Perhitungan Data Aktual

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PERHITUNGAN DATA AKTUAL A. Neraca Panas yang Masuk ke Melter (Q 1 ) Neraca Panas Urea Diketahui : m in = 37500 kg/jam BM = 60 kg/kmol M in = 625 kmol/jam Cp = 94 kJ/kmol x 0,239 kkal/kJ = 22,466 kkal/mol K T in = 71,4 o C = 344,4 o K T ref = 25 o C = 298 o K Q urea = M in . Cp . ∆T = 625 kmol/jam x 22,466 kkal/mol K x (344,4-298) o K = 625 kmol/jam x 22,466 kkal/mol K x 46,4 o K = 651514 kkal/jam Neraca Panas Air Diketahui : m in = 112 kg/jam BM = 18 kg/mol M in = 6,222 kmol/jam Cp = 8,22 + 0,00015T + 0,00000134T 2 T in = 71,4 o C = 344,4 o K T ref = 25 o C = 298 o K

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Transcript of Perhitungan Data Aktual

Page 1: Perhitungan Data Aktual

PERHITUNGAN DATA AKTUAL

A. Neraca Panas yang Masuk ke Melter (Q1)

Neraca Panas Urea

Diketahui :

min = 37500 kg/jam

BM = 60 kg/kmol

Min = 625 kmol/jam

Cp = 94 kJ/kmol x 0,239 kkal/kJ = 22,466 kkal/mol K

Tin = 71,4oC = 344,4 oK

Tref = 25 oC = 298 oK

Q urea = Min . Cp . ∆T

= 625 kmol/jam x 22,466 kkal/mol K x (344,4-298) oK

= 625 kmol/jam x 22,466 kkal/mol K x 46,4 oK

= 651514 kkal/jam

Neraca Panas Air

Diketahui :

min = 112 kg/jam

BM = 18 kg/mol

Min = 6,222 kmol/jam

Cp = 8,22 + 0,00015T + 0,00000134T2

Tin = 71,4 oC = 344,4 oK

Tref = 25 oC = 298 oK

Q air = Min .∫Tref

Tin

.Cp . ∆T

= 6,222 kmol/jam x ∫298

344,6

.¿¿ 8,22 + 0,00015T +

0,00000134T2) kkal/kmol K.dT

= 6,222 kmol/jam x (8,431 – 8,384) kkal/kmol

= 6,222 kmol/jam x 0,047 kkal/kmol

= 0,292 kkal/jam

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Neraca Panas Biuret

Diketahui :

min = 103 kg/jam

BM = 103,08 kg/kmol

Min = 0,999 kmol/jam

Cp = 131,3 kJ/kmol x 0,239 kkal/kJ = 31,381 kkal/kmol

K

Tin = 71,4 oC = 344,4 oK

Tref = 25 oC = 298 oK

Q biuret = Min . Cp . ∆T

= 0,999 kmol/jam x 31,381kkal/kmol K (344,4-298) oK

= 0,999 kmol/jam x 31,381kkal/kmol K x 46,4 oK

= 1454,622 kkal/jam

Panas yang masuk ke melter adalah Q1

Q1 = Qurea + Qair + Qbiuret

= 651514 kkal/jam + 0,292 kkal/jam + 1454,622 kkal/jam

= 652968,914 kkal/jam

B. Nerca Panas yang Keluar dari Melter (Q2)

Neraca Panas Urea

Diketahui :

mout = 37500 kg/jam

BM = 60 kg/kmol

Mout = 625 kmol/jam

Cp = 94 kJ/kmol K x 0,239 kkal/kJ = 22,466 kkal/mol K

Tout = 137 oC = 410 oK

Tref = 25 oC = 298 oK

Q urea = Mout . Cp . ∆T

= 625 kmol/jam x 22,466 kkal/mol K (410-298) oK

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= 625 kmol/jam x 22,466 kkal/mol K x 112 oK

= 1572620 kkal/jam

Neraca Panas Air

Diketahui :

mout = 112 kg/jam

BM = 18 kg/kmol

Mout = 6,222 kmol/jam

Cp = 8,22 + 0,00015T + 0,00000134T2

Tout = 137 oC = 410 oK

Tref = 25 oC = 298 oK

Q air = Min .∫Tref

Tout

.Cp . ∆T

= 6,222 kmol/jam x ∫298

410

.¿¿ 8,22 + 0,00015T +

0,00000134T2) kkal/kmol K.dT

= 6,222 kmol/jam x (8,507 – 8,384) kkal/kmol

= 6,222 kmol/jam x 0,123 kkal/kmol

= 0,765 kkal/jam

Neraca Panas Biuret

Diketahui :

mout = 103 kg/jam

BM = 103,08 kg/kmol

Mout = 0,999 kmol/jam

Cp = 131,3 kJ/kmol x 0,239 kkal/kJ = 31,381 kkal/kmol

K

Tout = 137 oC = 410 oK

Tref = 25 oC = 298 oK

Q biuret = Mout . Cp . ∆T

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= 0,999 kmol/jam x 31,381 kkal/kmol K x (410 - 298) oK

= 0,999 kmol/jam x 31,381 kkal/kmol K x 112oK

= 3511,157 kkal/jam

Panas yang masuk ke melter adalah Q2

Q2 = Qurea + Qair + Qbiuret

= 1572620 kkal/jam + 0,765 kkal/jam + 3511,157 kkal/jam

= 1576131,922 kkal/jam

C. Steam yang Masuk ke Melter

min = 8,4 T/H x 1000 kg/T = 8400 kg/jam

BM = 18 kg/kmol

Min = 466,667 kmol/jam

Tin = 184 oC = 457 oK

Pin = 5,78 kg = 0,567 Mpa

Tekanan

(MPa)

Entalphy

(kJ/kmol)

0,1

0,567

1,0

49,189

?

50,030

Interpolasi untuk mencari entalphy dari steam bertekanan 0,567 Mpa

x− x1x2−x 1 = y− y1

y2− y1

x−49,18950,030−49,189 = 0,567−0,1

1,0−0,1

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x−49,1890,841 = 0,467

0,9

0,9x – 44,270 = 0,374

0,9x = 44,644

X = 49,604 kJ/kmol

∆Hin = 49,604 kJ/kmol x 1000 mol/kmol = 11855,356 kJ/kmol

Q3 = Min x ∆H

= 466,667 kmol/jam x 11855,356 kJ/kmol

= 5532503 kkal/jam

D. Steam yang Keluar dari Melter (Q4)

Q4 = (Q1 + Q3) – Q2

= (652968,914 kkal/jam + 5532503 kkal/jam) - 1576131,922

kkal/jam

= 4609340,41 kkal/jam

Jadi, total panas yang masuk ke melter (Qin)

Qin = Q1 + Q3

= 652968,914 kkal/jam + 5532503 kkal/jam

= 6185472,332 kkal/jam

Dan total panas yang keluar dari melter (Qout)

Qout = Q2 + Q4

= 1576131,922 kkal/jam + 4609340,41 kkal/jam

= 6185472,332 kkal/jam

Menghitung Efisiensi

Efisiensi = NeracaPanas AktualNeraca Panas Design x 100 %

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= 6185472,33232147003,51 x 100 %

= 19,2 %