Catatan Teknis 3
1
Perhitungan Kalor Kalaor adalah suatu bntukdari persamaan di bawah ini: Q = m.c.(T2-T1) Volume = v = 3,14 x (9,8/2)^2 x 9 =678,5226 cm 3 Massa = m = 678,5226 cm 3 x8,4 gr/cm 3 = 5699,58984 gr = 5,7 kg kg c = 0,092 (kal/gr. o C) Q = 5699,58984 gr x 0,092 (kal/gr. o C) x (945 o C – 25 o C ) =5699,58984 gr x 0,092 (kal/gr. o C) x 920 o C = 482413,28 kalori = 482,4 kkal http://soal-smp.blogspot.com/p/contoh-contoh-soal-2-berilah- tanda.html https://zzagy.wordpress.com/ipa-3/hemat-listrik/ http://kartikasains.blogspot.com/p/kapasitas-kalor-dan-kalor- jenis.html
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Transcript of Catatan Teknis 3
Perhitungan KalorKalaor adalah suatu bntukdari persamaan di bawah ini:
Q = m.c.(T2-T1)Volume = v = 3,14 x (9,8/2)^2 x 9 =678,5226 cm3Massa = m = 678,5226 cm3 x8,4 gr/cm3 = 5699,58984 gr = 5,7 kg kgc = 0,092 (kal/gr.oC)
Q = 5699,58984 gr x 0,092 (kal/gr.oC) x (945 oC 25 oC ) =5699,58984 gr x 0,092 (kal/gr.oC) x 920 oC = 482413,28 kalori = 482,4 kkal
http://soal-smp.blogspot.com/p/contoh-contoh-soal-2-berilah-tanda.htmlhttps://zzagy.wordpress.com/ipa-3/hemat-listrik/http://kartikasains.blogspot.com/p/kapasitas-kalor-dan-kalor-jenis.html
