Tugas Neraca Energi (2311131029).docx
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Transcript of Tugas Neraca Energi (2311131029).docx
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PENYELESAIAN :
Misalnya :
T = 423 K
Dengan menggunkan rumus antoin
Dit : P & T ?
Jawab :
Mencari P masing-masing Komponen
P(etilen) : ln P = A(-B/t+C)
Ln P= 13.8182(-1427.22/423+(-14.3080)
Ln P= 10.326 kPa
P(Air) : Ln P= 16.5362(-3985.44/423+(-38.9974)
Ln P=6.1575 Kpa
Mencari P (total)
P(total) = P(etilen) * X(etilen) + P(Air) * X(air)
= 10.326 * 0.5 + 6.1575 * 6.1575
= 6.1575
F=1000 mol/menit
V=etilen 99%
L = Air 99%
Etilen = 50% Air = 50%
Mencari K masing-masing komponen :
K(etilen) : = P(etilen)/P(total)
= 10.326/6.1575
= 1.675
K(air) : = P(air)/P(total)
= 6.1575/6.1575
= 1
Mencari V :X1 = Z1/(1+V(K1-1))0.01 = 0.5/(1+V(1.676-1))
0.01+(6.76*10^-3V)=0.5
(6.76*10^-3)=0.5-0,01
V=0.49/(6.76*10^-3)
V = 72.485
Mencari Neraca massa total
F = L + V
100 = L + 72.485
L = 100 - 72.485
L = 27.615 Mol/Menit