perhitungan boiler
4
Boiler A pada P = 22,23 bar P abs = P atm + P = 1 + 22,23 = 23,23 bar T = 382 °C Interpolasi 20 bar h g = 3023,5 + (3247,6 – 3023,5) ( 382−300 ) ( 400−300 ) = 3023,5 + 224,1 (0,82) = 3207,262 KJ Kg 30 bar h g = 2993,5 + (3230,9 – 2993,5) ( 382−300 ) ( 400−300 ) = 2993,5 + 237,4 (0,82) = 3188,168 KJ Kg 23,23 bar h g = 3207,262 + (3188,168 – 3207,262) ( 23,23−20 ) ( 30−20 ) = 3207,262 + (-19,094) (0,323) = 3201,0946 KJ Kg = 765, 0808 Kkal Kg 83,5 °C h g = 334,92 + (355,91 – 334,92) ( 83,5 −80 ) ( 85−80 )
-
Upload
darul-ulum -
Category
Documents
-
view
78 -
download
8
description
dan lain-lain
Transcript of perhitungan boiler
Boiler A
pada P = 22,23 bar
Pabs = Patm + P
= 1 + 22,23
= 23,23 bar
T = 382 °C
Interpolasi
20 bar hg = 3023,5 + (3247,6 – 3023,5) (382−300)(400−300)
= 3023,5 + 224,1 (0,82)
= 3207,262 KJK g
30 bar hg = 2993,5 + (3230,9 – 2993,5) (382−300)(400−300)
= 2993,5 + 237,4 (0,82)
= 3188,168 KJK g
23,23 bar hg = 3207,262 + (3188,168 – 3207,262) (23,23−20)(30−20)
= 3207,262 + (-19,094) (0,323)
= 3201,0946 KJK g
= 765, 0808 KkalK g
83,5 °C hg = 334,92 + (355,91 – 334,92) (83,5−80)(85−80)
= 334,92 + 20,99 (0,7)
= 349,613 KJK g
= 83,5596 KkalK g
Boiler B
pada P = 22,47 bar
Pabs = Patm + P
= 1 + 22,47
= 23,47 bar
T = 418,67 °C
Interpolasi
20 bar hg = 3247,6 + (3467,6 – 3247,6) (418,67−400)(500−400)
= 3247,6 + 220 (0,1867)
= 3288,674 KJK g
30 bar hg = 3230,9 + (3456,5 – 3230,9) (418,67−400)(500−400)
= 3230,9 + 225,6 (0,1867)
= 3273,019 KJK g
23,23 bar hg = 3288,674 + (3273,019 – 3288,674) (23 ,47−20)
(30−20)
= 3288,674 + (-15,655) (0,347)
= 3283,2417 KJK g
= 784,7145 KkalK g
83,5 °C hg = 334,92 + (355,91 – 334,92) (83,5−80)(85−80)
= 334,92 + 20,99 (0,7)
= 349,613 KJK g
= 83,5596 KkalK g
