Tugas SCS Tikungan 1
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Transcript of Tugas SCS Tikungan 1
a) TIKUNGAN I
Vd= 60 km/jam
L jalan= 7 meter (2 arah, 2 lajur)
R= 409 m
= 32,574o
en= 2 %
e max= 10 % (jalan luar kota)
Vd= 60 km/jam
R= 409 m
b) tikungan II (S-C-S)
Vd= 60 km/jam
L jalan= 7 meter (2 arah, 2 lajur)
R= 409 m
= 117,17o
en= 2 %
e max= 10 % (jalan luar kota)
Vd= 60 km/jam
R= 409 m = 786,406 m
= = 695,069 m
= 50 = 49,981 m
Kontrol
Rounding (z) = Ts1 + Ts2 < d2
= 144,571 m + 695,09 m < 854,004 m
= 839,64 m < 8544,004 m okSTATIONING
1.( Tikungan I S-C-S )
d1
= 5000 m
Ts1
= 144,571 m
Ls1
= 50 m
Lc1
= 182,529 m
STA A= 0 + 000 ( awal proyek )
STA TS1= STA A + (d1 Ts1)
= (0 + 000) + (5000 - 144,571)
= (4 + 855,429)
STA SC1= STA TS1 + Ls1
= (4 + 855,429) + 50
= (4 + 905,429)
STA PI1= STA SC1 + Lc1
= (4 + 905,429) + (1/2 * 182,529)
= (4 + 996,694)
STA CS1= STA SC1 + Lc1
= (4 + 905,429) + (182,529)
= (5 + 087,958)
STA ST1= STA CS1 + Ls1
= (5 + 087,958) + (50)
= (5 + 137,958)
Nilai x = ?
2. Tikungan II (S C S )
d2=8544,004 m
d3=9697,534 m
Ts2=695,069 m
Ls2=50 m
Lc2=796,406 m
Sta TS2=Sta ST1 + Rounding
=(5+137,958) + (8544,004 -839,640)
=(5+137,958) + ( 7 + 704,364)
=12 + 842,322
Sta SC2=Sta TS2 + Ls2
=(12+842,322) + 50
=12 + 892,322
Sta PI2=Sta SC2 + . Lc2
=(12+892,322) + ( . 786,406)
=13 + 285,525
Sta ST2=Sta Cs2 + Ls2
=(13+678,701) + 50
=13 + 728,728
Sta B
=Sta ST2 + (d3 Ts2)
=(13+728,701) + (9697,534 695,069)Nilai x = ?
Berdasarkan table bina marga, maka didapat e = 0,048 dan Ls = 50 m
Berdasarkan table bina marga, maka didapat e = 0,048 dan Ls = 50 m