Tugas SCS Tikungan 1

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a) TIKUNGAN I

Vd= 60 km/jam

L jalan= 7 meter (2 arah, 2 lajur)

R= 409 m

= 32,574o

en= 2 %

e max= 10 % (jalan luar kota)

Vd= 60 km/jam

R= 409 m

b) tikungan II (S-C-S)

Vd= 60 km/jam

L jalan= 7 meter (2 arah, 2 lajur)

R= 409 m

= 117,17o

en= 2 %

e max= 10 % (jalan luar kota)

Vd= 60 km/jam

R= 409 m = 786,406 m

= = 695,069 m

= 50 = 49,981 m

Kontrol

Rounding (z) = Ts1 + Ts2 < d2

= 144,571 m + 695,09 m < 854,004 m

= 839,64 m < 8544,004 m okSTATIONING

1.( Tikungan I S-C-S )

d1

= 5000 m

Ts1

= 144,571 m

Ls1

= 50 m

Lc1

= 182,529 m

STA A= 0 + 000 ( awal proyek )

STA TS1= STA A + (d1 Ts1)

= (0 + 000) + (5000 - 144,571)

= (4 + 855,429)

STA SC1= STA TS1 + Ls1

= (4 + 855,429) + 50

= (4 + 905,429)

STA PI1= STA SC1 + Lc1

= (4 + 905,429) + (1/2 * 182,529)

= (4 + 996,694)

STA CS1= STA SC1 + Lc1

= (4 + 905,429) + (182,529)

= (5 + 087,958)

STA ST1= STA CS1 + Ls1

= (5 + 087,958) + (50)

= (5 + 137,958)

Nilai x = ?

2. Tikungan II (S C S )

d2=8544,004 m

d3=9697,534 m

Ts2=695,069 m

Ls2=50 m

Lc2=796,406 m

Sta TS2=Sta ST1 + Rounding

=(5+137,958) + (8544,004 -839,640)

=(5+137,958) + ( 7 + 704,364)

=12 + 842,322

Sta SC2=Sta TS2 + Ls2

=(12+842,322) + 50

=12 + 892,322

Sta PI2=Sta SC2 + . Lc2

=(12+892,322) + ( . 786,406)

=13 + 285,525

Sta ST2=Sta Cs2 + Ls2

=(13+678,701) + 50

=13 + 728,728

Sta B

=Sta ST2 + (d3 Ts2)

=(13+728,701) + (9697,534 695,069)Nilai x = ?

Berdasarkan table bina marga, maka didapat e = 0,048 dan Ls = 50 m

Berdasarkan table bina marga, maka didapat e = 0,048 dan Ls = 50 m