A concave—convex elliptic problem involving the fractional Laplacian

52
arXiv:1006.4510v2 [math.AP] 21 Oct 2010 A CONCAVE-CONVEX ELLIPTIC PROBLEM INVOLVING THE FRACTIONAL LAPLACIAN C. BR ¨ ANDLE, E. COLORADO, AND A. DE PABLO Abstract. We study a nonlinear elliptic problem defined in a bounded do- main involving fractional powers of the Laplacian operator together with a concave-convex term. We characterize completely the range of parameters for which solutions of the problem exist and prove a multiplicity result. 1. Introduction In the past decades the problem Δu = f (u) in Ω R N , u = 0 on Ω, has been widely investigated. See [3] for a survey, and for example the list (far from complete) [4, 12, 31] for more specific problems, where different nonlinearities and different classes of domains, bounded or not, are considered. Other different diffusion operators, like the p–Laplacian, fully nonlinear operators, etc, have been also treated, see for example [8, 15, 24] and the references there in. We deal here with a nonlocal version of the above problem, for a particular type of nonlinearities, i.e., we study a concave-convex problem involving the fractional Laplacian operator (1.1) (Δ) α/2 u = λu q + u p , u> 0 in Ω, u = 0 on Ω, with 0 <α< 2, 0 <q< 1 <p< N+α Nα , N>α, λ> 0 and Ω R N a smooth bounded domain. The nonlocal operator (Δ) α/2 in R N is defined on the Schwartz class through the Fourier transform, [(Δ) α/2 g] (ξ ) = (2π|ξ |) α g(ξ ), or via the Riesz potential, see for example [28, 35] for the precise formula. As usual, g denotes the Fourier Transform of g, g(ξ )= R N e 2πix·ξ g(x) dx. Observe that α = 2 corresponds to the standard local Laplacian. This type of diffusion operators arises in several areas such as physics, probability and finance, see for instance [6, 7, 20, 39]. In particular, the fractional Laplacian can be understood as the infinitesimal generator of a stable L´ evy process, [7]. There is another way of defining this operator. In fact, in the case α = 1 there is an explicit form of calculating the half-Laplacian acting on a function u in the whole space R N , as the normal derivative on the boundary of its harmonic extension to the upper half-space R N+1 + , the so-called Dirichlet to Neumann operator. The “α 1

Transcript of A concave—convex elliptic problem involving the fractional Laplacian

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A CONCAVE-CONVEX ELLIPTIC PROBLEM INVOLVING THE

FRACTIONAL LAPLACIAN

C. BRANDLE, E. COLORADO, AND A. DE PABLO

Abstract. We study a nonlinear elliptic problem defined in a bounded do-main involving fractional powers of the Laplacian operator together with aconcave-convex term. We characterize completely the range of parameters forwhich solutions of the problem exist and prove a multiplicity result.

1. Introduction

In the past decades the problem

−∆u = f(u) in Ω ⊂ RN ,

u = 0 on ∂Ω,

has been widely investigated. See [3] for a survey, and for example the list (farfrom complete) [4, 12, 31] for more specific problems, where different nonlinearitiesand different classes of domains, bounded or not, are considered. Other differentdiffusion operators, like the p–Laplacian, fully nonlinear operators, etc, have beenalso treated, see for example [8, 15, 24] and the references there in. We deal herewith a nonlocal version of the above problem, for a particular type of nonlinearities,i.e., we study a concave-convex problem involving the fractional Laplacian operator

(1.1)

(−∆)α/2u = λuq + up, u > 0 in Ω,

u = 0 on ∂Ω,

with 0 < α < 2, 0 < q < 1 < p < N+αN−α , N > α, λ > 0 and Ω ⊂ R

N a smoothbounded domain.

The nonlocal operator (−∆)α/2 in RN is defined on the Schwartz class through

the Fourier transform,

[(−∆)α/2g]∧ (ξ) = (2π|ξ|)α g(ξ),or via the Riesz potential, see for example [28, 35] for the precise formula. Asusual, g denotes the Fourier Transform of g, g(ξ) =

∫RN e

−2πix·ξg(x) dx. Observethat α = 2 corresponds to the standard local Laplacian.

This type of diffusion operators arises in several areas such as physics, probabilityand finance, see for instance [6, 7, 20, 39]. In particular, the fractional Laplaciancan be understood as the infinitesimal generator of a stable Levy process, [7].

There is another way of defining this operator. In fact, in the case α = 1 there isan explicit form of calculating the half-Laplacian acting on a function u in the wholespace R

N , as the normal derivative on the boundary of its harmonic extension tothe upper half-space R

N+1+ , the so-called Dirichlet to Neumann operator. The “α

1

2 BRANDLE, COLORADO, AND DE PABLO

derivative” (−∆)α/2 can be characterized in a similar way, defining the α-harmonicextension to the upper half-space, see [16] and Section 2 for details. This extensionis commonly used in the recent literature since it allows to write nonlocal problemsin a local way and this permits to use the variational techniques for these kind ofproblems.

In the case of the operator defined in bounded domains Ω, the above character-ization has to be adapted. The fractional powers of a linear positive operator in Ωare defined by means of the spectral decomposition. In [14], the authors considerthe fractional operator (−∆)1/2 defined using the mentioned Dirichlet to Neumann

operator, but restricted to the cylinder Ω × R+ ⊂ RN+1+ , and show that this defi-

nition is coherent with the spectral one, see also [36] for the case α 6= 1. We recallthat this is not the unique possibility of defining a nonlocal operator related to thefractional Laplacian in a bounded domain. See for instance the definition of the socalled regional fractional Laplacian in [9, 27], where the authors consider the Rieszintegral restricted to the domain Ω. This leads to a different operator related to aNeumann problem.

As to the concave-convex nonlinearity, there is a huge amount of results involvingdifferent (local) operators, see for instance [1, 4, 8, 17, 19, 24]. We quoted thework [4] from where some ideas are used in the present paper. In most of theproblems considered in those papers a critical exponent appears, which genericallyseparates the range where compactness results can be applied or can not (in thefully nonlinear case the situation is slightly different, but still a critical exponentappears, [17]). In our case, the critical exponent with respect to the correspondingSobolev embedding is given by 2∗α = 2N

N−α . This is a reason why problem (1.1) is

studied in the subcritical case p < 2∗α − 1 = N+αN−α ; see also the nonexistence result

for supercritical nonlinearities in Corollary 4.6.

The main results we prove characterize the existence of solutions of (1.1) in termsof the parameter λ. A competition between the sublinear and superlinear termsplays a role, which leads to different results concerning existence and multiplicityof solutions, among others.

Theorem 1.1. There exists Λ > 0 such that for Problem (1.1) there holds:

1. If 0 < λ < Λ there is a minimal solution. Moreover, the family of minimalsolutions is increasing with respect to λ.

2. If λ = Λ there is at least one solution.3. If λ > Λ there is no solution.

Moreover, we have the following multiplicity result:

Theorem 1.2. For each 0 < λ < Λ, Problem (1.1) has at least two solutions.

On the contrary, there is a unique solution with small norm.

Theorem 1.3. For each 0 < λ < Λ fixed, there exists a constant A > 0 such thatthere exists at most one solution u to Problem (1.1) verifying

‖u‖∞ ≤ A.

For α ∈ [1, 2) and p subcritical, we also prove that there exists an universalL∞-bound for every solution independently of λ.

A CONCAVE-CONVEX PROBLEM INVOLVING THE FRACTIONAL LAPLACIAN 3

Theorem 1.4. Let α ≥ 1. Then there exists a constant C > 0 such that, for any0 < λ ≤ Λ, every solution to Problem (1.1) satisfies

‖u‖∞ ≤ C.

The proof of this last result relies on the classical argument of rescaling in-troduced in [25] which yields to problems on unbounded domains, which requiresome Liouville-type results, which can be seen in [32]. This is the point where therestriction α ≥ 1 appears.

The paper is organized as follows: in Section 2 we recollect some properties of thefractional Laplacian in the whole space, and establish a trace inequality correspond-ing to this operator; the fractional Laplacian in a bounded domain is considered inSection 3, by means of the use of the α-harmonic extension; this includes studyingan associated linear equation in the local version. The main section, Section 4, con-tains the results related to the nonlocal nonlinear problem (1.1), where we proveTheorems 1.1–1.4.

2. The fractional Laplacian in RN

2.1. Preliminaries. Let u be a regular function in RN . We say that w = Eα(u)

is the α-harmonic extension of u to the upper half-space, RN+1+ , if w is a solution

to the problem

− div(y1−α∇w) = 0 in RN+1+ ,

w = u on RN × y = 0.

In [16] it is proved that

(2.1) limy→0+

y1−α∂w

∂y(x, y) = −κα(−∆)α/2u(x),

where κα = 21−αΓ(1−α/2)Γ(α/2) . Observe that κα = 1 for α = 1 and κα ∼ 1/(2 − α) as

α → 2−. As we pointed out in the Introduction, identity (2.1) allows to formulatenonlocal problems involving the fractional powers of the Laplacian in R

N as localproblems in divergence form in the half-space R

N+1+ .

The appropriate functional spaces to work with are Xα(RN+1+ ) and Hα/2(RN ),

defined as the completion of C∞0 (RN+1

+ ) and C∞0 (RN ), respectively, under the

norms

‖φ‖2Xα =

RN+1+

y1−α|∇φ(x, y)|2 dxdy,

‖ψ‖2Hα/2 =

RN

|2πξ|α|ψ(ξ)|2 dξ =∫

RN

|(−∆)α/4ψ(x)|2 dx.

The extension operator is well defined for smooth functions through a Poissonkernel, whose explicit expression is given in [16]. It can also be defined in the space

Hα/2(RN ), and in fact

(2.2) ‖Eα(ψ)‖Xα = cα‖ψ‖Hα/2 , ∀ψ ∈ Hα/2(RN ),

4 BRANDLE, COLORADO, AND DE PABLO

where cα =√κα , see Lemma 2.2. On the other hand, for a function φ ∈ Xα(RN+1

+ ),

we will denote its trace on RN × y = 0 as Tr(φ). This trace operator is also well

defined and it satisfies

(2.3) ‖Tr(φ)‖Hα/2 ≤ c−1α ‖φ‖Xα .

2.2. A trace inequality. In order to prove regularity of solutions to problem (1.1)we will use a trace immersion. As a first step we show that the corresponding resultfor the whole space holds. Although most of the results used in order to proveTheorem 2.1 below are known we have collected them for the readers convenience.

First of all we prove inequality (2.3). The Sobolev embedding yields then, that

the trace also belongs to L2∗α(RN ), where 2∗α = 2NN−α . Even the best constant

associated to this inclusion is attained and can be characterized.

Theorem 2.1. For every z ∈ Xα(RN+1+ ) it holds

(2.4)

(∫

RN

|v(x)| 2NN−α dx

)N−αN

≤ S(α,N)

RN+1+

y1−α|∇z(x, y)|2 dxdy,

where v = Tr(z). The best constant takes the exact value

(2.5) S(α,N) =Γ(α2 )Γ(

N−α2 )(Γ(N))

αN

2πα2 Γ(2−α

2 )Γ(N+α2 )(Γ(N2 ))

αN

and it is achieved when v takes the form

(2.6) v(x) =(|x− x0|2 + τ2

)−N+α2 ,

for some x0 ∈ RN , τ ∈ R, and z = Eα(v).

The analogous results for the classical Laplace operator can be found in [22, 31].

The proof of Theorem 2.1 follows from a series of lemmas, that we prove next.

Lemma 2.2. Let v ∈ Hα/2(RN ) and let z = Eβ(v) be its β-harmonic extension,

β ∈ (α/2, 2). Then z ∈ Xα(RN+1+ ) and moreover there exists a positive universal

constant c(α, β) such that

(2.7) ‖v‖Hα/2 = c(α, β)‖z‖Xα .

In particular if β = α we have c(α, α) = 1/√κα.

Inequality (2.4) needs only the case β = α, which was included in the proof ofthe local characterization of (−∆)α/2 in [16]. The calculations performed in [16]can be extended to cover the range α/2 < β < 2 and in particular includes the caseβ = 1 proved in [40].

Proof. Since z = Eβ(v), by definition z solves div(y1−β∇z) = 0, which is equivalentto

∆xz +1− β

y

∂z

∂y+∂2z

∂y2= 0.

Taking Fourier transform in x ∈ RN for y > 0 fixed, we have

−4π2|ξ|2z + 1− β

y

∂z

∂y+∂2z

∂y2= 0.

A CONCAVE-CONVEX PROBLEM INVOLVING THE FRACTIONAL LAPLACIAN 5

and z(ξ, 0) = v(ξ). Therefore z(ξ, y) = v(ξ)φβ(2π|ξ|y), where φβ solves the problem

(2.8) −φ+1− β

sφ′ + φ′′ = 0, φ(0) = 1, lim

s→∞φ(s) = 0.

In fact, φβ minimizes the functional

Hβ(φ) =

∫ ∞

0

(|φ(s)|2 + |φ′(s)|2)s1−β ds.

and it can be shown that it is a combination of Bessel functions, see [29]. Moreprecisely, φβ satisfies the following asymptotic behaviour

(2.9)

φβ(s) ∼ 1− c1sβ , for s→ 0,

φβ(s) ∼ c2sβ−12 e−s, for s→ ∞,

where

c1(β) =21−βΓ(1− β/2)

βΓ(β/2), c2(β) =

21−β2 π1/2

Γ(β/2).

Now we observe that∫

RN

|∇z(x, y)|2 dx =

RN

(|∇xz(x, y)|2 +

∣∣∣∂z∂y

(x, y)∣∣∣2)dx

=

RN

(4π2|ξ|2|z(ξ, y)|2 +

∣∣∣∂z∂y

(ξ, y)∣∣∣2)dξ.

Then, multiplying by y1−α and integrating in y,∫ ∞

0

RN

y1−α|∇z(x, y)|2 dxdy

=

∫ ∞

0

RN

4π2|ξ|2|v(ξ)|2(|φβ(2π|ξ|y)|2 + |φ′β(2π|ξ|y)|2

)y1−α dξdy

=

∫ ∞

0

(|φβ(s)|2 + |φ′β(s)|2)s1−α ds

RN

|2πξ|α|v(ξ)|2 dξ.

Using (2.9) we see that the integral∫∞

0(|φβ |2+ |φ′β|2)s1−α ds is convergent provided

β > α/2. This proves (2.7) with c(α, β) = (Hα(φβ))−1/2. 2

Remark 2.1. If β = 1 we have φ1(s) = e−s, and Hα(φ1) = 2α−1Γ(2 − α),see [40]. Moreover, when β = α, integrating by parts and using the equationin (2.8), and (2.9), we obtain(2.10)

Hα(φα) =

∫ ∞

0

[φ2α(s) + (φ′α)2(s)]s1−α ds = − lim

s→0s1−αφ′α(s) = αc1(α) = κα.

Lemma 2.3. Let z ∈ Xα(RN+1+ ) and let w = Eα(Tr(z)) be its α-harmonic associ-

ated function (the extension of the trace). Then

‖z‖2Xα = ‖w‖2Xα + ‖z − w‖2Xα .

6 BRANDLE, COLORADO, AND DE PABLO

Proof. Observe that, for h = z − w, we have

‖z‖2Xα =

RN+1+

y1−α(|∇w|2 + |∇h|2 + 2⟨∇w,∇h

⟩).

But, since Tr(h) = 0, we have

RN+1+

y1−α⟨∇w,∇h

⟩dxdy = 0. 2

Lemma 2.4. If g ∈ L2N

N+α (RN ), and f ∈ Hα/2(RN ), then there exists a constantℓ(α,N) > 0 such that

(2.11)

∣∣∣∣∫f(x) g(x) dx

∣∣∣∣ ≤ ℓ(α,N)‖f‖Hα/2‖g‖ 2NN+α

.

Moreover, the equality in (2.11) with the best constant holds when f and g take theform (2.6).

The proof follows and standard argument that can be found, for instance in [21,40].

Proof. By Parceval’s identity and Cauchy-Schwarz’s inequality, we have(∫

RN

f(x) g(x) dx

)2

=

(∫

RN

f(ξ) g(ξ) dξ

)2

≤(∫

RN

|2πξ|α |f(ξ)|2 dξ) (∫

RN

|2πξ|−α |g(ξ)|2 dξ).

The second term can be written using [30] as∫

RN

|2πξ|−α |g(ξ)|2 dξ = b(α,N)

R2N

g(x)g(x′)

|x− x′|N−αdxdx′,

where

b(α,N) =Γ(N−α

2 )

2απN/2Γ(α2 ),

We now use the following Hardy-Littlewood-Sobolev inequality,∫

R2N

g(x)g(x′)

|x− x′|N−αdxdx′ ≤ d(α,N)‖g‖22N

N+α,

see again [30], where

d(α,N) =π

N−α2 Γ(α/2)(Γ(N))

αN

Γ((N + α)/2)(Γ(N/2))αN,

with equality if g takes the form (2.6). From this we obtain the desired esti-

mate (2.11) with the constant ℓ(α,N) =√b(α,N)d(α,N).

When applying Cauchy-Schwarz’s inequality, we obtain an identity provided the

functions |ξ|α/2f(ξ) and |ξ|−α/2g(ξ) are proportional. This means

g(ξ) = c|ξ|αf(ξ) = c[(−∆)α/2f ]∧ (ξ).

We end by observing that if g takes the form (2.6) and g = c(−∆)α/2f then f alsotakes the form (2.6). In fact, the only positive regular solutions to (−∆)α/2f =

cfN+αN−α take the form (2.6), see [18]. 2

A CONCAVE-CONVEX PROBLEM INVOLVING THE FRACTIONAL LAPLACIAN 7

Proof of Theorem 2.1. We apply Lemma 2.4 with g = |f |N+αN−α−1f , then use

Lemma 2.2 and conclude using Lemma 2.3. The best constant is S(α,N) =ℓ2(α,N)/κα. 2

Remark 2.2. If we let α tend to 2, when N > 2, we recover the classical Sobolevinequality for a function in H1(RN ), with the same constant, see [38]. In order topass to the limit in the right-hand side of (2.4), at least formally, we observe that(2−α)y1−α dy is a measure on compact sets of R+ converging (in the weak-* sense)to a Dirac delta. Hence

limα→2−

∫ 1

0

(∫

RN

|∇z(x, y)|2 dx)(2− α)y1−α dy =

RN

|∇v(x)|2 dx.

We then obtain(∫

RN

|v(x)| 2NN−2 dx

)N−2N

≤ S(N)

RN

|∇v(x)|2 dx,

with the best constant S(N) = limα→2−

S(α,N)2−α = 1

πN(N−2)

(Γ(N)

Γ(N/2)

)N2

. It is achieved

when v takes the form (2.6) with α replaced by 2.

3. The fractional Laplacian in a bounded domain

3.1. Spectral decomposition. To define the fractional Laplacian in a boundeddomain we follow [14], see also [36]. To this aim we consider the cylinder

CΩ = (x, y) : x ∈ Ω, y ∈ R+ ⊂ RN+1+ ,

and denote by ∂LCΩ its lateral boundary. We also define the energy space

Xα0 (CΩ) = z ∈ L2(CΩ) : z = 0 on ∂LCΩ,

y1−α|∇z(x, y)|2 dxdy <∞,

with norm

‖z‖2Xα0:=

y1−α|∇z(x, y)|2 dxdy.

We want to characterize the space Θ(Ω), which is the image of Xα0 (CΩ) under the

trace operator,

Θ(Ω) = u = Tr(w) : w ∈ Xα0 (CΩ).

In particular we will show that the fractional Laplacian in a bounded domain Ωis well defined for functions in Θ(Ω). To this aim, let us start considering theextension operator and fractional Laplacian for smooth functions.

Definition 3.1. Given a regular function u, we define its α-harmonic extensionw = Eα(u) to the cylinder CΩ as the solution to the problem

(3.1)

− div(y1−α∇w) = 0 in CΩ,w = 0 on ∂LCΩ,

Tr(w) = u on Ω.

As in the whole space, there is also a Poisson formula for the extension operator ina bounded domain, defined through the Laplace transform and the heat semigroupgenerator et∆, see [36] for details.

8 BRANDLE, COLORADO, AND DE PABLO

Definition 3.2. The fractional operator (−∆)α/2 in Ω, acting on a regular functionu, is defined by

(3.2) (−∆)α/2u(x) = − 1

καlim

y→0+y1−α ∂w

∂y(x, y),

where w = Eα(u) and κα is given as in (2.1).

It is classical that the powers of a positive operator in a bounded domain aredefined through the spectral decomposition using the powers of the eigenvalues ofthe original operator. We show next that in this case this is coherent with theDirichlet-Neumann operator defined above.

Lemma 3.3. Let (ϕj , λj) be the eigenfunctions and eigenvectors of −∆ in Ω (with

Dirichlet boundary data). Then (ϕj , λα/2j ) are the eigenfunctions and eigenvec-

tors of (−∆)α/2 in Ω (with the same boundary conditions). Moreover, Eα(ϕj) =

ϕj(x)ψ(λ1/2j y), where ψ solves the problem

ψ′′ +(1− α)

sψ′ = ψ, s > 0,

− lims→0+

s1−αψ′(s) = κα,

ψ(0) = 1.

The proof of this result, based on separating variables, is straightforward. Thefunction ψ coincides with the solution φα in problem (2.8).

Lemma 3.4. Let u ∈ L2(Ω). If u =∑ajϕj , where

∑a2jλ

α/2j < ∞, then Eα(u) ∈

Xα0 (CΩ) and

Eα(u)(x, y) =∑

ajϕj(x)ψ(λ1/2j y).

Proof. The formula for the extension follows immediately from Lemma 3.3.

Put w = Eα(u). Using the orthogonality of the family ϕj, together with∫Ωϕ2j = 1,

∫Ω|∇ϕj |2 = λj , and (2.10), we have

RN+1+

y1−α|∇w(x, y)|2 dxdy

=

∫ ∞

0

y1−α

Ω

(∑a2j |∇ϕj(x)|2ψ(λ1/2j y)2 + a2jλjϕj(x)

2(ψ′(λ1/2j y))2

)dxdy

=

∫ ∞

0

y1−α∑

a2jλj

(ψ(λ

1/2j y)2 + (ψ′(λ

1/2j y))2

)dy

=∑

a2jλα/2j

∫ ∞

0

s1−α(ψ(s)2 + (ψ′(s))2

)ds = κα

∑a2jλ

α/2j <∞.

2

As in Section 2, we get that the extension operator minimizes the norm inXα

0 (CΩ).Lemma 3.5. Let z ∈ Xα

0 (CΩ) and let w = Eα(Tr(z)). Then

‖z‖2Xα0 (CΩ) = ‖w‖2Xα

0 (CΩ) + ‖z − w‖2Xα0 (CΩ).

A CONCAVE-CONVEX PROBLEM INVOLVING THE FRACTIONAL LAPLACIAN 9

Lemmas 3.4 and 3.5 imply that the space Θ(Ω) coincides with the space

Hα/20 (Ω) =

u =

∑ajϕj ∈ L2(Ω) :

∑a2jλ

α/2j <∞

,

equipped with the norm

‖u‖H

α/20 (Ω)

=(∑

a2jλα/2j

)1/2

= ‖(−∆)α/4u‖2.

Observe that Lemma 3.4 gives

‖u‖H

α/20 (Ω)

= κ−1/2α ‖Eα(u)‖Xα

0 (CΩ),

which is the same as in (2.2) but for the spaces and norms involved. As a directconsequence we get that the fractional Laplacian is well defined in this space.

Corollary 3.6. Let u ∈ Hα/20 (Ω), then (−∆)α/2u =

∑ajλ

α/2j ϕj.

Let now v ∈ Xα0 (CΩ). Its extension by zero outside the cylinder CΩ can be ap-

proximated by functions with compact support in RN+1+ . Thus, the trace inequal-

ity (2.4), together with Holder’s inequality, gives a trace inequality for boundeddomains.

Corollary 3.7. For any 1 ≤ r ≤ 2NN−α , and every z ∈ Xα

0 (CΩ), it holds

(3.3)

(∫

Ω

|v(x)|r dx)2/r

≤ C(r, α,N, |Ω|)∫

y1−α|∇z(x, y)|2 dxdy,

where v = Tr(z).

3.2. The linear problem. We now use the extension problem (3.1) and the ex-pression (3.2) to reformulate the nonlocal problems in a local way. Let g be aregular function and consider the following problems: the nonlocal problem

(3.4)

(−∆)α/2u = g(x) in Ω,

u = 0 on ∂Ω,

and the corresponding local one

(3.5)

− div(y1−α∇w) = 0 in CΩ,w = 0 on ∂LCΩ,

− 1

καlim

y→0+y1−α ∂w

∂y= g(x) on Ω.

We want to define the concept of solution to (3.4), which is done in terms of thesolution to problem (3.5).

Definition 3.8. We say that w ∈ Xα0 (CΩ) is an energy solution to problem (3.5),

if for every function ϕ ∈ C10(CΩ) it holds

(3.6)

y1−α⟨∇w(x, y),∇ϕ(x, y)

⟩dxdy =

Ω

καg(x)ϕ(x, 0) dx.

In fact more general test functions can be used in the above formula, when-ever the integrals make sense. A supersolution (subsolution) is a function thatverifies (3.6) with equality replaced by ≥ (≤) for every nonnegative test function.

10 BRANDLE, COLORADO, AND DE PABLO

Definition 3.9. We say that u ∈ Hα/20 (Ω) is an energy solution to problem (3.4)

if u = Tr(w) and w is an energy solution to problem (3.5).

In order to deal with problem (3.5) we will assume, without loss of generality,κα = 1, by changing the function g.

In [13] this linear problem is also mentioned. There some results are obtainedusing the theory of degenerate elliptic equations developed in [23], in particulara regularity result for bounded solutions to this problem is obtained in [13]. Weprove here that the solutions are in fact bounded if g satisfies a minimal integrabilitycondition.

Theorem 3.10. Let w be a solution to problem (3.5). If g ∈ Lr(Ω), r > Nα , then

w ∈ L∞(CΩ).

Proof. The proof follows the same ideas as in [26, Theorem 8.15] and uses thetrace inequality (3.3). Without loss of generality we may assume w ≥ 0, and thissimplifies notation. The general case is obtained in a similar way.

We define for β ≥ 1 and K ≥ k (k to be chosen later) a C1([k,∞)) function H ,as follows:

H(z) =

zβ − kβ , z ∈ [k,K],linear, z > K.

Let us also define v = w + k and choose as test function ϕ,

ϕ = G(v) =

∫ v

k

|H ′(s)|2 ds, ∇ϕ = |H(v)|2∇v.

Replacing this test function into the definition of energy solution we obtain on onehand:

(3.7)

y1−α⟨∇w,∇ϕ

⟩dxdy =

y1−α∣∣∇v|2|H ′(v)|2 dxdy

=

y1−α∣∣∇H(v)|2 dxdy

≥(∫

Ω

|H(v)| 2NN−α dx

)N−αN

= ‖H(v)‖22NN−α

,

where the last inequality follows by (3.3).

On the other hand

(3.8)

Ω

g(x)ϕ(x, 0) dx =

Ω

g(x)G(v) dx ≤∫

Ω

g(x)vG′(v) dx

≤ 1

k

Ω

g(x)v2|H ′(v)|2 dx =1

k

Ω

g(x)|vH ′(v)|2 dx.

Inequality (3.7) together with (3.8), leads to

(3.9) ‖H(v)‖ 2NN−α

≤(1

k‖g‖r

)1/2

‖(vH ′(v))2‖1/2rr−1

= ‖vH ′(v)‖ 2rr−1

,

by choosing k = ‖g‖r. Letting K → ∞ in the definition of H , the inequality (3.9)becomes

‖v‖ 2NβN−α

≤ ‖v‖ 2rβr−1

.

A CONCAVE-CONVEX PROBLEM INVOLVING THE FRACTIONAL LAPLACIAN 11

Hence for all β ≥ 1 the inclusion v ∈ L2rβr−1 (Ω) implies the stronger inclusion v ∈

L2NβN−α (Ω), since 2Nβ

N−α > 2rβr−1 provided r > N

α . The result follows now, as in [26], by

an iteration argument, starting with β = N(r−1)r(N−α) > 1 and v ∈ L

2NN−α (Ω). This gives

v ∈ L∞(Ω), and then w ∈ L∞(CΩ). In fact we get the estimate

‖w‖∞ ≤ c(‖w‖Xα + ‖g‖r).2

Corollary 3.11. Let w be a solution to problem (3.5). If g ∈ L∞(Ω), then w ∈Cγ(CΩ) for some γ ∈ (0, 1).

Proof. It follows directly from Theorem 3.10 and [13, Lemma 4.4]. 2

4. The nonlinear nonlocal problem

4.1. The local realization. We deal now with the core of the paper; i.e. thestudy of the nonlocal problem (1.1). We write that problem in local version in thefollowing way: a solution to problem (1.1) is a function u = Tr(w), the trace of won Ω× y = 0, where w solves the local problem

(4.1)

− div(y1−α∇w) = 0 in CΩ,w = 0 on ∂LCΩ,

∂w

∂να= f(w) in Ω,

where

(4.2)∂w

∂να(x) = − lim

y→0+y1−α∂w

∂y(x, y).

In order to simplify notation in what follows we will denote w for the functiondefined in the cylinder CΩ as well as for its trace Tr(w) on Ω× y = 0.

As we have said, we will focus on the particular nonlinearity

(4.3) f(s) = fλ(s) = λsq + sp.

However many auxiliary results will be proved for more general reactions f satis-fying the growth condition

(4.4) 0 ≤ f(s) ≤ c(1 + |s|p), for some p > 0.

Remark 4.1. In the definition (4.2) we have neglected the constant κα appearingin (3.2) by a simple rescaling. Therefore, the results on the coefficient λ for thelocal problem (4.1)–(4.3) in this section are translated into problem (1.1) with λ

multiplied by κp(q−1)−1α .

Following Definition 3.8, we say that w ∈ Xα0 (CΩ) is an energy solution of (4.1)

if the following identity holds∫

y1−α⟨∇w,∇ϕ

⟩dxdy =

Ω

f(w)ϕdx

12 BRANDLE, COLORADO, AND DE PABLO

for every regular test function ϕ. In the analogous way we define sub- and super-solution.

We consider now the functional

J(w) =1

2

y1−α|∇w|2 dxdy −∫

Ω

F (w) dx,

where F (s) =∫ s

0 f(τ) dτ . For simplicity of notation, we define f(s) = 0 for s ≤ 0.

Recall that the trace satisfies w ∈ Lr(Ω), for every 1 ≤ r ≤ 2NN−α if N > α, 1 < r ≤

∞ if N ≤ α. In particular if p ≤ N+αN−α , and f verifies (4.4) then F (w) ∈ L1(Ω), and

the functional is well defined and bounded from below.

It is well known that critical points of J are solutions to (4.1) with a generalreaction f . We consider also the minimization problem

I = inf∫

y1−α|∇w|2 dxdy : w ∈ Xα0 (CΩ),

Ω

F (w) dx = 1,

for which, by classical variational techniques, one has that below the critical expo-nent, the infimum I is achieved.

Proposition 4.1. If f satisfies (4.4) with p < N+αN−α , then there exists a nonnegative

function w ∈ Xα0 (CΩ) for which I is achieved.

We now establish two preliminary results. The first one is a classical procedureof sub- and supersolutions to obtain a solution. We omit its proof.

Lemma 4.2. Assume there exist a subsolution w1 and a supersolution w2 toproblem (4.1) verifying w1 ≤ w2. Then there also exists a solution w satisfyingw1 ≤ w ≤ w2 in CΩ.

The second one is a comparison result for concave nonlinearities. The prooffollows the lines of the corresponding one for the Laplacian performed in [10].

Lemma 4.3. Assume that f(t) is a function verifying that f(t)/t is decreasing fort > 0. Consider w1, w2 ∈ Xα

0 (CΩ) positive subsolution, supersolution respectively toproblem (4.1). Then w1 ≤ w2 in CΩ.

Proof. By definition we have, for the nonnegative test functions ϕ1 and ϕ2 to bechosen in an appropriate way,

y1−α⟨∇w1,∇ϕ1

⟩dxdy ≤

Ω

f(w1)ϕ1 dx,∫

y1−α⟨∇w2,∇ϕ2

⟩dxdy ≥

Ω

f(w2)ϕ2 dx.

Now let θ(t) be a smooth nondecreasing function such that θ(t) = 0 for t ≤ 0,θ(t) = 1 for t ≥ 1, and set θε(t) = θ(t/ε). If we put, in the above inequalities

ϕ1 = w2 θε(w1 − w2), ϕ2 = w1 θε(w1 − w2),

we get

I1 ≥∫

Ω

w1w2

(f(w2)

w2− f(w1)

w1

)θε(w1 − w2) dx,

A CONCAVE-CONVEX PROBLEM INVOLVING THE FRACTIONAL LAPLACIAN 13

where

I1 :=

y1−α⟨w1 ∇w2 − w2 ∇w1,∇(w1 − w2)

⟩θ′ε(w1 − w2) dxdy.

Now we estimate I1 as follows:

I1 ≤∫

y1−α⟨∇w1, (w1 − w2)∇(w1 − w2)

⟩θ′ε(w1 − w2) dxdy

=

y1−α⟨∇w1,∇γε(w1 − w2)

⟩dxdy

where γ′ǫ(t) = tθ′ε(t). Therefore, since 0 ≤ γε ≤ ε, we have

I1 ≤∫

Ω

f(w1)γε(w1 − w2) dx ≤ cε.

We end as in [4]. Letting ε tend to zero, we obtain

Ω∩w1>w2

w1w2

(f(w2)

w2− f(w1)

w1

)dx ≤ 0,

which together with the hypothesis on f gives w1 ≤ w2 in Ω. Comparison in CΩfollows easily by the maximum principle. 2

Now we show that the solutions to problem (4.1)–(4.4) are bounded and Holdercontinuous. Later on, in Section 4.4, we will obtain a uniform L∞-estimate in thecase where f is given by (4.3) and the convex power is subcritical.

Proposition 4.4. Let f satisfy (4.4) with p < N+αN−α , and let w ∈ Xα

0 (CΩ) be an

energy solution to problem (4.1). Then w ∈ L∞(CΩ) ∩ Cγ(Ω) for some 0 < γ < 1.

Proof. The proof follows closely the technique of [11]. As in the proof of Theo-rem 3.10, we assume w ≥ 0. We consider, formally, the test function ϕ = wβ−p,for some β > p + 1. The justification of the following calculations can be madesubstituting ϕ by some approximated truncature. We therefore proceed with theformal analysis. We get, using the trace immersion, the inequality

(∫

Ω

w(β−p+1)N

N−α

)N−αN

≤ C(β, α,N,Ω)

Ω

wβ .

This estimate allows to obtain the following iterative process

‖w‖βj+1 ≤ C‖w‖βj

βj−p+1

βj,

with βj+1 = NN−α(βj + 1 − p). To have βj+1 > βj we need βj >

(p−1)Nα . Since

w ∈ L2∗α(Ω), starting with β0 = 2NN−α , we get the above restriction provided p <

N+αN−α . It is clear that in a finite number of steps we get, for g(x) = f(w(x, 0)), the

regularity g ∈ Lr for some r > Nα . As a consequence, we obtain the conclusion

applying Theorem 3.10 and Corollary 3.11. 2

14 BRANDLE, COLORADO, AND DE PABLO

4.2. A nonexistence result.

Theorem 4.5. Assume f is a C1 function with primitive F , and w is an energysolution to problem (4.1). Then the following Pohozaev-type identity holds

1

2

∂LCΩ

y1−α⟨(x, y), ν

⟩|∇w|2 dσ −N

Ω

F (w) dx +N − α

2

Ω

wf(w) dx = 0.

Proof. Just use the identity

⟨(x, y), ν

⟩yα−1 div(y1−α∇w) + div

[y1−α

(⟨(x, y),∇w

⟩− 1

2(x, y)|∇w|2

)]

+(N + 2− α

2− 1

)|∇w|2 = 0,

where ν is the (exterior) normal vector to ∂Ω. It is calculus matter to check thisequality. 2

Corollary 4.6. If Ω is starshaped and the nonlinearity f satisfies the inequality((N − α)sf(s) − 2NF (s)) ≥ 0, then problem (4.1) has no solution. In particular,in the case f(s) = sp this means that there is no solution for any p ≥ N+α

N−α .

The case α = 1 has been proved in [14]. The corresponding result for theLaplacian (problem (1.1) with α = 2) comes from [34].

4.3. Proof of Theorems 1.1-1.2. We prove here Theorems 1.1-1.2 in terms ofthe solution of the local version (4.1). For the sake of readability we split the proofof Theorem 1.1 into several lemmas. From now on we will denote

(Pλ) ≡

− div(y1−α∇w) = 0 in CΩ,w = 0 on ∂LCΩ,

∂w

∂να= λwq + wp, w > 0 in Ω,

and consider the associated energy functional

Jλ(w) =1

2

y1−α|∇w|2 dxdy −∫

Ω

Fλ(w) dx,

where

Fλ(s) =λ

q + 1sq+1 +

1

p+ 1sp+1.

Lemma 4.7. Let Λ be defined by

Λ = supλ > 0 : Problem (Pλ) has solution.Then Λ <∞.

Proof. Consider the eigenvalue problem associated to the first eigenvalue λ1, andlet ϕ1 > 0 be an associated eigenfunction, i.e.,

− div(y1−α∇ϕ1) = 0 in CΩ,ϕ1 = 0 on ∂LCΩ,

∂ϕ1

∂να= λ1ϕ1 in Ω.

A CONCAVE-CONVEX PROBLEM INVOLVING THE FRACTIONAL LAPLACIAN 15

Then using ϕ1 as a test function in (Pλ) we have that

(4.5)

Ω

(λwq + wp)ϕ1 dx = λ1

Ω

wϕ1 dx.

There exist positive constants c, δ such that λtq + tp > cλδt, for any t > 0. Sinceu > 0 we obtain, using (4.5), that cλδ < λ1 which implies Λ <∞. 2

This proves the third statement in Theorem 1.1.

Lemma 4.8. Problem (Pλ) has a positive solution for every 0 < λ < Λ. Moreover,the family wλ of minimal solutions is increasing with respect to λ.

Remark 4.2. Although this Λ is not exactly the same as that of Theorem 1.1, seeRemark 4.1, we have not changed the notation for the sake of simplicity.

Proof. The associated functional to problem (Pλ) verifies, using Corollary 3.7,

Jλ(w) =1

2

y1−α|∇w|2 dxdy −∫

Ω

Fλ(w) dx

≥ 1

2

y1−α|∇w|2 dxdy − λC1

(∫

y1−α|∇w|2 dxdy) q+1

2

−C2

(∫

y1−α|∇w|2 dxdy) p+1

2

,

for some positive constants C1 and C2. Then for λ small enough there exist twosolutions of problem (Pλ), one given by minimization and another one given by theMountain-Pass Theorem, [5]. The proof is standard, based on the geometry of thefunction g(t) = 1

2 t2 − λC1t

q+1 − C2tp+1, see for instance [24] for more details.

We now show that there exists a solution for every λ ∈ (0,Λ). By definitionof Λ, we know that there exists a solution corresponding to any value of λ closeto Λ. Let us denote it by µ, and let wµ be the associated solution. Now wµ is asupersolution for all problems (Pλ) with λ < µ. Take vλ the unique solution toproblem (4.1) with f(s) = λsq. Obviously vλ is a subsolution to problem (Pλ).By Lemma 4.3 vλ ≤ wµ. Therefore by Lemma 4.2 we conclude that there is asolution for all λ ∈ (0, µ), and as a consequence, for the whole open interval (0,Λ).Moreover, this solution is the minimal one. The monotonicity follows directly fromthe comparison lemma. 2

This proves the first statement in Theorem 1.1.

Lemma 4.9. Problem (Pλ) has at least one solution if λ = Λ.

Proof. Let λn be a sequence such that λn ր Λ. We denote by wn = wλn the min-imal solution to problem (Pλn). As in [4], we can prove that the linearized equationat the minimal solution has nonnegative eigenvalues. Then it follows, as in [4] again,Jλn(wn) < 0. Since J ′(wλ) = 0, one easily gets the bound ‖wn‖Xα

0 (CΩ) ≤ k. Hence,there exists a weakly convergent subsequence in Xα

0 (CΩ) and as a consequence aweak solution of (Pλ) for λ = Λ. 2

This proves the second statement in Theorem 1.1 and finishes the proof of thistheorem.

16 BRANDLE, COLORADO, AND DE PABLO

Proof of Theorem 1.2. In order to find a second solution we follow some argumentsin [4]. It is essential to have that the first solution is given as a local minimum of theassociated functional, Jλ. To prove this last assertion we modify some argumentsdeveloped in [2].

Let λ0 ∈ (0,Λ) be fixed and consider λ0 < λ1 < Λ. Take φ0 = wλ0 , φ1 = wλ1

the two minimal solutions to problem (Pλ) with λ = λ0 and λ = λ1 respectively,then by comparison, φ0 < φ1. We define

M = w ∈ Xα0 (CΩ) : 0 ≤ w ≤ φ1.

Notice that M is a convex closed set of Xα0 (CΩ). Since Jλ0 is bounded from bellow

in M and it is semicontinuous on M , we get the existence of ω ∈ M such thatJλ0(ω) = infw∈M Jλ0(w). Let v0 be the unique positive solution to problem

(4.6)

− div(y1−α∇v0) = 0 in CΩ,v0 = 0 on ∂LCΩ,

∂v0∂να

= vq0 in Ω.

Since for 0 < ε << λ0, and Jλ0(εv0) < 0, we have εv0 ∈M , then ω 6= 0. ThereforeJλ0(ω) < 0. By arguments similar to those in [37, Theorem 2.4], we obtain that ωis a solution to problem (Pλ0). There are two possibilities:

• If ω 6≡ wλ0 , then the result follows.• If ω ≡ wλ0 , we have just to prove that ω is a local minimum of Jλ0 . Thenthe conclusion follows by using an argument close to the one in [4], so weomit the complete details.

We argue by contradiction.

Suppose that ω is not a local minimum of Jλ0 in Xα0 (CΩ), then there exists a

sequence vn ⊂ Xα0 (CΩ) such that ‖vn − ω‖Xα

0→ 0 and Jλ0(vn) < Jλ0(ω).

Let wn = (vn − φ1)+ and zn = max0,minvn, φ1. It is clear that zn ∈M and

zn(x, y) =

0 if vn(x, y) ≤ 0,

vn(x, y) if 0 ≤ vn(x, y) ≤ φ1(x, y),

φ1(x, y) if φ1(x, y) ≤ vn(x, y).

We set

Tn ≡ (x, y) ∈ CΩ : zn(x, y) = vn(x, y), Sn ≡ supp(wn),

Tn = Tn ∩ Ω, Sn = Sn ∩ Ω.

Notice that supp(v+n ) = Tn ∪ Sn. We claim that

(4.7) |Sn|Ω → 0 as n→ ∞,

where |A|Ω ≡∫Ω χA(x) dx.

A CONCAVE-CONVEX PROBLEM INVOLVING THE FRACTIONAL LAPLACIAN 17

By the definition of Fλ, we set Fλ0 (s) =λ0q + 1

sq+1+ +

1

p+ 1sp+1+ , for s ∈ R, and get

Jλ0(vn) =1

2

y1−α|∇vn|2 dxdy −∫

Ω

Fλ0 (vn) dx

=1

2

Tn

y1−α|∇zn|2 dxdy −∫

Tn

Fλ0(zn) dx +1

2

Sn

y1−α|∇vn|2 dxdy

−∫

Sn

Fλ0(vn) dx+1

2

y1−α|∇v−n |2 dxdy

=1

2

Tn

y1−α|∇zn|2 dxdy −∫

Tn

Fλ0(zn) dx

+1

2

Sn

y1−α|∇(wn + φ1)|2 dxdy −∫

Sn

Fλ0 (wn + φ1) dx

+1

2

y1−α|∇v−n |2 dxdy.

Since ∫

y1−α|∇zn|2 dxdy =

Tn

y1−α|∇vn|2 dxdy +∫

Sn

y1−α|∇φ1|2 dxdy

and ∫

Ω

Fλ0(zn) dx =

Tn

Fλ0(vn) dx+

Sn

Fλ0(φ1) dx,

by using the fact that φ1 is a supersolution to (Pλ) with λ = λ0, we conclude that

Jλ0(vn) = Jλ0(zn) +1

2

Sn

y1−α(|∇(wn + φ1)|2 − |∇φ1|2) dxdy

−∫

Sn

(Fλ0 (wn + φ1)− Fλ0(φ1)) dx +1

2

y1−α|∇v−n |2 dxdy

≥ Jλ0(zn) +1

2‖wn‖2Xα

0+

1

2‖v−n ‖2Xα

0

−∫

Ω

Fλ0(wn + φ1)− Fλ0(φ1)− (Fλ0 )u(φ1)wn dx

≥ Jλ0(ω) +1

2‖wn‖2Xα

0+

1

2‖v−n ‖2Xα

0

−∫

Ω

Fλ0(wn + φ1)− Fλ0(φ1)− (Fλ0 )u(φ1)wn dx.

On one hand, taking into account that 0 < q + 1 < 2, one obtains that

0 ≤ 1

q + 1(wn + φ1)

q+1 − 1

q + 1φq+11 − φq1wn ≤ q

2

w2n

φ1−q1

.

The well known Picone’s inequality (see [33]) establish:

|∇u|2 −∇(u2

v

)· ∇v ≥ 0,

for differentiable functions v > 0, u ≥ 0. In our case, by an approximation argumentwe get

λ0

Ω

w2n

φ1−q1

dx ≤ ‖wn‖2Xα0.

18 BRANDLE, COLORADO, AND DE PABLO

On the other hand, since p+ 1 > 2,

0 ≤ 1

p+ 1(wn + φ1)

p+1 − 1

p+ 1φp+11 − φp1wn ≤ r

2w2

n(wn + φ1)p−1

≤ C(p)(φp−11 w2

n + wp+1n ).

Hence using that p+ 1 < 2∗α and the claim (4.7)∫

Ω

1

p+ 1(wn + φ1)

p+1 − 1

p+ 1φp+11 − φp1wn

dx ≤ o(1)‖wn‖2Xα

0.

As a consequence we obtain that

Jλ0(vn) ≥ Jλ0(ω) +1

2‖wn‖2Xα

0(1− q − o(1)) +

1

2‖v−n ‖2Xα

0

≡ Jλ0(ω) +1

2‖wn‖2Xα

0(1− q − o(1)) + o(1).

Since q < 1, there results that Jλ0(ω) > Jλ0(vn) ≥ Jλ0(ω) for n > n0, a contradic-tion with the main hypothesis. Hence ω is a minimum.

To finish the proof we have to prove the claim (4.7). For ε > 0 small, and δ > 0(δ to be chosen later), we consider

En = x ∈ Ω : vn(x) ≥ φ1(x) ∧ φ1(x) > ω(x) + δ,Fn = x ∈ Ω : vn(x) ≥ φ1(x) ∧ φ1(x) ≤ ω(x) + δ.

Using the fact that

0 = |x ∈ Ω : φ1(x) < ω(x)| =

∣∣∣∣∣∣

∞⋂

j=1

x ∈ Ω : φ1(x) ≤ ω(x) +

1

j

∣∣∣∣∣∣

= limj→∞

∣∣∣∣x ∈ Ω : φ1(x) ≤ ω(x) +

1

j

∣∣∣∣ ,

we get for j0 large enough, that if δ < 1j0

then

|x ∈ Ω : φ1(x) ≤ ω(x) + δ| ≤ ε

2.

Hence we conclude that |Fn|Ω ≤ ε2 .

Since ‖vn − ω‖Xα0→ 0 as n → ∞, in particular by the trace embedding, ‖vn −

ω‖L2(Ω) → 0. We obtain that, for n ≥ n0 large,

δ2ε

2≥

|vn − ω|2dx ≥∫

En

|vn − ω|2dx ≥ δ2|En|Ω.

Therefore |En|Ω ≤ ε

2. Since Sn ⊂ Fn ∪ En we conclude that |Sn|Ω ≤ ε for n ≤ n0.

Hence |Sn|Ω → 0 as n→ ∞ and the claim follows. 2

4.4. Proof of Theorems 1.3-1.4 and further results. We start with the uni-form L∞-estimates for solutions to problem (1.1) in its local version given by (Pλ).

Theorem 4.10. Assume α ≥ 1, p < N+αN−α and N ≥ 2. Then there exists a constant

C = C(p,Ω) > 0 such that every solution to problem (Pλ) satisfies

‖w‖∞ ≤ C,

A CONCAVE-CONVEX PROBLEM INVOLVING THE FRACTIONAL LAPLACIAN 19

for every 0 ≤ λ ≤ Λ.

The proof is based in a rescaling method and the following two nonexistenceresults, proved in [32]:

Theorem 4.11. Let α ≥ 1. Then the problem in the half-space RN+1+ ,

− div(y1−α∇w) = 0 in RN+1+

∂w

∂να(x) = wp(x, 0) on ∂RN+1

+ = RN

has no solution provided p < N+αN−α , if N ≥ 2, or for every p if N = 1.

Theorem 4.12. The problem in the first quarter

RN+1++ = z = (x′, xN , y) |x′ ∈ R

N−1, xN > 0, y > 0,

− div(y1−α∇w) = 0, xN > 0, y > 0,∂w

∂να(x′, xN ) = wp(x′, xN , 0),

w(x′, 0, y) = 0,

has no positive bounded solution provided p < N+αN−α .

Proof of Theorem 4.10. Assume by contradiction that there exists a sequencewn ⊂ Xα

0 (CΩ) of solutions to (Pλ) verifying that Mn = ‖wn‖∞ → ∞, as n→ ∞.By the Maximum Principle, the maximum of wn is attained at a point (xn, 0) where

xn ∈ Ω. We define Ωn = 1µn

(Ω − xn), with µn = M(1−p)/αn , i.e., we center at xn

and dilate by 1µn

→ ∞ as n→ ∞.

We consider the scaled functions

vn(x, y) =wn(xn + µnx, µny)

Mn, for x ∈ Ωn, y ≥ 0.

It is clear that ‖vn‖ ≤ 1, vn(0, 0) = 1 and moreover

(4.8)

− div(y1−α∇vn) = 0 in CΩn ,

vn = 0 on ∂LCΩn ,

∂vn∂να

= λM q−pn vqn + vpn in Ωn × 0.

By the Arzela-Ascoli Theorem, there exists a subsequence, denoted again by vn,which converges to some function v as n→ ∞. In order to see the problem satisfiedby v we pass to the limit in the weak formulation of (4.8). We observe that ‖vn‖∞ ≤1 implies ‖vn‖Xα

0 (CΩ) ≤ C.

We define dn = dist (xn, ∂Ω), then there are two possibilities as n→ ∞ according

the behaviour of the ratio dn

µn:

(1)

dnµn

n

is not bounded.

(2)

dnµn

n

remains bounded.

20 BRANDLE, COLORADO, AND DE PABLO

In the first case, since Bdn/µn(0) ⊂ Ωn, for another subsequence if necessary, it

is clear that Ωn tends to RN and the limit function v is a solution to

− div(y1−α∇v) = 0 in RN+1+ ,

∂v

∂να= vp on ∂RN+1

+ .

Moreover, v(0, 0) = 1 and v > 0 which is a contradiction with Theorem 4.11.

In the second case, we may assume, again for another subsequence if necessary,that dn

µn→ s ≥ 0 as n → ∞. As a consequence, passing to the limit, the domains

Ωn converge (up to a rotation) to some half-space Hs = x ∈ RN : xN > −s. We

obtain here that v is a solution to

− div(y1−α∇v) = 0 in Hs × (0,∞),

∂v

∂να= vp on Hs × 0,

with ‖v‖∞ = 1, v(0, 0) = 1. In the case s = 0 this is a contradiction with thecontinuity of v. If s > 0, the contradiction comes from Theorem 4.12. 2

We next prove Theorem 1.3 in its local version.

Theorem 4.13. There exists at most one solution to problem (Pλ) with smallnorm.

We follow closely the arguments in [4], so we establish the following previousresult:

Lemma 4.14. Let z be the unique solution to problem (4.6). There exists a constantβ > 0 such that

(4.9) ‖φ‖2Xα0 (CΩ) − q

Ω

zq−1φ2 dx ≥ β‖φ‖2L2(Ω), ∀φ ∈ Xα0 (CΩ).

Proof. We recall that z can be obtained by minimization

min

1

2‖ω‖2Xα

0 (CΩ) −1

q + 1‖w‖q+1

Lq+1(Ω) : ω ∈ Xα0 (CΩ)

.

As a consequence,

‖φ‖2Xα0 (CΩ) − q

Ω

zq−1φ2 dx ≥ 0, ∀φ ∈ Xα0 (CΩ).

This implies that the first eigenvalue ρ1 of the linearized problem

− div(y1−α∇φ) = 0, in CΩ,φ = 0, on ∂LCΩ,

∂φ

∂να− qzq−1φ = ρφ, on Ω× 0,

is nonnegative.

Assume first that ρ1 = 0 and let ϕ be a corresponding eigenfunction. Takinginto account that z is the solution to (4.6) we obtain that

q

Ω

zqϕdx =

Ω

zqϕdx

A CONCAVE-CONVEX PROBLEM INVOLVING THE FRACTIONAL LAPLACIAN 21

which is a contradiction.

Hence ρ1 > 0, which proves (4.9). 2

Proof of Theorem 4.13. Consider A > 0 such that pAp−1 < β, where β is givenin (4.9). Now we prove that problem (Pλ) has at most one solution with L∞-normless than A.

Assume by contradiction that (Pλ) has a second solution w = wλ + v veri-fying ‖w‖∞ < A. Since wλ is the minimal solution, it follows that v > 0 in

Ω × [0,∞). We define now η = λ1

1−q z, where z is the solution to (4.6). Then itverifies −div(y1−α∇η) = 0, with boundary condition ληq. Moreover, wλ is a super-solution to the problem that η verifies. Then by comparison, Lemma 4.3, appliedwith f(t) = λtq, v = η and w = wλ, we get

(4.10) wλ ≥ λ1

1−q z on Ω× 0.Since w = wλ + v is solution to (Pλ) we have, on Ω× 0,

∂(wλ + v)

∂να= λ(wλ + v)q + (wλ + v)p ≤ λwq

λ + λqwq−1λ v + (wλ + v)p,

where the inequality is a consequence of the concavity, hence

∂v

∂να≤ λqwq−1

λ v + (wλ + v)p − wpλ.

Moreover, (4.10) implies wq−1λ ≤ λ−1zq−1. From the previous two inequalities we

get∂v

∂να≤ qzq−1v + (wλ + v)p − wp

λ.

Using that ‖wλ+v‖∞ ≤ A, we obtain (wλ+v)p−wp

λ ≤ pAp−1v. As a consequence,

∂v

∂να− qzq−1v ≤ pAp−1v.

Taking v as a test function and φ = v in (4.9) we arrive to

β

Ω

v2 dx ≤ pAp−1

Ω

v2 dx.

Since pAp−1 < β we conclude that v ≡ 0, which gives the desired contradiction. 2

Remark 4.3. This proof also provides the asymptotic behavior of wλ near λ = 0,

namely wλ ≈ λ1

1−q z, where z is the unique solution to problem (4.6).

Acknowledgments.

C.B. and A.dP. are partially supported by Spanish Project MTM2008-06326-C02-02; E.C.

is partially supported by Spanish Project MTM2009-10878.

References

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22 BRANDLE, COLORADO, AND DE PABLO

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[18] Chen, W.; Li, C.; Ou, B. Classification of solutions for an integral equation. Comm. PureAppl. Math. 59 (2006), no. 3, 330-343.

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tional derivatives. J. Math. Anal. Appl. 295 (2004), no. 1, 225-236.[22] Escobar, J. F. Sharp constant in a Sobolev trace inequality. Indiana Math. J. 37 (1988),

687-698.[23] Fabes, E. B. ; Kenig, C. E. ; Serapioni, R. P. The local regularity of solutions of degenerate

elliptic equations. Comm. Partial Differential Equations 7 (1982), no. 1, 77-116.[24] Garcıa Azorero J.; Peral I. Multiplicity of solutions for elliptic problems with critical exponent

or with non-symetric term. Trans. Amer. Math. Soc. 323 (1991), no. 2, 877-895.[25] Gidas, B.; Spruck, J. A priori bounds for positive solutions of nonlinear elliptic equations.

Comm. Partial Differential Equations 6 (1981), no. 8, 883-901.[26] Gilbarg, D.; Trudinger, N. S. “Elliptic partial differential equations of second order.” Reprint

of the 1998 edition. Classics in Mathematics. Springer-Verlag, Berlin, 2001[27] Guan, Q. Y.; Ma, Z. M. Reflected symmetric α-stable processes and regional fractional Lapla-

cian. Probab. Theory Related Fields 134 (2006), no. 4, 649-694.[28] Landkof, N. S. “Foundations of modern potential theory”, Die Grundlehren der mathematis-

chen Wissenschaften, Band 180. Springer-Verlag, New York-Heidelberg, 1972.[29] Lebedev, N. N. “Special functions and their applications”. Revised edition, translated from

the Russian and edited by Richard A. Silverman. Unabridged and corrected republication.Dover Publications, Inc., New York, 1972.

[30] Lieb, E.; Loss. M. “Analysis”, second ed., Graduate Studies in Mathematics, vol. 14, Amer.Math. Soc., Providence, RI, 2001.

A CONCAVE-CONVEX PROBLEM INVOLVING THE FRACTIONAL LAPLACIAN 23

[31] Lions, P.-L. The concentration-compactness principle in the calculus of variations. The limit

case. II. Rev. Mat. Iberoamericana 1 (1985), no. 2, 45-121.[32] de Pablo, A.; Sanchez, U. Some Liouville-type results for a fractional equation. Preprint.[33] Picone M. Sui valori eccezionali di un paramtro da cui dipende una equazione differenziale

lineare ordinaria del secondo ordine, Ann. Scuola. Norm. Pisa. 11 (1910), 1-144.[34] Pohozahev, S. On the eigenfunctions of quasilinear elliptic problems. Mat. Sbornik 82 (1970),

171188.[35] Stein, E. M. “Singular integrals and differentiability properties of functions”, Princeton Math-

ematical Series, No. 30 Princeton University Press, Princeton, N.J. 1970.[36] Stinga, P. R.; Torrea, J. L. Extension problem and Harnack’s inequality for some fractional

operators. Preprint, arXiv:0910.2569v2[37] Struwe, M. “Variational methods. Applications to nonlinear partial differential equations and

Hamiltonian systems”. Springer-Verlag, Berlin, 2000.[38] Talenti, G. Best constant in Sobolev inequality. Ann. Mat. Pura Appl. 110 (1976), no.4,

353-372.[39] Vlahos, L.; Isliker, H.; Kominis, Y.; Hizonidis, K. Normal and anomalous Diffusion: a

tutorial. In “Order and chaos”, 10th volume, T. Bountis (ed.), Patras University Press (2008).[40] Xiao, J. A sharp Sobolev trace inequality for the fractional-order derivatives. Bull. Sci. math.

130 (2006), 87-96.

E-mail address: [email protected], [email protected], [email protected]

Departamento de Matematicas, U. Carlos III de Madrid, 28911 Leganes (Madrid),Spain

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A concave-convex elliptic problem

involving the fractional Laplacian

C. Brandle, E. Colorado, A. de Pablo

Departamento de Matematicas, Universidad Carlos III de Madrid,

28911 Leganes, Spain.

October 22, 2010

Abstract

We study a nonlinear elliptic problem defined in a bounded domaininvolving fractional powers of the Laplacian operator together with aconcave-convex term. We characterize completely the range of param-eters for which solutions of the problem exist and prove a multiplicityresult.

Keywords: semilinear elliptic equations, fractional Laplacian, Sobolevtrace inequality.2000 Mathematics Subject classification: 35R11, 35J20, 46E35,

1 Introduction

In the past decades the problem

−∆u = f(u) in Ω ⊂ R

N ,u = 0 on ∂Ω,

has been widely investigated. See [3] for a survey, and for example the list(far from complete) [4, 12, 33] for more specific problems, where differentnonlinearities and different classes of domains, bounded or not, are consid-ered. Other different diffusion operators, like the p–Laplacian, fully nonlin-ear operators, etc, have been also treated, see for example [8, 15, 25] and thereferences there in. We deal here with a nonlocal version of the above prob-lem, for a particular type of nonlinearities, i.e., we study a concave-convexproblem involving the fractional Laplacian operator

(−∆)α/2u = λuq + up, u > 0 in Ω,

u = 0 on ∂Ω,(1.1)

1

with 0 < α < 2, 0 < q < 1 < p < N+αN−α , N > α, λ > 0 and Ω ⊂ R

N a smoothbounded domain.

The nonlocal operator (−∆)α/2 in RN is defined on the Schwartz class

of functions g ∈ S through the Fourier transform,

[(−∆)α/2g]∧ (ξ) = (2π|ξ|)α g(ξ),

or via the Riesz potential, see for example [30, 37]. Observe that α = 2corresponds to the standard local Laplacian.

This type of diffusion operators arises in several areas such as physics,probability and finance, see for instance [6, 7, 21, 41]. In particular, thefractional Laplacian can be understood as the infinitesimal generator of astable Levy process, [7].

There is another way of defining this operator. In fact, in the case α = 1there is an explicit form of calculating the half-Laplacian acting on a functionu in the whole space R

N , as the normal derivative on the boundary of itsharmonic extension to the upper half-space R

N+1+ , the so-called Dirichlet

to Neumann operator. The “α derivative” (−∆)α/2 can be characterized ina similar way, defining the α-harmonic extension to the upper half-space,see [17] and Section A for details. This extension is commonly used in therecent literature since it allows to write nonlocal problems in a local way andthis permits to use the variational techniques for these kind of problems.

In the case of the operator defined in bounded domains Ω, the abovecharacterization has to be adapted. The fractional powers of a linear pos-itive operator in Ω are defined by means of the spectral decomposition.In [14], the authors consider the fractional operator (−∆)1/2 defined usingthe mentioned Dirichlet to Neumann operator, but restricted to the cylinderΩ×R+ ⊂ R

N+1+ , and show that this definition is coherent with the spectral

one, see also [38] for the case α 6= 1. We recall that this is not the uniquepossibility of defining a nonlocal operator related to the fractional Laplacianin a bounded domain. See for instance the definition of the so called regionalfractional Laplacian in [9, 29], where the authors consider the Riesz integralrestricted to the domain Ω. This leads to a different operator related to aNeumann problem.

As to the concave-convex nonlinearity, there is a huge amount of resultsinvolving different (local) operators, see for instance [1, 4, 8, 18, 20, 25].We quoted the work [4] from where some ideas are used in the presentpaper. In most of the problems considered in those papers a critical exponentappears, which generically separates the range where compactness resultscan be applied or can not (in the fully nonlinear case the situation is slightlydifferent, but still a critical exponent appears, [18]). In our case, the criticalexponent with respect to the corresponding Sobolev embedding is given by2∗α = 2N

N−α . This is a reason why problem (1.1) is studied in the subcritical

2

case p < 2∗α − 1 = N+αN−α ; see also the nonexistence result for supercritical

nonlinearities in Corollary 3.5.

The main results we prove characterize the existence of solutions of (1.1)in terms of the parameter λ. A competition between the sublinear andsuperlinear terms plays a role, which leads to different results concerningexistence and multiplicity of solutions, among others. By a solution wemean an energy solution, see the precise definition in Section 3.

Theorem 1.1 There exists Λ > 0 such that for Problem (1.1) there holds:

1. If 0 < λ < Λ there is a minimal solution. Moreover, the family ofminimal solutions is increasing with respect to λ.

2. If λ = Λ there is at least one solution.

3. If λ > Λ there is no solution.

4. For any 0 < λ < Λ there exist at least two solutions.

For α ∈ [1, 2) and p subcritical, we also prove that there exists a universalL∞-bound for every solution independently of λ.

Theorem 1.2 Let α ≥ 1. Then there exists a constant C > 0 such that,for any 0 < λ ≤ Λ, every solution to Problem (1.1) satisfies

‖u‖∞ ≤ C.

The proof of this last result relies on the classical argument of rescalingintroduced in [27] which yields to problems on unbounded domains, whichrequire some Liouville-type results, which can be seen in [34]. This is thepoint where the restriction α ≥ 1 appears.

The paper is organized as follows: we devote Section 2 to settle thepreliminaries, such as define properly the fractional Laplacian in a boundeddomain, by means of the use of the α-harmonic extension, and study anassociated linear equation in the local version. The main section, Section 3,contains the results related to the nonlocal nonlinear problem (1.1), wherewe prove Theorems 1.1–1.2. We include an appendix where some traceinequality, needed in the proofs, is obtained, with sharp constant.

2 The fractional Laplacian in a bounded domain

2.1 The α-harmonic extension

To define the fractional Laplacian in a bounded domain we follow [14],see also [38]. The idea is to use the α-harmonic extension introduced in [17]

3

to define the same operator in the whole space, see also the Appendix, butrestricted to our bounded domain. To this aim we consider the cylinder

CΩ = (x, y) : x ∈ Ω, y ∈ R+ ⊂ RN+1+ ,

and denote by ∂LCΩ its lateral boundary.

We first define the extension operator and fractional Laplacian for smoothfunctions.

Definition 2.1 Given a regular function u, we define its α-harmonic ex-tension w = Eα(u) to the cylinder CΩ as the solution to the problem

− div(y1−α∇w) = 0 in CΩ,

w = 0 on ∂LCΩ,

w = u on Ω.

(2.1)

As in the whole space, there is also a Poisson formula for the extensionoperator in a bounded domain, defined through the Laplace transform andthe heat semigroup generator et∆, see [38] for details.

Definition 2.2 The fractional operator (−∆)α/2 in Ω, acting on a regularfunction u, is defined by

(−∆)α/2u(x) = − 1

καlim

y→0+y1−α∂w

∂y(x, y), (2.2)

where w = Eα(u) and κα is given as in (A.1) in the Appendix.

This operator can be extended by density to a fractional Sobolev space.

2.2 Spectral decomposition

It is classical that the powers of a positive operator in a bounded domain(or in an unbounded domain provided the spectrum is discrete) are definedthrough the spectral decomposition using the powers of the eigenvalues ofthe original operator. We show next that in this case this is coherent withthe Dirichlet-Neumann operator defined above. Let (ϕj , λj) be the eigen-functions and eigenvectors of −∆ in Ω with Dirichlet boundary data. Definethe space of functions defined in our domain Ω,

Hα/20 (Ω) = u =

∑ajϕj ∈ L2(Ω) : ‖u‖

Hα/20

=(∑

a2jλα/2j

)1/2<∞,

4

its topological dual H−α/2(Ω), and also the energy space of functions definedin the cylinder CΩ,

Xα0 (CΩ) = z ∈ L2(CΩ) : z = 0 on ∂LCΩ, ‖z‖2Xα

0=

(∫

y1−α|∇z|2)1/2

<∞.

Lemma 2.3 1. The eigenfunctions and eigenvectors of (−∆)α/2 in Ω

with Dirichlet boundary data are given by (ϕj , λα/2j ).

2. If u =∑ajϕj ∈ H

α/20 (Ω) then Eα(u) ∈ Xα

0 (CΩ) and

Eα(u)(x, y) =∑

ajϕj(x)ψ(λ1/2j y),

where ψ(s) solves the problem

ψ′′ +(1− α)

sψ′ = ψ, s > 0,

− lims→0+

s1−αψ′(s) = κα,

ψ(0) = 1.

3. In the same hypotheses, (−∆)α/2u ∈ H−α/2(Ω), and (−∆)α/2u =∑ajλ

α/2j ϕj .

4. It holds

‖(−∆)α/2u‖H−α/2 = ‖(−∆)α/4u‖L2 = ‖u‖H

α/20

= κ−1/2α ‖Eα(u)‖Xα

0.

The proof of this result is straightforward. The function ψ coincideswith the solution φα in problem (A.8). The calculation of the norms is alsostraightforward: Using the orthogonality of the family ϕj, together with∫Ω ϕ

2j = 1,

∫Ω |∇ϕj |2 = λj , and (A.10), we have

RN+1+

y1−α|∇Eα(u)(x, y)|2 dxdy

=

∫ ∞

0y1−α

Ω

(∑a2j |∇ϕj(x)|2ψ(λ1/2j y)2 + a2jλjϕj(x)

2(ψ′(λ1/2j y))2

)dxdy

=

∫ ∞

0y1−α

∑a2jλj

(ψ(λ

1/2j y)2 + (ψ′(λ

1/2j y))2

)dy

=∑

a2jλα/2j

∫ ∞

0s1−α

(ψ(s)2 + (ψ′(s))2

)ds = κα

∑a2jλ

α/2j

= κα∑

(ajλα/4j )2.

5

2.3 The linear problem

We now use the extension problem (2.1) and the expression (2.2) toreformulate the nonlocal problems in a local way. Let g be a regular functionand consider the following problems, the nonlocal problem

(−∆)α/2u = g(x) in Ω,

u = 0 on ∂Ω,(2.3)

and the corresponding local one

− div(y1−α∇w) = 0 in CΩ,

w = 0 on ∂LCΩ,

−1

καlimy→0+

y1−α∂w

∂y= g(x) on Ω.

(2.4)

We want to define the concept of solution to (2.3), which is done in termsof the solution to problem (2.4).

Definition 2.4 We say that w ∈ Xα0 (CΩ) is an energy solution to prob-

lem (2.4), if for every function ϕ ∈ C10(CΩ) it holds

y1−α⟨∇w(x, y),∇ϕ(x, y)

⟩dxdy =

Ωκαg(x)ϕ(x, 0) dx. (2.5)

In fact more general test functions can be used in the above formula, when-ever the integrals make sense. A supersolution (subsolution) is a functionthat verifies (2.5) with equality replaced by ≥ (≤) for every nonnegative testfunction.

Definition 2.5 We say that u ∈ Hα/20 (Ω) is an energy solution to prob-

lem (2.3) if it is the trace on Ω of a function w which is an energy solutionto problem (2.4).

It is clear that a solution exists for instance for every g ∈ H−α/2(Ω). Inorder to deal with problem (2.4) we will assume, without loss of generality,κα = 1, by changing the function g.

In [13] this linear problem is also mentioned. There some results areobtained using the theory of degenerate elliptic equations developed in [24],in particular a regularity result for bounded solutions to this problem isobtained in [13]. We prove here that the solutions are in fact bounded if gsatisfies a minimal integrability condition.

Theorem 2.6 Let w be a solution to problem (2.4). If g ∈ Lr(Ω), r > Nα ,

then w ∈ L∞(CΩ).

6

Proof. The proof follows from the well-known Moser’s iterative technique,that we take from [28, Theorem 8.15], and uses the trace inequality (A.12).Without loss of generality we may assume w ≥ 0, and this simplifies nota-tion. The general case is obtained in a similar way.

We define for β ≥ 1 and K ≥ k (k to be chosen later) a C1([k,∞))function H, as follows:

H(z) =

zβ − kβ , z ∈ [k,K],linear, z > K.

Let us also define v = w + k, ν = Tr(v), and choose as test function ϕ,

ϕ = G(v) =

∫ v

k|H ′(s)|2 ds, ∇ϕ = |H ′(v)|2∇v.

Observe that it is an admissible test function, though it is not C1. Replacingthis test function into the definition of energy solution we obtain on onehand:

y1−α⟨∇w,∇ϕ

⟩dxdy =

y1−α∣∣∇v|2|H ′(v)|2 dxdy

=

y1−α∣∣∇H(v)|2 dxdy

≥(∫

Ω|H(ν)|

2NN−α dx

)N−αN

= ‖H(ν)‖22NN−α

,

(2.6)where the last inequality follows by (A.12).

On the other hand∫

Ωg(x)ϕ(x, 0) dx =

Ωg(x)G(ν) dx ≤

Ωg(x)νG′(ν) dx

≤ 1

k

Ωg(x)ν2|H ′(ν)|2 dx =

1

k

Ωg(x)|νH ′(ν)|2 dx.

(2.7)

Inequality (2.6) together with (2.7), leads to

‖H(ν)‖ 2NN−α

≤(1

k‖g‖r

)1/2

‖(νH ′(ν))2‖1/2rr−1

= ‖νH ′(ν)‖ 2rr−1

, (2.8)

by choosing k = ‖g‖r. Letting K → ∞ in the definition of H, the inequal-ity (2.8) becomes

‖ν‖ 2NβN−α

≤ ‖ν‖ 2rβr−1

.

Hence for all β ≥ 1 the inclusion ν ∈ L2rβr−1 (Ω) implies the stronger inclusion

ν ∈ L2NβN−α (Ω), since 2Nβ

N−α > 2rβr−1 provided r > N

α . The result follows now,

7

as in [28], by an iteration argument, starting with β = N(r−1)r(N−α) > 1 and

ν ∈ L2N

N−α (Ω). This gives ν ∈ L∞(Ω), and then w ∈ L∞(CΩ). In fact we getthe estimate

‖w‖∞ ≤ c(‖w‖Xα + ‖g‖r).2

Corollary 2.7 Let w be a solution to problem (2.4). If g ∈ L∞(Ω), thenw ∈ Cγ(CΩ) for some γ ∈ (0, 1).

Proof. Using Theorem 2.6, the result follows directly from [13, Lemma 4.4],where it is proved that any bounded solution to problem (2.4) with abounded g is Cγ . 2

3 The nonlinear nonlocal problem

3.1 The local realization

We deal now with the core of the paper; i.e. the study of the nonlocalproblem (1.1). We write that problem in local version in the following way:a solution to problem (1.1) is a function u = Tr(w), the trace of w onΩ× y = 0, where w solves the local problem

− div(y1−α∇w) = 0 in CΩ,

w = 0 on ∂LCΩ,

∂w

∂να= f(w) in Ω,

(3.1)

where∂w

∂να(x) = − lim

y→0+y1−α ∂w

∂y(x, y). (3.2)

Note. In order to simplify notation in what follows we will denote, whenno confusio arises, w for the function defined in the cylinder CΩ as well asfor its trace Tr(w) on Ω× y = 0.

As we have said, we will focus on the particular nonlinearity

f(s) = fλ(s) = λsq + sp. (3.3)

However many auxiliary results will be proved for more general reactions fsatisfying the growth condition

0 ≤ f(s) ≤ c(1 + |s|p), for some p > 0. (3.4)

8

Remark 3.1 In the definition (3.2) we have neglected the constant κα ap-pearing in (2.2) by a simple rescaling. Therefore, the results on the coeffi-cient λ for the local problem (3.1)–(3.3) in this section are translated into

problem (1.1) with λ multiplied by κp(q−1)−1α .

Following Definition 2.4, we say that w ∈ Xα0 (CΩ) is an energy solution

of (3.1) if the following identity holds

y1−α⟨∇w,∇ϕ

⟩dxdy =

Ωf(w)ϕdx

for every regular test function ϕ. In the analogous way we define sub- andsupersolution.

We consider now the functional

J(w) =1

2

y1−α|∇w|2 dxdy −∫

ΩF (w) dx,

where F (s) =∫ s0 f(τ) dτ . For simplicity of notation, we define f(s) = 0

for s ≤ 0. Recall that the trace satisfies w ∈ Lr(Ω), (again this meansTr(w) ∈ Lr(Ω)), for every 1 ≤ r ≤ 2N

N−α if N > α, 1 < r ≤ ∞ if N ≤ α.

In particular if p ≤ N+αN−α , and f verifies (3.4) then F (w) ∈ L1(Ω), and the

functional is well defined and bounded from below.

It is well known that critical points of J are solutions to (3.1) with ageneral reaction f . We consider also the minimization problem

I = inf∫

y1−α|∇w|2 dxdy : w ∈ Xα0 (CΩ),

ΩF (w) dx = 1

,

for which, by classical variational techniques, one has that below the criticalexponent the infimum I is achieved. This gives a nonnegative solution. Lateron we will see that this infimum is positive provided λ > 0 is small enough.On the contrary, for λ large enough the infimum is the trivial solution.

We now establish two preliminary results. The first one is a classicalprocedure of sub- and supersolutions to obtain a solution. We omit itsproof.

Lemma 3.1 Assume there exist a subsolution w1 and a supersolution w2

to problem (3.1) verifying w1 ≤ w2. Then there also exists a solution wsatisfying w1 ≤ w ≤ w2 in CΩ.

The second one is a comparison result for concave nonlinearities. Theproof follows the lines of the corresponding one for the Laplacian performedin [10].

9

Lemma 3.2 Assume the function f(t)/t is decreasing for t > 0 and con-sider w1, w2 ∈ Xα

0 (CΩ) positive subsolution and supersolution, respectively,to problem (3.1). Then w1 ≤ w2 in CΩ.

Proof. By definition we have, for the nonnegative test functions ϕ1 and ϕ2

to be chosen in an appropriate way,∫

y1−α⟨∇w1,∇ϕ1

⟩dxdy ≤

Ωf(w1)ϕ1 dx,

y1−α⟨∇w2,∇ϕ2

⟩dxdy ≥

Ωf(w2)ϕ2 dx.

Now let θ(t) be a smooth nondecreasing function such that θ(t) = 0 fort ≤ 0, θ(t) = 1 for t ≥ 1, and set θε(t) = θ( tε). If we put, in the aboveinequalities

ϕ1 = w2 θε(w1 − w2), ϕ2 = w1 θε(w1 − w2),

we get

I1 ≥∫

Ωw1w2

(f(w2)

w2− f(w1)

w1

)θε(w1 − w2) dx,

where

I1 :=

y1−α⟨w1∇w2 − w2∇w1,∇(w1 − w2)

⟩θ′ε(w1 − w2) dxdy.

Now we estimate I1 as follows:

I1 ≤∫

y1−α⟨∇w1, (w1 − w2)∇(w1 − w2)

⟩θ′ε(w1 − w2) dxdy

=

y1−α⟨∇w1,∇γε(w1 − w2)

⟩dxdy

where γ′ǫ(t) = tθ′ε(t). Therefore, since 0 ≤ γε ≤ ε, we have

I1 ≤∫

Ωf(w1)γε(w1 − w2) dx ≤ cε.

We end as in [4]. Letting ε tend to zero, we obtain∫

Ω∩w1>w2w1w2

(f(w2)

w2− f(w1)

w1

)dx ≤ 0,

which together with the hypothesis on f gives w1 ≤ w2 in Ω. Comparisonin CΩ follows easily by the maximum principle. 2

Now we show that the solutions to problem (3.1)–(3.4) are boundedand Holder continuous. Later on, in Section 3.4, we will obtain a uniformL∞-estimate in the case where f is given by (3.3) and the convex power issubcritical.

10

Proposition 3.3 Let f satisfy (3.4) with p < N+αN−α , and let w ∈ Xα

0 (CΩ) be

an energy solution to problem (3.1). Then w ∈ L∞(CΩ) ∩ Cγ(CΩ) for some0 < γ < 1.

Proof. The proof follows closely the technique of [11]. As in the proof ofTheorem 2.6, we assume w ≥ 0. We consider, formally, the test functionϕ = wβ−p, for some β > p+1. The justification of the following calculationscan be made substituting ϕ by some approximated truncature. We thereforeproceed with the formal analysis. We get, using the trace immersion, theinequality (∫

Ωw

(β−p+1)NN−α

)N−αN

≤ C(β, α,N,Ω)

Ωwβ.

This estimate allows us to obtain the following iterative process

‖w‖βj+1≤ C‖w‖

βjβj−p+1

βj,

with βj+1 = NN−α(βj + 1 − p). To have βj+1 > βj we need βj >

(p−1)Nα .

Since w ∈ L2∗α(Ω), starting with β0 = 2NN−α , we get the above restriction

provided p < N+αN−α . It is clear that in a finite number of steps we get, for

g(x) = f(w(x, 0)), the regularity g ∈ Lr for some r > Nα . As a consequence,

we obtain the conclusion applying Theorem 2.6 and Corollary 2.7. 2

3.2 A nonexistence result

The following result relies on a the use of a classical Pohozaev typemultiplier.

Proposition 3.4 Assume f is a C1 function with primitive F , and w is anenergy solution to problem (3.1). Then the following Pohozaev-type identityholds

1

2

∂LCΩ

y1−α⟨(x, y), ν

⟩|∇w|2 dσ −N

ΩF (w) dx+

N − α

2

Ωwf(w) dx = 0.

Proof. Just use the identity

⟨(x, y), ν

⟩yα−1 div(y1−α∇w) + div

[y1−α

(⟨(x, y),∇w

⟩− 1

2(x, y)|∇w|2

)]

+(N + 2− α

2− 1

)|∇w|2 = 0,

where ν is the (exterior) normal vector to ∂Ω. It is calculus matter to checkthis equality. 2

11

As a consequence we obtain a nonexistence result in the supercriticalcase for domains with particular geometry.

Theorem 3.5 If Ω is starshaped and the nonlinearity f satisfies the in-equality ((N − α)sf(s)− 2NF (s)) ≥ 0, then problem (3.1) has no solution.In particular, in the case f(s) = sp this means that there is no solution forany p ≥ N+α

N−α .

The case α = 1 has been proved in [14]. The corresponding result forthe Laplacian (problem (1.1) with α = 2) comes from [36].

3.3 Proof of Theorem 1.1

We prove here Theorem 1.1 in terms of the solution of the local ver-sion (3.1). For the sake of readability we split the proof of into severallemmas. From now on we will denote

(Pλ) ≡

− div(y1−α∇w) = 0, in CΩ,

w = 0, on ∂LCΩ,

∂w

∂να= λwq + wp, u > 0 in Ω,

and consider the associated energy functional

Jλ(w) =1

2

y1−α|∇w|2 dxdy −∫

ΩFλ(w) dx,

where

Fλ(s) =λ

q + 1sq+1 +

1

p+ 1sp+1.

Lemma 3.6 Let Λ be defined by

Λ = supλ > 0 : Problem (Pλ) has solution.

Then 0 < Λ <∞.

Proof. Consider the eigenvalue problem associated to the first eigenvalueλ1, and let ϕ1 > 0 be an associated eigenfunction, see Lemma 2.3. Thenusing ϕ1 as a test function in (Pλ) we have that

Ω(λwq +wp)ϕ1 dx = λ1

Ωwϕ1 dx. (3.5)

Since there exist positive constants c, δ such that λtq + tp > cλδt, for anyt > 0 we obtain from (3.5) (recall that u > 0) that cλδ < λ1 which impliesΛ <∞.

12

To prove Λ > 0 we use the sub- and supersolution technique to constructa solution for any small λ. In fact a subsolution is obtained as w = εϕ1,ε > 0 small. A supersolution is a suitable multiple of the function e solutionto

− div(y1−α∇e) = 0 in CΩ,

e = 0 on ∂LCΩ,

∂e

∂να= 1 in Ω.

2

This proves the third statement in Theorem 1.1.

Lemma 3.7 Problem (Pλ) has a positive solution for every 0 < λ < Λ.Moreover, the family wλ of minimal solutions is increasing with respectto λ.

Remark 3.2 Although this Λ is not exactly the same as that of Theo-rem 1.1, see Remark 3.1, we have not changed the notation for the sake ofsimplicity.

Proof. We already proved in the previous lemma that Problem (Pλ) hasa solution for every λ > 0 small. Another way of proving this result is tolook at the associated functional Jλ. Using Theorem A.5, we have that thisfunctional verifies

Jλ(w) =1

2

y1−α|∇w|2 dxdy −∫

ΩFλ(w) dx

≥ 1

2

y1−α|∇w|2 dxdy − λC1

(∫

y1−α|∇w|2 dxdy) q+1

2

−C2

(∫

y1−α|∇w|2 dxdy) p+1

2,

for some positive constants C1 and C2. Then for λ small enough there existtwo solutions of problem (Pλ), one given by minimization and another onegiven by the Mountain-Pass Theorem, [5]. The proof is standard, basedon the geometry of the function g(t) = 1

2t2 − λC1t

q+1 − C2tp+1, see for

instance [25] for more details.

We now show that there exists a solution for every λ ∈ (0,Λ). Bydefinition of Λ, we know that there exists a solution corresponding to anyvalue of λ close to Λ. Let us denote it by µ, and let wµ be the associatedsolution. Now wµ is a supersolution for all problems (Pλ) with λ < µ. Takevλ the unique solution to problem (3.1) with f(s) = λsq. Obviously vλis a subsolution to problem (Pλ). By Lemma 3.2 vλ ≤ wµ. Therefore by

13

Lemma 3.1 we conclude that there is a solution for all λ ∈ (0, µ), and asa consequence, for the whole open interval (0,Λ). Moreover, this solutionis the minimal one. The monotonicity follows directly from the comparisonlemma. 2

This proves the first statement in Theorem 1.1.

Lemma 3.8 Problem (Pλ) has at least one solution if λ = Λ.

Proof. Let λn be a sequence such that λn ր Λ. We denote by wn = wλn

the minimal solution to problem (Pλn). As in [4], we can prove that thelinearized equation at the minimal solution has nonnegative eigenvalues.Then it follows, as in [4] again, Jλn(wn) < 0. Since J ′(wλ) = 0, one easilygets the bound ‖wn‖Xα

0 (CΩ) ≤ k. Hence, there exists a weakly convergentsubsequence in Xα

0 (CΩ) and as a consequence a weak solution of (Pλ) forλ = Λ. 2

This proves the second statement in Theorem 1.1. To conclude the proofof that theorem, we show next the existence of a second solution for every0 < λ < Λ. It is essential to have that the first solution is given as a localminimum of the associated functional, Jλ. To prove this last assertion wefollow some ideas developed in [2].

Let λ0 ∈ (0,Λ) be fixed and consider λ0 < λ1 < Λ. Take φ0 = wλ0 ,φ1 = wλ1

the two minimal solutions to problem (Pλ) with λ = λ0 andλ = λ1 respectively, then by comparison, φ0 < φ1. We define

M = w ∈ Xα0 (CΩ) : 0 ≤ w ≤ φ1.

Notice that M is a convex closed set of Xα0 (CΩ). Since Jλ0 is bounded from

bellow in M and it is semicontinuous on M , we get the existence of ω ∈Msuch that Jλ0(ω) = infw∈M Jλ0(w). Let v0 be the unique positive solutionto problem

− div(y1−α∇v0) = 0, in CΩ,

v0 = 0, on ∂LCΩ,

∂v0∂να

= vq0, in Ω.

(3.6)

(The existence and uniqueness of this solution is clear). Since for 0 < ε <<λ0, and Jλ0(εv0) < 0, we have εv0 ∈ M , then ω 6= 0. Therefore Jλ0(ω) < 0.By arguments similar to those in [39, Theorem 2.4], we obtain that ω is asolution to problem (Pλ0). There are two possibilities:

• If ω 6≡ wλ0 , then the result follows.

14

• If ω ≡ wλ0 , we have just to prove that ω is a local minimum of Jλ0 .Assuming that this is true, the conclusion in part 4 of Theorem 1.1follows by using a classical argument: The second solution is given bythe Mountain Pass Theorem, see for instance [5].

We prove now that the minimal solution wλ0 is in fact a local minimumof Jλ0 . We argue by contradiction.

Suppose that ω is not a local minimum of Jλ0 in Xα0 (CΩ), then there

exists a sequence vn ⊂ Xα0 (CΩ) such that ‖vn − ω‖Xα

0→ 0 and Jλ0(vn) <

Jλ0(ω).

Let wn = (vn−φ1)+ and zn = max0,minvn, φ1. It is clear that zn ∈M

and

zn(x, y) =

0 if vn(x, y) ≤ 0,

vn(x, y) if 0 ≤ vn(x, y) ≤ φ1(x, y),

φ1(x, y) if φ1(x, y) ≤ vn(x, y).

We set

Tn ≡ (x, y) ∈ CΩ : zn(x, y) = vn(x, y), Sn ≡ supp(wn),

Tn = Tn ∩ Ω, Sn = Sn ∩ Ω.

Notice that supp(v+n ) = Tn ∪ Sn. We claim that

|Sn|Ω → 0 as n→ ∞, (3.7)

where |A|Ω ≡∫Ω χA(x) dx.

By the definition of Fλ, we set Fλ0(s) =l0

q + 1sq+1+ +

1

p+ 1sp+1+ , for s ∈ R,

and get

Jl0(vn) =1

2

y1−α|∇vn|2 dxdy −∫

ΩFλ0(vn) dx

=1

2

Tn

y1−α|∇zn|2 dxdy −∫

Tn

Fλ0(zn) dx+1

2

Sn

y1−α|∇vn|2 dxdy

−∫

Sn

Fλ0(vn) dx+1

2

y1−α|∇v−n |2 dxdy

=1

2

Tn

y1−α|∇zn|2 dxdy −∫

Tn

Fλ0(zn) dx

+1

2

Sn

y1−α|∇(wn + φ1)|2 dxdy −∫

Sn

Fλ0(wn + φ1) dx

+1

2

y1−α|∇v−n |2 dxdy.

15

Since∫

y1−α|∇zn|2 dxdy =

Tn

y1−α|∇vn|2 dxdy +∫

Sn

y1−α|∇φ1|2 dxdy

and ∫

ΩFλ0(zn) dx =

Tn

Fλ0(vn) dx+

Sn

Fλ0(φ1) dx,

by using the fact that φ1 is a supersolution to (Pλ) with l = l0, we concludethat

Jl0(vn) = Jl0(zn) +1

2

Sn

y1−α(|∇(wn + φ1)|2 − |∇φ1|2) dxdy

−∫

Sn

(Fλ0(wn + φ1)− Fλ0(φ1)) dx+1

2

y1−α|∇v−n |2 dxdy

≥ Jl0(zn) +1

2‖wn‖2Xα

0+

1

2‖v−n ‖2Xα

0

−∫

ΩFλ0(wn + φ1)− Fλ0(φ1)− (Fλ0)u(φ1)wn dx

≥ Jl0(ω) +1

2‖wn‖2Xα

0+

1

2‖v−n ‖2Xα

0

−∫

ΩFλ0(wn + φ1)− Fλ0(φ1)− (Fλ0)u(φ1)wn dx.

On one hand, taking into account that 0 < q + 1 < 2, one obtains that

0 ≤ 1

q + 1(wn + φ1)

q+1 − 1

q + 1φq+11 − φq1wn ≤ q

2

w2n

φ1−q1

.

The well known Picone’s inequality (see [35]) establish:

|∇u|2 −∇(u2

v

)· ∇v ≥ 0,

for differentiable functions v > 0, u ≥ 0. In our case, by an approximationargument we get

l0

Ω

w2n

φ1−q1

dx ≤ ‖wn‖2Xα0.

On the other hand, since p+ 1 > 2,

0 ≤ 1

p+ 1(wn + φ1)

p+1 − 1

p+ 1φp+11 − φp1wn ≤ r

2w2n(wn + φ1)

p−1

≤ C(p)(φp−11 w2

n + wp+1n ).

Hence using that p+ 1 < 2∗α and the claim (3.7)∫

Ω

1

p+ 1(wn + φ1)

p+1 − 1

p+ 1φp+11 − φp1wn

dx ≤ o(1)‖wn‖2Xα

0.

16

As a consequence we obtain that

Jl0(vn) ≥ Jl0(ω) +1

2‖wn‖2Xα

0(1− q − o(1)) +

1

2‖v−n ‖2Xα

0

≡ Jl0(ω) +1

2‖wn‖2Xα

0(1− q − o(1)) + o(1).

Since q < 1, there results that Jl0(ω) > Jl0(vn) ≥ Jl0(ω) for n > n0, acontradiction with the main hypothesis. Hence ω is a minimum.

To finish the proof we have to prove the claim (3.7). For ε > 0 small,and δ > 0 (δ to be chosen later), we consider

En = x ∈ Ω : vn(x) ≥ φ1(x) ∧ φ1(x) > ω(x) + δ,Fn = x ∈ Ω : vn(x) ≥ φ1(x) ∧ φ1(x) ≤ ω(x) + δ.

Using the fact that

0 = |x ∈ Ω : φ1(x) < ω(x)| =

∣∣∣∣∣∣

∞⋂

j=1

x ∈ Ω : φ1(x) ≤ ω(x) +

1

j

∣∣∣∣∣∣

= limj→∞

∣∣∣∣x ∈ Ω : φ1(x) ≤ ω(x) +

1

j

∣∣∣∣ ,

we get for j0 large enough, that if δ < 1j0

then

|x ∈ Ω : φ1(x) ≤ ω(x) + δ| ≤ ε

2.

Hence we conclude that |Fn|Ω ≤ ε2 .

Since ‖vn − ω‖Xα0→ 0 as n→ ∞, in particular by the trace embedding,

‖vn − ω‖L2(Ω) → 0. We obtain that, for n ≥ n0 large,

δ2ε

2≥

|vn − ω|2dx ≥∫

En

|vn − ω|2dx ≥ δ2|En|Ω.

Therefore |En|Ω ≤ ε

2. Since Sn ⊂ Fn ∪ En we conclude that |Sn|Ω ≤ ε for

n ≤ n0. Hence |Sn|Ω → 0 as n→ ∞ and the claim follows. 2

3.4 Proof of Theorem 1.2 and further results

We start with the uniform L∞-estimates for solutions to problem (1.1)in its local version given by (Pλ).

Theorem 3.9 Assume α ≥ 1, p < N+αN−α and N ≥ 2. Then there exists a

constant C = C(p,Ω) > 0 such that every solution to problem (Pλ) satisfies

‖w‖∞ ≤ C,

for every 0 ≤ λ ≤ Λ.

17

The proof is based in a rescaling method and the following two nonexis-tence results, proved in [34]:

Theorem 3.10 Let α ≥ 1. Then the problem in the half-space RN+1+ ,

− div(y1−α∇w) = 0 in RN+1+

∂w

∂να(x) = wp(x, 0) on ∂RN+1

+ = RN

has no solution provided p < N+αN−α , if N ≥ 2, or for every p if N = 1.

Theorem 3.11 The problem in the first quarter

RN+1++ = z = (x′, xN , y) |x′ ∈ R

N−1, xN > 0, y > 0,

− div(y1−α∇w) = 0, xN > 0, y > 0,∂w

∂να(x′, xN ) = wp(x′, xN , 0),

w(x′, 0, y) = 0,

has no positive bounded solution provided p < N+αN−α .

Proof of Theorem 3.9. Assume by contradiction that there exists a sequencewn ⊂ Xα

0 (CΩ) of solutions to (Pλ) verifying that Mn = ‖wn‖∞ → ∞, asn→ ∞. By the Maximum Principle, which holds for our problem, see [24],the maximum of wn is attained at a point (xn, 0) where xn ∈ Ω. We define

Ωn = 1µn

(Ω − xn), with µn = M(1−p)/αn , i.e., we center at xn and dilate by

1µn

→ ∞ as n→ ∞.

We consider the scaled functions

vn(x, y) =wn(xn + µnx, µny)

Mn, for x ∈ Ωn, y ≥ 0.

It is clear that ‖vn‖ ≤ 1, vn(0, 0) = 1 and moreover

− div(y1−α∇vn) = 0 in CΩn ,

vn = 0 on ∂LCΩn ,

∂vn∂να

= λM q−pn vqn + vpn in Ωn × 0.

(3.8)

By Arzela-Ascoli Theorem (the solution is Cγ , see Proposition 3.3), thereexists a subsequence, which we denote again by vn, which converges to somefunction v as n → ∞. In order to see the problem satisfied by v we passto the limit in the weak formulation of (3.8). We observe that ‖vn‖∞ ≤ 1implies ‖vn‖Xα

0 (CΩ) ≤ C.

We define dn = dist(xn, ∂Ω), then there are two possibilities as n → ∞according the behaviour of the ratio dn

µn:

18

1.

dnµn

n

is not bounded.

2.

dnµn

n

remains bounded.

In the first case, since Bdn/µn(0) ⊂ Ωn, and Ωn is smooth, it is clear that

Ωn tends to RN and v is a solution to

− div(y1−α∇v) = 0 in RN+1+ ,

∂v

∂να= vp on ∂RN+1

+ .

Moreover, v(0, 0) = 1 and v > 0 which is a contradiction with Theorem 3.10.

In the second case, we may assume that dnµn

→ s ≥ 0 as n → ∞. As aconsequence, passing to the limit, the domains Ωn converge (up to a rotation)to some half-space Hs = x ∈ R

N : xN > −s. We obtain here that v is asolution to

− div(y1−α∇v) = 0 in Hs × (0,∞),

∂v

∂να= vp on Hs × 0,

with ‖v‖∞ = 1, v(0, 0) = 1. In the case s = 0 this is a contradiction withthe continuity of v. If s > 0, the contradiction comes from Theorem 3.11. 2

We next prove a uniqueness result for solutions with small norm.

Theorem 3.12 There exists at most one solution to problem (Pλ) withsmall norm.

We follow closely the arguments in [4], so we establish the following previousresult:

Lemma 3.13 Let z be the unique solution to problem (3.6). There exists aconstant β > 0 such that

‖φ‖2Xα0 (CΩ) − q

Ωzq−1φ2 dx ≥ β‖φ‖2L2(Ω), ∀φ ∈ Xα

0 (CΩ). (3.9)

Proof. We recall that z can be obtained by minimization

min

1

2‖ω‖2Xα

0 (CΩ) −1

q + 1‖w‖q+1

Lq+1(Ω): ω ∈ Xα

0 (CΩ)

.

As a consequence,

‖φ‖2Xα0 (CΩ) − q

Ωzq−1φ2 dx ≥ 0, ∀φ ∈ Xα

0 (CΩ).

19

This implies that the first eigenvalue a1 of the linearized problem

− div(y1−α∇φ) = 0, in CΩ,

φ = 0, on ∂LCΩ,

∂φ

∂να− qzq−1φ = aφ, on Ω× 0,

is nonnegative.

Assume first that a1 = 0 and let ϕ be a corresponding eigenfunction.Taking into account that z is the solution to (3.6) we obtain that

q

Ωzqϕdx =

Ωzqϕdx

which is a contradiction.

Hence a1 > 0, which proves (3.9). 2

Proof of Theorem 3.12. Consider A > 0 such that pAp−1 < β, where β isgiven in (3.9). Now we prove that problem (Pλ) has at most one solutionwith L∞-norm less than A.

Assume by contradiction that (Pλ) has a second solution w = wλ + vverifying ‖w‖∞ < A. Since wλ is the minimal solution, it follows that v > 0

in Ω × [0,∞). We define now η = λ1

1−q z, where z is the solution to (3.6).Then it verifies −÷ (y1−α∇η) = 0, with boundary condition ληq. Moreover,wλ is a supersolution to the problem that η verifies. Then by comparison,Lemma 3.2, applied with f(t) = λtq, v = η and w = wλ, we get

wλ ≥ λ1

1−q z on Ω× 0. (3.10)

Since w = wλ + v is solution to (Pλ) we have, on Ω× 0,

∂(wλ + v)

∂να= λ(wλ + v)q + (wλ + v)p ≤ λwq

λ + λqwq−1λ v + (wλ + v)p,

where the inequality is a consequence of the concavity, hence

∂v

∂να≤ λqwq−1

λ v + (wλ + v)p −wpλ.

Moreover, (3.10) implies wq−1λ ≥ λ−1zq−1. From the previous two inequalities

we get∂v

∂να≤ qzq−1v + (wλ + v)p − wp

λ.

Using that ‖wλ + v‖∞ ≤ A, we obtain (wλ + v)p − wpλ ≤ pAp−1v. As a

consequence,∂v

∂να− qzq−1v ≤ pAp−1v.

20

Taking v as a test function and φ = v in (3.9) we arrive to

β

Ωv2 dx ≤ pAp−1

Ωv2 dx.

Since pAp−1 < β we conclude that v ≡ 0, which gives the desired contradic-tion. 2

Remark 3.3 This proof also provides the asymptotic behavior of wλ near

λ = 0, namely wλ ≈ λ1

1−q z, where z is the unique solution to problem (3.6).

A Appendix: A trace inequality

A.1 Preliminaries. The problem in the whole space

Here we recall the definition of the fractional Laplacian in the wholespace and its local representation by means of the extension to one morevariable, as it is done in [17].

Let u be a regular function in RN . We say that w = Eα(u) is its α-

harmonic extension to the upper half-space, RN+1+ , if w is a solution to the

problem

− div(y1−α∇w) = 0 in R

N+1+ ,

w = u on RN × y = 0.

In [17] it is proved that

limy→0+

y1−α ∂w

∂y(x, y) = −κα(−∆)α/2u(x), (A.1)

where κα = 21−αΓ(1−α/2)Γ(α/2) .

The appropriate functional spaces to work with are Xα(RN+1+ ) and

Hα/2(RN ), defined as the completion of C∞0 (RN+1

+ ) and C∞0 (RN ), respec-

tively, under the norms

‖φ‖2Xα =

RN+1+

y1−α|∇φ(x, y)|2 dxdy,

‖ψ‖2Hα/2 =

RN

|2πξ|α|ψ(ξ)|2 dξ =∫

RN

|(−∆)α/4ψ(x)|2 dx.

21

The extension operator is well defined for smooth functions through aPoisson kernel, whose explicit expression is given in [17]. It can also bedefined in the space Hα/2(RN ), and in fact

‖Eα(ψ)‖Xα = cα‖ψ‖Hα/2 , ∀ψ ∈ Hα/2(RN ), (A.2)

where cα =√κα , see Lemma A.2. On the other hand, for a function

φ ∈ Xα(RN+1+ ), we will denote its trace on R

N × y = 0 as Tr(φ). Thistrace operator is also well defined and it satisfies

‖Tr(φ)‖Hα/2 ≤ c−1α ‖φ‖Xα . (A.3)

A.2 The trace immersion

From (A.3), the Sobolev embedding yields then that the trace also be-longs to L2∗α(RN ), where 2∗α = 2N

N−α . Even the best constant associated tothis inclusion is attained and can be characterized. Although most of theresults used in order to prove the following theorem are known, we havecollected them for the readers convenience.

Theorem A.1 For every z ∈ Xα(RN+1+ ) it holds

(∫

RN

|v(x)|2N

N−α dx

)N−αN

≤ S(α,N)

RN+1+

y1−α|∇z(x, y)|2 dxdy, (A.4)

where v = Tr(z). The best constant takes the exact value

S(α,N) =Γ(α2 )Γ(

N−α2 )(Γ(N))

αN

2πα2 Γ(2−α

2 )Γ(N+α2 )(Γ(N2 ))

αN

(A.5)

and it is achieved when v takes the form

v(x) = τN−α

2(|x− x0|2 + τ2

)−N−α2 , (A.6)

for some x0 ∈ RN , τ > 0, and z = Eα(v).

The analogous results for the classical Laplace operator can be foundin [23, 33].

Lemma A.2 Let v ∈ Hα/2(RN ) and let z = Eβ(v) be its β-harmonic ex-tension, β ∈ (α/2, 2). Then z ∈ Xα(RN+1

+ ) and moreover there exists apositive universal constant c(α, β) such that

‖v‖Hα/2 = c(α, β)‖z‖Xα . (A.7)

In particular if β = α we have c(α,α) = 1/√κα.

22

Inequality (A.4) needs only the case β = α, which is deduced directly fromthe proof of the local characterization of (−∆)α/2 in [17]. The calculationsperformed in [17] can be extended to cover the range α/2 < β < 2 and inparticular includes the case β = 1 proved in [42].

Proof. Since z = Eβ(v), by definition z solves div(y1−β∇z) = 0, which isequivalent to

∆xz +1− β

y

∂z

∂y+∂2z

∂y2= 0.

Taking Fourier transform in x ∈ RN for y > 0 fixed, we have

−4π2|ξ|2z + 1− β

y

∂z

∂y+∂2z

∂y2= 0.

and z(ξ, 0) = v(ξ). Therefore z(ξ, y) = v(ξ)φβ(2π|ξ|y), where φβ solves theproblem

− φ+1− β

sφ′ + φ′′ = 0, φ(0) = 1, lim

s→∞φ(s) = 0. (A.8)

In fact, φβ minimizes the functional

Hβ(φ) =

∫ ∞

0(|φ(s)|2 + |φ′(s)|2)s1−β ds.

and it can be shown that it is a combination of Bessel functions, see [31].More precisely, φβ satisfies the following asymptotic behaviour

φβ(s) ∼ 1− c1sβ, for s→ 0,

φβ(s) ∼ c2sβ−12 e−s, for s→ ∞,

(A.9)

where

c1(β) =21−βΓ(1− β

2 )

βΓ(β2 ), c2(β) =

21−β2 π1/2

Γ(β2 ).

Now we observe that∫

RN

|∇z(x, y)|2 dx =

RN

(|∇xz(x, y)|2 +

∣∣∣∂z∂y

(x, y)∣∣∣2)dx

=

RN

(4π2|ξ|2|z(ξ, y)|2 +

∣∣∣∂z∂y

(ξ, y)∣∣∣2)dξ.

Then, multiplying by y1−α and integrating in y,∫ ∞

0

RN

y1−α|∇z(x, y)|2 dxdy

=

∫ ∞

0

RN

4π2|ξ|2|v(ξ)|2(|φβ(2π|ξ|y)|2 + |φ′β(2π|ξ|y)|2

)y1−α dξdy

=

∫ ∞

0(|φβ(s)|2 + |φ′β(s)|2)s1−α ds

RN

|2πξ|α|v(ξ)|2 dξ.

23

Using (A.9) we see that the integral∫∞0 (|φβ |2 + |φ′β|2)s1−α ds is convergent

provided β > α/2. This proves (A.7) with c(α, β) = (Hα(φβ))−1/2. 2

Remark A.1 If β = 1 we have φ1(s) = e−s, and Hα(φ1) = 2α−1Γ(2 − α),see [42]. Moreover, when β = α, integrating by parts and using the equationin (A.8), and (A.9), we obtain

Hα(φα) =

∫ ∞

0[φ2α(s) + (φ′α)

2(s)]s1−α ds = − lims→0

s1−αφ′α(s) = αc1(α) = κα.

(A.10)

Lemma A.3 Let z ∈ Xα(RN+1+ ) and let w = Eα(Tr(z)) be its α-harmonic

associated function (the extension of the trace). Then

‖z‖2Xα = ‖w‖2Xα + ‖z − w‖2Xα .

Proof. Observe that, for h = z − w, we have

‖z‖2Xα =

RN+1+

y1−α(|∇w|2 + |∇h|2 + 2⟨∇w,∇h

⟩).

But, since Tr(h) = 0, we have

RN+1+

y1−α⟨∇w,∇h

⟩dxdy = 0. 2

Lemma A.4 If g ∈ L2N

N+α (RN ), and f ∈ Hα/2(RN ), then there exists aconstant ℓ(α,N) > 0 such that

∣∣∣∣∫f(x) g(x) dx

∣∣∣∣ ≤ ℓ(α,N)‖f‖Hα/2‖g‖ 2NN+α

. (A.11)

Moreover, the equality in (A.11) with the best constant holds when f and gtake the form (A.6).

The proof follows by an standard argument that can be found, for in-stance in [22, 42].

Proof. By Parceval’s identity and Cauchy-Schwarz’s inequality, we have

(∫

RN

f(x) g(x) dx

)2

=

(∫

RN

f(ξ) g(ξ) dξ

)2

≤(∫

RN

|2πξ|α |f(ξ)|2 dξ) (∫

RN

|2πξ|−α |g(ξ)|2 dξ).

24

The second term can be written using [32] as

RN

|2πξ|−α |g(ξ)|2 dξ = b(α,N)

R2N

g(x)g(x′)

|x− x′|N−αdxdx′,

where

b(α,N) =Γ(N−α

2 )

2απN/2Γ(α2 ),

We now use the following Hardy-Littlewood-Sobolev inequality, see again [32],

R2N

g(x)g(x′)

|x− x′|N−αdxdx′ ≤ d(α,N)‖g‖22N

N+α

,

where

d(α,N) =π

N−α2 Γ(α2 )(Γ(N))

αN

Γ(N+α2 )(Γ(N2 ))

αN

,

with equality if g takes the form (A.6). From this we obtain the desiredestimate (A.11) with the constant ℓ(α,N) =

√b(α,N)d(α,N).

When applying Cauchy-Schwarz’s inequality, we obtain an identity pro-vided the functions |ξ|α/2f(ξ) and |ξ|−α/2g(ξ) are proportional. This means

g(ξ) = c|ξ|αf(ξ) = c[(−∆)α/2f ]∧ (ξ).

We end by observing that if g takes the form (A.6) and g = c(−∆)α/2f thenf also takes the form (A.6). 2

Proof of Theorem A.1. We apply Lemma A.4 with g = |f |N+αN−α

−1f , then useLemma A.2 and conclude using Lemma A.3. The best constant is S(α,N) =ℓ2(α,N)/κα. 2

Related to this result we quote the work [19], where it is proved that the

only positive regular solutions to (−∆)α/2f = cfN+αN−α take the form (A.6).

Remark A.2 If we let α tend to 2, when N > 2, we recover the classi-cal Sobolev inequality for a function in H1(RN ), with the same constant,see [40]. In order to pass to the limit in the right-hand side of (A.4), at leastformally, we observe that (2 − α)y1−α dy is a measure on compact sets ofR+ converging (in the weak-* sense) to a Dirac delta. Hence

limα→2−

∫ 1

0

(∫

RN

|∇z(x, y)|2 dx)(2− α)y1−α dy =

RN

|∇v(x)|2 dx.

We then obtain

(∫

RN

|v(x)|2NN−2 dx

)N−2N

≤ S(N)

RN

|∇v(x)|2 dx,

25

with the best constant S(N) = limα→2−

S(α,N)2−α = 1

πN(N−2)

(Γ(N)

Γ(N2)

) 2N. It is

achieved when v takes the form (A.6) with α replaced by 2.

Let now v ∈ Xα0 (CΩ). Its extension by zero outside the cylinder CΩ

can be approximated by functions with compact support in RN+1+ . Thus,

the trace inequality (A.4), together with Holder’s inequality, gives a traceinequality for bounded domains.

Theorem A.5 For any 1 ≤ r ≤ 2NN−α , and every z ∈ Xα

0 (CΩ), it holds

(∫

Ω|v(x)|r dx

)2/r

≤ C(r, α,N, |Ω|)∫

y1−α|∇z(x, y)|2 dxdy, (A.12)

where v = Tr(z).

Acknowledgments.

CB and AdP partially supported by Spanish Project MTM2008-06326-C02-02; EC

partially supported by Spanish Project MTM2009-10878.

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