NCERT Exemplar Solutions For Grade 8 Mathematics Chapter ...
-
Upload
khangminh22 -
Category
Documents
-
view
3 -
download
0
Transcript of NCERT Exemplar Solutions For Grade 8 Mathematics Chapter ...
Class VIII Mathematics www.vedantu.com 1
NCERT Exemplar Solutions For Grade 8
Mathematics
Chapter 9.- Comparing Quantities
(B) Solved Examples
In examples 1 to 4, there are four options out of which one is correct. Write the
correct answer.
1. A shirt with marked price Rs 800 was sold at Rs 680. The rate of discount on
the shirt is
(a) 10%
(b) 15%
(c) 20%
(d) 10%
Ans: here, we have marked price (M.P) = Rs 800
And Selling price (S.P) = Rs 680
Thus, discount = M.P - S.P
800 680
= Rs 120
Now, Rate of discount Discount
= ×100M.P
120100
800
15 %
Hence, option (b) is the correct answer.
Class VIII Mathematics www.vedantu.com 2
2. If 7
%3
of a number is 42, then the number is
(a) 9800
(b) 8
(c) 1800
(d) 180
Ans: Let required number be .x
Now, according to question,
⇒7
%3
of x = 42
⇒7
3
1
100x = 42
⇒ x = 42 100 3
7
⇒ x = 1800
Hence, option (c) is the correct answer.
3. If the cost price of 10 shirts is equal to the selling price of 8 shirts, then which
of the following is true for the transaction?
(a) Profit of 25%
(b) Loss of 25%
(c) Profit of 20%
(d) Loss of 20%
Ans: here, we have the cost price of 10 shirts is equal to the selling price of 8 shirts.
⇒10 8 CP SP
Class VIII Mathematics www.vedantu.com 3
⇒8
10
CP SP
⇒4
5
CP
SP
Here, SP > CP, thus there will be profit
⇒ Profit % = . .
100 %.
S P C P
C P
=
4. .
5 100 %4
.5
S P S P
S P
=
1
5 100 %4
5
= 1
100 %4
= 25 %
Hence, option (a) is the correct answer.
4. Rs 1600 lent at a compound interest of 5 % per annum, compounded half
yearly for one year will amount to:
(a) Rs 1640
(b) Rs 1680
(c) Rs 1681
(d) Rs 1764
Ans: here, Principle (P) = Rs 1600
Class VIII Mathematics www.vedantu.com 4
⇒ rate of interest (R) = 5
2 % and time (t) = 1 year. So, n = 2
Now, Amount (A) = 1100
n
RP
=
2
51600 1
2 100
=
2
11600 1
40
=
2
411600
40
= 1681
16001600
= Rs 1681
Hence, option (c) is the correct answer.
In examples 5 to 7, fill in the blanks to make the statements true.
5. By selling 50 pens, a shopkeeper lost the amount equal to the selling price of 10
pens. His loss per cent is ………
Ans: let selling price of one pen is .Rs x
So, total selling price (S.P) = Rs 50x
And loss = Rs 10x
Thus, total cost price (C.P) = S.P + loss
= 50x + 10x
= 60x
Now, % loss 100 %loss
CP
Class VIII Mathematics www.vedantu.com 5
10 100 %60
x
x
1 100 %6
50 %3
Hence, by selling 50 pens, a shopkeeper lost the amount equal to the selling price of
10 pens. His loss per cent is 50
%.3
6. The discount per cent is calculated on the ……… price of an article.
Ans: As we know that the discount per cent is calculated on the Marked price of an
article.
7. Amna purchased a toy for Rs 660 including sales tax. If the rate of sales tax is
10 %, then the selling price of the toy is …….
Ans: Let the selling price of the toy be .Rs x
And the rate of sales tax = 10 %
Now, according to question
⇒1
10 660100
x x
⇒ 66010
xx
⇒11
66010
x
⇒ 6010
x
⇒ 600x Rs
Class VIII Mathematics www.vedantu.com 6
Hence, Amna purchased a toy for Rs 660 including sales tax. If the rate of sales tax is
10 %, then the selling price of the toy is Rs 600.
In Examples 8 to 11, state whether the statements are true (T) or false (F).
8. When the interest is compounded half yearly, the number of conversion
periods in a year is four.
Ans:As we know that when the interest is compounded half yearly, the number of
conversion periods in a year is two.
Hence, the given statement is False.
9. Arnav buys a book costing Rs 600. If the rate of sales tax is 7 %, then the total
amount payable by him is Rs 642.
Ans: here, cost price = Rs 600
And sales tax = 1
600 7 42100
Rs
Thus, payable amount = C.P + sales tax
= Rs 600 + Rs 42
= Rs 642
Hence, the given statement is True.
10. After allowing a discount of 15 % on the marked price of an article, it is sold
for Rs 680. The marked price of the article is Rs 800.
Ans:let the marked price of article be Rs .x
Now, according to question
⇒ 15 % 680x of x
Class VIII Mathematics www.vedantu.com 7
⇒1
15 680100
x x
⇒3 68020
xx
⇒17 68020
x
⇒ 4020
x
⇒ 800x Rs
Hence, the given statement is True.
11. Overhead charges, if any, are sometimes included in the cost price.
Ans: As we know that the cost price is the total amount of money that is it costs a
manufacture to produce a given article. It is the original cost of product. It does not
any include any overhead charges.
Hence, the given statement is False.
12. A number is increased by 20% and then it is decreased by 20%. Find the net
increase or decrease percent.
Ans: Let the required number be 100
Now, increase in the number = 20 % of 100 = 1
20 100 20100
So, increased number = 100 + 20 = 120
Decrease in the number = 20 % of 120 = 1
20 120 24100
So, decreased number = 120 24 96
Net decrease = 100 96 4
Class VIII Mathematics www.vedantu.com 8
Thus, net decrease percent = 4
100 % 4 %100
Hence, the net decrease percent is 4.
13.Vishakha offers a discount of 20 % on all the items at her shop and still makes
a profit of 12 %. What is the cost price of an article marked at Rs 280?
Ans: here, we have marked price (M.P) = Rs 280
And discount = 20% of Rs 2801
20 280 56100
Rs
So, selling price (S.P) = Rs 280 56 224Rs
Let the cost price (C.P) be Rs 100.
And profit = 12 % of 100 = 1
12 100 1 2100
Rs
So, selling price (S.P) = Rs 100 12 1 12Rs
Thus, if the selling price is Rs 112, then cost price = Rs 100
If the selling price is Rs 224, cost price = Rs 100
224 200112
Rs
Hence, the required cost price is Rs 200.
14. Find the compound interest on Rs 48,000 for one year at 8 % per annum
when compounded half yearly.
Ans: here, Principal (P) = Rs 48,000
⇒ Rate (R) 8
% 4 %2
and time period (n) = 2
Now, 1100
n
RA P
Class VIII Mathematics www.vedantu.com 9
⇒
2
448,000 1
100A
⇒
2
148,000 1
25A
⇒
2
2648,000
25A
⇒676
48,000625
A
⇒ 51,916.80 A Rs
Thus, compound interest (C.I) A P
51,916.80 48000Rs Rs
3,916.80Rs
Hence, the required compound interest is 3,916.80.Rs
15. Lemons were bought at Rs 60 a dozen and sold at the rate of Rs 40 per 10.
Find the gain or loss percent.
Ans: here, C.P of 1 dozen lemons = Rs 60
.C P of 1 lemon = Rs 60
512
Rs
Thus, C.P of 10 lemons = Rs 50
And S.P of 10 lemons = Rs 40
Here, C.P > S.P, it means there will be loss.
Now, % loss . .
100 %.
C P S P
C P
50 40100 %
50
Class VIII Mathematics www.vedantu.com 10
10100 %
50
20 %
Hence, the required loss percent is 20 %.
Multiple Choice Questions
1. Suppose for the principal P, rate R% and time T, the simple interest is S and
compound interest is C. Consider the possibilities
(i) C>S
(ii) C = S
(iii) C <S Then,
(a) only (i) is correct (b) either (i) or (ii) is correct
(c) either (ii) or (iii) is correct (d) only (iii) is correct
Ans:(a) Let the principal (P) = Rs. 100
Rate of interest (R) = 100% and time period (T) = 2 yr
Then, simple interest =
100
Px R xT =
100 1 0 2
100
x x = Rs20
We know that ,
A = 1 100
T
RP
A = 100 x 11
10 x
11
10 = Rs 121
Compound Interest = A - P = Rs121 - Rs100 = Rs21
so , C > S
Therefore , the correct option is (a).
Class VIII Mathematics www.vedantu.com 11
2. Suppose a certain sum doubles in 2 yr at r% rate of simple interest per annum
and R°/o rate of interest per annum compounded annually. Then,
(a) r < R
(b) R < r
(c)R = r
(d) Cannot be determined
Ans: If the total amount received after 2 yr is the same for both simple interest and
compound interest on the same principal, then the rate of simple interest is greater than
the rate of compound interest.
Hence , R< r
Hence, option (b) is correct.
3. The compound interest on Rs. 50000 at 4% per annum for 2 yr compounded
annually is
(a) Rs. 4000
(b) Rs. 4080
(c) Rs. 4280
(d) Rs. 4050
Ans: Principal (P) = Rs. 50000
Rate of interest (R%) = 4% per annum
Time period (T) = 2 yr
We know that,
A = 1 100
T
RP
Class VIII Mathematics www.vedantu.com 12
=
2
4 50000 1
100
=
2
1 50000 1
25
= 50000×26
25×
26
25 = Rs54080
Compound Interest (CI) = A - P = Rs 54080 - Rs 50000 = Rs 4080
Hence the correct option is (b)
4. If marked price of an article is Rs. 1200 and the discount is 12%, then the
selling price of the article is
(a)Rs. 1056
(b) Rs. 1344
(c) Rs. 1212
(d)Rs.1188
Ans: Marked price of an article = Rs. 1200
Discount % = 12%
Discount selling price = Discount % x marked price
= 12
100x 1200=12 x 12 = Rs.144
Selling price = Marked price – Discount Selling price
= Rs.11200 – Rs. 144
= Rs.1056
Hence the correct option is (a).
Class VIII Mathematics www.vedantu.com 13
5. If 90% of x is 315 km, then the value of x is
(a) 325 km
(b) 350 km
(c) 350 m
Ans: We have, 90% of x = 315 km
90
100 x = 315
x = 315 10
9
x = 350
Hence the correct option is (b)
6.To gain 25% after allowing a discount of 10%, the shopkeeper must mark the
price of the article which cost him Rs. 360 as
(a) Rs. 500
(b) Rs. 450
(c) Rs. 460
(d) Rs. 486
Ans: Let the marked price of the article be Rs. x.
Cost price of the article = Rs. 360
According to the question,
x - x of 10% - 25 360
100
= 360
x -
10
x - 90 = 360
Class VIII Mathematics www.vedantu.com 14
9
10
x = 450
x = 450 10
9
x = 500
So, the Market Price is Rs 500.
Hence the correct option is (a)
7. If a% is the discount percent on marked price x, then discount is
(a) x
a
(b) a
x
(c) ax
100
(d) 100
xa
Ans: We know that discount can be calculated always on marked price, when
discount percentage is given.
Discount = Discount % on marked price = a% of x
Discount =
100
ax
Hence, option (c) is correct.
8. Ashima took a loan of Rs. 100000 at 12% per annum compounded half-yearly.
She paid Rs. 112360. If (1.06)2 is equal to 1.1236, then the period for which she
took the loan is
Class VIII Mathematics www.vedantu.com 15
(a) 2 yr
(b) 1 yr
(c) 6 months
(d) 11
2
Ans: Principal (P) = Rs.100000
Rate of interest (R%) = 12% per annum compounded half-yearly.
Let m be the time period
Amount paid = Rs.112360
We know that,
Amount, when interest is compounded half - yearly
i.e. A =
2
1 200
n
RP
, where n = time period
112360 = 100000
2
12 1
200
m
P
2
53
50
m
= 112360
100000
2
53
50
n
= 2809
2500
2
53
50
=
2
53
50
n
On comparing both sides , we get
2n = 2
n = 1
So the time period is 1yr
Class VIII Mathematics www.vedantu.com 16
Hence option (b) is correct .
9 For calculation of interest compounded half-yearly, keeping the principal the
same, which one of the following is true?
(a) Double the given annual rate and half the given number of years
(b) Double the given annual rate as well as the given number of years
(c) Half the given annual rate as well as the given number of years
(d) Half the given annual rate and double the given number of years
Ans: If interest is compounded half-yearly, then R becomes 2
R and T becomes 2T
and 2T = 2nSo, we have
2
1 200
n
RP
C = A-P
So, half the given annual rate and double the given number of years.
Hence, option (d) is correct.
10. Shyama purchases a scooter costing Rs. 36450 and the rate of sales tax is 9%,
then the total amount paid by her is
(a) Rs. 36490.50
(b) Rs. 39730.50
(c) Rs. 36454.50
(d) Rs. 33169.50
Ans: We know that sales tax is charged on the sale of an item by the government and
is added to the bill amount.
Shyama purchase a scooter of costing = Rs. 36450 Sales tax paid =9%
Class VIII Mathematics www.vedantu.com 17
So, total amount paid by her
= Rs. 36450 of 9% + Rs. 36450
= 9
100× 36450 + 36450
= 9 × 364.5 + 36450 = 3280.5 + 36450 = Rs. 39730.5
Hence, option (b) is correct.
11 The marked price of an article is Rs. 80 and it is sold at Rs. 76, then the
discount rate is
(a) 5%
(b) 95%
(c) 10%
(d) approx 11 %
Ans: The marked price of an article = Rs. 80
Sold price of the article = Rs. 76
We know that,
Selling price = Marked price – Discount Discount
Marked price – Selling price
Discount = Rs.80-Rs.76 = Rs.4
Discount % = 4
80×100 = 5%
Hence, option (a) is correct.
12. A bought a tape recorder for Rs. 8000 and sold it to B. B in turn sold it to C,
each earning a profit of 20%. Which of the following is true?
Class VIII Mathematics www.vedantu.com 18
(a) A and B earn the same profit
(b) A earns more profit than B
(c) A earns less profit than < 5
(d) Cannot be determined
Ans: Cost price of tape recorder for A = Rs.8000
Cost price of tape recorder for B =20% profit on cost price for A
= 20
100× 8000 + 8000
=20 × 80 + 8000
=1600 + 8000
=Rs.9600
Cost price of tape recorder for C=20% profit on cost price for B
= 20
100× 9600 + 9600
=1929 + 9600
=Rs.11520
Here, profit for A= Rs.1600
Profit for B = Rs.1920
So, A earns less profit than B.
Hence, option (c) is correct.
13. Latika bought a teapot for Rs. 120 and a set of cups for Rs. 400. She sold
teapots at a profit of 5% and cups at a loss of 5%. The amount received by her is
(a) Rs. 494
(b) Rs.7546
Class VIII Mathematics www.vedantu.com 19
(c) Rs. 506
(d) Rs. 534
Ans:Latika bought a teapot = Rs. 120
Set of cups = Rs. 400
She sold teapot at a profit of 5%,
So, selling price of teapot =5
100 x 120 + 120
= 120
20 +120
= 6 + 120 = Rs.126
Also, she sold cups at a loss of 5%.
So, selling price of cups = 400 –5
100 x 400
= 400 – 20 = Rs. 380
Total amount received by her = Rs. 126 + Rs. 380 = Rs. 506
Hence, option (c) is correct.
14. A jacket was sold for Rs. 1120 after allowing a discount of 20%. The marked
price of the jacket is
(a) Rs. 1440
(b) Rs. 1400
(c) Rs. 960
(d) Rs. 866.66
Ans: Let the marked price of the jacket be Rs. x.
Discount % on marked price = 20%
Class VIII Mathematics www.vedantu.com 20
Selling Price of jacket = Rs1120
Then ,
1120 = x - x 20
100
1120 = x - 5
x
4
5
x = 1120
x = Rs1400
So, market price of the jacket is Rs1400
Hence , option (b) is correct .
15. A sum is taken for two years at 16% per annum. If interest is .compounded
after every three months, the number of times for which interest is charged in 2
yrs is
(a) 8
(b)4
(c) 6
(d) 9
Ans: Here since the rate of interest is calculated after every three months. Similarly,
the time period for the amount in a year will be 4 times.
If the amount is taken for 2 yr, it means 4×2 = 8 times charged in 2 yr.
Hence the correct option is (a)
16 The original price of a washing machine which was bought for Rs. 13500
including of 8% VAT, is
Class VIII Mathematics www.vedantu.com 21
(a) Rs. 12420
(b) Rs. 14580
(c) Rs.12500
(d) Rs. 13492
Ans: The price of the washing machine = Rs.13500
VAT [Value Added Tax] is included in the selling price, which is 8%.
The original price of the washing machine including of 8% VAT
= 13500-13500 × 8
100
= 13500-135 × 8 = 13500-1080= Rs.12420
Hence, option (a) is correct.
17. Avinash bought an electric iron for Rs. 900 and sold it at a gain of 10%. He
sold another electric iron at 5% loss which was bought
Rs. 1200. On the transaction, he has a
(a) profit of Rs. 75
(b) loss of Rs. 75
(c) profit of Rs. 30
(d) loss of Rs. 30
Ans: Avinash bought an electric iron = Rs. 900
He sold it, at 10% profit.
So, selling price of the electric iron = 10
100× 900 + 900
= 90+ 900 = Rs. 990
He also sold another electric iron at a 5% loss.
Class VIII Mathematics www.vedantu.com 22
Cost price of another electric iron = Rs.1200
So, selling price of the electric iron = 1200
5
100× 1200
= 1200-60 = Rs.1140
Total amount paid by Avinash for purchasing electric irons = Rs. 900 + Rs.1200 =
Rs.2100
Total received amount = Rs. 990 + Rs. 1140
= Rs. 2130
So, his profit = Rs.2130- Rs.2100 = Rs.30 in transaction.
Hence, option (c) is correct.
18 A TV set was bought for t 26250 including 5% VAT. The original price of the
TV set is
(a) Rs. 27562.50
(b) Rs. 25000
(c) Rs. 24937.50
(d) Rs. 26245
Ans:Cost price of TV set = Rs. 26250.
VAT including = 5%
Original price = Cost price of article including VAT = 26250 - 5
100× 26250
= 26250-1312.5
= Rs. 24937.5
So, the original price of the TV set = Rs. 24937.5
Class VIII Mathematics www.vedantu.com 23
Hence, option (c) is correct.
19. 40% of [100 – 20% of 300] is equal to
(a) 20
(b) 16
(c) 140
(d) 64
Ans:40% of [100-20% of 300]
40
100 [100 -
20
100300]
40
100[100-60]
40
10040
16
Hence, option (c) is correct.
20. Radhika bought a car for Rs. 250000. Next year, its price decreased by 10%
and further next year, it decreased by 12%. In the two years, overall decrease per
cent in the price of the car is
(a) 3.2%
(b) 22%
(c) 20.8%
(d) 8%
Ans: Radhika bought a car for Rs. 250000.
Class VIII Mathematics www.vedantu.com 24
Cost price of a car = Rs.250000
Its price decreased next year by 10%.
So, Price becomes = 250000 - 10
100250000
= 250000 - 25000
= Rs225000
Next year , Price decreases by 12% , price becomes = 225000 - 10
100225000
= 225000 - 27000
=Rs198000
Overall decreased % in two years = 250000 1 980000
250000
100
= 20.8%
Hence the correct option is (c)
Fill in the blanks
21. ……………. is a reduction on the marked price of the article.
Ans:Discount is a reduction on the marked price of the article.
22. Increase of a number from 150 to 162 is equal to an increase of
………………..percent.
Ans:Initial number = 150
Final number = 162
Increased number = 162 -150 = 12
Class VIII Mathematics www.vedantu.com 25
Percent of increased number = 12
150 x 100 = 8%
Therefore , Increase of a number from 150 to 162 is equal to an increase of 8 percent.
23.15% increase in price of an article, which is Rs. 1620, is the increase of
……………..?
Ans:Let the price of the article be Rs. x.
It is given that after 15% increase in price , price became Rs1620
So, x + 15
100 x = 1620
x + 3
20 x = 1620
23
20
x = 1620
x = Rs1408
Increase in price = Rs1620 - Rs1408
= Rs212
Therefore, 15% increase in price of an article, which is Rs. 1620, is the increase Rs212
24.Discount =…………….
Ans:Discount = Market Price (MP) – Selling Price (SP)
Here, MP = Marked price, and SP = Selling price
25.Discount = Discount % of ……………
Ans:Discount = Discount % of marked price
Class VIII Mathematics www.vedantu.com 26
Discount is referred to a reduction given on marked price
26. ………is charged on the sale of an item by the government and is added to the
bill amount.
Ans:Sales tax is charged on the sale of an item by the government and is added to the
bill amount.
Sales tax = Tax % of bill amount
27. Amount when interest is compounded annually, is given by the
formula……………….
Ans: Amount when interest is compounded annually, is given by the formula
A = 1 100
T
RP
where, P = principal, R = rate per- annum and T = time
28. Sales tax = Tax% of……………….
Ans: Sales tax=Tax % of bill amount
29.The time period after which the interest is added each time to form a new
principal, is called the ……………
Ans: The time period after which the interest is added each time to form a new
principal, is called the conversion period.
30.……………… expenses are the additional expenses incurred by a buyer for an
item over and above its cost of purchase.
Ans:Overhead expenses are the additional expenses incurred by a buyer for an item
over and above its cost of purchase.
Class VIII Mathematics www.vedantu.com 27
31.The discount on an item for sale is calculated on the ……………..
Ans:The discount on an item for sale is calculated on the marked price.
32. When principal P is compounded semi-annually at r% per annum for t years,
then amount = ……………..
Ans:When principal P is compounded semi-annually at r% per annum for t years.
i.e Rate = 2
r and Time = 2t
Then , Amount (A) =
2
1 200
t Time
Rate rPrincipal P
A =
2
1 200
t
rP
33.Percentages are to fractions with ………………. equal to 100.
Ans:Percentages are equal to fractions with denominators equal to 100.
34. The marked price of an article when it is sold for 880 after a discount of
12%, is ……………..
Ans:Selling price of an article = Rs.880
Discount % = 12%
We know that, discount is calculated on the marked price.
Let the marked price be Rs. x.
x - 12
100 x = 880
88
100
x = 880
Class VIII Mathematics www.vedantu.com 28
x = Rs1000
Marked Price = Rs1000
Therefore , The marked price of an article when it is sold for 880 after a discount of
12%, is Rs1000.
35. The compound interest on Rs. 8000 for one year at 16% per annum
compounded half-yearly is …………… , given that 21.08 = 1.1664.
Ans:We have,
Principal(P) = Rs.8000
Time period = 1 yr
Rate = 16% per annum compounded half-yearly
A = 1 100
T
RP
A 20.16
(1 )2
P
A = 8000 21.08
A = 8000 21.08
A = 8000 1.1664
A = Rs9331.2
Therefore, The compound interest on Rs. 8000 for one year at 16% per annum
compounded half-yearly is Rs9331.2
36. In the first year on an investment of Rs 6,00,000 the loss is 5% and in the
second year the gain is 10%, the net result is _________.
Ans: Investment amount = Rs6,00,000
Loss in first year = 5%
Class VIII Mathematics www.vedantu.com 29
1st year Investment = 600000 - 5
100600000
= Rs570000
Net Investment when gain is 10% = 570000 +10
100 x 570000= 570000 + 57000
= Rs7627000
37.If amount on the principal of Rs 6,000 is written as 600(35
1 )100
and
compound interest payable half yearly, then rate of interest p.a. is _________ and
time in years is _________.
Ans:Here amount on the principal of 6000 is written as 600( 351 )
100
of and compound interest payable half-yearly, then rate of interest per annum is 10%
and time (in years) is 11
2yr.
38.By selling an article for Rs 1,12,000 a girl gains 40%. The cost price of the
article was _________.
Ans:Selling Price of Article = Rs 1,12,000
Gain% = 40%
Let the cost price of an article be x
x + 40% of x = Selling price of an article
x + 40
100x = 1,12,000
x + 2
5x= 1,12,000
Class VIII Mathematics www.vedantu.com 30
7
5x = 1,12,000
x = Rs 80,000
Therefore , By selling an article for Rs 1,12,000 a girl gains 40%. The cost price of the
article was Rs 80,000
39. The loss per cent on selling 140 geometry boxes at the loss of SP of 10
geometry boxes is equal to ………………..
Ans:Suppose, the selling price of 1 geometry box = 1.
Now, the selling price for 140 geometry boxes = 1 × 140 = Rs. 140
Similarly, selling price of 10 geometry boxes = 1 × 10 = Rs. 10
Loss = selling price of 10 geometry boxes = Rs. 10
So, loss percentage = Loss
CP x 100
By using this formula,
Loss percentage = 62
3%
Hence, The loss per cent on selling 140 geometry boxes at the loss of SP of 10
geometry boxes is equal to 62
3%
40. The cost price of 10 tables is equal to the sale price of 5 tables. The profit per
cent in this transaction is ……………..
Ans:Let the cost price of 1 table be Rs. 1.
The cost price of 10 tables = Sale price of 5 tables Profit
= Cost price of 5 tables
= Rs. 5
Class VIII Mathematics www.vedantu.com 31
Profit percentage = Profit
CP× 100 =
5
5× 100 = 100%
Hence, The cost price of 10 tables is equal to the sale price of 5 tables. The profit per
cent in this transaction is 100%
41.Abida bought 100 pens at the rate of Rs. 3.50 per pen and pays a sales tax of
4%. The total amount paid by Abida is ___________
Ans:Number of pens bought by Abida = 100
Rate of per pen = Rs.3.50 So, cost of 100 pens = 100 x 3.50 = 135
Abida also paid 4% sales tax on Rs. 350.
Hence ,the total amount paid by Abida = 350 x 4
100 + 350 = Rs 364
Therefore, Abida bought 100 pens at the rate of Rs. 3.50 per pen and pays a sales tax
of 4%. The total amount paid by Abidais Rs 364
42. The cost of a tape recorder is Rs. 10800 inclusive of sales tax charged at 8%.
The price of the tape recorder before sales tax was charged, is ……………….
Ans: Suppose the price of the tape recorder before sales tax be Rs. x.
The cost of a tape recorder , inclusive of sales tax charged at 8%. = Rs. 10800
According to the question
x + 8
100× x = 10800
108
100
x = 10800
x = Rs10,000
Class VIII Mathematics www.vedantu.com 32
Hence, The cost of a tape recorder is Rs. 10800 inclusive of sales tax charged at 8%.
The price of the tape recorder before sales tax was charged, is Rs10000
43. 2500 is greater than 500 by …………..%.
Ans:Difference between 2500 and 500 = 2500 – 500 = 2000
Greater % = 500
Difference× 100 =
2000
500×100 = 400%
Hence, 2500 is greater than 500 by 400%
44. Four times a number is a …………….% increase in the number.
Ans:Let the number be x
Four times of x = 4x.
Hence, 4x is greater than x by 4x – x = 3x
Percentage increase in x = 3x
x x 100 = 300%
45. 5% sales tax is charged on an article marked X 200 after allowing a discount
of 5%, then the amount payable is …………….
Ans:Given marked price of the article = 1200 Discount = 5%
Selling price = 200 – 5
100× 200 =200 -10 = Rs.190
Selling price (including 5% sales tax) = 190 + 5
100× 190= 190+ 9.5 = Rs.199.5
Amount to be paid = Rs. 199.50
Class VIII Mathematics www.vedantu.com 33
Therefore, 5% sales tax is charged on an article marked X 200 after allowing a
discount of 5%, then the amount payable is Rs. 199.50
State whether the statements are true (T) or false (F).
46. To calculate the growth of bacteria if the rate of growth is known, the formula
for calculation of amount in compound interest can be used.
Ans:For calculating the growth of a bacteria for the rate of growth is known, then
formula for calculation of amount in compound interest.where, A = growth after n
years, P = initial number of bacteria and R = rate of growth can be used .
Hence the given statement is true.
47.Additional expenses made after buying an article are included in the cost price
and are known as Value Added Tax.
Ans: The given statement is false. VAT is always included in the selling price.
Therefore, Value Added Tax is always added to the selling price.
48.Discount is a reduction given on the cost price of an article.
Ans: Discount is termed as the reduction given on market price of an article , so the
statement is False .
49. Compound interest is the interest calculated on the previous year’s amount.
Ans:Compound interest is referred to as the interest calculated on the previous year’s
amount.
Hence the given statement is true.
50.C.P. = M.P. – Discount.
Class VIII Mathematics www.vedantu.com 34
Ans:The given statement is False as
Selling price = Market price – discount
51. A man purchased a bicycle for Rs 1,040 and sold it for Rs 800. His gain
percent is 30%.
Ans:Given, CP of a bicycle = Rs. 1,040
SP of this bicycle = Rs. 800
We know that, loss = cost price – selling price = 1040 = 800 = Rs. 240
Now we know that ,
Loss% = Loss
CP× 100 =
240
1040× 100 = 23.07%
Hence, the given statement is false.
52. Three times a number is a 200% increase in the number, then one-third of the
same number is a 200% decrease in the number.
Ans: Let us suppose x be the number.
So, three times of x is given by 3x
Difference = 3x-x = 2x
Percentage increase in x = 2x
x x 100 = 200%
One third of x is given by 3
x
Difference = x - 3
x
= 2
3
x
Class VIII Mathematics www.vedantu.com 35
Decreased % is given by =2
3
xx
100
= 2
3×100
= 66.66%
53. Simple interest on a given amount is always less than or equal to the
compound interest on the same amount for the same time period and at the same
rate of interest per annum.
Ans:The S.I. and C.I. For some amount the equal rate of interest is always equal for
the first year.
The S.I. is less than the C.I. for an equal amount on the same rate of interest for the
second year.
Hence,the given statement is false.
54.The cost of a sewing machine is Rs. 7000. Its value depreciates at 8% per
annum. Then, the value of the machine after 2 yr is Rs. 5924.80.
Ans:Given, Principal = Rs.7000
Depreciation Rate = 3% per annum
Time period = 2 yr
According to the Question ,
A = 1 100
n
RP
A =
2
8 7000 1
100
A = 23 23
700025 25
Class VIII Mathematics www.vedantu.com 36
A = Rs5924.80
Hence the given statement is True.
55. If the discount of Rs. y is available on the marked price of Rs. x, then the
discount percent is x
y x 100%.
Ans:Given,
Marked Price = Rs x
Discount available = Rs y
Discount% =
Discount
Marked Price x 100 =
y
x x 100%
Hence the given statement is False .
56. Number of students appearing for class X CBSE examination increases from
91422 in 1999-2000 to 116054 in 2008-09. Increase in the number of students
appeared is approximately 27%.
Ans:Increase in students from 2008-09 to 1999-2000
= 116054 – 91422 = 24632
%Increase in students =
noof studentsincrease
noof studentsin previous year× 100
=24632
91422×100
= 27%(approx)
Hence the given statement is True..
Class VIII Mathematics www.vedantu.com 37
57. Selling price of 9 articles is equals to the cost price of 15 articles .In this
transaction the profit of 662
3%
Ans:SP of 9 articles =CP of 15 articles
Here in transaction, cost price of 6 articles is the profit
Profit% = 6
9×100 =
200
3 =
2 66
3%
Hence, the given statement is True.
58.The compound interest on a sum of Rs. P for T years at R% per annum
compounded annually is given by the formula, 1 100
RP
Ans:The Formula for compound interest on a sum of Rs. P for T years at
R% per annum compounded annually is given by 1 100
T
RP
Hence the given statement is False .
59.In the case of gain, SP= 100
100
gain
Ans:The statement given is true.
We know that,
Gain is given by = Selling price - Cost price
Therefore now gain % =
100
Gain
Cost price
Class VIII Mathematics www.vedantu.com 38
Therefore Selling price = 100 %
100100
Gain
It should be noted that gain or the loss is always calculated based on the cost price.
60.In the case of loss, CP= 100
100
SP
Loss
Ans:The statement is false.
Loss is given by = Cost price - Selling price.
Therefore Loss % =
100
Loss
Cost price
Therefore , Cost price = 100
100 %
Selling priceLoss
61.The value of a car, bought for Rs. 440000 depreciates each year by 10% of its
value at the beginning of that year. So, its value becomes Rs. 308000 after three
years.
Ans:The above statement if false,
The value of the car which is the principal= Rupees 440000 Rate of depreciation (R%)
=10% per annum Time period (T) = 3 yr
The value of the car after depreciation in 3 years is given by
A= P 1100
T
R
= 440000
3
101
100
= 440 729 320760Rupees
62. The cost of a book marked at Rs. 190 after paying a sales tax of 2% is Rs. 192.
Class VIII Mathematics www.vedantu.com 39
Ans:The statement given is false.
The marked price of the book = Rs.190
Sales tax = 2%
The cost price of the book after 2% sales tax = 190 + 2
19010
= 190+38 = rupees 193.8
63.The buying price of 5 kg of flour with the rate Rs. 20 per kg, when 5% sales
tax is added on the purchase, is Rs. 21.
Ans: The above statement is true.
The total flour bought = 5 kg
Rate of one kg flour = 5 kg
The cost of 5 kg flour with 5% sales tax = 5 5
20 5 2010
= 100 5
10010
= 105 rupees.
The per kg flour rate after 5% sales tax = 105
5= Rupees 21
64.The original price of a shampoo bottle bought for Rs. 324, if 8% VAT is
included in the price, is Rs. 300.
Ans:The above statement is false.
The original price of a shampoo bottle = rupees 300
The cost price of the shampoo bottle after 8% VAT
= 300+ 8
300100
Class VIII Mathematics www.vedantu.com 40
= 300 + 24 = Rupees 324.
65. Sales tax is always calculated on the cost price of an item and is added to the
value of the bill.
Ans:The above statement of false as the sales tax is always calculated on the selling
price of an item and is added to the value of the bill.
66. In a factory, women are 35% of all the workers, the rest of the workers being
men. The number of men exceeds that of women by 252. Find the total number of
workers in the factory.
Ans:
It is given that the percentage of women in the factory = 35%
The percentage of men in the factory = 100 -35 = 65%
Let the number of the persons in the factory be x.
Based on the question,
65 35 252
100 100x x
65 35252
100
x x
30 100
x =252
x = 2520
3 = 840
So there fore the total numberof workers in the factory.
Class VIII Mathematics www.vedantu.com 41
67.Three bags contain 64.2 kg of sugar. The second bag contains 4
5 of the
contents of the first and the third contains 45 ½ % of what there is in the second
bag. How much sugar is there in each bag?
Ans:From the question we can say that the total weight of sugar in three bags = 64.2
kg.
Now let us assume that the first bag contains x kg sugar.
The secondbag contains = x 4
5=
4
5
x kg
The third bag contains = 4 91% 91 5 2 250
xx kg
As per the question,
4 91% 5 2
x 64.2
541x = 64.2 250
x = 16050
541= 29.67 kg
So now the first bag contains the sugar = 29.67 4
23.73 . 5
kg and
The third bag contains the sugar = 91
29.67 10.8 . 250
kg
68. Find the SP, if
(a) MP = Rs. 5450 and discount = 5%
(b) MP = Rs.1300 and discount = 15%
Ans:
(a) Here from the question Marked price = 5450 and the discount percentage is = 5%
Class VIII Mathematics www.vedantu.com 42
Therefore the selling price = Marked price - %
100
DiscountMarked price
= 1300 -15
1300 1300 19.5 1 280.5100
Rupees
69. Find the MP, if
(a) SP = Rs. 495 and discount = 1%
(b) SP = Rs. 9250 and discount = 7 ½ %
Ans: (a) Selling price (SP) = 7495 and discount % = 1%
Now let the marked price be rupees x
Therefore selling price = Marked price - %
100
DiscountMP
495 = x - 1
100x , on solving we get
x = 500
Hence the marked price = Rupees 500.
(b) SP = Rs. 9250 and discount = 7 ½ %
The selling price (SP) = Rupees 9250
Discount % = 7 ½ % = 15
%2
Let the marked price be rupees x.
Therefore the selling price = Marked price - %
100
DiscountMP
9250 = x - 15
2 100x
Class VIII Mathematics www.vedantu.com 43
9250 = 185
200
x
1 0000x rupees
Hence the marked price = rupees 10000
70. Find discount in percent when
(a) MP = Rs.625 and SP = Rs.562.50
(b) MP = Rs.900 and SP = Rs.873
Ans:
(a) MP = Rs.625 and SP = Rs.562.50
Since discount = marked price - selling price = 625-562.5 = rupees 62.5
Therefore discount % = 62.5
100 100 1 0% 625
Discount
Marked price
(b) MP = Rs.900 and SP = Rs.873
The mark price (MP) = Rupees 900
Selling price (SP) = 873
Therefore discount = marked price -selling price = 900-873= Rupees 27
Therefore discount % = 27
100 100 3% 900
Discount
Marked price
71. The marked price of an article is Rs. 500. The shopkeeper gives a discount of
5% and still makes a profit of 25%. Find the cost price of the article.
Ans: It is given that the marked price of an article = Rs.500 Discount % = 5%
It is given that the profit made by the owner = 25%
So now let the cost price of the article be Rs. x
Class VIII Mathematics www.vedantu.com 44
The cost price after 5% discount = 500 - 5
500100
= 500 - 25 = Rupees 475.
As per the question,
(100+25)% of x = 475
So now after solving, x = Rupees 380.
Hence the cost price of the article is Rupees 380.
72. In 2007-08, the number of students who appeared for Class X examination
was 105332 and in 2008-09 the number was 116054. If 88151 students pass the
examination in 2007-08 and 103804 students in 2008-09. What is the increase or
decrease in pass percentage in class X result?
Ans: From the question the number of students who appeared in 2007-08 = 105332
Number of students appeared in 2008-09 = 116054
The number of students passed in 2007-08 = 88151
The number of students passed in 2008-09 = 103804
The pass percentage of students for the period of 2007-08
= 2007 08
100 2008 09
Number of students passed in
Number of studentsappeared in
= 88151
100105332
= 83.68%
The passed percentage of students in 2008-09
= 2008 09
100 2008 09
Number of students passed in
Number of studentsappeared in
Class VIII Mathematics www.vedantu.com 45
= 103804
1001 16054
= 89.44%
There fore the total increase in percentage would be = 89.44 - 83.68 = 5.76%
73.A watch worth Rs. 5400 x is offered for sale at Rs. 4500. What per cent
discount is offered during the sale?
Ans:The marked price of the watch = Rs.5400
The selling price = Rs.4500
Discount = Marked price – Selling price = Rs.5400 – Rs.4500 = Rs.900
Therefore discount % =
100
Discount
marked price
= 900
54
= 150
9=
50%
3
74. In the year 2001, the number of malaria patients admitted in the hospitals of a
state was 4375. Every year this number decreases by 8%. Find the number of-
patients in 2003.
Solution. The number of malaria patients admitted in a hospital in 2001 = 4375
Rate of decrement of malaria patients = 8%
Time period = 2 yri.e.2003-2001=2 yr
Let the number of patients in 2003 be A.
Ans: From the question we can say that the number of malaria pateints which were
admitted in a hospital in 2001 = 4375
The rate of decrement of malaria patients = 8%
Time period = 2 year which is between 2003 -2001
Let the number of patients in 2003 be A.
Class VIII Mathematics www.vedantu.com 46
Let us use the formula,
A = P 1100
T
R
= 4375
2
81
100
= 4375
2
23
25
= 3703
Therefore the number of patients in 2003 was 3703.
75. Jyotsana bought a product for Rs. 3155 including 4.5% sales tax. Find the
price before tax was added.
Ans: From the question we can say that the product bought by Jyotsana for Rs. 3155
including 4.5% sales tax.
Let the price of the product before sales tax be Rs. x .
So now, 4.5
100x x =3155
On solving we get .3019.14x Rs
76. An average Urban Indian uses about 150 L of water everyday.
Activity Litres per person per day
Drinking 3
Cooking 4
Bathing 20
Class VIII Mathematics www.vedantu.com 47
Sanitation 40
Washing clothes 40
Washing utensils 20
Gardening 23
Total 150
(a) What per cent of water is used for bathing and sanitation together per day?
Ans: From the given details, water used for bathing per day = 20 L
Water used for sanitation = 40 L
Total water used per day = 150 L
The percentage of water that is used for bathing and sanitation together per day
= 20 40 60
100 100150 150
= 600
40% 15
(b) How much less per cent of water is used for cooking in comparison to that
used for bathing?
Ans: Water which is been used to cook per day = 4L
Water which is been used for bathing per day = 20L
The total difference between the water used for cooking and bathing = 20-4 = 16 L
Therefore 16L of water is less used for cooking in comparison of bathing.
In percentage = 16
100150
= 32
3%.
Class VIII Mathematics www.vedantu.com 48
(c) What per cent of water- is used fdr drinking, cooking and gardening
together?
Ans: The water which is been used for drinking per day = 3L
Water used for cooking per day = 4L
Water used for gardening per day = 23L
Total water which is been used for drinking , cooking and gardening = 3+4+23 = 30L.
In percentage the value is = 30
100 20%.150
77. In 1975, the consumption of water for human use was about 3850 cu km/yr. It
increased to about 6000 cu km/yr in the year 2000.
Find the per cent increase in the consumption of water from 1975 to 2000. Also,
find the annual per cent increase in consumption
(assuming water consumption increases uniformly).
Ans: The consumption of water for human in 1975 = 3850 cu km/yr
The consumption of water for human in 2000 = 6000 cu km/yr
Increase in consumption of water in 1975 to 2000 = 6000 - 3850 =2150 cu km/yr
In percentage = 2150
100 55.84% 3850
In 25 years total increase in water consumption = 2150 cu km/yr
Therefore per year annual consumption = 2150
50= 86 cu km/yr
Therefore now, consumption in percentage is given by = 86
1003850
= 8600
3850 =2.23%
78. Harshna gave her car for service at service station on 27-05-2009 and was
charged as follows
Class VIII Mathematics www.vedantu.com 49
(a) 3.10 L engine oil @ Rs. 178.75 per litre and VAT @ 20%.
(b) Rs. 1105.12 for all other services and VAT @ 12.5%.
(c) Rs. 2095.80 as labour charges and service tax @ 10%.
(d) 3% cess on service tax.
Find the bill amount.
Ans:
(a) The total litres of engine oil used = 3.10L
Rate of engine oil per litres =Rs. 178.75
The cost of engine oil = 3.10 x 17875= Rs. 554.125
The cost of engine oil including 20% VAT = 554.125 + 554.125 20
100
= 554.125 + 554.125
5
= Rs. 664.95
(b) Amount paid for all the services = Rs. 1105.12
Amount paid including 12.5% VAT = 1105.12 + 12.5
1105.12 100
= Rs.1243.26
(c) Labour charges = Rs. 2095.90
Service tax = 10%
The total labour charges including 10% service tax
= 2095.80+ 10
2095.8 2095.80 209.58 . 2305.38100
Rs
(d) Cess on service tax at 3% = 209.583
2.095 3100
Class VIII Mathematics www.vedantu.com 50
= Rs. 6.29
Thus the total bill amount = Rs. 664.95+ Rs.1243.26+ Rs.2305.38+Rs.6.29 = Rs.
4219.88
79. Given, the principal = Rs.40000, rate of interest = 8% per annum
compounded annually. Find
(a) Interest if the period is one year.
(b) Principal for the 2nd year.
(c) Interest for 2nd year.
(d) Amount if the period is two year.
Ans: Given, principal (P)= Rs.40000
Rate of interest (R) = 8% per annum
a) Compound interest for one year,
1100
n
RA P
1
840000 1
100
[ ∵ n = 1 year]
10840000
100
So, 400 108 .43200A Rs
Compound Interest, 43200 40000 .3200CI A P Rs
b) Amount of first year = Principal of second year = Rs. 43200
c) Now, For second year,
Principal = Rs. 43200
Rate of interest, R = 8% per annum
Class VIII Mathematics www.vedantu.com 51
Time, n = 1 year
1100
n
RA P
1
843200 1
100
[ ∵ n = 1 year]
10843200
100
So, 432 108 .46656A Rs
Compound Interest, 46656 43200 .3456CI A P Rs
d) For period of 2 years, Amount is A= .46656Rs
80. In Delhi University, in the year 2009-10, 49000 seats were available for
admission to various courses at graduation level. Out of these 28200 seats were
for the students of General Category while 7400 seats were reserved for SC and
3700 seats for ST. Find the percentage of seats available for
(a) students of General Category.
(b) students of SC Category and ST Category taken together.
Ans: The total number of seats which are available for admission in 2009-10 = 49000
Seats reserved for General Category students = 28200
Seats reserved for SC Category students = 7400
Seats reserved for ST Category students = 3700
(a) Percentage of seats for the students of General Category.=28200 100
49000
= 57.55%
(b)The percentage of seats students of SC Category and ST Category taken together.
Seats reserved for SC Category students = 7400
Seats reserved for ST Category students = 3700
Class VIII Mathematics www.vedantu.com 52
Taken together = 7400+3700 = 11100
Therefore now the percentage of seats = 11100
49000= 22.65%
81. Prachi bought medicines from a medical store as prescribed by her doctor for
Rs 36.40 including 4% VAT. Find the price before VAT was added.
Ans: As per question,
We know that, Selling price = cost price +VAT
So, Cost price = 4
36.40 36.40100
36.40 4 0.364
36.40 1.456 .35Rs (Approx.)
82. Kritika ordered one pizza and one garlic bread from a pizza store and paid
Rs 387 inclusive of taxes of Rs 43. Find the tax%.
Ans: From the question we can figure out that the cost of one pizza and a garlic bread
inclusive of tax = Rs. 43
Therefore the cost of one pizza and a garlic bread without adding any tax = 387 -43 =
Rs.344
Therefore Tax % = 43
100344
= 100
8= 12.5%
83. Arunima bought household items whose marked price and discount % is as
follows
ITEM QUANTITY RATE DISCOUNT %
Atta 1 packet 200 16%
Class VIII Mathematics www.vedantu.com 53
Detergent 1 packet 371 22.10%
Namkeen 1 packet 153 18.30%
Find the total amount of the bill she has to pay.
Ans:
Based on the data given above in the table we can say that
The rate of one packet of atta = Rs.200
Discount % = 16%
So now price= 200 -16
200100
=200-32 =Rs.168
The rate of one packet of detergent = Rs.371
Discount % =22.10%
So now the price = 371-37122.10
100 = Rs.289.009
Rate of one packet of namkeen = 153
Discount % = 18.30%
So now, price = 153-15318.30
100 =Rs.125.001
Therefore the total bill amount = 168+ 289.009+125.001 =Rs.582.01
84. Devangi’s phone subscription charges for the period 17-02-09 to 16-03-09
were as follows.
Period Amount Service tax%
17-01-09 to 23-02-09 199.75 12%
Class VIII Mathematics www.vedantu.com 54
24-02-09 to 16-03-09 599.25 10%
Find the final bill amount, if 3% education cess was also charged on service tax.
Ans:
From the data given above in the table we can say that,
The amount fpr period 17-02-09 to 23-02-09 = Rs 199.75
Therefore the amount with service tax 12% = 199.75 + 12
199.75 233.72100
Rs
Amount for period 24-02-09 to 16-03-09 = Rs 599.25
Amount with service tax at 10% = 599.25+599.2510
100 =Rs 659.175
The total bill amount = Rs . 223.72 +650.175 = Rs. 882.895
Total bill amount including education cess of 3%
= 882.895+3% of 882.895
= 882.895 + 3
882.895100
= Rs. 909.39.
85. If principal = Rs 100000, rate of interest = 10% compounded half-yearly.
Find.
(a) Interest for 6 months. (b) Amount after 6 months.
(c) Interest for next 6 months, (d) Amount after one year.
Ans: From the question, Principal(P) = Rs. 100000
Rate of interest (R) = 10% compounded half yearly.
a) Interest for 6 months.
Class VIII Mathematics www.vedantu.com 55
Given, n = 6 months
We know that, CI = A - P
And where for six months amount, 1200
n
RA P
1
101 100000 1
200 200
n
RA P
(As n = 1, for 6 months)
A = Rs. 105000
Now CI = A - P
CI = 105000 - 100000 = Rs.5000
(b)The amount after 6 months = Rs. 105000
(c) Interest for next 6 months.
Principal = Amount after 6 months
Therefore principal(P) = Rs.105000
Rate of interest (R)= 10%
1200
n
RA P
= 100000
1
101
200
= Rs.110250.
Compound interest, CI = A - P
CI = 110250 - 10500 = Rs. 5250
(d) Amount after one year = Rs. 110250.
Class VIII Mathematics www.vedantu.com 56
86. Babita bought 160 kg of mangoes at Rs 48 per kg. She sold 70% of the
mangoes at Rs 70 per kg and the remaining mangoes at Rs 40 per kg. Find
Babita’s gain or loss per cent on the whole dealing.
Ans:
Babita bought 160 kg of mangoes = Rs. 48 per kg
So now the total amount she paid = 48 160 .7680Rs
She sold 70% of the mangoes at Rs.70 per kh.
Therefore the cost of 70% mangoes = 16070
70 . 7890100
Rs
Remaining mangoes = (100-70)% = 30%
Cost remaining at Rs. 40 per kg = 16030
40 .1920100
Rs
The total amount received after selling the mangoes = 7840+1920 = Rs. 9760
Therefore SP > CP, Hence there is a gain.
Gain = SP-CP = 9760 - 7680 =Rs,2080
Gain% = 100Gain
CP =
2080100 27.08%
7680
87.A shopkeeper was selling all his items at 25% discount. During the off season,
he offered 30% discount over and above the existing discount. If Pragya bought a
skirt which was marked for Rs 1200, how much did she pay for it?
Ans:
From the question we know that the marked price of the skirt = Rs. 1200
During normal season discount at 25% = 25
1200 .300100
Rs
The price of the skirt after discount = Rs. 1200-Rs 300= RS.900
Class VIII Mathematics www.vedantu.com 57
During off season time the shopkeeper also offers discount at 30 % =
30900 270
100Rs
The price of the skirt after 30% discount = Rs. 900-270 = Rs.630.
Therefore Pragya paid Rs.630 while purchasing the skirt.
88. Ayesha announced a festival discount of 25% on all the items in her mobile
phone shop. Ramandeep bought a mobile phone for himself. He got a discount of
? 1960. What was the marked price of the mobile phone?
Ans:
Let us assume that the marked price of the mobile phone be Rs. x
We know that the festival discount on the mobile phone = 25%
The total discount which Ramandeep accepted = Rs. 1960
So according to the given data we can say that,
1960 -= x 25
100
So now, x = Rs.7840.
Hence the mared price of the mobile phone was Rs. 7840.
89. Find the difference between compound interest and simple interest on Rs
45000 at 12% per annum for 5 yr.
Ans:
From the question we know that
Principal (P) = Rs. 45000
Rate of interest (R) = 12% per annum
Time period (T) = 5 years
Class VIII Mathematics www.vedantu.com 58
Simple Interest = 100
PRT=
4500 12 5
100
= Rs. 27000
Compound interest is given by,
CI = A - P
Now , A = P 1100
T
R
A = 4500
5
121
100
On calculating we get Amount, A as Rs. 79200
Therefore now the Compound interest is given by,
CI = 79200 - 45000
CI = Rs. 34200.
Therefore now the difference between SI and CI = 34200- 27000 = Rs. 7200.
90. A new computer costs Rs 100000. The depredation of computers is very high
as new models with better technological advantages are coming into the market.
The depredation is as high as 50% every year. How much will the cost of
computer be after two years?
Ans: From the question,
The cost of the new computer = Rs. 100000
The depreciation rate = 50% per annum
Time period (T) = 2 years
Now let the cost of computer after 2 years be Rs. A
A = P 1100
T
R
Class VIII Mathematics www.vedantu.com 59
= 100000
2
501
100
A = Rs. 25000
Therefore the cost of the computer after 2 years will be Rs. 25000.
91. The population of a town was decreasing every year due to migration, poverty
and unemployment. The present population of the town is 6,31,680. Last year the
migration was 4% and the year before last, it was 6%. What was the population
two years ago?
Ans:As per question,
Suppose, two years ago the population = P
We know that,
1 1100 100
R RA P
So,
4 6631680 1 1
100 100P
24 47631680
25 50P
631680 25 50700000
24 47P
92. Lemons were bought at Rs 48 per dozen and sold at the rate of Rs 40 per 10.
Find the gain or loss per cent.
Ans: As per question,
Cost of one dozen lemons = Rs. 48
Class VIII Mathematics www.vedantu.com 60
We know that, 1 dozen = 12 pieces.
So cost of 1 lemon = 48
. .412
Rs Rs
Also 10 lemons sold for Rs. 40. So, Selling price of one lemons = 40
.410
Rs
Now the cost price of one lemon = selling price of one lemon.
So zero profit and zero loss.
93. If the price of petrol, diesel and LPG is slashed as follows:
Fuel Old prices/litre (in Rs) New prices/litre (in Rs) % Decrease
Petrol/L 45.62 40.62 -------------
Diesel/L 32.86 30.86 -------------
LPG/14.2kg 304.70 279.70 -------------
Complete the above table.
Ans: From the above table,
For per litre petrol, old price = Rs. 45.62 and
New price = Rs. 40.62
Decrement in price = Rs. 45.62 - Rs. 40.62 = Rs. 5
So, Decrease percentage 5
100 10.96%45.62
For per litre diesel, old price = Rs. 32.86 and
New price = Rs. 30.86
Decrement in price = Rs. 32.86 - Rs. 30.86 = Rs. 2
Class VIII Mathematics www.vedantu.com 61
So, Decrease percentage 2
100 6.09%32.86
For LPG, old price = Rs. 304.70 and
New price = Rs. 279.70
Decrement in price = Rs. 304.70 - Rs. 279.70 = Rs. 25
So, Decrease percentage 25
100 8.20%304.70
94. What is the percentage increase or decrease in the number of seats won by A,
B, C and D in the general elections of 2009 as compared to the results of 2004?
Political Party Number of seats won in 2004 Number of seats won in 2009
A 206 145
B 116 138
C 4 24
D 11 12
Ans: For political party A,
Number of seats won in 2004 = 206
Number of seats won in 2009 = 145
Decreased number of seats won by the party A, = 206 - 145 = 61 seats
So, Decreased percentage 61
100 29.61%206
For political party B,
Number of seats won in 2004 = 116
Class VIII Mathematics www.vedantu.com 62
Number of seats won in 2009 = 138
Increased number of seats won by the party B, = 138 - 116 = 22 seats
So, Increased percentage 22
100 18.96%116
For political party C,
Number of seats won in 2004 = 4
Number of seats won in 2009 = 24
Increased number of seats won by the party C, = 24 - 4 = 20 seats
So, Increased percentage 20
100 500%4
For political party D,
Number of seats won in 2004 = 11
Number of seats won in 2009 = 12
Increased number of seats won by the party D, = 12 - 11 = 1 seats
So, Increased percentage 1
100 9.09%11
95. How many more percent seats were won by X as compared to Y in Assembly
Election in the state based on the data given below.
Party Won (out of 294)
X 158
Y 105
Z 18
W 13
Class VIII Mathematics www.vedantu.com 63
Ans: As per question,
Net number of seats won by the party X = 158
Net number of seats won by the party Y = 105
So, the total number of seats in election = 294
And the % of seats won by party X 158
100 53.74%294
And also, the % of seats won by party Y 105
100 35.71%294
Now, the difference of percentage = 53.74% 35.71% 18.03%
Therefore, party X won 18.03% as compared to party Y.
96. Ashima sold two coolers for Rs 3,990 each. On selling one cooler she gained
5% and on selling the other she suffered a loss of 5%. Find her overall gain or
loss % in the whole transaction.
Ans: SP of each cooler = Rs. 3990
Suppose, the CP of both coolers for Ashima = x
We know that, Profit = SP - CP
So,
53990
100x x
213990
20
x
3990 20.3800
21x Rs
And also, on another transaction of other cooler she has a loss = 5%
So,
Class VIII Mathematics www.vedantu.com 64
53990
100x x
193990
20
x
3990 20.4200
19x Rs
Now, the net CP for Ashima = Rs.3800 + Rs.4200 = Rs.8000
Ashima sold both coolers = Rs.3990 2 = Rs.7980
Here, CP > SP.
So, Ashima has loss her whole transaction.
Now, Loss = Rs.8000 - Rs.7980 = Rs.20
And, loss percentage 20 1
100 % 0.25%8000 4
97. A lady buys some pencils for Rs 3 and an equal number for Rs 6. She sells
them for Rs 7. Find her gain or loss%.
Ans: As per question,
cost price of some pencils = Rs. 3
For other equal no. of pencils = Rs. 6
Net selling price = Rs.7
Suppose, the lady buys ‘n’ pencils for Rs = 3. (Type - 1 pencil)
CP for one such pencil 3
n
And for ‘n’ pencils of other type, she paid = Rs 6 (Type -2 pencil)
CP for one such pencil 6
n
Class VIII Mathematics www.vedantu.com 65
Net selling price of ‘2n’ pencils = Rs.7
Now, Calculation for type - 1
We know that, Gain = selling price - cost price
By using above formula,
Gain = 7 3
2n n
7 6 1
2 2n n
Also, gain percentage 100Gain
CP
1502 100 %
3 3
n
n
Now, Calculation for type - 2
We know that, Loss = cost price - selling price
By using above formula,
Loss = 6 7
2n n
12 7 5
2 2n n
Also, loss percentage 100loss
CP
51252 100 %
6 3
n
n
Class VIII Mathematics www.vedantu.com 66
Net loss percentage = 125 50 75
25%3 3 3
98. On selling a chair for Rs 736, a shopkeeper suffers a loss of 8%. At what price
should he sell it so as to gain 8%?
Ans: Given, selling price of chair = Rs.736,
This led to a loss of 8%.
Suppose, the cost price of a chair = Rs. x
As per question,
Selling price = Cost price - loss
8736
100x x
92736
100
x
73600.800
92x Rs
To gain 8% profit the price should be,
8800 800 800 64 .864
100Rs
99. A dining table is purchased for Rs 3,200 and sold at a gain of 6%. If a
customer pays sales tax at the rate of 5%. How much does the customer pay in all
for the table?
Ans: As per question,
Selling price of the dining table = 6
3200 3200 .3392100
Rs
Class VIII Mathematics www.vedantu.com 67
Selling price with sales tax = 5
3392 3392 .3561.6100
Rs
100. Achal bought a second-hand car for Rs 2,25,000 and spent Rs 25,000 for
repairing. If he sold it for Rs 3,25,000, what is his profit percent?
Ans: As per question,
Achal cost for the car = Rs. 2,25,000 + Rs. 25,000
= Rs. 2,50,000
Achal sold his car = Rs. 3,25,000
Now, profit = Rs. 3,25,000 - Rs. 2,50,000 = 75,000
So, profit percentage 100%Profit
CP
75,000100%
2,50,000
30%
101. A lady bought an air-conditioner for Rs 15,200 and spent Rs 300 and Rs 500
on its transportation and repair respectively. At what price should she sell it to
make a gain of 15%?
Ans: Actual cost price of air conditioner with transportation charge and repair charges
= Rs. 15,200 + Rs. 300 + Rs. 500
= Rs. 15,500 + Rs. 500
= Rs. 16,000
For getting gain 15% she should sell it for Rs =15
16,000 16,000100
16,000 2,400 .1,84,000Rs
Class VIII Mathematics www.vedantu.com 68
102. What price should a shopkeeper mark on an article that costs him Rs 600 to
gain 20%, after allowing a discount of 10%.
Ans: Given, gain percentage = 20% and the CP of an articl = Rs. 600
Now, 600 20
.120100
Gain Rs
By using formula SP = Gain + CP
10 600 .720SP Rs
Suppose, the MP = x
Since, he allows 10% discount. So,
10720
100x x
9720
10
x
7200.800
9x Rs
103. Brinda purchased 18 coats at the rate of Rs 1,500 each and sold them at a
profit of 6%. If customer is to pay sales tax at the rate of 4%, how much will one
coat cost to the customer and what will be the total profit earned by Brinda after
selling all coats?
Ans: As per question,
Net cost of 18 coats 1500 18 .27000Rs
The amount received by Brinda,
627,000 27,000 .28,620
100Rs
If customer pay sale tax = 4%
Class VIII Mathematics www.vedantu.com 69
Now, CP with sale tax 4
28,620 28,620 .29764.80100
Rs
CP for 1 coat for customer 29,764.80
.1653.6018
Rs
Now, profit earned by Brinda,
.28,620 .27,000 .1,620Rs Rs Rs
104. Rahim borrowed Rs 10,24,000 from a bank for one year. If the bank charges
interest of 5% per annum, compounded half-yearly, what amount will he have to
pay after the given time period. Also, find the interest paid by him.
Ans: As per question,
Suppose, amount = A
We know that, in half yearly, 2
RR and 2T T
So, for compounded half-yearly,
2 2
51 10,24,000 1
200 200
T
RA P
.10,75,840A Rs
Also, CI = A - P
.10,75,840 .10,24,000Rs Rs
.51,840Rs
105. The following items are purchased from showroom:
T-Shirt worth Rs 1200. Jeans worth Rs 1000. 2 Skirts worth Rs 1350 each.
What will these items cost to Shikha if the sales tax is 7%?
Ans: As per question,
Class VIII Mathematics www.vedantu.com 70
Net cost .1200 .1000 .1350 .3550Rs Rs Rs Rs
Shikha have to pay sale tax 7%
Now, the net amount to pay 7
3550 3550 .3798.5100
Rs
106. The food labels given below give information about 2 types of soup: cream of
tomato and sweet corn. Use these labels to answer the given questions. (All the
servings are based on a 2000 calorie diet.)
Sweet Corn
Nutrition Facts
Serving Size 1 cup (240ml)
About 2 serving per Container
Cream of Tomato
Nutrition Facts Serving
Size 1 cup (240ml)
About 2 serving per Container
Amount Per Serving
Calories 90 Calories from Fat 9
Amount Per Serving
Calories 100 Calories from Fat 20
% Daily
Value*
Total Fat 2g 2%
Saturated Fat-0g 0%
Cholesterol 0mg 0%
Sodium 540mg 22%
Total Carbohydrate 17g 6%
Dietary Fibre 3 gram 14%
% Daily
Value*
Total Fat 2g 3%
Saturated Fat-1.5g 6%
Cholesterol 10mg 3%
Sodium 690mg 29%
Total Carbohydrate 17g 6%
Dietary Fibre 4 gram 18%
Class VIII Mathematics www.vedantu.com 71
Sugar 5g
Protein 3g
Sugar 11g
Protein 2g
Vitamin A 30% Vitamin C 10% Vitamin A 20% Vitamin C 20%
Calcium 2% Iron 6% Calcium 0% Iron 8%
*Percent Daily Values are based on a
2,000 calorie diet.
*Percent Daily Values are based on a
2,000 calorie diet.
(a) Which can be measured more accurately : the total amount of fat in cream of
tomato soup or the total amount of fat in sweet corn soup? Explain.
(b) One serving of cream of tomato soup contains 29% of the recommended daily
value of sodium for a 2000 calorie diet. What is the recommended daily value of
sodium in milligrams? Express the answer upto 2 decimal places.
(c) Find the increased percent of sugar consumed if cream of tomato soup is
chosen over sweet corn soup.
(d) Calculate ratio of calories from fat in sweet corn soup to the calories from fat
in cream of tomato soup.
Ans: As per question,
a) Serving size of one cup of sweet corn = 240mL
Net fat = 2g on 2%
The total amount of fat in sweet corn soup,
2240 4.8
100g
Now, for one serving 4.8
2.42
g
Class VIII Mathematics www.vedantu.com 72
Given, serving cost of one cup of tomato cream,
3240 7.2
100g
Now, for one serving 7.2
3.62
g
b) According to the question,
29% of 2000 calories = 690 mg
c) The increase percent of sugar consumed = 11g - 5g = 6g
So, increased percentage 6
100% 120%5
d) fat in sweet corn soup in calories = 9
And fat in cream tomato soup in calories = 20
The ratio 9
20
107. Music CD originally priced at Rs 120 is on sale for 25% off. What is the
S.P.? Sonia and Rahul have different ways of calculating the sale price for the
items they bought.
Class VIII Mathematics www.vedantu.com 73
As you work on the next problem, try both of these methods to see which you
prefer.
Ans: As per question,
Original price of CD = Rs. 120
25% discount on Rs. 120.
If the sale is applicable, Discount 25
120 .30100
Rs
So, selling price after discount = Rs. 120 - Rs. 30 = Rs. 90
108. Store A and Store B both charge Rs 750 for a video game. This week the
video game is on sale for Rs 600 at Store B and for 25% off at Store A. At which
store is the game less expensive?
Ans: As per question,
20% discount at store A. So,
Selling price at store A 20
750 750100
750 150
.600Rs
Given, selling price at store B = Rs.600
So, both are equally expensive.
109. At a toy shop the price of all the toys is reduced to 66% of the original price.
(a) What is the sale price of a toy that originally costs Rs 90?
(b) How much money would you save on a toy costing Rs 90?
Ans: As per question,
a) When price reduced to 66% of the original price,
Class VIII Mathematics www.vedantu.com 74
Then the price 66
90 90 .30.6100
Rs
b) Saved money 66
90 .59.4100
Rs
110. A store is having a 25% discount sale. Sheela has a Rs 50 gift voucher and
wants to use it to buy a board game marked for Rs 320. She is not sure how to
calculate the concession she will get. The sales clerk has suggested two ways to
calculate the amount payable.
Method 1: Subtract Rs 50 from the price and take 25% off the resulting price.
Method 2: Take 25% off the original price and then subtract Rs 50.
a. Do you think both the methods will give the same result? If not, predict which
method will be beneficial for her.
b. For each method, calculate the amount Sheela would have to pay. Show your
work.
c. Which method do you think stores actually use? Why?
Ans: As per question,
a) In method 1,
Rs. 320 - Rs. 50 = Rs. 270
25% discount on Rs. 270 25
270 270 .202.5100
Rs
In method 2,
25% discount on Rs. 320 25
320 320 .240100
Rs
Price = Rs. 240 - Rs. 50 = Rs. 190
So, method 2 is beneficial for her.
b) In method 1, Amount paid = Rs. 202.5
Class VIII Mathematics www.vedantu.com 75
In method 2, Amount paid = Rs. 190
c) Method 1. This method shows actual discount in loss.
111. Living on your own: Sanjay is looking for a one-bedroom apartment on rent.
At Neelgiri apartments, rent for the first two months is 20% off. The one
bedroom rate at Neelgiri is Rs 6,000 per month. At Savana apartments, the first
month is 50% off. The one bedroom rate at Savana apartments is Rs 7000 per
month. Which apartment will be cheaper for the first two months? By how
much?
Ans: As per question,
Rent for first two months,
202 6000 6000 .9600
100Rs
By comparison of Savana apartment, it offers 50% off for her first month, where the
rent for bedroom .7000 /Rs month
507000 7000 .3500
100Rs
So, the rent for two months in Savana apartment,
3500 7000 .10500Rs
Therefore, Neelgiri apartment will be cheaper by,
= .10500 .9600 .900Rs Rs Rs
112. For an amount, explain why, a 20% increase followed by a 20% decrease is
less than the original amount.
Ans: Suppose, the original price = x
20% increase in original price =20 6
100 5
xx x
Class VIII Mathematics www.vedantu.com 76
Now, 20% decrease in 6 6 20 6
5 5 100 5
x x x
30 6 24
25 25 25
x x x
So the decreased price is less than the original price because decrement is calculated
on increased price and increment is calculated on original price. So Decrement is more
than increment.
113. Sunscreens block harmful ultraviolet (UV) rays produced by the sun. Each
sunscreen has a Sun Protection Factor (SPF) that tells you how many minutes
you can stay in the sun before you receive one minute of burning UV rays. For
example, if you apply sunscreen with SPF 15, you get 1 minute of UV rays for
every 15 minutes you stay in the sun.
1. A sunscreen with SPF 15 allows only 1
15 of the sun’s UV rays. What percent of
UV rays does the sunscreen abort?
2. Suppose a sunscreen allows 25% of the sun’s UV rays.
a. What fraction of UV rays does this sunscreen block? Give your answer in
lowest terms.
b. Use your answer from Part (a) to calculate this sunscreen’s SPF. Explain how
you found your answer.
3. A label on a sunscreen with SPF 30 claims that the sunscreen blocks about
97% of harmful UV rays. Assuming the SPF factor is accurate, is this claim true?
Explain.
Ans:i) According to the question, 14
15 of the sun’s UV rays aborted by sunscreen.
In percentage
14
15 100 93.33%1
ii) a) Lowest fraction of blocked UV rays,
Class VIII Mathematics www.vedantu.com 77
= 100 - 25 =75% = 75 3
100 4
b) Sunscreen allows 25% or 3
4 of UV rays. Means, it protects UV rays
3 11
4 4
Therefore, its SPF = 4
iii) The given statement is false.
114. A real estate agent receives Rs 50,000 as commission, which is 4% of the
selling price. At what price does the agent sell the property?
Ans: Let the selling price = .Rs x
According to question,
4% of x is equal to Rs. 50,000.
450,000
100x
25 50,000x
12,50,000x
115. With the decrease in prices of tea by 15% Tonu, the chaiwallah, was able to
buy 2 kg more of tea with the same Rs 45 that he spent each month on buying tea
leaves for his chai shop. What was the reduced price of tea? What was the
original price of tea?
Class VIII Mathematics www.vedantu.com 78
Ans: As per question,
Suppose, purchased tea = y kg
Price of tea per kg = Rs. x
Discount 15% per kg,
15 85
100 100
xx x
A chaiwallah can buy 2 kg extra with 15% of discount.
But without discount, xy = 45 .....(i)
And 85
2 45100
xy ii
By solving equation (i) and (ii):
85 85 245
100 100
xy x
85 2 85 4545
100 100
x
170 4500 85 45x
45 1 00 45 85 45 1 53.97
170 170x per kg
So, the reduced price = 85 3.97
3.37 100
per kg
Class VIII Mathematics www.vedantu.com 79
116.116 Below is the report card of ViditAtrey. Vidit’s teacher left the last
column blank. Vidit is not able to make out, in which subject he performed better
and in which he needs improvement. Complete the table to help Vidit know his
comparative performance.Assessment report for- 2009-2010
Assessment Report for 2009-2010
Class : 9B Name : Vidit Atrey Date : 31 March 2010
S.No Subject Internal assessment Examination Total Final%
1. English Literature 20/25 82/100 102/125
2. English Language 22/25 91/100 113/125
3. Hindi Literature 18/25 67/75 85/100
4. Hindi Language 16/25 68/75 84/100
5. Mathematics 42/50 88/100 130/150
6. Sanskrit 14/20 75/100 99/120
7. Physics 45/50 90/100 135/150
8. Chemistry 41/50 82/100 123/150
9. Biology 43/50 87/100 130/150
10. History and Civics 19/25 68/75 87/100
11. Geography 17/20 71.5/80 88.5/100
Ans:
From the data which is been given in the table , we can calculate the final percentage
of each subjects.
1. English Literrature = 102 408
100 81.6%125 5
2. English language = 113 452
100 90.4%125 5
3. Hindi literature = 85
100 85%100
4. Hindi language = 84
100 84%100
5. Mathematics = 130 1300
100 150 15
86.67%
Class VIII Mathematics www.vedantu.com 80
6. Sanskrit = 89 890
100 74.16%100 5
7. Physics = 135 1350
100 90%150 15
8. Chemistry = 123
100 82%150
9. Biology= 130 1300
100 86.66%150 15
10. History and Civics = 87
100 87%100
11. Geography = 88.5 452
100 88.5%100 5
117.Sita’s practicing basket ball. She has managed to score 32 baskets in 35
attempts. What is her success rate in percentage?
Ans:
It is given that Sita managed to score 32 baskets in 35 attempts.
Class VIII Mathematics www.vedantu.com 81
Now her success rate will be = 32
10035
=91.428%= 91.43%
118. During school hours, Neha finished 73% of her homework and Minakshi
completed 5
8 of her, homework. Who must finish a greater per cent of 8
homework?
Ans:
It is given in the question that during school hours, Neha finished 73% of her
homework and Minakshi completed 58 of her homework.
In percentage Neha finished her homework = 73%= 73
100
Simillarly Minakshi completed 5
8 of her homework.
Homework left from Minakshi = 1- 5
8 =
3
8
In percentage = 3
100 37.58 %
Homework left for Neha = (100-73) = 27% = 27
100
Hence from the calculation we can say that Minashi finishes a greater percentage of
homework compared to Neha.
119. Rain forests are home to 90000 of the 250000 identified plant species in the
world. What per cent of the world’s identified plant species are found in rain
forests?
Ans:
It is given that rain forests are home to 90000 of the 250000 identified plant species in
the world.
Class VIII Mathematics www.vedantu.com 82
Percentage = 90000 900
100 36% 250000 25
120.Madhu’s room measures 6m x 3m. Her carpet covers 8 m2. What per t cent
of floor is covered by the carpet?
Ans:
From the question we know that,
Madhu’s room measures = 6m 3 m
Area of the room = 6 3 = 18 2m (From area of the rectangle = l b )
Madhu’s carpet covers = 8 2m
Therefore area covered by the carpet in percentage = 8
100 44.44%18
121.The human body is made up mostly of water. In fact about 67% of a person
total body weight is water. If Jyoti weights 56 kg, how much of her weight is
water?
Ans:
From the question we can say that
Jyoti’s weight = 56 kg
We know that 67% of a person total body weight is water
Water in Jyoti body = 67
56 37.52 100
kg
122.The per cent of pure gold in 14 carat gold is about 58.3%. A 14 carat gold
ring weights 7.6 grams. How many grams of pure gold are in the ring?
Ans:
Class VIII Mathematics www.vedantu.com 83
The percentage of gold in 14 carat gold = 58.3%
Weight of 14 carat gold = 7.6 g
Pure gold in 14 carat gold of 7.6 g = 7.6 58.3 443.08
4.431 100 100
g
Hence, pure gold in 7.6 g 0f 14 carat gold is equal to 4.431 g.
123.A student used the proportion 100 325n to find 5% of 32. What did the
student do wrong?
Ans:It is given in the question that the student used the proportion 100 325n to find 5%
of 32 , which is an incorrect approach.
5% of 32 will be calculated as = 5
32100
=1.6
124.The table shows the cost of sunscreen of two brands with and without sales
tax. Which brand has a greater sales tax rate? Give the sales tax rate of each
brand?
Cost in Rs Cost + Tax in Rs
1 X (100 g) 70 75
2 Y (100 g) 62 65
Ans:
From the question we can say that,
The brand X sunscreen cost = Rs. 70
With sales tax = Rs.75
Sales tax paid = Rs.75-Rs.70 = Rs.5
The cost of rand Y sunscreen = Rs. 62