BAB IV ELMES ku

8/18/2019 BAB IV ELMES ku

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BAB IVPERHITUNGAN DAN DESAIN

4.1 Perhitungan dan desain belt

Diketahui ;Putaran motor (n 1) = 1300 rpm

Putaran poros = 700 rpm

Putaran perontok = 500 rpm

Daya motor = 2,2 kW

Diameter pulley 2 (d 2) = 500 mm (tab e 20!1) be t type "

#arak antar poros ($) = 100% mm

"ahan belt = ku it

"ahan pulley = besi &or

'assa enis belt = 1000 k *m 3

+oe sien esek μ = 0,25

-e an an i.in = 2 'pa

1! Diameter pulley (d 1)

n2n1 = d1

d 2

700

1300 =d 1500

d 1 = 2/ ,23 mm

2! +e&epatan inear belt ( )

v=π . d 2 . n260000

=3,14.500.700

60000

= 1%,32 m*s

3! Pan an be t ( )


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L=π 2 (d 1+d 2)+2 x+ (d 1− d 2)

2

4 x

=3,14

2 (2/ ,23 4 500) 4 2(100%) 4(269,23 − 500 )²

4 (1008 )

= 323/, mm = 3,2 m

! 6udut +ontak ( θ ¿

d 2− ¿d12 x

sin α = ¿

6in =500 − 269,23

2(1008 )

6in α = 0,11 5

α = /,57 8

θ = (1%0 9 2 )π

180 rad

θ = (1%0 : 2(/,57))3,14180

θ = 2, 1 rad5! -arikan pada be t

P = (T 1− T 2)V 2200 = (- 19- 2) 1%,32

(- 19- 2) = 120,0


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log (T 1T 2

) = 2, 2*2,3

T 1T 2 = 11,2%


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C =131,77

1,66

C = 7 ,3% mm 2

Perhitungan Roda gigi / gear

Diketahui ;

Putaran pinion (n p) = 700 rpm

Putaran ear (n ) = 500 rpm

Daya motor = 2,2 kW

#enis = roda i i urus full – depth involute

6udut tekan = 20 o

#um ah i i pinion ( p) = 20

'odu = 3

1! e o&ity ratio ( >)

VR=n pn g

> = 700500

> = 1,2! #um ah i i ear ( A)

N G= N P .VR

A = 20!1, A = 2%

3! Diamteter pit&h (D)• Pinion

D p= N p . M

Dp = 20!3Dp = /0 mm

• Aear

D G= N G . M

D A = 2%!3DA = % mm


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! #arak antar poros (F)

C =( N p+ N G ). M

2

F =

(20 +50 ).3

2

F = 105 mm5! +e&epatan pit&h ine ( )

V =π . D p . n p60000

=3,14.60 .700

60000

= 2,1 % m*s/! ebar roda i i

b= 12 M

b = 12!3b = 3/ mm G 0 mm

7! "eban tan ensia pada roda i i

W T = Pv

xCs= 2,2 x 103

2,198 x 1= 1000,91 N

%! "eban dinamik dan Hear oad 1072

DeBormation oad Ba&tor diambi 5/

C oHab e tooth error in a&tion 0,0%3W D= W T +

21 v(b . C +W T )21 v+√ b .C +W T

W D= 1000,91 +21 x 2,198 x(40 x456 +1000,91 )21 x 2,198 +√ 40 x 456 +1000,91

W D= 1000,91 +888121,9

184,87

W D= 5804,94 ! Iaktor bentuk roda i i

y p= 0,175 − 0,0021 m

y p= 0,175 − 0,0021 x 3

y p= 0,1687

10! "eban stati& roda i i


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Dari tabe 2%!% didapat batas ketahanan untuk &ast iron = % *mm 2W s= σ e . b . π .m . y p

W s= 84 x 40 x 3,14 x 3 x 0,1687

W s= 5339,56

11! Iaktor >asio

= 2 xV . RV . R+1

= 2 x 1,41,4 +1

= 1,167

12! 'aksimum Wear oadDiambi + (materia &ombination Ba&tor) = 0,111

W ! = D p . b . . "

W ! = 60.40.1,167 .0,111

W ! = 310,888 N

Perhitungan Poros"ahan besi &or ke abu


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+ekuatan tarik (J t) = 207 'pa+ekuatan eser K u = 2 0 'paFactor of safety (I6) = /

-e an an eser i in =# $

%& =240

6 = 0 'pa

1! Poros 1

a! -orsi yan di transmisikan poros

T = Px 602 πN

= 2200 x 602 x 3,14 x 700

= 30,027 Nm= 30027 Nmm

b! Aaya pada pu ey CW A= T 1 +T 2

= 131,77 4 11,/% = 1 3, 5

&! Aaya tan ensia pada roda i i

% ' = T Rb= 3002730 = 1000,9 N

d! >eaksi pada tumpuan F dan D- Dimisa kan momen di titik D = 0

Rc x 100 = 143,45 x 200 +1000,9 x 100 = 128780 N

Rc=128780

100 = 1287,8 N

11,/131,7

/0

500100100100

/0

500


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- LI =0

R D +143,45 = RC +1000,9

R D= 1287,8 +1000,9 − 143,45

R D= 2145,25 N

e! "endin momen"endin momen pada titik C dan " = 0

"endin momen di titik F = 143,45 x 100 = 14 (345 x 103

Nmm

"endin momen di titik D = 1000,9 x 100 = 100 (09 x 103 Nmm

(maksimum)B! MNui a ent tHistin moment

" m= 2 , " ' = 1,5

T e= √ ( " m xM )2 + ( " ' xT )2

T e= √ (2 x 100,09 x 10 3)2+(1,5 x 30 (027 x 10 3)2

T e= 205,18 x 103 Nmm

! Diameter poros -e an an eser i in materia = /3 'Pa

T e= π 16

x#x d3

1000,> d

/0

100100100

500

> &1 3,


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BAB IV ELMES ku

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