I II III 435341540.docx
6
| 40 42 123 33 41 109 30 49 94 | 40 42 33 41 30 49 D 7 = 490.391 – 495.214 = - 4823 x= Dx D = −418 −1681 = 418 1681 y= Dy D = −910 −1681 = 910 1681 z= Dz D = −4823 −1681 = 4823 1681 Banyak bus = x+y+z ¿ 418 1681 + 910 1681 + 4823 1681 ¿ 6151 1681 ¿ 3 1108 1681 Halm 85 14. a) Kalsium x biscuit = (12 16) ( 18 32 ) = (12.18) + (16.32) = 216 + 512 = 728 kalsium dalam biscuit b
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Transcript of I II III 435341540.docx
D7 = 490.391 495.214 = - 4823
Banyak bus = x+y+z Halm 8514. a) Kalsium x biscuit = (12 16) = (12.18) + (16.32) = 216 + 512 = 728 kalsium dalam biscuit b b) Biscuit biscuit biskuitAbc
Biscuit a mengandung 688 kalsium, 1368 proteindan 680 karbohidratBiscuit b mengandung 728 kalsium, 1344 protein dan 616 karbohidratBiscuit c mengandung 556 kalsium, 1184 protein dan 628 karbohidrat
13. - Matriks harga sewa hotel, transportasi dan makan Matriks paket yg ditawarkan:Paket Hotel Transportasi makan
Biaya = paket x harga
1. Kapal I II III
a) 4x1 +5x2 +2x3 = 423x1 +2x2 +2x3 = 272x1 +3x2 +3x3 = 33b) A X = B X= A-1 B Det A = (24+20+18)-(8+24+45) = 62-77 = -15C11 = + (6-6) = 0C12 = - (9-4) = -5C13 = + (9-4) = 5C21 = - (15-6) = -9C22 = + (12-4) = 8C23 = - (12-10) = -2C31 = + (10-4) = 6C32 = - (8-6) = -2C33 = + (8-15) = -7
X= A-1B
X1=3X2=4X3=5
Halm 677 a)
Paket I =Rp 1.120.000Paket II = Rp 1.775.000Paket III Rp 895.000
b)paket III yaitu hanya Rp895.000
8) 40x + 42y + 41z = 123 33x + 41y + 35z = 109 30x + 39y + 28z = 94 Det A = (142.157)-(143.838) = -1681 Dx = 453.675-454.694 = -418 Dy = 378.412-379.322 =-910
