7/24/2019 Kompressor Dan Sistem Udara Tekan

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KOMPRESSOR DAN SISTEM UDARA TEKAN

1. Tujuan Percobaan2. Dasar Teori3. Alat an !a"an #an$ Di$una%an&. 'an$%a" Kerja

(. Data Pen$a)atanTabel S*esi+i%asi Ko)*ressor

TipeKompressor

HorsePower

Displacement

MaxPressure

Tank Size

7/24/2019 Kompressor Dan Sistem Udara Tekan

2/7

hp Kw f/m L/m Psig

kg/cm 2 Liter alon

!"#$% #$ !&' (% #2#! #)) #% 2%$ *$

Tabel Pen$a)atan Percobaan

+ompressor T,pe

Po-Kpa. un

0aktu -menit.P-Tekanan

KompressorHi1up Mati P # P 2

!"#$%

- eciprocating+ompressor.

#$#&%2' # $2 2' $$ (2 *$ #$$

#$#&%

2' 2 $2 2% $$ %' !$ #$$#$#&%2' % $2 #' $$ 2) )$ #$$

,. Per"itun$anDi%-P / 1 at) 0 1 1 32( %*a 1 at) / 1 1 32( %*aP)a%s / ,( %*aP)in / 3( K*a

Run 1

P1 / , *si /6,893 Kpa

1 psi = 413,58 Kpa

P2 / 1 *si /6,893 Kpa

1 psi = 689,3 Kpa

Run 2

P1 / *si /6,893 Kpa

1 psi = 482,51 Kpa

P2 / 1 *si /6,893 Kpa

1 psi

= 689,3 Kpa

Run 3

P1 / 4 *si /6,893 Kpa

1 psi = 551,41 Kpa

P2 / 1 *si /6,893 Kpa

1 psi = 689,3 Kpa

7/24/2019 Kompressor Dan Sistem Udara Tekan

3/7

Mencari 5ar$a T 2

Run 1

T 2T 1 / [ P 2 P 1 ] y 1 y

[ P 2

P 1 ]=

T 2

T 1

y 1

y

689,3413,58

= [T 2T 1 ]3 (1,667 = [T 2T 1 ]3 (T 2T 1

= [1,667 ] 3 (

T 2 / 1 1( . T 1

T 2 / 1 1( . 2678

T 2 / 33 ((378

T 2 / 3 , ((3 K

Run 2T 2

T 1 / [ P 2

P 1 ] y 1

y

[ P 2 P 1 ]= T 2T 1 y 1 y 689,3

482,51=[ T 2T 1 ]3 (

1,428 = [T 2T 1 ]3 (

7/24/2019 Kompressor Dan Sistem Udara Tekan

4/7

T 2T 1

= [1,428 ] 3 (

T 2 / 1 1 . T 1

T 2 / 1 1( . 2678

T 2 / 32 1 378

T 2 / 3 ( 1 3 K

Run 3T 2T 1 / [

P 2 P 1 ]

y 1 y

[ P 2 P 1 ]= T 2T 1 y 1 y 689,3551,4

= [ T 2T 1 ]3 (1,250 =

[T 2T 1

]3 (

T 2T 1

= [1,250 ] 3 (

T 2 / 1 ,,. T 1

T 2 / 1 ,,. 2678

T 2 / 3 61&78

T 2 / 3 3 61& K

Men$"itun$ Ka*asitas Ko)*ressor Run 1

Q = P 2 P 1 Po

= V t

x[T 2T 1 ]Q =

689,3 413,58101,325 Kpa

=0,230 m3

135 det x[306,553 K 302 K ]

7/24/2019 Kompressor Dan Sistem Udara Tekan

5/7

/ & ) 3 eti%

Run 2

Q = P 2 P 1 Po

= V t

x[T 2T 1 ]Q =

689,3 482,51101,325 Kpa

=0,230 m3

133,8 det x[305,103 K 302 K ]

/ 3(& ) 3 eti%

Run 3

Q = P 2 P 1 Po

= V t

x[T 2T 1 ]Q=

689,3 551,4101,325 Kpa

= 0,230 m3

129 det x[303,914 K 302 K ]

/ 2&3 ) 3 eti%

Q= Q1 + Q 2 + Q 3

3

/ 3((, ) 3 eti%

Men$"itun$ Ka*asitas Ko)*ressor

P= Wst

9s / 4, 66, Kj

N!- Karena 9s ti a% i*en$aru"i ole" :a%tu )a%a :a%tu #an$ i$una%anuntu% %oe+isien bernilai sa)a

Ma%a Da#a Ko)*ressor-Run 1t/ 2.2( )enit / 13( eti%

7/24/2019 Kompressor Dan Sistem Udara Tekan

6/7

P= Wst

P=86,996 kJ 135 detik

/ ,&& %; eti% / ,&& %9Run 2t/ 2.23 )enit / 133 4 eti%

P= Wst

P= 86,996 kJ 133,8 detik

/ ,( %; eti% / ,( %9

Run 3t/ 2.1( )enit / 126 eti%

P= Wst

P=86,996 kJ 129 detik

/ , & %; eti% / , & %9Da#a Ko)*ressor Rata

7/24/2019 Kompressor Dan Sistem Udara Tekan

7/7

0,644 kW 7,5 kW

X 100

/ 4 (, =Run 3

/ P praktek

P teori x100

0,674 kW 7,5 kW

X 100

/ 4 64 =E+isiensi Ko)*ressor Rata