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BAB IVPERHITUNGAN DAN DESAIN
4.1 Perhitungan dan desain belt
Diketahui ;Putaran motor (n 1) = 1300 rpm
Putaran poros = 700 rpm
Putaran perontok = 500 rpm
Daya motor = 2,2 kW
Diameter pulley 2 (d 2) = 500 mm (tab e 20!1) be t type "
#arak antar poros ($) = 100% mm
"ahan belt = ku it
"ahan pulley = besi &or
'assa enis belt = 1000 k *m 3
+oe sien esek μ = 0,25
-e an an i.in = 2 'pa
1! Diameter pulley (d 1)
n2n1 = d1
d 2
700
1300 =d 1500
d 1 = 2/ ,23 mm
2! +e&epatan inear belt ( )
v=π . d 2 . n260000
=3,14.500.700
60000
= 1%,32 m*s
3! Pan an be t ( )
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L=π 2 (d 1+d 2)+2 x+ (d 1− d 2)
2
4 x
=3,14
2 (2/ ,23 4 500) 4 2(100%) 4(269,23 − 500 )²
4 (1008 )
= 323/, mm = 3,2 m
! 6udut +ontak ( θ ¿
d 2− ¿d12 x
sin α = ¿
6in =500 − 269,23
2(1008 )
6in α = 0,11 5
α = /,57 8
θ = (1%0 9 2 )π
180 rad
θ = (1%0 : 2(/,57))3,14180
θ = 2, 1 rad5! -arikan pada be t
P = (T 1− T 2)V 2200 = (- 19- 2) 1%,32
(- 19- 2) = 120,0
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log (T 1T 2
) = 2, 2*2,3
T 1T 2 = 11,2%
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C =131,77
1,66
C = 7 ,3% mm 2
Perhitungan Roda gigi / gear
Diketahui ;
Putaran pinion (n p) = 700 rpm
Putaran ear (n ) = 500 rpm
Daya motor = 2,2 kW
#enis = roda i i urus full – depth involute
6udut tekan = 20 o
#um ah i i pinion ( p) = 20
'odu = 3
1! e o&ity ratio ( >)
VR=n pn g
> = 700500
> = 1,2! #um ah i i ear ( A)
N G= N P .VR
A = 20!1, A = 2%
3! Diamteter pit&h (D)• Pinion
D p= N p . M
Dp = 20!3Dp = /0 mm
• Aear
D G= N G . M
D A = 2%!3DA = % mm
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! #arak antar poros (F)
C =( N p+ N G ). M
2
F =
(20 +50 ).3
2
F = 105 mm5! +e&epatan pit&h ine ( )
V =π . D p . n p60000
=3,14.60 .700
60000
= 2,1 % m*s/! ebar roda i i
b= 12 M
b = 12!3b = 3/ mm G 0 mm
7! "eban tan ensia pada roda i i
W T = Pv
xCs= 2,2 x 103
2,198 x 1= 1000,91 N
%! "eban dinamik dan Hear oad 1072
DeBormation oad Ba&tor diambi 5/
C oHab e tooth error in a&tion 0,0%3W D= W T +
21 v(b . C +W T )21 v+√ b .C +W T
W D= 1000,91 +21 x 2,198 x(40 x456 +1000,91 )21 x 2,198 +√ 40 x 456 +1000,91
W D= 1000,91 +888121,9
184,87
W D= 5804,94 ! Iaktor bentuk roda i i
y p= 0,175 − 0,0021 m
y p= 0,175 − 0,0021 x 3
y p= 0,1687
10! "eban stati& roda i i
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Dari tabe 2%!% didapat batas ketahanan untuk &ast iron = % *mm 2W s= σ e . b . π .m . y p
W s= 84 x 40 x 3,14 x 3 x 0,1687
W s= 5339,56
11! Iaktor >asio
= 2 xV . RV . R+1
= 2 x 1,41,4 +1
= 1,167
12! 'aksimum Wear oadDiambi + (materia &ombination Ba&tor) = 0,111
W ! = D p . b . . "
W ! = 60.40.1,167 .0,111
W ! = 310,888 N
Perhitungan Poros"ahan besi &or ke abu
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+ekuatan tarik (J t) = 207 'pa+ekuatan eser K u = 2 0 'paFactor of safety (I6) = /
-e an an eser i in =# $
%& =240
6 = 0 'pa
1! Poros 1
a! -orsi yan di transmisikan poros
T = Px 602 πN
= 2200 x 602 x 3,14 x 700
= 30,027 Nm= 30027 Nmm
b! Aaya pada pu ey CW A= T 1 +T 2
= 131,77 4 11,/% = 1 3, 5
&! Aaya tan ensia pada roda i i
% ' = T Rb= 3002730 = 1000,9 N
d! >eaksi pada tumpuan F dan D- Dimisa kan momen di titik D = 0
Rc x 100 = 143,45 x 200 +1000,9 x 100 = 128780 N
Rc=128780
100 = 1287,8 N
11,/131,7
/0
500100100100
/0
500
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- LI =0
R D +143,45 = RC +1000,9
R D= 1287,8 +1000,9 − 143,45
R D= 2145,25 N
e! "endin momen"endin momen pada titik C dan " = 0
"endin momen di titik F = 143,45 x 100 = 14 (345 x 103
Nmm
"endin momen di titik D = 1000,9 x 100 = 100 (09 x 103 Nmm
(maksimum)B! MNui a ent tHistin moment
" m= 2 , " ' = 1,5
T e= √ ( " m xM )2 + ( " ' xT )2
T e= √ (2 x 100,09 x 10 3)2+(1,5 x 30 (027 x 10 3)2
T e= 205,18 x 103 Nmm
! Diameter poros -e an an eser i in materia = /3 'Pa
T e= π 16
x#x d3
1000,> d
/0
100100100
500
> &1 3,
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