soal fisika dan jawaban kelas II

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  • 8/9/2019 soal fisika dan jawaban kelas II

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    No

    .

    Standart

    Kompetensi

    Kompeten

    si Dasar

    Materi Indikator

    Soal

    Soal Jawaban Panjang

    1.

    8. Momentum

    Sudut dan

    Keseimbanga

    n Benda Tegar

    8.7

    Dinamika

    Gerak

    Rotasi

    Kecepatan

    gerak

    menggelind

    ing benda

    pada bidang

    miring

    Siswa dapat

    menentukan

    kecepatan

    gerak

    menggelindi

    ng benda

    pada bidang

    miring jika

    diketaui !

    " solid c#linder rolls $rom rest down te incline

    is %& meters ig. Determine te speed o$ te

    c#linder wen it arri'ed at te $oot o$ te

    incline(.a. )8*)+ m,s)

    b. )7*)8 m,s)

    c. )+*)8 m,s)

    d. )7*)+ m,s)

    e. )%*)7 m,s)

    Data - ! %& m g !& m,s)/ ),0 mR)

    1roblem - 2b 3"nswer -4p" 5 4ktrans " 5 4krot " 4pB5 4ktrans B 5 4krot B

    m g"51

    2 m '")5

    1

    2 /

    ") m g B 5

    1

    2 m 'B)5

    1

    2 /

    B)

    m g"5 & 5 & & 51

    2 m 'B)5

    1

    2 /

    B

    )

    g" 5+210 'B

    )

    'B

    60010

    7

    'B )+*)8 m,s)

    6adi jawabann#a 9 'B )+*)8 m,s)

    )+*)8 m,s)

    'B )

    2. 10. Fluida

    Dinamis

    10.9

    Penerapa

    n hukum

    Bernoulli

    Kecepata

    n pada

    tabung

    venturi

    Sisa

    dapat

    menentuk

    an

    kecepatan

    pada

    salah satu

    pipa

    tabung

    venture.

    Tis is in addition to te 'enture meter is

    used to determine te $luid $low 'elocit#. /$

    :& cm and a densit# o$ !&&& kg,m :

    $luid* cross sectional areas "! 0 cm) and

    ") : cm). ;at is te 'elocit# o$ $luid

    $low in cross section "(a. !*8: m,sb. ) m,s

    Data - :& "! 0 cm) ") : cm).

    1roblem - 2! 3

    "nswer -

    2! ") 2gh

    A1A2

    2

    3

    !*8

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    !ika

    diketahui

    luas area

    "1# "2

    dan

    c. )*:< m,sd. :*!< m,se. 0*% m,s

    : = !&>< 2103010

    2

    (5104)2(3104)2

    : = !&>< 23

    251089108

    2!9)+ = !&>8=6

    16108

    2! 3,375 !*8: m,s

    6adi jawabann#a "9 2! 3,375 !*8: m,s

    $.11. %eori

    Kinetik &as

    11.'(nergi

    Dalam

    dan

    Dera)at

    Kebebasa

    n

    *ata+rataenerg,

    kinetic

    pada

    benda

    ,ang

    memiliki

    $ gerak.

    Sisa

    dapat

    menentukan rata+

    rata

    energ,

    kinetic

    pada

    benda

    ,ang

    memiliki $

    gerak.

    (ach molecule o- a particular

    pol,atomic gas at 1#200 K has three

    translational# three rotational# andvibrational degrees o- -reedom is -our

    contributes to mechanical energ,. %he

    average kinetic energ, per molecule

    is.

    a. /#/ 10+2$!b. /#9 10+20!c. /#$ 10+20!d. /#0 10+2

    !e. /# 10+2$!

    Data - T !)&& k K1,3810

    23J

    K $ !&

    1roblem - 4K 3

    "nswer -

    Ek=f(12 k T)Ek=10( 12 )(1,381023

    J

    K) (1.200K)=8,3

    6adi jawabann#a 9Ek 8,310

    20J

    Ek

    8,3

    . 11. %eori

    Kinetik &as

    11.

    Kecepata

    n e-ekti-

    gas

    Kecepata

    n e-ekti-

    gas

    Sisa

    dapat

    menentuk

    an

    kecepatan

    3alculate the e4ective speed o-

    o,gen gas 56 7 $2 kg 8 kmol

    situated in the container temperature

    2: ; 3. 5K 7 1.$/ < 10+2$ ! 8 K

    a. // m8s

    Data = 6 7 $2 kg8kmol %7 2:o3 K7!.:8 ? !&>):

    6 , K

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    e-ekti- gas)ika

    diketahui

    6 dan %.

    b. /' m8sc. / m8sd. /$# m8se. /#9 m8s

    1roblem -vRMS

    "nswer -

    m0=M

    NA=

    32 kg

    kmol

    6,021026molekul

    kmol

    5,311026

    kg /molekul

    vRMS=3kTm0 =

    3(1,381023 JK)(300K)

    (5,311026 kgmolekul )483,6m /s

    Jadi jawabannya (D) 483,6m /s

    '.11. %eori

    Kinetik &as

    11.1

    %ingkat

    Keadaan

    gas

    %ekanan

    akhir gas

    Sisa

    dapat

    mentukan

    tekanan

    akhir gas

    )ika

    diketahui

    %1# P1# >

    dan %2.

    %he to liters o- gas at a temperature

    o- 2: ; 3 and a pressure o- 1 atm is

    compressed up to 1 liter at

    atmospheric and heated up to the

    temperature to 12: ; 3. %he ?nal

    pressure o- the gas is

    a. 2#/: atmb. 1 atmc. #2 atmd. $ atm

    e. 2#: atm

    Data - T! )7o 1 ! atm 2 )l T) !)7o

    1roblem - 1) 3

    "nswer -

    P1

    .V1

    T1=

    P2

    .V2

    T2

    P2=

    P1

    V1

    T2

    V2 T1=

    (1atm ) (2L) (400K)(1L) (300K)

    =2,67 atm

    Jadi jawabannya (E)

    2,67atm

    2,

    11. %eori

    Kinetik &as

    11.'

    (nergi

    dalam

    dan

    Dera)at

    (nergi

    Kinetik

    *ata+rata

    Sisa

    dapat

    menentuk

    an (nergi

    kinetic

    Determine te a'erage kinetic energ# and

    energ# in 0 mol ideal gas at a temperature o$

    !)7o i$ te gas is-a.gas monatomic@ b.gas diatomic k !.:8 =!& >

    ): 6 , K@NA %.&) =!&)%molecules , mol 9.

    Data - n 0 mol@ T !)7o k !.:8 =!& >): 6 , K@NA %.&)

    =!&)%molecules , mol

    1roblem - a9 4K gas monoatomik

    b9 4K gas diatomic

    "nswer -

    d9 ).olume

    akhir gas

    Sisa

    dapatmenentuk

    an volume

    akhir gas

    )ika

    diketahui

    ,gen gas at a temperature o- 2: ; 3

    has a volume o- 0 dm$ and apressure o- 1.01 < 10' @8m2. Ehat is

    its volume hen the pressure is 1 raksa !:.%&& kg,m:

    >raksa 7% cm &*7% m

    1 E . g . !:.%&& ? +*8 ? &*7% !&!.)+)*8 C,m)

    v=3P

    v=3(101.292,8 Nm2 )

    1,251kg

    m3

    v=492,8m /s

    92#/

    10 11. %eori

    Kinetik &as

    11.2

    Persama

    an

    Gmum

    %ekanan

    gas

    Sisa

    dapat

    menentuk

    an

    o man, moles o- gas pressure o-

    10 ho are in a tank that has a

    volume o- 100 liters# i- the

    temperature is /: ; 3 and g 7 9./

    Data-n !& mol2 !&& Fiter &*! m:

    T 87A :%& K

    2,96

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    %ingkat

    Keadaan

    &as

    tekanan

    gas )ika

    diketahui

    n# > dan %

    m8s2Ca. )*7 atmb. )*+% atmc. ) atmd. !*%7 atm

    e. :*: atm

    1roblem - 1 . . . 3

    "nswer -

    PV= R T ! P= R T

    V

    P=(10) (8.314)(360)

    0,1

    P=299,304 C,m)

    P= 299,304

    13.600 (9,8) (0,76)

    P=2,96atm

    No. Standart

    Kompetensi

    Materi Indikator

    Soal

    Soal Jawaban Panjang Jawaban

    Pendek

    Aspek

    Intelektual!. 8.7 Dinamika

    Gerak Rotasi

    Kecepatan

    gerakmenggelind

    ing benda

    pada bidang

    miring

    Siswa dapat

    menentukankecepatan

    gerak

    menggelindi

    ng benda

    pada bidang

    miring

    " solid c#linder rolls $rom restdown te incline is %& meters ig.

    Determine te speed o$ te c#linder

    wen it arri'ed at te $oot o$ te

    incline(.

    $. )8*)+ m,s)

    g. )7*)8 m,s)

    . )+*)8 m,s)

    i. )7*)+ m,s)

    j. )%*)7 m,s)

    4p" 5 4ktrans " 5 4krot " 4pB5 4ktrans B 5 4krot B

    m g"51

    2 m '")5

    1

    2 /

    ") m g B

    51

    2 m 'B)5

    1

    2 /

    B)

    m g"5 & 5 & & 51

    2 m 'B) 5

    1

    2 /

    B)

    g" 5+2

    10 'B)

    'B )+*)8 m,s)

    9

    :

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    'B 60010

    7

    'B )+*)8 m,s)

    6adi jawabann#a 9 'B )+*)8 m,s)

    )+*)8 m,s)

    ).

    !&.+

    1enerapan

    ukum

    Bernoulli

    Kecepatan

    pada tabung

    'enturi

    Siswa dapat

    menentukan

    kecepatan

    pada sala

    satu pipa

    tabung'enture.

    Tis is in addition to te 'enture

    meter is used to determine te $luid

    $low 'elocit#. /$ :& cm

    and a densit# o$ !&&& kg,m: $luid*

    cross sectional areas "! 0 cm)and

    ") : cm). ;at is te 'elocit# o$

    $luid $low in cross section "(

    $. !*8: m,sg. ) m,s. )*:< m,si. :*!< m,sj. 0*% m,s

    2! ") 2gh

    A1A2

    : = !&>< 2103010

    2

    (5104)2(3104)2

    : = !&>< 23

    251089108

    2!9)+ = !&>8=

    6

    16108

    2! 3,375 !*8: m,s

    6adi jawabann#a "9 2! 3,375 !*8: m,s

    2!

    3,375

    !*8: m,s

    "9

    :

    :. !!.0 4nergi

    Dalam dan

    Derajat

    Kebebasan

    Rata>rata

    energ#

    kinetic pada

    benda #ang

    memiliki :gerak.

    Siswa dapat

    menentukan

    rata>rata

    energ#

    kinetic padabenda #ang

    memiliki :

    gerak.

    4ac molecule o$ a particular

    pol#atomic gas at !*)&& K as tree

    translational* tree rotational* and

    'ibrational degrees o$ $reedom is

    $our contributes to mecanicalenerg#. Te a'erage kinetic energ#

    per molecule is(.

    $. 8*8 = !&>):6g. 8*+ = !&>)&6. 8*: = !&>)& 6i. 8*& = !&>)

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    j. 8*% = !&>):6

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    )& = !&>:I 2 !"#$2 N.m

    7.Rotation

    D#namics

    Total

    energ#

    kinetic in

    rolling

    To anal#He

    te total

    energ#

    kinetic o$

    rolling object

    " solid c#linder is rolling on a $lat

    $loor wit 'elocit# !& m,s. Mass o$

    te solid c#linder is < kg and te

    diameter is 8& cm. Determine te

    total kinetic energ# o$ te solid

    c#linder -

    ". :&& 6B. :& 6. :&&& 6D. ::&& 64. : 6

    Data - Solid c#linder

    ' !& m,s

    m < kg

    / 1

    2 mr)

    d 8& cm r

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    B.R

    #

    .6R

    #

    D.#R

    3

    4.

    4R

    #

    R

    1

    632 # R . R

    R2

    1

    3# R

    3R

    #

    +. Oluid Statics

    Fiuid

    le'er rise in

    capillar#

    To anal#He

    te distance

    o$ te center

    o$ gra'it#Mercur# as a densit# o$ !:*%

    g,cm:. "t te mercur# placed te

    small tube wit diameter 0 mm. /t

    turns out tat te mercur# in te

    tube ) cm lower tan te mercur#

    in te outer tube. /$ te contact

    angle is !)7Q

    * ow muc doessur$ace tension o$ mercur#3

    ". 0%*7 C,mB. 0*00% C,m. 0*%7 C,mD. 0*7% C,m4. 0*%& C,m

    Data - Em !:*% g,cm: !:%&& kg,m:

    d 0 mm 0=!&>:m r )*0=!& >:m ) cm )=!& >)m

    !)7Q g !& m,s)

    1roblem- 3

    "nswer - 2&cos'

    g"

    )=!&>)

    2 . &cos127

    13600 .10.2,5x103

    )=!&>). !:%&& . !& . )*0=!&>: 2 . &0,6

    %*8 >!*) &

    & 6,8

    1,2

    & & $()*+ N,m & ()*+ N,m

    &

    0*%7 C,m9

    !&. Oluid Statics 1ascalUs

    Faw

    To anal#He

    te

    application

    o$ 1ascalUs

    law

    " c#lindrical #draulic pump wit

    eac diameter 8 cm and )& cm. /$

    te small tube pressed wit $orce

    0&& C* ten te $orce tat can be

    produced b# te big tube is -

    ". :*!)0 CB. :!)0 C. :)!0 C

    Data - d! 8 cm r < cm &*&< m

    d) )& cm r !& cm &*! m

    O! 0&& C

    1roblem - O)3

    "nswer -(1

    A1 (2

    A2

    O) :!)0 CB9

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    D. :!)*0 C%. :)*!0 C

    (1

    # "2

    (2

    # "2

    500

    #0,042

    (2

    #0,12

    500

    0,0016 (2

    0,01

    &*&&!%O) 0

    O)5

    0,0016

    O) '"2( N

    !!.Oluid

    D#namics

    Te

    principle o$

    continuit#

    To anal#He

    te diameter

    o$ pipe basic

    on principle

    o$ continuit#Te 'elocit# o$ water in a pipe wit

    diameter % cm is &*)0 m,s. Tat te

    water out wit speed < m,s* te pipemust be connected wit anoter

    pipe* wic one end is a smaller

    diameter. So* te diameter o$ tat

    pipe is3

    ". !0 cmB. !0=!&>0cm. !0=!&>:cmD. !*0 cm4. !0& cm

    Data - d! % cm %=!&>)m r :=!&>)m

    '! &*)0 m,s ') < m,s

    1roblem - d)3

    "nswer - "!. '! "). ')

    #

    r!)

    . '!

    #

    r))

    . ')

    # :=!&>)9). &*)0

    # r) . : m

    d & 2 ! +)(!"#$'

    & #)#"( m & ")( -m

    d !*0 cm

    D9

    !). Oluid

    D#namics

    Generator

    e$icienc#

    To calculate

    a'erage

    power in

    application

    o$ $luid

    " water$all wit ig )& m is used

    $or #dropower 1FT"9. 4'er#

    second te water $lowing at !& m :.

    /$ te generator e$$icienc# 00V and

    acceleration o$ gra'it# g !& m,s)*

    Data - )& m

    E !&&& kg,m:

    g !& m,s W 00V 2 !& m:

    1listrik

    !!&& k;

    B9

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    d#namics

    so te a'erage power tat can be

    produced is - in k;9

    ". !!&B. !!&&. ))&&D. )0&&4. 00&&

    1roblem - 1listrik3

    "nswer - X V

    t 10

    1 !& m:,s

    1 W E X g 00V !&&& !& !& )&

    &*00 !&&& !& !& )&

    !!&&&&& ;

    Plistrik& ""## k

    !:.Kinetic Gas

    Teor#

    "'erage o$

    kinetic

    energ#

    To anal#He

    te a'erage

    o$ kinetic

    energ#

    /n a bo=* its contents &*0 m:. Tere

    are !&0 gas particle. /$ te gas

    pressure is ! atm* ow muc te

    a'erage kinetic energ#3

    ". &*70 k6B. 70 6. 70&&& k6

    D. 70& 64. &*70 6

    Data - 2 &*0 m:

    C !&0

    1 ! atm !&0Cm)

    1roblem - 4kY3

    "nswer - 12 1

    3 C m ')

    &1

    3 1

    2 m ')C

    12 2

    3 4kC

    4k3PV2N

    310

    50,5

    2105

    4k &*70 6

    4k &*70 6

    49

    !

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    2x 10

    6

    33,24x 105

    E &*% kg,m:

    !0.Kinetic Gas

    Teor#

    /n energ# o$

    ideal gas

    To calculate

    te in energ#

    o$ ideal gasCeon Ce9 is monoatomic gas. ow

    muc te in energ# o$ ) gram Ce

    gas at temperature 0&Q i$ relati'e

    molecular mass Mr !& kg,kmol3". 8&0)*< 6B. 8&*0)< 6. 8*&0)< 6D. 8&0)< 64. 8&0*)< 6

    Data - m ) gram )=!&>:kg T 0&Q :):QK

    Mr !& kg,kmol3

    R 8*:! Z !&:6,kmol K1roblem - P3

    "nswer - n

    m

    M"

    2x103

    10 )=!&>