tugas metodenumerik
9
1 metode persegi (raimann) h= 0.2 x 0 0.2 0.4 0.6 0.8 1 1.2 f(x) 3 3.952 4.776 5.424 5.848 6 5.832 `= 0,2 ×48,4 9.68 metode trapezoida h= 0.2 x 0 0.2 0.4 0.6 0.8 1 1.2 f(x) 3 3.952 4.776 5.424 5.848 6 5.832 `= h/2(f0+2f1+2f2+.....+fn) `=0,2/2(3+1+2(3,952+4776+5,424+5,848+6+5,832+5,296+4,344+2,928)) = 9.28 metode Simson h= 0.2 x 0 0.2 0.4 0.6 0.8 1 1.2 f(x) 3 3.952 4.776 5.424 5.848 6 5.832 `=0,2/3(3+1+4(3,952+5,424+6 9.33333333 5 metode persegi (raimann) h= 0.2 x 0 0.2 0.4 0.6 0.8 1 1.2 f(x) 0 0.244281 0.59673 1.093271 1.780433 2.718282 3.98414 `= 0,2 ×48,4 9.937349 metode trapezoida ^2▒ 〖− x^3−x^2+5x+3ⅆx 〗 − x^3−x^2+5x+3ⅆx=h.∑24_ =0) ( ( ^▒ _ ) 〗 )+4∑24_ =1)^ −1) ) +2 ( ( ▒( ∑_ = ( 2)^ − ( 2) ) ▒( ] ^2▒ 〖 ⅆx x^ 〗
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Transcript of tugas metodenumerik
1
metode persegi (raimann)h= 0.2
x 0 0.2 0.4 0.6 0.8 1 1.2f(x) 3 3.952 4.776 5.424 5.848 6 5.832
`= 0,2 ×48,4 9.68
metode trapezoidah= 0.2
x 0 0.2 0.4 0.6 0.8 1 1.2f(x) 3 3.952 4.776 5.424 5.848 6 5.832
`= h/2(f0+2f1+2f2+.....+fn)`=0,2/2(3+1+2(3,952+4776+5,424+5,848+6+5,832+5,296+4,344+2,928))
= 9.28
metode Simsonh= 0.2
x 0 0.2 0.4 0.6 0.8 1 1.2f(x) 3 3.952 4.776 5.424 5.848 6 5.832
`=0,2/3(3+1+4(3,952+5,424+6+5,296+4,344)+2(4,776+5,848+5,832+4,344))
9.33333333
5
metode persegi (raimann)h= 0.2
x 0 0.2 0.4 0.6 0.8 1 1.2f(x) 0 0.244281 0.59673 1.093271 1.780433 2.718282 3.98414
`= 0,2 ×48,4 9.937349
metode trapezoida
∫24_0^2▒〖− x^3−x^2+5x+3ⅆx〗
∫24_0^2▒〖− x^3−x^2+5x+3ⅆx=h.∑24_ =0) ((� ^�▒� �_� ) 〗
∆�/3 )+[�(� (� �)+4∑24_ =1)^ −1) ) +2(� (� ▒�(�� ∑_ =(� 2)^ −(� 2) ) ▒�(�� ]
∫24_0^2▒〖 ⅆxx�^� 〗
h= 0.2x 0 0.2 0.4 0.6 0.8 1 1.2f(x) 0 0.244281 0.59673 1.093271 1.780433 2.718282 3.98414
`= h/2(f0+2f1+2f2+.....+fn)`=0,2/2(3+1+2(3,952+4776+5,424+5,848+6+5,832+5,296+4,344+2,928))
= 8.459538
metode Simsonh= 0.2
x 0 0.2 0.4 0.6 0.8 1 1.2f(x) 0 0.244281 0.59673 1.093271 1.780433 2.718282 3.98414
`=0,2/3(3+1+4(3,952+5,424+6+5,296+4,344)+2(4,776+5,848+5,832+4,344))
8.38935587
8
metode persegi (raimann)h= 0.314159
x 0 0,2∏ 0,3∏ 0,4∏ 0,5∏ 0,6∏f(x) 4 4.010966 4.021932 4.032897 4.043861 4.054824 4.065785
`= 0,2 ×48,4 14.01244
metode trapezoidah= 0.314159
x 0 0,2∏ 0,3∏ 0,4∏ 0,5∏ 0,6∏f(x) 4 4.010966 4.021932 4.032897 4.043861 4.054824 4.065785
`= h/2(f0+2f1+2f2+.....+fn)`=0,2/2(3+1+2(3,952+4776+5,424+5,848+6+5,832+5,296+4,344+2,928))
= 12.73858
metode Simsonh= 0.314159
x 0 0,2∏ 0,3∏ 0,4∏ 0,5∏ 0,6∏f(x) 4 4.010966 4.021932 4.032897 4.043861 4.054824 4.065785
`=0,2/3(3+1+4(3,952+5,424+6+5,296+4,344)+2(4,776+5,848+5,832+4,344))
0,1∏
0,1∏
0,1∏
∆�/3 )+[�(� (� �)+4∑24_ =1)^ −1) ) +2(� (� ▒�(�� ∑_ =(� 2)^ −(� 2) ) ▒�(�� ]
∫24_0^π▒(4+2 sin )ⅆx�
∆�/3 )+[�(� (� �)+4∑24_ =1)^ −1) ) +2(� (� ▒�(�� ∑_ =(� 2)^ −(� 2) ) ▒�(�� ]
12.7385846
1.4 1.6 1.8 2 ∑5.296 4.344 2.928 1 48.4
1.4 1.6 1.8 2 ∑5.296 4.344 2.928 1 48.4
1.4 1.6 1.8 2 ∑ untuk rumus yg ini jangan liat materi yang punya pak arif soalny salah. Ikutin rumusyang udah di tulis disini5.296 4.344 2.928 1 48.4
`=0,2/3(3+1+4(3,952+5,424+6+5,296+4,344)+2(4,776+5,848+5,832+4,344))
fungsi integral langsungny 1.4 1.6 1.8 2 ∑ 8.389056
5.67728 7.924852 10.88937 14.77811 49.68675
18.45611
1.4 1.6 1.8 2 ∑5.67728 7.924852 10.88937 14.77811 49.68675
0.840165
1.4 1.6 1.8 2 ∑5.67728 7.924852 10.88937 14.77811 49.68675
`=0,2/3(3+1+4(3,952+5,424+6+5,296+4,344)+2(4,776+5,848+5,832+4,344))
0,7∏ 0,8∏ 0,9∏ ∏ ∑ fungsi integral langsungny 4.076745 4.087702 4.098656 4.109607 44.60298 12.73858
9.999963
0,7∏ 0,8∏ 0,9∏ ∏ ∑4.076745 4.087702 4.098656 4.109607 44.60298
0,7∏ 0,8∏ 0,9∏ ∏ ∑4.076745 4.087702 4.098656 4.109607 44.60298
`=0,2/3(3+1+4(3,952+5,424+6+5,296+4,344)+2(4,776+5,848+5,832+4,344))
fungsi integral langsungny 9.333333 3.952
untuk rumus yg ini jangan liat materi yang punya pak arif soalny salah. Ikutin rumusyang udah di tulis disini
fungsi integral langsungny
fungsi integral langsungny
18 360.314159 0.6283190.314159
