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Transcript of Modelling the motion of a falling styrofoam cup
Sreenidhi International School Physics Extended Essay
Candiadate Name: Baig Mirza Amanullah Candidate number: 004976-0013
1
MODELLING THE
MOTION OF A FALLING
STYROFOAM CUP
Subject : Physics.
Topic: Mechanics.
Candidate name: Baig Mirza Amanullah
Candidate number: 004976-0013
Supervisor name: Gyaneshwaran Gomathinayagam.
School: Sreenidhi International School.
Word count:
Sreenidhi International School Physics Extended Essay
Candiadate Name: Baig Mirza Amanullah Candidate number: 004976-0013
2
Abstract
The falling motion of a Styrofoam cup was modelled using a simulation which I programmed in
Vpython1.
An empty Styrofoam cup was dropped and its motion was compared with the predicted motion of
three models. The first model ignored the effects of friction and considered only free fall motion.
The second model added the effects of laminar drag force along with gravitational force. The third
model added the effects of turbulent drag force along with gravitational force. The second model
consisting of laminar drag force and gravitational force matched the actual motion of the
Styrofoam cup best and the predicted terminal velocity matched very closely with the actual
terminal velocity of the Styrofoam cup. The laminar drag coefficient b of the model was
0.00325 kg and the predicted terminal velocity of 1.22 ms-1
matched the terminal velocity value of
1.22 ms-1
measured using TRACKER analysis. The model was also used to make predictions
about the motion of the Styrofoam cup if it had been thrown down with non-zero velocities or if it
had some mass placed inside it.
(Word Count 199)
1 Scherer, David. "Vpython 3D Programming for Ordinary Mortals." Vpython. National Science Foundation,
1 Jan. 2000. Web. 13 Mar. 2015. <http://vpython.org/>.
Sreenidhi International School Physics Extended Essay
Candiadate Name: Baig Mirza Amanullah Candidate number: 004976-0013
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Table of Contents Abstract ........................................................................................................................................................... 2
List of Figures .................................................................................................................................................. 4
List of Tables.................................................................................................................................................... 5
Acknowledgement .......................................................................................................................................... 6
Introduction .................................................................................................................................................... 7
Investigation ................................................................................................................................................... 7
Vpython program to model the motion of the Styrofoam cup ………………………………………………………9
Discussion of Results..................................................................................................................................... 15
Comparision of position vs time for actual and predicted data……………………………………………………15
Predicted drag force and net force vs time………………………………………………………………………………….16
Predicted velocity vs time for different initial velocities (under drag force)…………………………………17
Predicted velocity vs time for different masses kept inside Styrofoam cup (with drag force)………18
Conclusion ..................................................................................................................................................... 19
Evaluation ..................................................................................................................................................... 19
Bibliography .................................................................................................................................................. 20
Appendix ....................................................................................................................................................... 20
Raw Data .................................................................................................................................................... 20
Sreenidhi International School Physics Extended Essay
Candiadate Name: Baig Mirza Amanullah Candidate number: 004976-0013
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List of Figures Figure 1: Screenshot of TRACKER software being used to track the position of the styrofoam cup while
falling ............................................................................................................................................................... 8
Figure 2: Comparison of position vs time of actual and predicted data ....................................................... 15
Figure 3: Predicted drag force and net force vs time .................................................................................... 16
Figure 4: predicted velocity vs time graph for different initial velocities (considering drag force) .............. 17
Figure 5: Predicted velocity vs time graphs for different masses kept inside the styrofoam cup (considering
drag force) ..................................................................................................................................................... 18
Sreenidhi International School Physics Extended Essay
Candiadate Name: Baig Mirza Amanullah Candidate number: 004976-0013
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List of Tables Table 1 Position and velocity data of Styrofoam cup obtained from TRACKER analysis of the video of the
falling cup. ..................................................................................................................................................... 20
Table 2 Position and velocity data of Styrofoam cup obtained from Vpython simulation of the falling
Styrofoam cup for the model with drag force and gravitational field. ......................................................... 24
Sreenidhi International School Physics Extended Essay
Candiadate Name: Baig Mirza Amanullah Candidate number: 004976-0013
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Acknowledgement
I am very grateful to my supervisor Mr. Gyaneshwaran G for his guidance in completing the
extended essay.
I would like to thank my physics teacher Mr. Thavamani T for his guidance.
Sreenidhi International School Physics Extended Essay
Candiadate Name: Baig Mirza Amanullah Candidate number: 004976-0013
7
Introduction
Every evening our school provides snacks in Styrofoam cups. I felt it would be interesting to
model its falling motion when it is dropped from a height. Styrofoam cup is very light and so will
experience the effects of air resistance significantly.
Air resistance is typically considered to be of two types – laminar drag and turbulent drag. In the
real world, for low speeds, laminar drag dominates, and for high speeds, turbulent drag dominates,
but mostly it is a mix of both. Thus, the best model should include the effects of both drag forces
in the model. However, I’ve only tried to use one of the drag forces at a time and tried to find out
which drag force fits the actual motion of the falling Styrofoam cup best.
The magnitude of turbulent drag force is given by the equation �� = −�|�|� where b is called the
drag coefficient. Thus, turbulent drag force is proportional to the square of the magnitude of the
velocity of the object.
The magnitude of laminar drag force is given by the equation � = −�|�| where b is again the
drag coefficient. Here, laminar drag force is proportional to the magnitude of the velocity of the
object.
Investigation
I took a video of the falling motion of a Styrofoam cup by dropping it from a height. I took the
usual precautions like keeping the camera surface parallel to the plane of the motion of the
Styrofoam cup, and ensuring that there was no side wind. I used an iphone to take the video in
slow motion mode. Slow motion mode lets us take videos in more frames per second. So we can
capture the position data at shorter time intervals.
Sreenidhi International School Physics Extended Essay
Candiadate Name: Baig Mirza Amanullah Candidate number: 004976-0013
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After taking the video, I opened the video file in TRACKER software2.
Figure 1: Screenshot of TRACKER software being used to track the position of the styrofoam cup while falling
After loading the video in TRACKER, the first step is to choose the starting and ending frame of
the relevant motion to be tracked. Then using the meter scale in the background, I calibrated the
video using the calibration stick. Then I set the coordinate system with the origin at the point of
release of the Styrofoam cup. So the Styrofoam cup falls along the negative y axis after it is
dropped.
Then I created a ‘point mass’ to track the bottom-center of the Styrofoam cup’s position through
each frame by SHIFT+Click again and again, until I reached the last frame of the selected portion
2 Brown, Douglas. "Tracker Video Analysis and Modeling Tool for Physics Education."Tracker
Video Analysis and Modeling Tool for Physics Education. Open Source Physics, 1 Jan. 2015. Web.
13 Jan. 2015.
Sreenidhi International School Physics Extended Essay
Candiadate Name: Baig Mirza Amanullah Candidate number: 004976-0013
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of the video which I decided to track. The y position, and y components of velocity and
acceleration are automatically generated in the table and can be copy pasted onto a spreadsheet.
The graph which I got for the position of the Styrofoam cup can be seen in the above screenshot.
Vpython program to model the motion of the Styrofoam cup
I wrote the following program in Vpython to model the motion of the Styrofoam cup with gravity,
with gravity and laminar drag, and with gravity and turbulent drag.
# STARTUP (Don't edit, typically)
from __future__ import division, print_function
from visual import *
from physutil import *
import csv
# VISUALIZATION & GRAPH INITIALIZATION
# ===========================================
# Setup window for plotting
pos_graph = PhysGraph(1)
vel_graph = PhysGraph(1)
# Setup Display window for visualization
scene = display(width = 700, height = 700, background = color.white, range = 10, title
= "Styrofoam cup falling model")
scene.autoscale = 0
#scene.center = (0,-6,0)
scene.center = (0,0,0)
# Create object for visualization
cup = sphere(color = color.blue, radius = 0.3, pos = (0,15,0))
# Create a track behind object to visualize trajectory
trail = curve(color = color.green, radius = 0.06)
Sreenidhi International School Physics Extended Essay
Candiadate Name: Baig Mirza Amanullah Candidate number: 004976-0013
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# Create small sphere to mark the origin in Display window
origin = sphere(pos=vector(0,0,0), color = color.black, radius = 0.1)
# Create arrows to represent vector quantities in the Display window
DragForce_arrow = arrow(pos=cup.pos, axis = (0,0,0), color = color.black);
Weight_arrow = arrow(pos=cup.pos, axis = (0,0,0), color = color.red);
# SYSTEM PROPERTIES and INITIAL CONDITIONS
# ===========================================
# System Mass
#EDIT THIS (next one line):
cup.m = 0.0005
#cup.m = 0.0005+0.0041 # mass of crocodile clip = 4.1+-0.2 g
#Initial Conditions
#EDIT THIS (next three lines, as necessary)
cup.pos = vector(0,0,0)
cup.vel = vector(0,0,0)
#cup.vel = vector(0,-1.4,0) #setting non-zero downward initial velocity
#cup.vel = vector(0,1,0) # setting non-zero upward initial velocity of 1 m/s
#cup.vel = vector(0,10,0) # setting non-zero upward initial velocity of 10 m/s
t = 0 #the time when we choose to start our clock
# OTHER INITI#ALIZATION
# ===========================================
Sreenidhi International School Physics Extended Essay
Candiadate Name: Baig Mirza Amanullah Candidate number: 004976-0013
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#
#Timestep
#EDIT THIS (next one line, as necessary)
#deltat = 0.001
deltat=0.008
#Interaction Initialization
#unit vector of velocity
vhat=cup.vel.norm()
#proportionality constant, b, for magnitude of drag force
b=0.00325
#b=0
#proportionality constant, g, for magnitude of weight force
#set g to magnitude of gravitational field near earth's surface
g=9.8
#g=3.6314 modified g based on acceleration observed in experimental data
#unit vector for y axis---choose "up" as direction of +y axis
jhat=vector(0,1,0)
#constant weight force acting downwards on styrofoam cup
w=-cup.m*g*jhat
Fd=vector(0,0,0)
Fnet=vector(0,0,0)
#OPTIONAL: Output model predictions to file (.csv format)
#To use, uncomment next five lines (delete leftmost # ONLY)
outputfile = open('Lab2_StyrofoamCupFalling_v01.csv', 'w') # Set name of output file.
Sreenidhi International School Physics Extended Essay
Candiadate Name: Baig Mirza Amanullah Candidate number: 004976-0013
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# # NOTE: if the file already exists,
# # it will be overwritten
DataWriter = csv.writer(outputfile, delimiter=',', lineterminator='\n',quotechar='|',
quoting=csv.QUOTE_MINIMAL) # Create writer object
DataWriter.writerow(['Time (s)','Position (m)','Velocity (m/s)','Drag force (N)','Net
force (N)']) # Write column headers for time, position, and velocity
DataWriter.writerow([t,cup.pos.y,cup.vel.y,Fd.y,Fnet.y])
#print(t,cup.pos.y)
#Update the object's track
trail.append(pos = cup.pos)
#Plot something as a function of time
#EDIT THIS (next one line, as necessary)
pos_graph.plot(t,cup.pos.y)
vel_graph.plot(t,cup.vel.y)
# CALCULATION LOOP(Motion Prediction and Visualization)
# ===========================================
while t < 1.58125:
#turbulent drag force proportional to square of velocity and directed opposite to
it
Fd = -b*cup.vel.mag2*vhat
print ("Fd=",Fd,"w=",w,"vhat=",vhat)
#Calculate Net Force
#EDIT THIS (next one line; add more lines if necessary)
Fnet = w + Fd
#Predict new velocity (Insert Newton's 2nd Law here)
#EDIT THIS (next one line)
cup.vel = cup.vel + (Fnet/cup.m)*deltat
vhat=cup.vel.norm()
#Predict new position
Sreenidhi International School Physics Extended Essay
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13
#EDIT THIS (next one line)
cup.pos = cup.pos + cup.vel*deltat
# advance the clock
t = t + deltat
print(t,cup.pos.y)
DataWriter.writerow([t,cup.pos.y,cup.vel.y,Fd.y,Fnet.y])
#Update the object's track
trail.append(pos = cup.pos)
#EDIT THIS: Draw arrows to show quantities of interest
DragForce_arrow.pos = cup.pos;
Weight_arrow.pos = cup.pos;
# determines how long to draw arrows to represent vectors; here, the value of
arrowscale tells us what arrow length (in meters) corresponds to a force with a
magnitude of 1 Newton
Force_arrowscale = 2.0/w.mag # max distance available on screen = max[(max(X)-
min(X)),(max(Y),min(Y))] = 1.34e+12 m
# max magnitude of force vector that needs to be
plotted = max(Fnet,Fnetpar,Fnetperp) = 2.79e+25
# scaling factor for the arrows of all force vectors
(all similar quantities should
# be plotted using same scaling factor so that we can
compare their magnitudes by
# observing their relative lengths) = max distance
available on screen/max magnitude of force vector
# So I obtained arrowscale1 = 1.34e+12/2.79e+25 =
4.80e-14, which is PERFEECCCCT!
DragForce_arrow.axis = Fd*Force_arrowscale;
Weight_arrow.axis = w*Force_arrowscale;
#Plot something as a function of time
#EDIT THIS (next one line, as necessary)
pos_graph.plot(t,cup.pos.y)
Sreenidhi International School Physics Extended Essay
Candiadate Name: Baig Mirza Amanullah Candidate number: 004976-0013
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vel_graph.plot(t,cup.vel.y)
#To speed up or slow down program execution
#Edit next line (larger number, faster execution)
rate(20)
#OPTIONAL: Output model predictions to file (.csv format)
#To use, uncomment next line
outputfile.close()
The part of the code which has the important physics equations is made bold.
The logic of the program is as follows:
The program assigns a sphere to represent the Styrofoam cup. So, the mass of the Styrofoam cup
is assigned to this sphere. The motion of this sphere will represent the motion of the Styrofoam
cup. Its initial conditions are set as zero velocity and its initial position is set as origin. The
acceleration value due to gravity, g is set as 9.8 ms-2
.
A loop condition is started and made to last for the duration of the video motion which we tracked.
The time of the last frame in our video is 1.58125 s. So we’ll run the loop by incrementing the
time in small intervals of deltat=0.008 s, till the final time reaches 1.58125 s. Then the loop ends
and the program stops.
During this loop, before each time the time value is incremented by deltat, the position and
velocity values are updated based on the net force equations and kinematics equations.
For example, let the initial velocity be v. After the time interval of deltat, the new velocity will be
the old velocity v + a*deltat, where a is the acceleration due to the net force acting on the object.
We know that =�� �
� and �� � = � + �� where w = weight force and �� = drag force.
Sreenidhi International School Physics Extended Essay
Candiadate Name: Baig Mirza Amanullah Candidate number: 004976-0013
15
The expressions for weight and drag force are typed in the program. Thus, the new velocity value
is used to update the new position value using new x = v*deltat. Thus, the program keeps updating
the position and velocity of the Styrofoam cup based on the expressions we have typed for weight
force w and drag force Fd.
The correct value of the drag coefficient b is arrived at by trial and error. I ran the program and
generated the data of the velocity as a function of time. The program will output any data we want
as a .csv file which can be opened as a spreadsheet in EXCEL. By comparing this data with the
actual TRACKER data of the Styrofoam cup, I adjusted the value of b till both the data matched.
That’s how I figured out that the drag coefficient must be b = 0.00325.
Discussion of Results
The position and velocity data for the Styrofoam cup obtained from TRACKER analysis of the
video and generated by the Vpython program are in the Appendix.
Figure 2: Comparison of position vs time of actual and predicted data
-14
-12
-10
-8
-6
-4
-2
0
0 0.5 1 1.5 2
y /
m
t / s
yvst
ExperimentalDa
tag=9.8only
Predicted
b=0.00325
Sreenidhi International School Physics Extended Essay
Candiadate Name: Baig Mirza Amanullah Candidate number: 004976-0013
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From the graph, it is clear that the model for drag force matches almost perfectly with the actual
data of position vs time of Styrofoam cup which was obtained from TRACKER analysis. If we
ignore the effects of air resistance, model predicts that the cup would have travelled a much larger
distance in the same time, as shown by the blue curve. The experimental data and the model with
drag force predicts that the slope of the position-time graph will become constant at around 0.5 s.
So that is when its velocity will become constant, in other words, it acquires terminal velocity.
Figure 3: Predicted drag force and net force vs time
From this graph, we can see that the drag force (shown in red) starts from zero, and quickly
reaches a plateau value, after which it remains constant. This means, the object has reached
terminal velocity. The weight force is constant throughout the motion of the object. So this plateau
is reached, when the object stops accelerating because the drag force has become equal to the
weight force in magnitude while being opposite in direction. Thus these two forces cancel each
other out, resulting in zero net force, which is seen by the blue curve. Just when the drag force
reaches its maximum value, the net force reaches zero value, after starting out with maximum
-0.006
-0.004
-0.002
0
0.002
0.004
0.006
0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.8Fo
rce
, N
time / s
Predicted Drag force (N) and Net force (N) vs
time
Fd
Fnet
Sreenidhi International School Physics Extended Essay
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magnitude negative value at the start of the motion. The maximum magnitude negative value of
the initial net force is just equal to the weight of the object.
Figure 4: predicted velocity vs time graph for different initial velocities (considering drag force)
This graph shows the predictions made by the program for the velocity of the Styrofoam cup as a
function of time if the Styrofoam cup were thrown with different initial velocities instead of just
dropping it from rest. To make these new predictions, I don’t have to write any new code in the
program, since the laws of motion and net force equation are still the same. I just have to change
the value of the initial velocity from zero to each of these values like -1 m/s, -1.4 m/s, -2 m/s and -
5 m/s.
We find that for all the cases, the Styrofoam cup is predicted to attain the SAME terminal velocity
of 1.22 ms-1
at nearly the same time of around 0.36 s! If a Styrofoam cup starts with very high
non-zero velocity, it takes the same time to attain terminal velocity as a Styrofoam cup which
starts out with a much lower initial velocity. The reason is that greater initial velocity results in
greater drag force, since turbulent drag force is proportional to square of the magnitude of the
-6
-5
-4
-3
-2
-1
0
0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.8
v m
/s
time t / s
predicted v vs t for different vi [with drag force]
v vs t for vi=-1 m/s [with drag
force]"
v vs t for vi=0 m/s [with drag
force]
v vs t for vi=-2 m/s [with drag
force]
v vs t for vi=-5 m/s [with drag
force]
v vs t for vi = -1.4 m/s [with
drag force]
Sreenidhi International School Physics Extended Essay
Candiadate Name: Baig Mirza Amanullah Candidate number: 004976-0013
18
velocity of the object. So the acceleration is greater and the greater change in velocity happens in
the same time and it attains terminal velocity around the same time.
It would be very interesting to try this out for real and verify these predictions.
Figure 5: Predicted velocity vs time graphs for different masses kept inside the styrofoam cup (considering drag force)
From this graph, we can see that the heavier Styrofoam cup attains terminal velocity much later
than the lighter Styrofoam cup. This makes sense, since the net force will become zero for heavier
cup only when the drag force becomes equal to the much larger weight of the heavier cup. The
drag force will attain this larger value only after attaining the greater velocity as shown by the blue
curve. The lighter cup requires a smaller drag force to cancel its weight, and hence smaller
velocities are sufficient to cause the drag force to cancel the weight, and make the Styrofoam cup
achieve terminal velocity.
It would be interesting to verify this graph by experimental data obtained from video analysis
using TRACKER.
-4
-3.5
-3
-2.5
-2
-1.5
-1
-0.5
0
0 0.5 1 1.5 2
ve
rtic
al
ve
loci
ty,
v /
m/s
time, t / s
predicted v vs t for different masses kept inside
styrofoam cup [with drag force]
m=0.0046: v vs t; with drag
force; vi=0
v vs t; m=0.0005; vi=0; with
drag force
Sreenidhi International School Physics Extended Essay
Candiadate Name: Baig Mirza Amanullah Candidate number: 004976-0013
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Conclusion
1. Vpython is an extremely simple and powerful 3D programming language which can be used to
simulate and model any physics phenomena. The program does the integration numerically to
calculate the new position and velocity based on the net force equation which we feed into the
program. Thus, all we need to know to simulate a real-life situation, is a knowledge of the net
force equation. Unknown constants can be found out by trial and error method by comparing the
output data of the program with the TRACKER data obtained from motion analysis of the videos.
2. The model made many interesting and logically sound predictions about the motion of the
Styrofoam cup in new situations like if it had different non-zero initial velocities and if it had
different initial masses.
Evaluation
1. I should have taken the videos and analysed them using TRACKER and compared the actual
data with the predicted data. That would have been ideal. Unfortunately, I ran out of time.
Tracking the data by clicking the position of the object in each frame is very time-consuming,
especially since the number of frames runs into thousands when we take slow-motion videos at
say, 240 frames per second. So there is tons of raw data to process.
2. The model should incorporate a mix of both types of drag forces to obtain an even better match
with the actual position vs time data of the Styrofoam cup.
3. The model’s predictions for different masses and different initial velocities of the Styrofoam
cup should be verified with actual data.
Sreenidhi International School Physics Extended Essay
Candiadate Name: Baig Mirza Amanullah Candidate number: 004976-0013
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Bibliography Brown, Douglas. "Tracker Video Analysis and Modeling Tool for Physics Education."Tracker Video Analysis
and Modeling Tool for Physics Education. Open Source Physics, 1 Jan. 2015. Web. 13 Jan. 2015.
Scherer, David. "Vpython 3D Programming for Ordinary Mortals." Vpython. National Science Foundation,
1 Jan. 2000. Web. 13 Mar. 2015. <http://vpython.org/>.
Appendix
Raw Data
Table 1 Position and velocity data of Styrofoam cup obtained from TRACKER analysis of the
video of the falling cup.
mass_A y coordinate of position y component of velocity y component of acceleration
time , t / s y / m v_{y} / ms-1 a_{y} / ms
-2
0 0
0.008333 -0.00111 -0.19994
0.016667 -0.00333 -0.13329 0
0.025 -0.00333 -0.13329 -9.14013
0.033333 -0.00555 -0.33323 -6.8551
0.041667 -0.00889 -0.26659 4.570063
0.05 -0.01 -0.19994 -2.28503
0.058333 -0.01222 -0.33323 -11.4252
0.066667 -0.01555 -0.39988 0
0.075 -0.01888 -0.33323 -7.02974
0.083333 -0.0211 -0.47849 -11.7162
0.09125 -0.02666 -0.6152 -2.34325
0.099583 -0.0311 -0.46653 7.02974
0.107917 -0.03443 -0.46653 -2.28503
0.11625 -0.03888 -0.53317 -9.14013
0.124583 -0.04332 -0.59982 -6.8551
0.132917 -0.04887 -0.66647 -9.14013
0.14125 -0.05443 -0.73311 11.42516
0.149583 -0.06109 -0.53317 -4.57006
0.157917 -0.06331 -0.66647 -4.57006
0.16625 -0.0722 -0.79976 -9.14013
0.174583 -0.07664 -0.66647 9.140127
0.182917 -0.08331 -0.73311 -6.8551
0.19125 -0.08886 -0.73311 -11.4252
0.199583 -0.09553 -0.93305 -9.14013
0.207917 -0.10441 -0.93305 18.28025
0.21625 -0.11108 -0.59982 -6.8551
0.224583 -0.11441 -0.93305 0
0.232917 -0.12663 -0.86641 6.855095
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0.24125 -0.12885 -0.53317 9.140127
0.249583 -0.13552 -0.86641 -15.9952
0.257917 -0.14329 -0.79976 -4.57006
0.26625 -0.14884 -0.86641 -11.4252
0.274583 -0.15773 -1.06635 -36.5605
0.282917 -0.16662 -1.39958 2.285032
0.29125 -0.18106 -1.19964 27.42038
0.299583 -0.18661 -0.73311 29.70541
0.307917 -0.19328 -0.79976 -31.9904
0.31625 -0.19994 -1.19964 -9.14013
0.324583 -0.21327 -1.13299 11.42516
0.332917 -0.21882 -0.79976 -4.57006
0.34125 -0.2266 -1.26629 -15.9952
0.349583 -0.23993 -1.19964 0
0.357917 -0.24659 -1.06635 9.140127
0.36625 -0.2577 -1.19964 0
0.374583 -0.26659 -0.9997 -20.5653
0.382917 -0.27436 -1.46623 9.372987
0.39125 -0.29102 -1.16205 21.08922
0.399167 -0.29325 -0.75191 7.02974
0.4075 -0.30324 -1.26629 -35.1487
0.415833 -0.31435 -1.26629 -2.28503
0.424167 -0.32435 -1.26629 -2.28503
0.4325 -0.33546 -1.33294 0
0.440833 -0.34656 -1.26629 11.42516
0.449167 -0.35656 -1.13299 2.285032
0.4575 -0.36545 -1.19964 -4.57006
0.465833 -0.37655 -1.26629 25.13535
0.474167 -0.38655 -0.79976 -9.14013
0.4825 -0.38988 -1.19964 -27.4204
0.490833 -0.40655 -1.59952 -27.4204
0.499167 -0.41654 -1.39958 20.56529
0.5075 -0.42987 -1.39958 6.855095
0.515833 -0.43987 -1.19964 9.140127
0.524167 -0.44987 -1.26629 11.42516
0.5325 -0.46097 -1.06635 0
0.540833 -0.46764 -1.13299 -6.8551
0.549167 -0.47986 -1.33294 -13.7102
0.5575 -0.48985 -1.26629 -2.28503
0.565833 -0.50096 -1.39958 -6.8551
0.574167 -0.51318 -1.39958 2.285032
0.5825 -0.52429 -1.33294 27.42038
0.590833 -0.5354 -0.9997 11.42516
0.599167 -0.54095 -0.9997 2.285032
0.6075 -0.55206 -1.13299 -34.2755
Sreenidhi International School Physics Extended Essay
Candiadate Name: Baig Mirza Amanullah Candidate number: 004976-0013
22
0.615833 -0.55983 -1.39958 -6.8551
0.624167 -0.57538 -1.46623 13.71019
0.6325 -0.58427 -0.9997 20.56529
0.640833 -0.59205 -1.13299 -34.2755
0.649167 -0.60315 -1.59952 -18.2803
0.6575 -0.6187 -1.53288 20.56529
0.665833 -0.6287 -1.13299 25.13535
0.674167 -0.63759 -1.13299 -2.28503
0.6825 -0.64758 -1.19964 -9.14013
0.690833 -0.65758 -1.26629 2.285032
0.699167 -0.66869 -1.19964 -9.37299
0.7075 -0.67758 -1.36711 -9.37299
0.715417 -0.6909 -1.50382 0
0.72375 -0.70201 -1.26629 16.40273
0.732083 -0.71201 -1.19964 -4.57006
0.740417 -0.72201 -1.33294 0
0.74875 -0.73423 -1.26629 -2.28503
0.757083 -0.74311 -1.26629 -6.8551
0.765417 -0.75533 -1.46623 -4.57006
0.77375 -0.76755 -1.33294 18.28025
0.782083 -0.77755 -1.13299 2.285032
0.790417 -0.78643 -1.26629 -15.9952
0.79875 -0.79865 -1.46623 -18.2803
0.807083 -0.81087 -1.53288 -2.28503
0.815417 -0.8242 -1.53288 15.99522
0.82375 -0.83642 -1.26629 11.42516
0.832083 -0.8453 -1.26629 6.855095
0.840417 -0.85752 -1.26629 6.855095
0.84875 -0.86641 -1.06635 4.570063
0.857083 -0.87529 -1.19964 -36.5605
0.865417 -0.8864 -1.66617 -15.9952
0.87375 -0.90306 -1.59952 22.85032
0.882083 -0.91306 -1.13299 38.84554
0.890417 -0.92195 -0.9997 -2.28503
0.89875 -0.92972 -1.13299 -25.1353
0.907083 -0.94083 -1.46623 -4.57006
0.915417 -0.95416 -1.26629 6.855095
0.92375 -0.96193 -1.19964 -4.57006
0.932083 -0.97415 -1.46623 -9.14013
0.940417 -0.98637 -1.33294 13.71019
0.94875 -0.99637 -1.19964 0
0.957083 -1.00637 -1.33294 -27.4204
0.965417 -1.01858 -1.66617 -11.4252
0.97375 -1.03414 -1.59952 13.71019
0.982083 -1.04524 -1.33294 22.85032
Sreenidhi International School Physics Extended Essay
Candiadate Name: Baig Mirza Amanullah Candidate number: 004976-0013
23
0.990417 -1.05635 -1.26629 6.855095
0.99875 -1.06635 -1.19964 4.686493
1.007083 -1.07635 -1.2304 -9.37299
1.015 -1.08634 -1.36711 -23.4325
1.023333 -1.09856 -1.59952 -18.746
1.031667 -1.113 -1.66617 20.56529
1.04 -1.12633 -1.26629 25.13535
1.048333 -1.13411 -1.13299 -2.28503
1.056667 -1.14521 -1.39958 -11.4252
1.065 -1.15743 -1.33294 -9.14013
1.073333 -1.16743 -1.46623 4.570063
1.081667 -1.18187 -1.39958 -2.28503
1.09 -1.19076 -1.33294 9.140127
1.098333 -1.20408 -1.39958 -2.28503
1.106667 -1.21408 -1.26629 -6.8551
1.115 -1.22519 -1.53288 -6.8551
1.123333 -1.23963 -1.46623 22.85032
1.131667 -1.24963 -1.06635 9.140127
1.14 -1.2574 -1.26629 -20.5653
1.148333 -1.27073 -1.53288 -6.8551
1.156667 -1.28295 -1.33294 9.140127
1.165 -1.29295 -1.33294 4.570063
1.173333 -1.30517 -1.33294 -31.9904
1.181667 -1.31516 -1.73282 4.570063
1.19 -1.33405 -1.53288 29.70541
1.198333 -1.34071 -0.93305 22.85032
1.206667 -1.3496 -1.26629 -29.7054
1.215 -1.36182 -1.46623 0
1.223333 -1.37403 -1.26629 20.56529
1.231667 -1.38292 -1.06635 -13.7102
1.24 -1.39181 -1.46623 -18.2803
1.248333 -1.40736 -1.53288 2.285032
1.256667 -1.41735 -1.26629 15.99522
1.265 -1.42846 -1.33294 -4.57006
1.273333 -1.43957 -1.33294 -13.7102
1.281667 -1.45068 -1.53288 11.42516
1.29 -1.46512 -1.26629 20.56529
1.298333 -1.47178 -0.9997 2.285032
1.306667 -1.48178 -1.33294 -13.7102
1.315 -1.494 -1.26629 -7.02974
1.323333 -1.50288 -1.36711 0
1.33125 -1.51621 -1.43547 -7.02974
1.339583 -1.52621 -1.33294 28.11896
1.347917 -1.53843 -1.06635 0
1.35625 -1.54398 -1.13299 -20.5653
Sreenidhi International School Physics Extended Essay
Candiadate Name: Baig Mirza Amanullah Candidate number: 004976-0013
24
1.364583 -1.55731 -1.59952 -18.2803
1.372917 -1.57064 -1.39958 34.27548
1.38125 -1.58064 -0.9997 2.285032
1.389583 -1.5873 -1.26629 -38.8455
1.397917 -1.60174 -1.79946 -11.4252
1.40625 -1.61729 -1.46623 31.99044
1.414583 -1.62618 -1.13299 25.13535
1.422917 -1.63618 -1.13299 -11.4252
1.43125 -1.64506 -1.26629 -20.5653
1.439583 -1.65728 -1.53288 -11.4252
1.447917 -1.67061 -1.46623 13.71019
1.45625 -1.68172 -1.26629 -2.28503
1.464583 -1.69172 -1.46623 -9.14013
1.472917 -1.70616 -1.53288 6.855095
1.48125 -1.71726 -1.26629 11.42516
1.489583 -1.72726 -1.33294 13.71019
1.497917 -1.73948 -1.13299 25.13535
1.50625 -1.74615 -0.79976 0
1.514583 -1.75281 -1.13299 -20.5653
1.522917 -1.76503 -1.26629 -61.6959
1.53125 -1.77391 -1.93276 -11.4252
1.539583 -1.79724 -1.86611 50.2707
1.547917 -1.80502 -0.73311 70.83598
1.55625 -1.80946 -0.73311 -15.9952
1.564583 -1.81723 -1.06635 -27.4204
1.572917 -1.82723 -1.19964
1.58125 -1.83723
Table 2 Position and velocity data of Styrofoam cup obtained from Vpython simulation of the
falling Styrofoam cup for the model with drag force and gravitational field.
Time (s) Position (m) Velocity (m/s) Drag force (N) Net force (N)
0 0 0 0 0
0.008 -0.00063 -0.0784 0 -0.0049
0.016 -0.00188 -0.15648 2.00E-05 -0.00488
0.024 -0.00375 -0.23361 7.96E-05 -0.00482
0.032 -0.00622 -0.30917 0.000177 -0.00472
0.04 -0.00928 -0.3826 0.000311 -0.00459
0.048 -0.01291 -0.45339 0.000476 -0.00442
0.056 -0.01708 -0.5211 0.000668 -0.00423
0.064 -0.02176 -0.58538 0.000883 -0.00402
0.072 -0.02693 -0.64596 0.001114 -0.00379
Sreenidhi International School Physics Extended Essay
Candiadate Name: Baig Mirza Amanullah Candidate number: 004976-0013
25
0.08 -0.03255 -0.70266 0.001356 -0.00354
0.088 -0.03859 -0.75539 0.001605 -0.0033
0.096 -0.04503 -0.80412 0.001854 -0.00305
0.104 -0.05182 -0.84889 0.002101 -0.0028
0.112 -0.05894 -0.88982 0.002342 -0.00256
0.12 -0.06635 -0.92705 0.002573 -0.00233
0.128 -0.07404 -0.96076 0.002793 -0.00211
0.136 -0.08197 -0.99116 0.003 -0.0019
0.144 -0.09012 -1.01847 0.003193 -0.00171
0.152 -0.09846 -1.04294 0.003371 -0.00153
0.16 -0.10698 -1.06477 0.003535 -0.00136
0.168 -0.11565 -1.08422 0.003685 -0.00122
0.176 -0.12446 -1.10149 0.00382 -0.00108
0.184 -0.1334 -1.1168 0.003943 -0.00096
0.192 -0.14244 -1.13034 0.004054 -0.00085
0.2 -0.15158 -1.14231 0.004152 -0.00075
0.208 -0.1608 -1.15285 0.004241 -0.00066
0.216 -0.1701 -1.16214 0.004319 -0.00058
0.224 -0.17946 -1.17031 0.004389 -0.00051
0.232 -0.18888 -1.17749 0.004451 -0.00045
0.24 -0.19835 -1.18379 0.004506 -0.00039
0.248 -0.20787 -1.18932 0.004554 -0.00035
0.256 -0.21742 -1.19417 0.004597 -0.0003
0.264 -0.22701 -1.19841 0.004635 -0.00027
0.272 -0.23662 -1.20213 0.004668 -0.00023
0.28 -0.24627 -1.20539 0.004697 -0.0002
0.288 -0.25593 -1.20823 0.004722 -0.00018
0.296 -0.26562 -1.21072 0.004744 -0.00016
0.304 -0.27532 -1.2129 0.004764 -0.00014
0.312 -0.28504 -1.2148 0.004781 -0.00012
0.32 -0.29477 -1.21646 0.004796 -0.0001
0.328 -0.30451 -1.21791 0.004809 -9.07E-05
0.336 -0.31427 -1.21918 0.004821 -7.92E-05
0.344 -0.32403 -1.22029 0.004831 -6.92E-05
0.352 -0.3338 -1.22125 0.00484 -6.04E-05
0.36 -0.34358 -1.2221 0.004847 -5.27E-05
0.368 -0.35336 -1.22283 0.004854 -4.60E-05
0.376 -0.36315 -1.22348 0.00486 -4.02E-05
0.384 -0.37294 -1.22404 0.004865 -3.51E-05
0.392 -0.38274 -1.22453 0.004869 -3.06E-05
0.4 -0.39254 -1.22496 0.004873 -2.67E-05
0.408 -0.40234 -1.22533 0.004877 -2.33E-05
0.416 -0.41214 -1.22566 0.00488 -2.03E-05
0.424 -0.42195 -1.22594 0.004882 -1.78E-05
0.432 -0.43176 -1.22619 0.004885 -1.55E-05
Sreenidhi International School Physics Extended Essay
Candiadate Name: Baig Mirza Amanullah Candidate number: 004976-0013
26
0.44 -0.44157 -1.2264 0.004886 -1.35E-05
0.448 -0.45138 -1.22659 0.004888 -1.18E-05
0.456 -0.4612 -1.22676 0.00489 -1.03E-05
0.464 -0.47101 -1.2269 0.004891 -8.97E-06
0.472 -0.48083 -1.22703 0.004892 -7.83E-06
0.48 -0.49065 -1.22713 0.004893 -6.83E-06
0.488 -0.50046 -1.22723 0.004894 -5.96E-06
0.496 -0.51028 -1.22731 0.004895 -5.20E-06
0.504 -0.5201 -1.22739 0.004895 -4.53E-06
0.512 -0.52992 -1.22745 0.004896 -3.96E-06
0.52 -0.53974 -1.2275 0.004897 -3.45E-06
0.528 -0.54956 -1.22755 0.004897 -3.01E-06
0.536 -0.55938 -1.22759 0.004897 -2.63E-06
0.544 -0.5692 -1.22763 0.004898 -2.29E-06
0.552 -0.57903 -1.22766 0.004898 -2.00E-06
0.56 -0.58885 -1.22769 0.004898 -1.74E-06
0.568 -0.59867 -1.22772 0.004898 -1.52E-06
0.576 -0.60849 -1.22774 0.004899 -1.33E-06
0.584 -0.61831 -1.22775 0.004899 -1.16E-06
0.592 -0.62813 -1.22777 0.004899 -1.01E-06
0.6 -0.63796 -1.22779 0.004899 -8.80E-07
0.608 -0.64778 -1.2278 0.004899 -7.68E-07
0.616 -0.6576 -1.22781 0.004899 -6.70E-07
0.624 -0.66742 -1.22782 0.004899 -5.84E-07
0.632 -0.67725 -1.22783 0.004899 -5.10E-07
0.64 -0.68707 -1.22783 0.0049 -4.45E-07
0.648 -0.69689 -1.22784 0.0049 -3.88E-07
0.656 -0.70672 -1.22784 0.0049 -3.38E-07
0.664 -0.71654 -1.22785 0.0049 -2.95E-07
0.672 -0.72636 -1.22785 0.0049 -2.57E-07
0.68 -0.73618 -1.22786 0.0049 -2.25E-07
0.688 -0.74601 -1.22786 0.0049 -1.96E-07
0.696 -0.75583 -1.22786 0.0049 -1.71E-07
0.704 -0.76565 -1.22786 0.0049 -1.49E-07
0.712 -0.77548 -1.22787 0.0049 -1.30E-07
0.72 -0.7853 -1.22787 0.0049 -1.13E-07
0.728 -0.79512 -1.22787 0.0049 -9.89E-08
0.736 -0.80494 -1.22787 0.0049 -8.63E-08
0.744 -0.81477 -1.22787 0.0049 -7.53E-08
0.752 -0.82459 -1.22787 0.0049 -6.57E-08
0.76 -0.83441 -1.22787 0.0049 -5.73E-08
0.768 -0.84424 -1.22788 0.0049 -5.00E-08
0.776 -0.85406 -1.22788 0.0049 -4.36E-08
0.784 -0.86388 -1.22788 0.0049 -3.80E-08
0.792 -0.87371 -1.22788 0.0049 -3.32E-08
Sreenidhi International School Physics Extended Essay
Candiadate Name: Baig Mirza Amanullah Candidate number: 004976-0013
27
0.8 -0.88353 -1.22788 0.0049 -2.89E-08
0.808 -0.89335 -1.22788 0.0049 -2.52E-08
0.816 -0.90317 -1.22788 0.0049 -2.20E-08
0.824 -0.913 -1.22788 0.0049 -1.92E-08
0.832 -0.92282 -1.22788 0.0049 -1.68E-08
0.84 -0.93264 -1.22788 0.0049 -1.46E-08
0.848 -0.94247 -1.22788 0.0049 -1.27E-08
0.856 -0.95229 -1.22788 0.0049 -1.11E-08
0.864 -0.96211 -1.22788 0.0049 -9.70E-09
0.872 -0.97194 -1.22788 0.0049 -8.46E-09
0.88 -0.98176 -1.22788 0.0049 -7.38E-09
0.888 -0.99158 -1.22788 0.0049 -6.44E-09
0.896 -1.0014 -1.22788 0.0049 -5.62E-09
0.904 -1.01123 -1.22788 0.0049 -4.90E-09
0.912 -1.02105 -1.22788 0.0049 -4.27E-09
0.92 -1.03087 -1.22788 0.0049 -3.73E-09
0.928 -1.0407 -1.22788 0.0049 -3.25E-09
0.936 -1.05052 -1.22788 0.0049 -2.84E-09
0.944 -1.06034 -1.22788 0.0049 -2.47E-09
0.952 -1.07017 -1.22788 0.0049 -2.16E-09
0.96 -1.07999 -1.22788 0.0049 -1.88E-09
0.968 -1.08981 -1.22788 0.0049 -1.64E-09
0.976 -1.09964 -1.22788 0.0049 -1.43E-09
0.984 -1.10946 -1.22788 0.0049 -1.25E-09
0.992 -1.11928 -1.22788 0.0049 -1.09E-09
1 -1.1291 -1.22788 0.0049 -9.51E-10
1.008 -1.13893 -1.22788 0.0049 -8.29E-10
1.016 -1.14875 -1.22788 0.0049 -7.23E-10
1.024 -1.15857 -1.22788 0.0049 -6.31E-10
1.032 -1.1684 -1.22788 0.0049 -5.50E-10
1.04 -1.17822 -1.22788 0.0049 -4.80E-10
1.048 -1.18804 -1.22788 0.0049 -4.19E-10
1.056 -1.19787 -1.22788 0.0049 -3.65E-10
1.064 -1.20769 -1.22788 0.0049 -3.19E-10
1.072 -1.21751 -1.22788 0.0049 -2.78E-10
1.08 -1.22733 -1.22788 0.0049 -2.42E-10
1.088 -1.23716 -1.22788 0.0049 -2.12E-10
1.096 -1.24698 -1.22788 0.0049 -1.85E-10
1.104 -1.2568 -1.22788 0.0049 -1.61E-10
1.112 -1.26663 -1.22788 0.0049 -1.40E-10
1.12 -1.27645 -1.22788 0.0049 -1.22E-10
1.128 -1.28627 -1.22788 0.0049 -1.07E-10
1.136 -1.2961 -1.22788 0.0049 -9.32E-11
1.144 -1.30592 -1.22788 0.0049 -8.13E-11
1.152 -1.31574 -1.22788 0.0049 -7.09E-11
Sreenidhi International School Physics Extended Essay
Candiadate Name: Baig Mirza Amanullah Candidate number: 004976-0013
28
1.16 -1.32557 -1.22788 0.0049 -6.18E-11
1.168 -1.33539 -1.22788 0.0049 -5.40E-11
1.176 -1.34521 -1.22788 0.0049 -4.71E-11
1.184 -1.35503 -1.22788 0.0049 -4.11E-11
1.192 -1.36486 -1.22788 0.0049 -3.58E-11
1.2 -1.37468 -1.22788 0.0049 -3.12E-11
1.208 -1.3845 -1.22788 0.0049 -2.72E-11
1.216 -1.39433 -1.22788 0.0049 -2.38E-11
1.224 -1.40415 -1.22788 0.0049 -2.07E-11
1.232 -1.41397 -1.22788 0.0049 -1.81E-11
1.24 -1.4238 -1.22788 0.0049 -1.58E-11
1.248 -1.43362 -1.22788 0.0049 -1.38E-11
1.256 -1.44344 -1.22788 0.0049 -1.20E-11
1.264 -1.45327 -1.22788 0.0049 -1.05E-11
1.272 -1.46309 -1.22788 0.0049 -9.13E-12
1.28 -1.47291 -1.22788 0.0049 -7.97E-12
1.288 -1.48273 -1.22788 0.0049 -6.95E-12
1.296 -1.49256 -1.22788 0.0049 -6.06E-12
1.304 -1.50238 -1.22788 0.0049 -5.29E-12
1.312 -1.5122 -1.22788 0.0049 -4.61E-12
1.32 -1.52203 -1.22788 0.0049 -4.02E-12
1.328 -1.53185 -1.22788 0.0049 -3.51E-12
1.336 -1.54167 -1.22788 0.0049 -3.06E-12
1.344 -1.5515 -1.22788 0.0049 -2.67E-12
1.352 -1.56132 -1.22788 0.0049 -2.33E-12
1.36 -1.57114 -1.22788 0.0049 -2.03E-12
1.368 -1.58096 -1.22788 0.0049 -1.77E-12
1.376 -1.59079 -1.22788 0.0049 -1.55E-12
1.384 -1.60061 -1.22788 0.0049 -1.35E-12
1.392 -1.61043 -1.22788 0.0049 -1.18E-12
1.4 -1.62026 -1.22788 0.0049 -1.03E-12
1.408 -1.63008 -1.22788 0.0049 -8.95E-13
1.416 -1.6399 -1.22788 0.0049 -7.81E-13
1.424 -1.64973 -1.22788 0.0049 -6.81E-13
1.432 -1.65955 -1.22788 0.0049 -5.94E-13
1.44 -1.66937 -1.22788 0.0049 -5.18E-13
1.448 -1.6792 -1.22788 0.0049 -4.52E-13
1.456 -1.68902 -1.22788 0.0049 -3.94E-13
1.464 -1.69884 -1.22788 0.0049 -3.44E-13
1.472 -1.70866 -1.22788 0.0049 -3.00E-13
1.48 -1.71849 -1.22788 0.0049 -2.62E-13
1.488 -1.72831 -1.22788 0.0049 -2.28E-13
1.496 -1.73813 -1.22788 0.0049 -1.99E-13
1.504 -1.74796 -1.22788 0.0049 -1.74E-13
1.512 -1.75778 -1.22788 0.0049 -1.52E-13
Sreenidhi International School Physics Extended Essay
Candiadate Name: Baig Mirza Amanullah Candidate number: 004976-0013
29
1.52 -1.7676 -1.22788 0.0049 -1.32E-13
1.528 -1.77743 -1.22788 0.0049 -1.15E-13
1.536 -1.78725 -1.22788 0.0049 -1.01E-13
1.544 -1.79707 -1.22788 0.0049 -8.78E-14
1.552 -1.80689 -1.22788 0.0049 -7.66E-14
1.56 -1.81672 -1.22788 0.0049 -6.68E-14
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