1. Menghitung Temperatur film pada condenser shell and tube

T f=T i+T o

2

t a=ti+t o2

DimanaT i = Temperatur Masuk Fluida Panas [℉ ]T o = Temperatur Keluar Fluida Panas [℉ ]t i = Temperatur Masuk Fluida Dingin [℉ ]t o = Temperatur Keluar Fluida Dingin [℉ ]T f = Temperatur Film Fluida Panas [℉ ]t a = Temperatur Film Fluida Panas [℉ ]

2. Menghitung Heat LoadQ=W . (H s−H c )

Dimana

Q = Heat Load [ Btuh ]W = Massa Aliran Fluida [ lbhr ]H s = Entalphy Steam [ Btulb ]H c = Entalphy Condensate [ Btulb ]

3. Menghitung Overall Heat Transfer CoefficientU=U 1 . Fw . Fm. Fc

U = Heat Transfer Coefficient [ Btu

ft2℉ hr ]U 1 = Uncorrected Heat Transfer Coefficient [ Btu

ft2℉ hr ]Fw = Faktor Koreksi Untuk Temperatur Air MasukFm = Faktor Koreksi Untuk Material TubeF c = Cleanliness Factor

4. Menghitung LMTD

LMTD=t o−ti

ln( T i−tiT i−t o )

DimanaLMTD = Log Mean Temperature Difference [℉ ]

5. Menghitung Luas Permukaan Condenser

A= QU . LMTD

DimanaA = Luas Permukaan Condenser [ ft2 ]

6. Menghitung Circulating Water Flow

Flcw=Q

500. ( to−ti )

DimanaFlcw = Circulating Water Flow [gpm]

7. Menghitung Jumlah Tube

N=Flcw .np

g . v

DimanaN = Jumlan Tubenp = Jumlah Passes pada Shellg = gpm per tube at 1,0 [ ft /s ] (from tube characteristic table)v = Velocity [ ft /s ]

8. Menghitung Panjang tube

L= AN .m

DimanaL = Panjang Tube [ ft ]m = Surface External, sq.ft per linear foot (from tube characteristic table)

1. Menghitung Temperatur film pada condenser shell and tubea. T i=53,78 [℃ ]=128,804 [℉ ]

T o=53,78 [℃ ]=128,804 [℉ ]

T f=T i+T o

2

T f=128.804 [℉ ]+128.804 [℉ ]

2T f=128.804 [℉ ]=53,78 [℃ ]

b. t i=33,79 [℃ ]=92,822 [℉ ]t o=50,46 [℃ ]=122,828 [℉ ]

t a=ti+t o2

t a=92,822 [℉ ]+122,828 [℉ ]

2t a=107,825 [℉ ]=42,125 [℃ ]

2. Menghitung Heat Load

W=514,5[ tonhr ]=1134278,338941 [ lbhr ]H s=2597,968[ kJkg ]=1116,925[ Btulb ]H c=225,0977 [ kJkg ]=96,774579 [ Btulb ]Q=W . (H s−H c )

Q=1134278,338941 [ lbhr ] .(1116,925 [Btulb ]−96,774579 [ Btulb ])Q=1157134525 [ Btuhr ]

3. Menghitung Overall Heat Transfer Coefficienta. do=1.125 [¿ ]

U 1=685,2[ Btu

ft2℉ hr ]Fw=1,083Fm=0,862F c=90%=0.9

v=2.273[ ms ]=7.339[ fts ]

U=U 1 . Fw . Fm. Fc

U=685,2[ Btu

ft2℉ hr ] .1,083 .0,862 .0.9U=575,699[ Btu

ft2℉ hr ]=3268,97 [ W

m2℃ ]b. do=1 [¿ ]

U 1=695,8[ Btu

ft2℉ hr ]Fw=1,083Fm=0,862F c=90%=0.9

v=2.273[ ms ]=7.339[ fts ]U=U 1 . Fw . Fm. Fc

U=685,2[ Btu

ft2℉ hr ] .1,083 .0,862 .0.9U=584,61[ Btu

ft2℉ hr ]=3319,569526 [ W

m2℃ ]4. Menghitung LMTD

T i=53,78 [℃ ]=128,804 [℉ ]t i=33,79 [℃ ]=92,822 [℉ ]t o=50,46 [℃ ]=122,828 [℉ ]

LMTD=t o−ti

ln( T i−tiT i−t o )

LMTD=122,828 [℉ ]−92,822 [℉ ]

ln( 128,804 [℉ ]−92,822 [℉ ]128,804 [℉ ]−122,828 [℉ ] )

LMTD=16,7139 [℉ ]=−8,492278 [℃ ]

5. Menghitung Luas Permukaan Condensera. LMTD=16,7139 [℉ ]

Q=1157134525 [ Btuhr ]U=575,699[ Btu

ft2℉ hr ]

A=1157134525 [ Btuhr ]

575,699 [ Btuft 2℉ hr ] .16,7139 [℉ ]

A=120257,0586 [ ft2 ]=11173,92 [m2 ]

b. LMTD=16,7139 [℉ ]

Q=1157134525 [ Btuhr ]U=584,61[ Btu

ft2℉ hr ]

A=1157134525 [ Btuhr ]

584,61[ Btuft2℉ hr ] .16,7139 [℉ ]

A=118424 [ ft2 ]=11001,9 [m2 ]

6. Menghitung Circulating Water Flow

Q=1157134525 [ Btuhr ]t i=33,79 [℃ ]=92,822 [℉ ]t o=50,46 [℃ ]=122,828 [℉ ]

Flcw=Q

500. ( to−ti )

Flcw=1157134525 [Btuhr ]

500. (122,828 [℉ ]−92,822 [℉ ] )

Flcw=77126,87629 [gpm ]=21037,54 m3

hr

7. Menghitung Jumlah Tubea. Flcw=77126,87629 [gpm ]

np=2

g=2,797[ gpmfps ] (gpm per tube at 1,0 [ ft / s ]) (from tube characteristic table)

v=2.273[ ms ]=7,339[ fts ]N=

77126,87629 [ gpm ] .2

2,797 [ gpmfps ] .7,339[ fts ]N=7514,6 ≈7515buah tube

b. Flcw=77126,87629 [gpm ]np=2

g=2,182[ gpmfps ] (gpm per tube at 1,0 [ ft / s ]) (from tube characteristic table)

v=2,273[ ms ]=7.339[ fts ]N=

77126,87629 [gpm ] .2

2,182[ gpmfps ].7,339 [ fts ]N=9632,61≈ 9633buahtube

8. Menghitung Panjang tubea. A=120257,0586 [ ft2 ]

N=7515 (buah tube )m=0,2944 (Surface External , sq . ft per linear foot ) (from tube characteristic table)

L= AN .m

L=120257,0586 [ ft 2 ]

7515 .0,2944ft2

ftL=54,3555 [ ft ]=16,567556 [m ]

b. A=118424 [ ft2 ]N=9633 (buah tube )m=0,2618 (Surface External , sq . ft per linear foot ) (from tube characteristic table)

L= AN .m

L=118424 [ ft2 ]

9633 .0,2618ft2

ft

L=46.95788 [ ft ]=14,313 [m ]