 3 SR:: JEE MAINS MODEL 07 – 06 – 2020
9. The solution of the differential equation 2 2 2 0y dx x xy y dy is
A) 1tan log 0x
y cy
B) 12 tan log 0
xx c
y
C) 2 2log log 0y x y y c D) 2 2log 0x x y c
10. If y t satisfies the differential equation 1 22 2 , 0 2 1ty t y t e y y
A) 3
e B)
2
3
e C)
4
e D)
2
4
e
11. Let 31 .f x x x In which of the following intervals, inequality 31 1 5f x f x f x
is satisfied
A) 2,0 2, B) 3,4 4,5 C) 3, 2 4, 3 D) 6,7
12. If 2 3 , 0, 0ab a b a b then the minimum value of ab is
A) 12 B) 24 C) 1
3 D)
1
4
13. Let a, b, c, d, e, f, g, h be distinct elements in the set 7, 5, 3, 2,2,4,6,13 . The minimum
value of 2 2
a b c d e f g h is
A) 30 B) 32 C) 34 D) 40
14. If 3 29 9 3f x kx x x is monotonically increasing in R, then
A) 3k B) 2k
C) 3k D) 0k
15. The value of ' 'a for which the function 1
sin sin 33
f x a x x has an extremed at 3
x
is
A) 1 B) -1 C) 0 D) 2
16. The number of values of x where the function cos cos 2f x x x attains its maximum is
A) 0 B) 1 C) 2 D) 4
17. Let f x and g x be two continuous functions from ,R R such the
1 2 1 2 1 2f x f x and g x g x x x the solution set of 2 2 3 4f g f g is
A) 1,4 B) ,1 C) 4, D) ,1 4,
18. Area enclosed by the curve y f x defined parametrically as 2
2 2
1 2,
1 1
t tx y
t t
is equal to
A) .sq units B) .2
sq units
C) 3
.4
sq units
D) 2
.2
sq units
19. The area enclosed between the curves 2 2 0 1 .y ax and x ay wherea is sq unit then the value
of a is
A) 1
3 B)
1
2 C) 1 D)
1
3
20. The solution of the differential equation
3 5
2 4
...3! 5!
1 ...2! 4!
x xx
dx dy
x x dx dy
is
A) 2 22 1x xye ce B) 2 22 1x xye ce C) 2 2 2x xye ce D) 2 2 2x xye ce
S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A
Page | 4 SR:: JEE MAINS MODEL 07 – 06 – 2020
SECTION-II
(Numerical Value Answer Type)
This section contains 5 questions. The answer to each question is a Numerical values
comprising of positive or negative decimal numbers. Each question has 4 options (1), (2), (3)
and (4) for its answer, out of which ONLY ONE option can be correct. Marking scheme: +4 for correct answer, 0 in all other cases.
21. If 2 2, 1 1 2dy
x y y ydx
__________
22. The function 25
1k
f x x k
assumes the minimum value of x given by _____________
23. If m is the minimum value of 2 2, 4 6f x y x x y y when x and y are subjected to the
restrictions ___________
24. Let y y x be the solution of differential equation sin cos 4 , 0, .dy
x y x x xdx
If
20,2 6 9
ky then y k
25. If y y x satisfies the differential equation
8 9 4 9 , 0, 0 7 256x x dy x dx x and y then y
SECTION – I
(SINGLE CORRECT ANSWER TYPE) This section contains 20 multiple choice questions. Each question has 4 options (1), (2),
(3) and (4) for its answer, out of which ONLY ONE option can be correct.
Marking scheme: +4 for correct answer, 0 if not attempted and -1 if not correct.
PHYSICS
SYLLABUS: Electro magnetism, EMI and AC
26. The magnetic field intensity at the point ‘0’ of a loop with current i, whose shape is illustrated
below is
A) 0 3 2
4 2
i
a b
B) 0
2
2
4
ib
a
C) 0 1 1
2
i
a b
D) 0 1 1
4
i
a b
S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A
Page | 5 SR:: JEE MAINS MODEL 07 – 06 – 2020
27. A square frame of side l carries a current. The magnetic field at its centre is B. The same
current is passed through a circular coil having the same perimeter as the square. The field at
the centre of the circular coil is 1.B The ratio of
1
B
B is
A) 8 2
B)
3
8 2
C)
8 2
D)
2
4 2
28. The oscillator frequency of a cyclotron is 10 MHZ . What should be the operating magnetic
field for accelerating proton?
A) 0.156T B) 0.256T C) 0.356T D) 0.656T
29. The radius of a circular current carrying coil is R. At what distance from the centre of the coil
on its axis, the in tensing of magnetic field will be 1
2 2times that at the centre?
A) 2 R B) 3
2
R C) R D)
2
R
30. A proton and an alpha particle entre the same magnetic field which is perpendicular to their
velocity. If they have same kinetic energy then ratio of radii of their circular path is
A) 1 : 1 B) 1 : 2 C) 2 : 1 D) 1 : 4
31. A galvanometer having a coil resistance of 60 shows full scale deflection when a current of
1.0 A passes through it. It can be converted into an ammeter to read currents up to 5.0 A by
A) putting in parallel a resistance of 15 B) putting in parallel a resistance of 240
C) putting in series a resistance of 15 D) putting in series a resistance of 240
32. If the planes of two identical concentric coils are perpendicular and magnetic moment of each
coil is then the resultant magnetic moment of the two coils will be
A) M B) 2 M C) 3 M D) 2M
33. Flux (in weber) in a closed circuit of resistance 10 various with time (in second) according to
the equation 26 5 1t t . What is the magnitude of the induced current at 0.25sect
A) 1.2 A B) 0.2 A C) 0.6 A D) 0.8 A
34. An aeroplane is flying horizontally with a velocity of 360km/h. The distance between the tips
of the wings of aeroplane is 25m. The vertical component of earth’s magnetic field is 4 24 10 /wb m . The induced e.m.f. is
A) 1 V B) 100 V C) 100 KV D) Zero
35. A coil of resistance 20 ohm and inductance 5H has been connected to a 100 volt battery. The
energy stored in coil is
A) 31.25 J B) 62.5 J C) 125 J D) 250 J
36. When the number of turns in a solenoid are doubled without any change in the length of the
solenoid, itself inductance becomes
A) Half B) Double C) 4 times D) 8 times
37. A flat coil of 500 turns, each of area 250 ,cm rotates in a uniform magnetic field of 20.14 /wb m
about an axis normal to the field at an angular speed of 150 / .rad s The coil has resistance of
15 . The induced e.m.f. is applied to an external resistance of 10 . The peak current
through the resistance is
A) 1.5 A B) 2.5 A C) 3.5 A D) 4.5 A
38. A conducting rod AB of length l is projected on frictionless frame PSRQ with velocity 0v at
any instant. The velocity of the rod after time t is
S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A
Page | 6 SR:: JEE MAINS MODEL 07 – 06 – 2020
A) 0v v B)
0v v C) 0v v D) None of these
39. A copper disc of radius 0.1m is rotated about its centre with 10 /rev s . In a uniform magnetic
field of 0.1T with its plane perpendicular to field. The e.m.f. induced across the radius of disc
is
A) 10
valt
B) 100
valt
C) 1000
valt
D) Zero
40. Figure shows an L R circuit. When the switch is s is closed, the current through resistors
A) 1 2 3 0I I I B) 1 2 3
1
, 0E
I I IR
C) 1 2 3
2 3
0, ,E E
I I IR R
D) 1 2 3
1 2 1 3 3
, ,E E E
I I IR R L R L
41. In a series RLC circuit, potential across R, L and C are 30 V, 60 V, 100 V respectively as
shown in figure. The e.m.f. of source (in volts) is
A) 190 B) 70 C) 50 D) 40
42. The reading of ammeter in the circuit
A) 2 A B) 3 A C) Zero D) 1 A
43. The mean value of current for half cycle for a current variation shown & by the graph is
A) 0
2
i B) 0i C) 0
3
i D) 0
3
i
S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A
Page | 7 SR:: JEE MAINS MODEL 07 – 06 – 2020
44. In a series RLC circuit, the r.m.s. voltage across the resistor and the inductor are respectively
400 V and 700 V. If the equation for the applied voltage is 500 2 sin t then the peak
voltage across the capacitor is,
A) 1200V B) 1200 2V C) 400V D) 400 2V
45. A step-up transformer operates on 220V line and supplies 2.2 A. The ratio of primary and
secondary winding is 11 : 50. The output voltage in the secondary is
A) 220V B) 100V C) 1000V D) 0V
SECTION- II
(Numerical Value Answer Type)
This section contains 5 questions. The answer to each question is a Numerical values
comprising of positive or negative decimal numbers. Each question has 4 options (1), (2), (3)
and (4) for its answer, out of which ONLY ONE option can be correct. Marking scheme: +4 for correct answer, 0 in all other cases.
46. A coil has resistance 30 and inductive reactance 20 at 50HZ frequency. If an AC source
of 200 valt, 100 HZ is connected across the coil, the current in the coil (in ampears) will be
________
47. With the decrease of current in the primary coil from 2A to zero in 0.01s, the e.m.f generated
in the secondary coil is 1000 V. The mutual inductance of the two coil is (in H) ________
48. The magnetic field of given length of wire for single turn coil at its center is B then its value
for two turns coil for the same wire interms of B is __________
49. A coil having 500 square loops each of side 10cm is placed with its plane perpendicular to a
magnetic field which increases at a rate of 1.0 tesla/s. The induced e.m.f. (in volts) is _______
50. In a coil of resistance 10 , the induced current developed bt changing magnetic flux through
it, is shown in fig as a function of time. The magnitude of change in flux through the coil in
weber is ____________
SECTION – I
(SINGLE CORRECT ANSWER TYPE) This section contains 20 multiple choice questions. Each question has 4 options (1), (2),
(3) and (4) for its answer, out of which ONLY ONE option can be correct.
Marking scheme: +4 for correct answer, 0 if not attempted and -1 if not correct.
CHEMISTRY
SYLLABUS: Chemical properties of Alcohols and Amines, conversions of Alcohols and Aldehyde
S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A
Page | 8 SR:: JEE MAINS MODEL 07 – 06 – 2020
51. Arrange the reactivity of given four alcohols in decreasing order for hydration
A) A>B>C>D B) D>C>B>A C) C>B>D>A D) B>C>A>D
52. 0.037 g of an alcohol R OH was added to 3CH MgBr and the gas evolved measured of 11.2 ml
at STP the molecular mass of R OH will be
A) 47 B) 79 C) 74 D) 77
53.
What is B in the above conversion?
54. ________ formed when methyl amine is treated with chloroform and alcoholic solution of
potassium hydroxide.
A) 3 3CH CH B) 3CH CN C) 3CH COOH D) 3CH NC
55. Which one of the following oxidizing agent is suitable to oxidizing 03 alchohol
A) Alkaline 4KMnO B) Neutral
4KMnO C) chromic acid D) Acidified 4KMnO
56. In the reaction 2 2
2 5 2 ;NaNO H O
HClC H NH Y
unstable
Y is
A) 2 5 2C H N Cl B) 2 5C H Cl C) 2 5C H OH D) 2 6C H
57. 3 2 ;PCC OHCH CH OH A B
What is B in the above conversion?
A) 2 2CH CH B) 3CH CHO
C) 3 2CH CH OH D) 3 2CH CH OH CH CHO
58. An organic compound 3 3CH CH OH CH on treatment with acidified 2 2 7K Cr O gives a
compound ‘Y’ which reacts with 2I and sodium carbonate to form tri iodo methane. The
compound ‘Y’ is
A) 3CH OH B) 3 3CH COCH C) 3CH CHO D) 3 3CH CH OH CH
S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A
Page | 9 SR:: JEE MAINS MODEL 07 – 06 – 2020
59. is
60. For the conversion of Aniline to N-methyl aniline, the reagent used is
A) 3CH I B) 2 5C H Cl C) 4CH D)
6 5C H Cr
61. What is the end product is the following sequence of reactions?
5 32
2 3 2
PCl NHHNOC H NH A B C
A) Ethyl cyanide B) Methyl amine C) Acetamide D) Ethyl amine
62. 3 2 2
3 2
CH CO O Br H
CH COOH H OA B C
What is ‘C’?
A) B)
C) D)
63. The reagent which is easily converts alcohol to carboxylic acid is
A) PCC B) Anhydrous 3CrO C) / 573Cu K D) 4 /KMnO H
64. ?
2 2 2 2 2 2R CH CH OH RCH CH CH NH
Identify the sequence of the reagents in order to carry out the above conversion.
A) 3 4i PBr ii KCN iii LiAlH B) 3 2i PBr ii KCN iii H
C) 3 4i HCN ii PBr iii LiAlH D) 4i HCN ii LiAlH
S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A
Page | 10 SR:: JEE MAINS MODEL 07 – 06 – 2020
65. Which of the following product is formed in the given reaction?
NH2
2 2/
2 ?Br H O
Br
A)
NH2
Br
B)
NH2
Br C)
NH2
Br
BrBr
D) Both A and B
66. Dehydration of alcohols is an example of ____________
A) Bimolecular elimination/E2 reaction B) SN2 reaction
C) SN1 reaction D) Unimolecular elimination/E1 reaction
67. Compound ‘A’ undergoes formation of cyanohydrins which on hydrolysis gives lactic acid
3CH CHOHCOOH therefore compound ‘A’ is
A) Formaldehyde B) Acetaldehyde C) acetone D) benzaldehyde
68. Compounds A and C in the following reaction
3
23
CH MgBr
H OCH CHO A 2 4H SO
Hydroboration
oxidation CB
A) Identical B) position isomers C) functional isomers D) optical isomers
69. In the given reaction:
6 5 6 5 2 2 2C H CH CH CHO C H CH CH CH OH
will be
A) 4NaBH B) Aluminium isopropoxide
C) 4LiAlH D)
4KMnO
70. Which one of the following will not NOT give carbylamine reaction?
A) 2 2 2CH CH CH NH B) 6 5 2C H NH
C)
NH2
D) 6 5C H NH R
SECTION-II
(Numerical Value Answer Type)
This section contains 5 questions. The answer to each question is a Numerical values
comprising of positive or negative decimal numbers. Each question has 4 options (1), (2), (3)
and (4) for its answer, out of which ONLY ONE option can be correct. Marking scheme: +4 for correct answer, 0 in all other cases.
71. Among the following the number of alcohols showing iodoform test is
3 3 2 3 32 3
3 2 2 2 3 2 3 3 2 2
2 5 3 32 2
, , , ,
, ,
,
CH OH CH CH OH CH CHOH CH C OH
CH CH CH CH OH CH CHOHCH CH CH CH CH OH
C H CHOH CH CHOHCH CH
S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A
Page | 11 SR:: JEE MAINS MODEL 07 – 06 – 2020
72. How many of the following amines can give carbylamine reaction?
NH2
,
N
H ,
N
3CH
,
N
H
3CH
,
PH
2NH
H
3H C
,
2NH
73. Of the following amines how many can be separated by Hoffmann’s mustard oil reaction?
2NH,
N
H
3CH
, 2NH,
N
3CH
PH
3CH
2NHPH
,
2NH2CH -
,
NPH
H
74. In the following reaction 6.0g of 3CH COOH reacts with 4.6g of 3 2CH CH OH .
3 3 2 3 2 5 2CH COOH CH CH OH CH COOC H H O the amount (in grams) of water formed is
____
75. Alcoholic group at _______ position reacts fastest with Lucas’ reagent.
OH
5
OH
4
3
OH
2
1
S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A
Page | 12 SR:: JEE MAINS MODEL 07 – 06 – 2020
SRIGAYATRI EDUCATIONAL INSTITUTIONS
INDIA
OUTGOING SR Date: 07-06-2020 Time: 3 Hours Max. Marks: 300 M
KEY SHEET MATHEMATICS
1) 3 2) 2 3) 4 4) 1 5) 3 6) 1 7) 4 8) 4 9) 1 10) 4
11) 1 12) 2 13) 2 14) 3 15) 4 16) 2 17) 1 18) 1 19) 1 20) 2
21) 2 22) 3 23) 3 24) 8 25) 3
PHYSICS
26) 1 27) 1 28) 4 29) 3 30) 1 31) 1 32) 4 33) 2 34) 1 35) 2
36) 3 37) 3 38) 3 39) 2 40) 2 41) 3 42) 1 43) 1 44) 4 45) 3
46) 4 47) 5 48) 4 49) 4 50) 2
CHEMISTRY
51) 3 52) 3 53) 2 54) 4 55) 4 56) 3 57) 4 58) 2 59) 3 60) 1
61) 4 62) 3 63) 4 64) 1 65) 3 66) 4 67) 2 68) 2 69) 3 70) 4
71) 4 72) 3 73) 4 74) 1.8
or
1.80
75) 3
HINTS & SOLUTIONS
MATHEMATICS
1. 2 2sin cosy xand y x solving
2 2 3sin cos , .
4 4x x x
Graph of functions is as shown in the following figure.
JEE MAINS MODEL UT-III
S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A
Page | 13 SR:: JEE MAINS MODEL 07 – 06 – 2020
From the figure, the required are
3 3
4 42 2
4 4
3
4
4
sin cos cos 2
sin 2 11 1 1
2 2
x x dx xdx
x
2. 2y x is upward parabola0
0
x xy x
x x
The graph of the function is as shown in the following figure.
2
0,1, 1
x x
x
11 3 3
2 2
0 0
22 2
3 3
2.
3
xA x x dx x
sq unit
3. The graph of the function is as shown in the following figure.
1
0
1
0
1
2
1 1
12
x x
x x
A e e dx
e e
e e
ee
S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A
Page | 14 SR:: JEE MAINS MODEL 07 – 06 – 2020
4. Graph of the functions is as shown
in the following figure.
A=Area quarter of circle-(Area bounded by
sin 0 )2
y x and x axisbetween x and x
2
3
12
4
8
4
5.
2
2
2
2
cos 3 cos
sin 3 sin
sin 1 3 1 sin
4sin 2
1sin
2 6
k
k
k
k
xdx xdx
x x
k k
k
k k
6.
1 2 3
324 1
324
1 cos 2 1 cos 2cos 2
2 2
cos 22 2
2 2
cos 2
x xy c x c c
ccc y c x
ccc
y A B x
There are two independent parameters.
The order of D.E is 2.
7.
2 2 2
2
2
2
3
1 1 11
11
1
1 1log
2 1 3
dy dyx y x dx
dx y
dy x dxy
y xx c
y
S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A
Page | 15 SR:: JEE MAINS MODEL 07 – 06 – 2020
8.
2 1
1 11 1
log .
It passes through 0,0
1
x c x c
c x x
x x
x x
x
dy dpy y Let p p
dx dx
dp dx dp dxp p
p x c p e p e e
Let e k p e k p ke
dyke dy ke dx
dx
dy k e dx y ke
k
y k e
9.
2
2
2
2
2
-1
1
1 0
1
1 11
1
integrating tan log
tan log 0
dx x xput x vy
dy y y
dx dv dvv y v y v v
dy dy dy
dvy v dv dy
dy v y
v c y
xy c
y
10.
1
2
2dt 2 2t 2 2
2
2
2 1
2
2
2 is linear differential equation
If=e .solution is y e 2 .
2 0 2 0, 2
2 2 2
put 1 1 2 2
41
t
t t t
t
t
y t y t
e
e c e e dt
y e c t y put t y
c y e t
t y e
ye
11.
3 1 2
1 3
3 3
1 1 3
0 is decreasing for all x. Now 1- 1 52
1 5 1 5
1 1 5 4 0
2 2 0
f x x x f x x
f x x R f x f x f x f
f f x f x f x x
x x x x x
x x x
2,0 2,x
S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A
Page | 16 SR:: JEE MAINS MODEL 07 – 06 – 2020
12.
2
22
2 2
22 22
22
2
2
2 3 3 2
23 2
3
22
3 3
23 2 12
3 3
0 0, 6
3 2 6 6 3
3
At 6 , 12 0
4
minimum at / min 6 4
ab a b ab b a
ab a a b
a
a aLet z ab a
a a
a baa a adz
da a a
dza a
da
a a a a ad z
da a
a d zz
b da
has a b a b
24
13.
22
2
2
22
8
, 8
8 1
2 2 8 1
2 16 2 4 16
4 0, 0
4 16 0 4
min 4
min 4 8 4 32
a b c d e f g h
Let a b c d x e f g h x
Let y x x
dyx x
dx
dyx x x
dx
d y dyNow
dx dx
x x
y has at x
y
14.
1 2 23 18 9 3 6 3 0
0, 0 . 36 12 0
3
f x kx x kx x
x R k i e k
k
15.
1 1cos cos3 03
11 0 2
2
f x a x x f
a a
16. The maximum value of cos cos 2f x x x
Occurs when
cos 1 cos 2 1 2 ,
2 2 , . comparing the value of ,
22 0, 0
2
0 .
x and x x x n z and
x m m z x
mm m n
x only
S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A
Page | 17 SR:: JEE MAINS MODEL 07 – 06 – 2020
17.
2
2
2 2
is increasing and g is decreasing in R.
f g 2 3 4
2 3 4
2 3 4 5 4 0
1,4
Given f
f g
g g
18.
2
2
2
2 2 2
2
1 tantan
1 tan
2 tancos 2 , sin 2
1 tan
1 1,
1 .
Let t x
x y
x y r Area r
sq units
19.
2 2
2 2 2
2
2
16Thearea bounded by 4 4
3
1 11
4 4Thearea bounded by 33
1 1 11
3 3 3
10
3
aby ax and x by is
bx y a ay x is aa a
Given a aa
a a
20.
2
2 2
22
2 2
2
2
Applying componendo & dividendo
dy
dx
2
22
2 1
x x
x x
x x
x x
xx
x
x xdx
xx
x x
e edx dy
e e dx dy
e e dx dy
e e dx dy
ee
e
dy e dx dy e
ey k y e c
y e ce
21.
1
log
2 2
1 2
1Now general solution by
2 1
1 12,
1, 1 2
2 2 2 2 2 2 2 2
dxx
x
dyy x If e
dx x x
ex
yc x dx
x x x
y putyx c
x x x y c
y x x y
S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A
Page | 18 SR:: JEE MAINS MODEL 07 – 06 – 2020
22.
2 2 2 2
2 1
1 11
1 2 3 4
5 2 1 2 3 4 5 2 5 15
0 3 10 0
min 3
f x x x a x
x f x x x x x x x
f x x and f x
x f x is for x
23.
2 2
2 2
1
, 4 6
, cos ,sin 0,2
, cos sin
4cos 6sin 1 4cos 6sin
6cos 4sin 0 0,2
is strictly increasing in 0,2
0 1 4
min 3
3 3
f x y x y x y
Let x y then
and f x y f
f
f
f f
f
m m
24.
2
2 2
22
2 2
22
2
sin cos 4
sin 4 Integrating we get
sin 2
,0 0 22 4 2
sin 22
6
12
2 36 2
436
88
6 9
xdy y xdx x
d y x xdx
y x x c passes through
c c
y x x
Put x
y
y
y k
S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A
Page | 19 SR:: JEE MAINS MODEL 07 – 06 – 2020
25.
2
2
12 2
19 2
2
4 9
8 9 4 4 9
12 Integrating
4
2 2 4
4 9 12
0, 7
7 7 02
4 9
256 4 9 256 3
Put x t dx tdtx
dx t t dt
t t dy t t t dt
dy dtt
y t c
cy x
Put x y
cc
y x
y
PHYSICS
26.
00 01
0 02
to square part:-
to side OA and OC
will be zero at point OB due to
side AB and BC will be equal. So,
B 2 sin 45 04 2 2
to circular part
3
32
2 2 8
B due
B due
i i
b b
B due
i iB
a a
1 2 0
0
3 1
8 2 2
3 2
4 2
net
net
B B B ia b
iB
a b
S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A
Page | 20 SR :: JEE MAINS MODEL 07-06-2020
27. 2
lOD
0 00
0
1 0 0
1 0
2
1
4 sin 45 sin 45
42
2 2
For circle 2 r=4
2
222
4
8
iB
l
iB
l
l
i ilr so B
lr
iB
l
Bso
B
28.
196
27
2
2
1.6 1010 10
2 1.6 10
0.656
qB mf T
m qB
B
B T
29.
2
0 0
32 2 2
33 2 2 2
23 2 2 2
2 2 2 2
1
22 22
2 2
2 2
2
iR i
RR x
R R x
R R x
x R R R
x R
30.
2.
1 21:1
4 1
p p
p
mkr here k is same
qB
mso r
q
r m q
r m q
S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A
Page | 21 SR :: JEE MAINS MODEL 07-06-2020
31. 60
155
1 11
g
s
g
RR
i
i
32. 2 2
2
netM M M
M
33.
26 5 1
12 5
112 5
40.2
10
t t
dt
dt
I AR
34. 4 54 10 360 25
18
Blu
IV
35. 22
1005
20
1 15 5
2 2
62.5
I A
Li
J
36.
2
1
1
2
4
L n
soif n n
L L
37.
2 2500, 50 , 0.14 /
150 / , 5 2
3.5
man
manman
N A cm B wb m
w rod s R
NBAW
I AR
38. The rod will experience magnetic for i.e in the direction
Opposite to initial force. So velocity will decrease with time.
39.
2
2
1, 0.1 , 0.1
2
20 /
10.1 0.1 20
2
100
BWR R m B J
w rod s
volt
40. 1 2 3
1
0,inductor offers intinite resistance
so I , 0
At t
EI I
R
S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A
Page | 22 SR :: JEE MAINS MODEL 07-06-2020
41.
22
2 2
2 2
. .
30 100 60
. . 30 40 50
rms R L ce m f v v v v
e m f V
42.
22
255 55
110
55
2
cz R x
z
V IZ
I
I A
43.
/ 2
0
0
0
22 2
00
0 0
2
02
0
2
0 straight line.2
so the function I
2
2
22 2 2
2
4 10
2 4
2
J
mean
T T
mean
Idt
IT
TFrom tp graph is
iwill be t
J
it
T
i tso I t dt i
T T T T
Ti
T
i
S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A
Page | 23 SR :: JEE MAINS MODEL 07-06-2020
44.
2
0 2
22
2 2 2
2
2
500 2 sin
400 , 700
500500
2 2
500 400
250000 16000
90000
300
700 300
400
2 400 2
R
rms
rms R L c
L c
L c
L c
L c
c
c
c rms
wt
V V V V
VV
V V V
V V
V V
V V
V V
V
V V
V V V
45.
50
220 10011
P P
S S
S Ps
P
N V
N V
N VV
N
v
46.
2 22 2
20 100
1
5
12 100 40
5
30
30 40 50
2004
50
L
L
L
L
WL
and R
Z R X
I A
47.
21000
0.01
110 5
2
Mi
d diM
dt dt
M
M
S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A
Page | 24 SR :: JEE MAINS MODEL 07-06-2020
48.
0
1 0
0
1
2
2
22
42
4
4
iB N
R
iB N
R
iN
R
B B
49. 2
500 0.1 1
5
dBNA
dt
V
50.
.
10.1 4 2
2
It R
I t R
or d Idt R
Total flux R Idt
idt represents area under it curve
so R
CHEMISTRY
51. Nearer is the –I group to the alcoholic group, greater is it reactivity for dehydration.
.
52. 3 4R OH CH MgBr CH Mg
Br
OR
4
4
1 1
22400
11.2 is formed by 0.037g ROH
22400 ml is formed by?
22400 0.03774
11.2
mole mole
ml STP
ml CH
CH
53.
54. 3 2 3 3 2CH 3 3 3NH CHCl KOH CH NC KCl H O
55. Only with strong acidic oxidizing agent like acidified
4 3KMnO and conc HNO is used because first it has to
S R I G A Y A T R I E D U C A T I O N A L I N S T I T U T I O N S - I N D I A
Page | 25 SR :: JEE MAINS MODEL 07-06-2020
Undergo elimination to alkene and then oxidation.
56. Alcohol is obtained for when an 01 amine is treated with
2 /NaNO HCl .
57.
1
3 2 3 3 2
PCC OHCH CH OH CH CHO CH CH OH CH CHO
Aldol Aldol
condensation
58. Secondary alcohols on oxidation gives ketones.
59.
60. Alkylation with 3CH I , Aniline gives N-methyl aniline.
61.
62. Acetylation protects amino group and bromination
occurs at ortho position to amino group.
63. Strong oxidizing agents such as acidified 4KMnO are used for getting carboxylic acids from alcohols
directly.
64.
2 2 3 2 2
2 2 2 2
2 2 4 2 2 2 2
i RCH CH OH PBr R CH CH Br
ii RCH CH Br KCN RCH CH CN
iii RCH CH CN LiAlH RCH CH CH NH
65. Aniline reacts with bromine water at room temperature to give a white precipitate of 2,4,6-
tribomoaniline.
66. Dehydration of alcohols is an example of unimolecular elimination reaction (E1)
67.
3
3 3 3
H OHCNCH CHO CH CH CN CH CH COOH
lactic acid
OH OH
68.
3 2 4
23 3 3 3 2 3 2 2
Hydroborationi CH MgBr H SO oxidation
ii H OCH CHO CH CH CH CH CH CH CH CH CH CH
OH
I
A B C
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Page | 26 SR :: JEE MAINS MODEL 07-06-2020
69. 4LiAlH is good reducing agent for unsaturated aldehyde to change to an alcohol.
70. 02 amines will not give carbylamines reaction.
71.
4
4 6 64
5
100 5 0.52 0.1
100 0.262 100.262
b b
b
b
T i k m
K fe CN K Fe CN
i
T
T
72.
1
0
0
. .
1 ( 1) 2
1 1 0.3 1.3
.
. 0 .
e
e
Tf i kf m
HX H X
l n n
l
T Tf ikf m
Tf T ikf m i kf m
ikfm
73. 1 , 0.542
xi i
74. Electrodes with low S.R.P is always taken as Anode(L.H.S)
75. 1 2
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