Seorang penemu pikir ia telah mengembangkan katalis baru yang dapat reaksi fase gasCO2 + 4H2 2H2O + CH4Memproses 100% konversi, T1 500C, hitung T2jawab :tabulated dataCO2 4H2 2H2O CH4- Hf (J/g mol)393.5130241.82674.848Hrxn298K = [-74.848 2(241.826)] [4(0) 393.513]= -164.987 J/g mol CO2Hp - HrxCp CO2 = 26,75 + 42,26(10-3)T - 14,25(10-6)T2 Cp H2 = 26,88 + 4,35(10-3)T 0,33(10-6)T2Cp H2O = 29,16 + 14,49(10-3)T 2,02(10-6)T2Cp CH4 = 13,41 + 77,03(10-3)T 18,74(10-6)T2a = [1(13,41) + 2(29,16) 1(26,75) + 4(26,88)]= -62,54b= [1(77,03(10-3)) + 2(14,49(10-3)) 1(42,26(10-3)) + 4(4,35(10-3))]= 46,35(10-3)c= [1(-18,74(10-6)) + 2(-2,02(10-6)) 1(-14,25(10-6)) + 4(-0,33(10-6))]= -7,21(10-6)Hp - Hrx= 773T [-62,54 + 46,35(10-3)T -7,21(10-6) T2] dTHp - Hrx = -62,54T + 46,35(10-3)/2 T2 -7,21(10-6)/3 T3Hp - Hrx = -62,54T + 23,175 (10-3) T2 2,4003(10-6) T3Hp - Hrx = -62,54T + 23,175 (10-3) T2 2,4003(10-6) T3Hp - Hrx = -62,54T + 23,175 (10-3) T2 2,4003(10-6) T3

Hrxn298K = Hp - Hrx-164.987 = -62,54T + 23,175 (10-3) T2 2,4003(10-6) T30= -62,54T + 23,175 (10-3) T2 2,4003(10-6) T3 + 164.987T= T2= T 773T2=