Bab 3 fedi aritmatika bimbel

7/23/2019 Bab 3 fedi aritmatika bimbel

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BAB III

PERENCANAAN TANGGA

A. Perencanaan Dimensi Plat Tangga dan Bordes1. Ketentuan Umum:

Lebar tangga = 120-200 cm

Lebar bordes = 100-200 cm

Ukuran lebar dan tinggi anak tangga di tentukan dengan rumus

2O + A = 60-65

O : tinggi anak tangga (Otrade! = 16-20 cm

A : lebar anak tangga (Atrade! = 20-"0 cm

#umla$ anak tangga =Selisihtinggilantai

O 1

a

a

1,825

3,65

0,00

Lebar Otrade dan Antrade di$itung dengan rumus : 2%O + A = 60-65

&irencanakan #umla$ Otrade = 11 bua$

Otrade =182,5

11 = 16'50 cm diakai 1) cm = " bua$

#umla$ anak tangga =Selisihtinggilantai

O * 1 =182,5

16,5909 * 1 =

10 bua$

&iambil Antrade = "0 cm

Lebar ordes = 200 cm

#arak tangga ("0%10! = "00 cm

,ek dengan rumus :

2%O + A = 60-65 cm

2%1) + "0 = 6 cm K !

29


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30

tg . =182,5

300 = 0'61

. = arc tg 0'61 = "1'"/"1lebar tangga (0'5 % 6'5! = "22'5 cm

anang ruang tangga (200 + "00! = 500 cm

ebal bordes ($1! = 15 cm

cm262"2'26"1'"/"1cos

"01)

"0%1)%15

.cos

AO

%O%A$

$22

21

22

21

1

2 =+

+

=+

+

=

$2 = 26 cm

$1 = 15 cm

""1'"/"1

A = "0 cm

O = 1) cm


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31

B. #itung Be$an %atuan &ang Be'er(a

1. Plat Tangga

a. ban 3ati (4&L!

- erat sendiri elat tangga (26 cm! = 0'26 % 2 % 1 = 6'2 km

- erat sesi (tebal 2 cm! = 2 % 0'21 % 1 = 0'2 km

- erat keramik (tebal 1 cm! = 1 % 0'21 % 1 = 0'21 km- erat agar besi sisi tangga = 2 % 0'25 = 0'50 km+

4&L1 = )'") km

b% eban 7idu (4LL!

&ari 889U 1/" beban $idu untuk elat tangga (engkel! sebesar 00 kgm2

4LL1 = 00 kgm2= km2


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c% eban Ultimate (4U!

4u1 = 1' % 4&L= 1' % )'")

= 10'"1/ km2

4u2 = 1'2%4&L+ 1'6%4LL= 1'2 % )'") + 1'6 %

= 15'2 km2(terakai!

). Plat Bordes

a% eban 3ati (4&L!

- erat sendiri elat bordes (15 cm! = 0'15 % 2 % 1 = "'60 km2

- erat sesi (tebal 2 cm! = 2 % 0'21 % 1 = 0'2 km2

- erat keramik (tebal 1 cm! = 1 % 0'21 % 1 = 0'21 km2+

4&L2 = '2" km2

b% eban 7idu (4LL!

&ari 889U 1/" beban $idu untuk bordes (engkel! sebesar 00 kgm2

4LL1 = 00 kgm2= km2

c% eban Ultimate (4U!

4u1 = 1' % 4&L= 1' % '2"

= 5'22 km2

4u2 = 1'2%4&L+ 1'6%4LL= 1'2 % '2" + 1'6 %

= 11')6 km2(terakai!

*. Portal

a% eban 3ati (4&L!

;&L1 = )'")


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=

!2"%(5%12

2%2"'!""%2%2%6(

5%12

"%)'") 2222

2

++++

= 12'602)+ "'/0

= 16'550) km

&LA =L

3+A

L

b!!c12(-(Lc%412b!-b(L%4 %&L1&L2

++

=5

550)'16

5

!!2"%21(5("%")')!2%215(2%2"'

++

= 1"'010 * "'"101

= 10'00 k

&L =L

3+A

L

c!12-(Lc%4c!!(12b-b(L%4 %&L1&L2+

++

=5

550)'16

5

!"%215("%)'")!!"2%21(5(2%2"'+

++

= 1)'160 + "'"101

= 20')1 k

b% eban 7idu (4LL!

4LL1 =


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34

LLA =L

3+A

L

b!!(12%c-c(L%412b!-b(L%4 LL1LL2

++

=5

10'5)

5

!!2"%21(5("%!2%215(2%

++

= 10 * 2'11

= )'/ k

LL =L

3+A

L

12%c!-c(L%4c!!(12b-b(L%4 LL1LL2+

++

=5

10'5)

5

!"%215("%!!"2%21(5(2%+

++

= 10 + 2'11

= 12'11 k

c% eban er>aktor

4u1 = 15'2


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35

=5

"6'))/1

5

!!2"%21(5("%15'2!2%215(2%11')6

++

= "2'0/12 * )'"556 = 2')256 k

=L

3+A

L

12c!-c%(L%4c!!(12b-b(L%4 U1U2+

++

=5

"6'))/1

5

!"%215("%15'2!!"2%21(5(2%)6'11+

++

= "6'602/ + )'"556

= "'5/ k

d% 3omen-momen

41 = A% ? % b * ? % 4u2 % ( ? % b!2

= 2')256% ? % 2 * ? % 11')6% (?% 2!2

= 1/'/)6 km42 = A % b * ? % 4u2 % b

2

= 2')256% 2 * ? % 11')6% 22

= 26'2 km4" = % 1" c * ? % 4u1 (1" c!

2- 3A= "'5/% 1" % " * ? % 15'2 (1"% "!2* "6'))/1

= -0'1) km

4 = % ? c * ? % 4u1 (12c!

2

- 3A = "'5/% ? % " * ? % 15'2 (12 % "!2* "6'))/1

= 12'01 km

@(4u1%c! - (15'2% "! * "'5/ = 1'))"6 k

c=3 m

b= 2 m


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36

x '

1,7736 =cx '

RB

x '

1,7736 =3x '

43 ,9584

"'5/ B = 5'"20/ * 1'))"6 B5')"2 B = 5'"20/

B = 0'116"

= b + B

= 2 + 0'116"

= 2'116" m

45 = A % * 4u2 % b (12 % b + B! * ? % 4u1 % (B!2

= 2')256% 2'116" * 11')6% 2(12 % 2 + 0'116"! * 12% 15'2 (0'116"!2

= 26'602 km

C. Penulangan Tangga

1% 8er$itungan ulangan Lentur&iakai momen terbesar Caitu :

3u = "6'))/1 km&iakai diameter tulangan okok =12 mm

Delimut beton = 20 mm

$ = 150 mm

d = $ * 8b *1

2

= 150 * 20 -1

2 %12

= 12 mm

3n =

mm10%)26'-5km)26'-5/'0

"6'))/1

0'/

3u 6===

b =

>C600

600%

>C

c%>E%%%/5'0

+

karena >Bc = "5 3a F"0 3a' maka:

= 0,850,05.( f ' c30)

7


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= 0,850,05.(3530)

7=0.8143

b = 0'/5 % 0'/1"%

35

240 %

600

600+240

= 0'0)21

maks = 0')5 %b

= 0')5 % 0'0)21

= 0'051

min = =1,4

fy =1,4

240 = 0'005/

m =fy

0,85 . f ' c =240

0,85.35 = /'06)2

Rn =

Mn

b .d2 = 1000 .124

2 = 2'/

perlu =1

m [112.m.Rnfy ]

=1

8,0672 [112 .8,0672 .2,9899240 ]

= 0'01"2

&ari $itungan rasio tulangan (! di atas dierole$:

max= 0'051

min= 0'005/ DCarat : min GGmaks


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perlu= 0'01"2

karenaperlu Fmin' diakaiperlu= 0'01"2

Asperlu =perlu% b % d

= 0'01"2% 1000 % 12

= 16"6'/ mm2

&iakai tulangan H = 12 mm

Luas tulangan (A! = I % % &2

= I % % 122

= 11"'0)" mm2

#arak tulangan (D! =A . b

Asperlu

=113,0973 .1000

1636,8

= 6'066 mm

&iakai arak tulangan )0 mm

#umla$ tulangan (n! ada setia 1000 mm (1 m! =1000

70 = 1'2/5) J 15 bua$


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= 166'6 % 20

= 0)150'

DCarat:

,c = s

2)50 a = 0)150'

a =407150,4

29750

= 1"'6/5) mm3ntotal = s % (d * ? % a!

= 0)150' % (12 * ? % 1"'6/5)!

= ))005/0' mm= )')006 km

3ntotal = )')006 km F 3n =

)26'-5

km Ok

2% 8er$itungan ulangan agi

Asperlu 0'001/ % b % $

0'001/ % 1000 % 150

2)0 mm2

&iakai tulangan H = 10 mm

Luas tulangan (A! = I % % &2

= I % % 102

= )/'5"/ mm2

#arak tulangan bagi (D! =A . b

As perlu

=78,5398 .1000

270

= 20'///1 mm

&iakai arak tulangan 250 mm

#umla$ tulangan (n! ada setia 1000 mm (1 m! =1000

250 = bua$


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As =1

4 % K % H2%

1000

s

=1

4 % K % 102%

1000

250

= "1'152 mm2 F Asperlu= 2)0 mm2 Ok#adi tulangan bagi tangga diakai H10 * 250

D. #itungan Pondasi

= 8>= &L+ LL

= 20')1 + 12'11

= "2'5/1 k

= "25/'1 kg

ilai tana$ = (0'1 * 1'0! kgcm2

&iambil tana$= 1 kgcm2= 100 km2' maka :

A>ondasi =P

=32

,6712

100

= 0'"26) m2

Untuk 1 m anang :

L

A=fB

m0'"26)1

0'"26)==fB


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0,30 m

H = 1 m

0,60 m

41

cm0"m"'06'02

1

2

1==== xBxb ff

J diambil 60cm

2

!%( HbBA

ff +=

2

!%"%06%0("26)'0

H+=

mmH 1)26'00'

65"'0==

0'65" = 0' 7

=fB =fb

&itetakan ukuran ondasi :

b> = 0'" m

> = 0'6 m

batukaliff LHbB %%!%%(2

1+

7 = 1 m


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1'2%1%1!%"'06'0%(2

1+

erat sendiri ondasi (8bs! =

=

= 0'5 on = 5 kg

erat total (8! = 8>+ 8bs

= "25/'1 + 5

= 20"'1 kg

ondasi baNa$ = 0'6 m = 60 cm

c. &iakai tinggi >ondasi = 1'0 m = 100 cm

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