1
2
3
4
π = 1 + (π β 1) (2) π
(π, π)
π = 1
π = 2
π = 3
π = 4
π = 5
5
3
35
3
35
3
35 X 350 mililitros =
1050
35= 30 mililitros de alcohol
6
1
41
3
24
6
24
7
24
8
24
10
5 1 6
7 7 7
5 1 4
7 7 7
4
5
6
1
12
215
12
17
4
5
6
1
12
215
12
13
7
1 β7
12=
12 β 7
12=
5
12
12
12β
7
12=
5
12
5
12(
2
2) =
10
24
3/2
3
8
(1
2) (
3
8) (
8
1) =
24
16
8
24
16=
12
8=
6
4=
3
2
2500ml1
351
=2500 ml
35=
500
7= 71.429 ml
9
π = 3/2
(3 + 2 = 5)
80/5 = 16
10
(π΄ = ππ) π΄
π΄ π π΄
π΅ π΄
Mosaicos tipo π΅
Mosaico tipo π΄
5 m
3 m
3 m
11
π΄
π΄ π΅
12
π΄ π΅
π΄ π΅
π΄ π΅
π΄ π΅
π΄
5π΄ + 1 = π΅
π΄
π΅ = 5(64) + 1; π΅ = 320 + 1; π΅ = 321
13
π
π π
ππ
π
π
π = ππ + π
π = 3000
π = 4 000 β 3 000 = 1 000
π¦ = 3 000π₯ + 1 000
π
π
π
π
π¦ = 3000(1) + 1000 π¦ = 3000 + 1000 π¦ = 4000
π¦ = 3000(2) + 1000 π¦ = 6000 + 1000 π¦ = 7000
π¦ = 3000(3) + 1000 π¦ = 9000 + 1000 π¦ = 10,000
14
26, 56, 86, 116, β¦.
π
15
2
3
2
31
2(π₯ β
2
3π₯) =
1
2(
1
3π₯) =
1
6π₯
2
3π₯ +
1
6π₯ = 20 litros
2(2π₯)+ 1π₯
6π₯ 4π₯ + π₯ = 6(20)
5π₯ = 120 π₯ =120
5π₯ = 24 πππ‘πππ
π₯
π΄1π₯ + π΅1π¦ = πΆ1
π΄2π₯ + π΅2π¦ = πΆ2
16
π₯
π¦
π₯
π¦
3π₯ + π¦ = 36
π₯ + 4π¦ = 56
(β3)
(β3)(π₯ + 4π¦) = (56)(β3)
β3π₯ β 12π¦ = β168
β3π₯ β 12π¦ = β168
3π₯ + π¦ = 36
β11π¦ = β132
π¦ =132
11
π = ππ
π₯ = (36 β π¦
3) = (
36 β 11
3) =
24
3= 8
π₯ π¦
17
18
π₯
π₯2 = 902 + 902
π₯ = β8100 + 8100
π₯ = β16200
π₯ = 127.27 pies
π₯ = 127.27 pies
π΄ =(π π)
2
π = 5π = (5)(6) = 30 cm
π΄ =(30)(4)
2= 60 cm2
π₯
90
90
19
20
21
β10
β10
π π
π2 = π2 + π2 π2 = π2 + π2
π = βπ2 + π2
π = βπ2 β π2
π = βπ2 β π2
π
π
π π
π
π
22
π
π = β1 + 9
π = β10
β10
3
1
23
π₯
2=
π₯ + 8
4
16
2
π β(4)2 β(16)
3β
π β(2)2 β(8)
3
1000
234.572
π1
3πβ(π2 + πβ²2 + ππβ²) πβ²
4 cm
8 cm
X cm
24
5
12
15
8
15 aΓ±os
14 aΓ±os
13 aΓ±os
12 aΓ±os
25
30Β°
45Β°
72Β°
288Β°
40
5=
360
π₯π₯ =
(360)(5)
40 =
1800
40 = 45
π·π =|11β12|+|11β11|+|11β11|+|11β10|+|11β11|
5=
2
5= 0.4
26
πΆπ΅πΈ π΄π΅π· π΄π΅πΆ π΄π΅π·
π΅π΄πΆ π΄πΆπ΅
π΅π΄πΆ = 30Β° π¦ π΄πΆπ΅ = 30Β°
π΅π΄πΆ = 60Β° π¦ π΄πΆπ΅ = 30Β°
π΅π΄πΆ = 60Β° π¦ π΄πΆπ΅ = 60Β°
π΅π΄πΆ = 30Β° π¦ π΄πΆπ΅ = 60Β°
π₯ + 2π₯ + 3π₯ = 180 π₯ = 30 π΅π΄πΆ = π₯ π΄πΆπ΅ = 2π₯
π΅π΄πΆ = 30 π΄πΆπ΅ = 60
27
1.5
π₯=
0.6
20π₯ =
(20)(1.5)
0.6=
30
0.6 = 50 π
28
29
ππππππππππΓ³π πππππβππππππππππΓ³π πππππππ
π‘πππππ πππππβπ‘πππππ πππππππ=
750β950
5β1=
β200
4= β50
π¦ = β50π₯ + 1000
π¦ = β50(8) + 1000 = 600
(π₯)
(π¦)
30
π₯
π¦ = 5π₯ + 15
31
Dulces vendid
Mes
32
π π£πππ‘π πππππβπ£πππ‘π πππππππ
π‘πππππ πππππβπ‘πππππ πππππππ
π
π =π£πππ‘π πππππβπ£πππ‘π πππππππ
π‘πππππ πππππβπ‘πππππ πππππππ
700β200
3β1=
500
2=
250
1
π
π₯
π₯2 + 3π₯ + 8
π₯2 + 4π₯ + 7
π₯2 + 5π₯ + 3
π₯2 + 6π₯ + 2
33
π₯2 + 6π₯ + 2
o
o
o
π
π
π
π
π¦ = 15π₯
π¦ π₯
34
π = 3π₯ + 8
π₯
25
40+
15
40= 1
π = 3π₯ + 8
π = 3(1) + 8 = 3 + 8 = 11
π = 3(2) + 8 = 6 + 8 = 14
π = 3(3) + 8 = 9 + 8 = 17
π = 3(4) + 8 = 12 + 8 = 20
π = 3(5) + 8 = 15 + 8 = 23
35
36
37
38
39
40
41
42
45
46
47
48
49
LAS TIC
SON
INCLUYEN TecnologΓas
desarrolladas para INFLUYEN
PERMITEN
las tecnologΓas para almacenar
informaciΓ³n y recuperarla despuΓ©s
la adquisiciΓ³n el almacenamiento la producciΓ³n
el tratamiento la comunicaciΓ³n el registro
en el avance educativo
y social
DE LA INFORMACIΓN A
TRAVΓS DE IMΓGENES,
SONIDO Y VIDEOS
50
51
52
24
5
35
7
5
1
60
10
2/3
1/4
1/3
2/7
7/7
4/12
1/12
π¦ π₯
π¦ = 150π₯ β 1500
π¦ = 150π₯ + 1500
π¦ = 1500π₯ β 20 000
π¦ = 1500π₯ + 150
π΄ 2π₯2 +ππ₯2
2
π΄ 3π₯ +ππ₯2
4
π΄ 3π₯ +ππ₯2
2
π΄ 2π₯2 +ππ₯2
4
π₯ 2π₯
1/π₯ 1/2π₯
2π₯
π₯
π₯ + π¦ = $5000
( π₯ + 0.1π₯) + ( π¦ + 0.15π¦) = $ 5560
(π = 3.14).
π΄ π΅
πΆ
π΄ π΅
πΆ = 5π₯ β 4
2π₯ + 11 4π₯ + 8
π΅ π΄
π΅πΆ
π΅πΆ
A)
B)
C)
D)
π΄
πΈ
πΆ
π·
π΅
50
40
20
π₯
0
10
20
30
40
50
60
Grande Mediana Chica
Tallas de uniformes
15
55
30
π = 2700 + 38π₯
π = 2700 + 8π₯
π = 2700 + 8π₯
π = 2700 + 38π₯
A) 3/10
1/2
C) 2/5
D) 7/10
DegustaciΓ³n
π₯
A) π₯2 + 3π₯ + 8 B) π₯2 + 4π₯ + 7 C) π₯2 + 6π₯ + 2 D) π₯2 + 5π₯ + 3
π‘
A) π‘2
B) 2π‘
C) 2π‘
D) π‘ + 2
π = 3.14
9
1512
8
4
0
5
10
15
20
NΓΊm Alumnos
NΓΊm Alumnos
3
1
39
11
3
2
37
13
1/5
3/8 1/4
1. AnΓ‘lisis grΓ‘fico de tendencia de obesidad en niΓ±os de 1er aΓ±o de primaria. Mexicali, B.C.
2. AnΓ‘lisis grΓ‘fico de tendencia de obesidad en niΓ±os de 5to aΓ±o de primaria. Mexicali, B.C.
3. AnΓ‘lisis grΓ‘fico de tendencia de obesidad en niΓ±as de 1er aΓ±o de primaria. Mexicali, B.C.
4. AnΓ‘lisis grΓ‘fico de tendencia de obesidad en niΓ±as de 5to aΓ±o de primaria. Mexicali, B.C.
DESNUTRICIΓN NORMAL SOBREPESO
CATEGORΓA POR PESO
DESNUTRICIΓN NORMAL SOBREPESO
CATEGORΓA POR PESO
DESNUTRICIΓN NORMAL SOBREPESO
CATEGORΓA POR PESO
DESNUTRICIΓN NORMAL SOBREPESO
CATEGORΓA POR PESO
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