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3.b Absolute Bioavaibility (F) F=¿¿ F= 528 ng.h / ml 1289ng.h / ml x 500 ng 500 ng F= 528 ng.h / ml 1289ng.h / ml F=0.4 Klirens total (Cl) Cl= D 0 IV ¿¿ Cl= 500 ng 1289 ng.h / ml Cl= 0.38ml / h Obat dalam plasma pada saat diserap pada 92% k= 0.693 3.9 h k=0.17 h −1 92% obat diabsorbsi D 0 = 92% x 500 ng D 0 = 460 ng C 0 = D 0 V C 0 = 460 ng 234 L C 0 =1.96 ng / L log Cp = k.t 2.303 +log C 0 log Cp = ( 0.17 h −1 )( 24 h) 2.303 +log 1.96 ng / L log Cp =1.77+0.29 log Cp =2.06 Cp= 10 ( 2.06) Cp= 2.06 ng / L
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3.b
Absolute Bioavaibility (F)
F=¿¿
F= 528ng .h /ml1289ng .h /ml
x500ng500ng
F= 528ng .h /ml1289ng .h /ml
F=0. 4
Klirens total (Cl)
Cl=D0 IV¿¿
Cl= 500ng1289ng .h /ml
Cl=0.38ml /h
Obat dalam plasma pada saat diserap pada 92%
k=0.6933.9h
k=0.17h−1
92% obat diabsorbsi
D0= 92% x 500 ng
D0= 460 ng
C0=D0
V
C0=460ng234 L
C0=1.96ng /L
logCp= k .t2.303
+logC0
logCp=(0.17h−1)(24h)
2.303+ log 1.96ng/L
logCp=1.77+0.2 9
logCp=2.06
Cp=10(2.06)
Cp=2.06 ng/L