Tugas Geometirk Jalan Januari 2010
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Transcript of Tugas Geometirk Jalan Januari 2010
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8/14/2019 Tugas Geometirk Jalan Januari 2010
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Nama : Rizal Zubad FirdausiSemester : V (lima)NIM : 07.10203.020Mata Kuliah : Geometrik Jalan Raya
Data lapangan: D1 1000 m D2 700 m D3= 500 m D4= 1000 m
PI 1Diketahui: V = 70 Km/jam e= 0.1 Lebar Jalan standart = 2 x3.75 m
9 f= 0.15
Jenis = Full Circle 0.02
Ditanya : Geometrik Jalan tersebut?
Jawab :R min =
127(e+f)
= 156.21 = 157
D max = 181913.53 (e+f)
= 9.17
Lc min = t . v
= 6 x 70 x 1000
3600= 116.67 m
Rc = Lc min . 360 Dari tabel 4.7 bina marga diperoleh:
Ls = 60 m= 743.1 e = 0.04
Tc == 58.48
Ec =
= 2.3
Lc =180
= 116.67
Landai Relatif = Lebar jalan . (e normal + e)
Ls= 0
Data lengkung Circle dari jalan tersebut adalah:V = 70
= 9 Rc = 743.1 mTc = 58.48 mLc = 116.67 m
=
e normal =
V
V
. 2 .
R . tg
T . Tg
. . Rc
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Ec = 2.3 mLs = 116.67 me = 3.7 %
Tugas Geometrik Jalan Raya Smt V
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PI 2
Diketahui: V = 70 Km/jam e= 0.1 Lebar Jalan standart = 2 x3.75 m
14 f= 0.15Jenis = Sp-Cr-Sp 0.02
Ditanya : Geometrik Jalan tersebut?
Jawab :R min = 156.21 = 157 mD max = 9.17Lc min = 116.67 m
R = Lc min x 360 Dari tabel 4.7 bina marga diperoleh:Ls = 60 m
= 477.71 m e = 0.055
= 90 . Ls
. R
= 3.6
P = - R (1 - cos s)6 . R
= 0.31
K = - R . Sin s
= 29.98 m
== 6.8
E = (R + P) sec - R= 3.9 m
T = (R + P) tg + K)= 88.67 m
Lc = L = Lc + 2 Ls180 = 176.67
= 56.67 m
Data-data lengkung Jalan dg jenis Spiral-Circle-Spiral:V = 70 Km/jamR = 477.71 mLs = 60 me = 5.5 %
= 3.6 P = 0.31 mK = 29.98 m
= 6.8
=e normal =
x 2 x
s
Ls
Ls - Ls
40 . R
c - 2 s
c . . R
s
c
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E = 3.9 mT = 88.67 mLc = 56.67 mL = 176.67 m
Tugas Geometrik Jalan Raya Smt V
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PI 3
Diketahui: V = 70 Km/jam e= 0.1 Lebar Jalan standart = 2 x3.75 m
24 f= 0.15Jenis = Spiral 0.02
Ditanya : Geometrik Jalan tersebut?
Jawab :R min = 156.21 = 157 mD max = 9.17Lc min = 116.67 m
Rs = Lc min x 360 Dari tabel 4.7 bina marga diperolehe = 0.078
= 278.66 = 279 m
= 1/2 .
1/2 . 24
= 12.0
Ls =90
= 116.7 m
P = - Rs (1 - cos s)
6 . Rs= 2.05
K = - Rs . Sin s
= 58.22 m
Es = (Rs + P) sec - Rs= 8.32 m
Ts = (Rs + P) tg + K)= 117.89 m
L = 2 . Ls= 233.33 m
Data-data lengkung Jalan dg jenis Spiral-Circle-Spiral:R = 278.66 m
= 24 Ls = 116.7 m
= 12.0 P = 2.05 mK = 58.22 mEs = 8.32 m
=e normal =
x 2 x
s
s . . Rs
Ls
Ls - Ls40 . Rs
s
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Ts = 117.89 mL = 233.33 me = 0.078
Tugas Geometrik Jalan Raya Smt V